Solve UW. how do I get the answer?

Answer:

ok dude

Step-by-step explanation:

Wʜᴇʀᴇ ɪs ǫᴜᴇsᴛɪᴏɴ?

Answer:

what help l don't understand please sorry I didn't help you explain your problem l will help you

Answer:

Step-by-step explanation:

PEMDAS- Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

Answer= -91

Answer:

y = 4x - 3

Step-by-step explanation:

Slope intercept form is made up of these components:

    The question gives you the slope and the y-intercept. Now all you need to do is substitute the values for the variables. Therefore, the equation is y = 4x - 3.

Answer:

Step-by-step explanation:

10 dozen is equal to 120 so ratio is 800/120 or 80/12

same ration on the other side but 200/x.Cross multiply and u get 3

9514 1404 393

Answer:

  3 in

Step-by-step explanation:

Ratios of corresponding sides are equal, so we have the proportion ...

  x/(5 in) = (6 in)/(10 in)

  x = (5 in)(6/10) = 3 in

The missing side (x) is 3 in.

Answer:

i would say true

Step-by-step explanation:

Answer:

6(3) - 4 - 3²

Step-by-step explanation:

(g - f) = 6x - (4 - 2x²)

= 6x - 4 - 2x²

and when we replace x with 3 ,it will be

6(3) - 4 - 3²

hope this helps

Answer:

Basically what the person on top of me said

Step-by-step explanation:

Got it right !

Answer:

25d + 100

Step-by-step explanation:

I will call "d" the days passed

25d + 100

Answer:

-40

Step-by-step explanation:

[tex] \sqrt{5} \times - 4 \sqrt{20} [/tex]

Multiplication is commutative.

[tex] - 4 \sqrt{20} \times \sqrt{5} [/tex]

Apply Profuct Rule

[tex] - 4 \sqrt{100} [/tex]

Simplify sqr root of 100

[tex] - 4 \times 10 = - 40[/tex]

Hi ;-)

√5 · (-4√20) = -4√(5 · 20) =

= -4√100 = -4 · 10 = -40

Answer:

[tex]\displaystyle \lim_{x\rightarrow 0^{+}} \frac{x\ln x}{\tan x}=-\infty\implies \text{B. Nonexistent (best answer)}[/tex]

Step-by-step explanation:

Recall L'Hopital's rule:

[tex]\displaystyle \lim_{x\rightarrow c}\frac{f(x)}{g(x)}=\lim_{x\rightarrow c}\frac{f'(x)}{g'(x)}[/tex]

First derivative of [tex]x\ln x[/tex]:

Recall the product rule:

[tex](f\cdot g)'=f'\cdot g+g'\cdot f[/tex]

[tex]\displaystyle \frac{d}{dx} (x\ln x)=\frac{d}{dx}(x)\cdot \ln (x)+\frac{d}{dx}(\ln x)\cdot x[/tex]

Note that:

[tex]\displaystyle \frac{d}{dx}(x)=1,\\\frac{d}{dx}(\ln (x))=\frac{1}{x}[/tex]

Simplifying, we get:

[tex]\displaystyle \frac{d}{dx} (x\ln x)=1\cdot \ln x+\frac{1}{x}\cdot x,\\\frac{d}{dx}(x\ln x)=\ln x+1[/tex]

First derivative of [tex]\tan x[/tex]:

[tex]\displaystyle \frac{d}{dx}(\tan x)=\sec^2 x[/tex]

Therefore, we have:

[tex]\displaystyle \lim_{x\rightarrow 0^{+}}\frac{x\ln x}{\tan x}=\lim_{x\rightarrow 0^{+}}\frac{\ln x+1}{\sec^2{x}}[/tex]

By definition, [tex]\cos x=\frac{1}{\sec x}[/tex]. Therefore,

[tex]\displaystyle \lim_{x\rightarrow 0^{+}}\frac{x\ln x}{\tan x}=\lim_{x\rightarrow 0^{+}}\frac{\ln x+1}{\sec^2{x}}=\lim_{x\rightarrow 0^{+}}\cos^2x(\ln x+1)[/tex]

Note:

[tex]\displaystyle \lim_{x\rightarrow 0^{+}}\cos^2x=1,\\\lim_{x\rightarrow 0^{+}}\ln x+1=-\infty[/tex]

Substitute:

[tex]\displaystyle \lim_{x \rightarrow0^{+}} \cos^2x(\ln x+1)=1\cdot (-\infty)=-\infty[/tex]

Therefore, we have:

[tex]\displaystyle \lim _{x\rightarrow 0^{+}}\frac{x\ln x}{\tan x}=-\infty \text{}[/tex], which best corresponds with [tex]\boxed{\text{B. Nonexistent}}[/tex]

*Commentary:

Technically speaking, a limit exists only if it is equal to a real number. By proper definition, infinity is not a number. With that being said, you will see limits expressed as infinity or negative infinity.

Here's what I will say about this specific problem.

The problem is stipulating that we approach [tex]x[/tex] from the right side. Because of this condition, it may be unorthodox to say this limit doesn't exist. However, if the problem just asked for [tex]\displaystyle \lim_{x\rightarrow 0}\frac{x\ln x}{\tan x}[/tex], it is common and preferred to say this limit does not exist, since [tex]\displaystyle \lim_{x\rightarrow 0^{-}}\frac{x\ln x}{\tan x}\neq \displaystyle \lim_{x\rightarrow 0^{+}}\frac{x\ln x}{\tan x}[/tex].

For example, [tex]\displaystyle \lim_{x\rightarrow 0}\frac{1}{x}=\text{DNE}[/tex], because [tex]\displaystyle \lim_{x\rightarrow 0}\frac{1}{x}[/tex] diverges. In other words, [tex]\displaystyle \lim_{x\rightarrow 0^{-}}\frac{1}{x}=-\infty \neq \displaystyle \lim_{x\rightarrow 0^{+}}\frac{1}{x}=\infty[/tex].

But again, the problem is asking for the limit as [tex]x[/tex] approaches from the right, in which case [tex]\displaystyle \lim _{x\rightarrow 0^{+}}\frac{x\ln x}{\tan x}=-\infty }[/tex]. It's really a pedagogical choice whether to say a limit equal to infinity or negative infinity exists or not since infinity implies there is no limit, so saying the limit of something is infinity becomes an oxymoron. In this case, the person who wrote the answer choices chose to express a limit of infinity as nonexistent, but it is worth mentioning that someone else solving this problem might express [tex]-\infty[/tex] as the answer, and they would be just as, if not more, correct.

Without resorting to L'Hopital's rule, recall that

[tex]\displaystyle \lim_{x\to0}\frac{\sin(ax)}{ax} = 1[/tex]

for a ≠ 0. Then

[tex]\displaystyle \lim_{x\to0^+} \frac{x \ln(x)}{\tan(x)} = \lim_{x\to0^+}\frac x{\sin(x)} \times \lim_{x\to0^+}\cos(x) \times \lim_{x\to0^+}\ln(x)[/tex]

The first two limits exist and are equal to 1, but the last limit is -∞.

Answer:

292

Step-by-step explanation:

73 students in 1 group

4 groups all together

73 Students times 4 groups = amount of students all together

so 73x4=292

300000000000000000000000

Answer:

The most basic question I have ever seen lol

XY = 9*3 = 27

Answer:

Step-by-step explanation:

P ___15cm______T____10cm______B

As shown above,

PB is a line segment and point T in it forming - PT = 15 and TB = 10

So,

PB = PT + TB

= 15 + 10

= 25 (Ans)

Answer:

64 km per hour

Step-by-step explanation:

544/8.5=64

Answer:

Answer:

If:   153  words = 3  minutes  :

Then:  1 minute =  153 3 =  51 words

10 minutes is:

10 × 51 = 510

Ben can type 510 words in 10 minutes

Answer:

(0.5, -1)

Step-by-step explanation:

Answer:

Area: [tex]27y^{3} -24y^{2}[/tex]

Perimeter: [tex]6y^{2} +7y+5[/tex]

Step-by-step explanation:

Area:

[tex]\frac{1}{2}[/tex] x base x height

[tex]6y^{2} (\frac{1}{2} )(9y-8)\\3y^{2} (9y-8)\\27y^{3} -24y^{2}[/tex]

Perimeter:

[tex]6y^{2} +4y+(3y+5)\\6y^{2} +7y+5[/tex]

Answer:

a. isosceles

b. isosceles

c. scalene

Answer:

$127.875

Step-by-step explanation:

cost of 3 pizzas= $15*3

cost of 3 pizzas=$45

cost of 15 drinks=$1.50*15

cost of 15 drinks=$22.5

cost of 6 nachos=$5.80*6

cost of 6 nachos=$34.8

Total cost = pizza cost+ drinks+nachos

total cost=$45+$22.5+$34.8

total cost=$102.3

Now ,

Tip cost=$102.3*20%

=$20.46

tex cost=$102.3*5%

=$5.115

Bill which all friends pay=total cost+ tip cost+tex cost

= $102.3+$20.46+$5.115

=$127.875

Answer:

b

Step-by-step explanation:

9514 1404 393

Answer:

  (B)  Function 2

Step-by-step explanation:

We can compute the slope of Function 2 using the slope formula.

  m = (y2 -y1)/(x2 -x1) . . . . where x and y are the independent and dependent variables.

  m = (0.2 -0.8)/(3 -2) = -0.6

The slope of Function 1 is about ...

  -3/7 ≈ -0.43

The slope of Function 2 is more negative.

__

On a graph, the line representing function 2 has a steeper downward slope.

Answer:

A = W² + 6W

Step-by-step explanation:

The width is W.

The length is 6 units greater than the width, so the length is W + 6.

The area is the product of the length and width.

A = (W + 6)W

A = W² + 6W

Answer:

y = c1 e^-x + c2 e^(3x)

Step-by-step explanation:

Review linear DE's

(D-3)(D+1)y = 0

Answer:

The coordinates of a point are a pair of numbers that define its exact location on a two-dimensional plane.

jet1 = 549 mi/h

jet2 = 620 mi/h

x= jet1

x + 71 = jet2

6 hours

6 * x

6 * x + 71

6x + 6x + 426 = 7014

12x = 7014 - 426

12x = 6588

x = 6588/12

x= 549

x + 71 = 620

wyzant

Answer:

B two congruent pieces

Step-by-step explanation:

Perpendicular means at a 90 degree angle

bisector means it divides in it half, into two equal pieces