Solve the inequality: x + 5 < 7 x < 3 , x > -2. , x > 12. , x < 2

Answer:

x = 42

Step-by-step explanation:

2x + 8 + 2x + 4 = 180

4x + 12 = 180

4x = 168

x = 42

Answer:

$69 is correct

hope this helps

Answer: $69

Step-by-step explanation:

multiply 23 and 3

Answer:

with what

Step-by-step explanation:

Answer:

help with? there's nothing there

Answer:

B a vertical translation 50units right

Answer:

ok you to !!!!!!!!! good night!!

Step-by-step explanation:

Answer:

d because your taking away 6 from the 275

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

The answer is C. Either the date the property was acquired by the donor or the date of the gift.

Step-by-step explanation:

The donor's holding time is included in the holding period connected with the gain basis rule. The loss basis rule's holding period begins on the day of the donation.

Answer:

i need the question

Step-by-step explanation:

Answer:

42.20

Step-by-step explanation:

132 ×0.32

=42.24

rounded off it give 42.20

there you go the answer is in the picture

Answer:

Uuuuh thats kind of suspicious, maybe you could post your question without  a link? But links are usually scams, so dont do that :)

Answer:

Step-by-step explanation:

A' = (2 + 3, 1 + 2) = (5, 3)

B' = (-1 + 3, -3 + 2) = (2, -1)

C' = (3 + 3, -3 + 2) = (6, -1)

Answer:8x-40

Step-by-step explanation:

Because when we simply 4(x-5)/2

We multiply both sides by 2 because the inverse operations of division is multiplication. 2*4(x-5)*2/2 we cancel two by two then it leave us 4*2(x-5).

Next four times two is eight. So 8(x-5) we distribe eight that means eight times x and 5, 8x-40thos is the answer. Hope this help

1. The given equation is probably supposed to read

y'' - 2y' - 3y = 64x exp(-x)

First consider the homogeneous equation,

y'' - 2y' - 3y = 0

which has characteristic equation

r² - 2r - 3 = (r - 3) (r + 1) = 0

with roots r = 3 and r = -1. Then the characteristic solution is

[tex]y = C_1 e^{3x} + C_2 e^{-x}[/tex]

and we let y₁ = exp(3x) and y₂ = exp(-x), our fundamental solutions.

Now we use variation of parameters, which gives a particular solution of the form

[tex]y_p = u_1y_1 + u_2y_2[/tex]

where

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x}y_2}{W(y_1,y_2)} \, dx[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x}y_1}{W(y_1,y_2)} \, dx[/tex]

and W(y₁, y₂) is the Wronskian determinant of the two fundamental solutions. This is

[tex]W(y_1,y_2) = \begin{vmatrix}e^{3x} & e^{-x} \\ (e^{3x})' & (e^{-x})'\end{vmatrix} = \begin{vmatrix}e^{3x} & e^{-x} \\ 3e^{3x} & -e^{-x}\end{vmatrix} = -e^{2x} - 3e^{2x} = -4e^{2x}[/tex]

Then we find

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x} \cdot e^{-x}}{-4e^{2x}} \, dx = 16 \int xe^{-4x} \, dx = -(4x + 1) e^{-4x}[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x} \cdot e^{3x}}{-4e^{2x}} \, dx = -16 \int x \, dx = -8x^2[/tex]

so it follows that the particular solution is

[tex]y_p = -(4x+1)e^{-4x} \cdot e^{3x} - 8x^2\cdot e^{-x} = -(8x^2+4x+1)e^{-x}[/tex]

and so the general solution is

[tex]\boxed{y(x) = C_1 e^{3x} + C_2e^{-x} - (8x^2+4x+1) e^{-x}}[/tex]

2. I'll again assume there's typo in the equation, and that it should read

y''' - 6y'' + 11y' - 6y = 2x exp(-x)

Again, we consider the homogeneous equation,

y''' - 6y'' + 11y' - 6y = 0

and observe that the characteristic polynomial,

r³ - 6r² + 11r - 6

has coefficients that sum to 1 - 6 + 11 - 6 = 0, which immediately tells us that r = 1 is a root. Polynomial division and subsequent factoring yields

r³ - 6r² + 11r - 6 = (r - 1) (r² - 5r + 6) = (r - 1) (r - 2) (r - 3)

and from this we see the characteristic solution is

[tex]y_c = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}[/tex]

For the particular solution, I'll use undetermined coefficients. We look for a solution of the form

[tex]y_p = (ax+b)e^{-x}[/tex]

whose first three derivatives are

[tex]{y_p}' = ae^{-x} - (ax+b)e^{-x} = (-ax+a-b)e^{-x}[/tex]

[tex]{y_p}'' = -ae^{-x} - (-ax+a-b)e^{-x} = (ax-2a+b)e^{-x}[/tex]

[tex]{y_p}''' = ae^{-x} - (ax-2a+b)e^{-x} = (-ax+3a-b)e^{-x}[/tex]

Substituting these into the equation gives

[tex](-ax+3a-b)e^{-x} - 6(ax-2a+b)e^{-x} + 11(-ax+a-b)e^{-x} - 6(ax+b)e^{-x} = 2xe^{-x}[/tex]

[tex](-ax+3a-b) - 6(ax-2a+b) + 11(-ax+a-b) - 6(ax+b) = 2x[/tex]

[tex]-24ax+26a-24b = 2x[/tex]

It follows that -24a = 2 and 26a - 24b = 0, so that a = -1/12 = -12/144 and b = -13/144, so the particular solution is

[tex]y_p = -\dfrac{12x+13}{144}e^{-x}[/tex]

and the general solution is

[tex]\boxed{y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x} - \dfrac{12x+13}{144} e^{-x}}[/tex]

Answer:

Just go to the 6 on the bottom line, and add a point

Answer:

see below

Step-by-step explanation:

(6,0)

 The first coordinate is the x coordinate.  Since it is positive we go to the right 6 units.  The second coordinate is the y coordinate.  We go up zero units

Answer:

20:12

brainlest if it helped

Step-by-step explanation:

Answer:

20:12

Step-by-step explanation:

if you multiply 5:3 by 4, they'll end up with 20:12.

Answer:

250

Step-by-step explanation:

You can take the explicit formula and simply substitute the n value with 64:

-2 + 4 * (64 - 1)

-2 + 4 * (63)

-2 + 252

250

Answer:

answer is 746.

have a nice day and do good in math

Answer:

1/24

Step-by-step explanation:

8x + 1/3 = 2/3

    - 1/3   - 1/3

8x = 1/3

8x/8 = (1/3)/8

x = 1/24

Answer:

This is indeed a function

Answer:

95% of 80 is 76 and 85% of 60 is 51.

Step-by-step explanation:

Answer:

a. 76,  b. 60.

Step-by-step explanation:

a)  80 * 0.95 = 76.

b)   0.85 x = 51

x = 51/0.85 = 60.

Answer:

1/98

Step-by-step explanation:

Step 1: Translate statement into equation.

Step 2: Multiply both sides by 7x.

Step 3: Divide both sides by 98.

Step 4: Check if solution is correct.

Therefore, the answer is 1/98.

Answer:

Hello!

Judging by the link you provided I have come up with the correct solution:

x= 61°

y= 29°

Step-by-step explanation:

I will link my work below:

The first step to finding the two solutions it to first identify one of them.

I chose to identify x first.

To identify the value of x in this problem you have to notice that the x value corresponds with the value "29°" to form a perfect right angle, being 90°.

Thus you can simply find the value of x by doing this formula:

x+29°=90°

You then subtract 29° from both sides to simplify, and you come up with the solution

x=61°

Now we need to find the value of y.

To find the value of y I noticed that again, like x, y corresponds with another variable (being x) to form a perfect right angle (90°).

The way I realized this is a perfect right angle is because, as you can see in the picture you provided, the y+x angle are alternate exterior angles with another angle that is 90°.

Thus you can assume that:

x+y=90°

x= 61°

61°+y=90°

You then subtract 61° from both sides to get:

y=29°

Answer:

Yes, because (-1,2) is a solution to both inequalities

Step-by-step explanation:

2>-1 so the first inequality is correct

-1+2>0 so the second inequality is correct

Answer:

Step-by-step explanation:

0 = 5x + 7

-7 = 5x

x = - 7/5 = -1.4

Answer:

-1.4

Step-by-step explanation:

h(x)=0=5x+7

or, 5x= -7

x= -7/5= -1.4

Answer:

Step-by-step explanation:

A board foot is 1 inch thick by 1 ft by 1 ft

(3) 1 x 6  8'  are already 1 inch thick ½ ft wide and 8 ft long

  3 x 1 x (6/12) x 8 = 12 board ft.

(6) 2" x 10" x 12'  are 2 thick x 10/12 ft wide by 12 ft long

  6 x 2 x (10/12) x 12 = 120 board ft.

(6)  1" x 8" x 10'

  6 x 1 x (8/12) x 10 = 40 board ft

12 + 120 + 40 = 172 board ft