Solve for x, using the tangent lines.
X
46°
× = [ ? ]°
Please answer ASAP, if you could include an explanation that would also help!

(a) Dataset with mean substantially less than median:

9, 10, 11, 12, 90

The mean of this dataset is (9+10+11+12+90)/5 = 26.4, while the median is 11, which is substantially greater than the mean. The last data value is 90, which is a positive integer less than 100.

(b) Dataset with mean substantially more than median:

98, 99, 100, 101, 200

The mean of this dataset is (98+99+100+101+200)/5 = 119.6, while the median is 100, which is substantially less than the mean. The last data value is 200, which is a positive integer less than 100.

(c) Dataset with mean equal to median:

2, 3, 4, 4, 5

The mean of this dataset is (2+3+4+4+5)/5 = 3.6, which is equal to the median (the middle value of the dataset). The last data value is 5, which is a positive integer less than 100.

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Answer:

x= 2√ 7

Step-by-step explanation:

We can solve it with applying the sin of 30°

Sin 30° = opposite leg / hypotenuse

Sin 30° = √ 7 / x

Being x unknown.

Now, being 30°  a notable angle, we know that its sin is 1/2.

Sin 30° = 1/2

Replacing,

Sin 30° = √ 7 / x.           (we clear x)

1/2 = √ 7 / x

x/2 = √ 7

x= 2√ 7

The simplified form of the given expression as required to be determined in the task content is; 2x⁴√5.

It follows from the task content that the Simon form of the given expression √20x⁸ is required to be determined from the task content.

On this note, since the given expression is; √20x⁸.

We have that; = √ (4 × 5 × x⁸)

Therefore, since 4 and x⁸ are perfect squares; it follows that we have;

= 2x⁴ √5.

Ultimately, the simplified form of the given expression as required to be determined is; 2x⁴ √5.

Complete question; The correct expression is; √20x⁸.

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Based on the exponential decay equation, the number of employees for the company that has been decreasing yearly by 5%, will in 10 years be approximately 515.

The exponential decay equation or function gives the value in t years that has a constant ratio of decrease.

Exponential decay equation is one of the two exponential functions.  The other is the exponential growth equation.

The annual decrease in the number of employees = 5%

The current number of employees in the company = 860

The expected time = 10 years.

The exponential decay equation is as follows, y = 860 x 0.95^10.

y = 860 x 0.95^10 = 515

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Answer:

Step-by-step explanation:

2/5-1 2/5

Answer:

[tex]5x {}^{3} - x + 5x + 2[/tex]

Step-by-step explanation:

Greetings!!!

So to find the sum of (f+g)(x) just simply add these two functions

Add like terms together

If you have any questions tag it on comments

Hope it helps!!!

The total weight of the granola bars in the box is 6.7 ounces.

To calculate the total weight of the granola bars with the correct number of significant digits, we need to multiply the weight of a single bar by the number of bars in the box.

Given parameters:

Total weight of the granola bars

= Weight of a single bar x Number of bars in the box

= 0.84 ounces x 8

= 6.72 ounces

Since the weight of a single bar is given with two significant digits, and we have multiplied it by a whole number, the answer should be reported with two significant digits.

so we can say that, the total weight of the granola bars is 6.7 ounces.

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The rate of change in candies sold per month is 3 hundred candies.

The momentum of a variable is conveyed by the rate of change, which is used for expressing the percentage change in value over a particular amount of time.

To find the rate of change in candies sold per month, it is necessary to find the slope of the line connecting the two points.

The slope formula is given by: Δ[tex]\frac{y}{x}[/tex][tex]\frac{y2-y1}{x2-x1}[/tex]

Using the coordinates of the points, [tex]\frac{8-2}{6-4} =\frac{6}{2} =3[/tex]

The slope is 3. This means that for every month, the store sells 300 more candies.

Therefore, the rate of change, in candies sold per month is 300.

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Using the mean formula we know that the new mean height of 14 people is 159.7 cm.

A mean in math is the average of a data set, calculated by adding all numbers together and then dividing the total of the numbers by the number of numbers.

For illustration, with the dataset containing: 8, 9, 5, 6, 7, the mean is 7, as 8 + 9 + 5 + 6 + 7 = 35, 35/5 = 7.

The mean height given is 159 cm.

Let, x1, x2, x3 ..... x15 be the height of 15 people.

x1+x2+x3 ..... x15/15 = 159

x1+x2+x3 ..... x15 = 159 * 15 = 2385 cm ...(1)

Let, x1 = 148 cm, who leaves the group.

148+x2+x3 ..... x15 = 2385 cm

x2+x3 ..... x15 = 2237 cm

Now, we have 14 people.

New mean = x2+x3 ..... x15/14

= 2237/14

= 159.7 cm

Therefore, using the mean formula we know that the new mean height of 14 people is 159.7 cm.

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Answer:

Step-by-step explanation:

Answer:

12.

Step-by-step explanation:

Given: 3(x + 2) + 5x

Put in x:

3(2 + 2) + (5 x 2)

(3 x 4) + 10

12 + 10

= 12.

The height of an open cylinder of radius of 8cm given that it has a curved surface area of 1000 cm² is equals to the 159.24 cm.

The area obtained after substracting the circular area from the total area of the cylinder is called as curved surface area. Curved surface area is calculated by formula, 2πrh

where r --> radius of cylinder

h --> height of cylinder

π --> math special constant

We have an open cylinder with the following dimensions,

Radius of cylinder, r = 8 cm

Curved surface area of cylinder, A = 1000 cm². We have to calculate the height of this open cylinder. Let the height of an open cylinder be 'h cm' . Using the above formula, height of cylinder, h = curved Area/ 2πr

=> h = A/2π

=> h = 1000/2 ( 3.14)

=> h = 1000/6.28

=> h = 159.24

Hence, required value of height is 159.24 cm.

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Answer:

The number x that is midway between x and 27, and has a midpoint of -3, is -33

midpoint = (x + 27) / 2

We also know that the midpoint is equal to -3, so we can set these two expressions equal to each other and solve for x:

-3 = (x + 27) / 2

Multiplying both sides by 2 gives:

-6 = x + 27

Subtracting 27 from both sides gives:

x = -33

Answer:

A = 32 ft²

Step-by-step explanation:

the area (A ) of a square is calculated as

A = s² ( s is the side length )

the diagonal divides the square into 2 right triangles

using Pythagoras' identity on the lower right triangle with hypotenuse 8 and sides s , then

s² + s² = 8²

2s² = 64 ( divide both sides by 2 )

s² = 32

Then

A = s² = 32 ft²

Answer:

Below in bold.

Step-by-step explanation:

10,16,22,28

16-10 = 6, 22-16 = 6 and 28-22 = 6

This is an arithmetic sequence with first term a1 = 10 and common difference d = 6

General (nth) term = a1 + d(n - 1)

10th term =  10 + 6(9 -1)

                 =  10 + 48

                 = 58.

The value of x= 10.2.

This is the boundary or contour length of a 2D geometric shape.

Depending on their size, multiple shapes may have the same circumference. For example, imagine a triangle made up of wires of length L.

The same wire can be used to create a square if all sides are the same length.

The length covered by the perimeter of the shape is called the perimeter. Therefore, the units of circumference are the same as the units of length.

As we can say, the surroundings are one-dimensional. As a result, you can measure in meters, kilometers, millimeters, etc.

Inches, feet, yards, and miles are other globally recognized units of circumference measurement.

Hence, The value of x= 10.2.

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Answer: the answer is c I think

Answer:

CP of computer = 27000 rs.

Step-by-step explanation:

D% = Dis/MP*100

We know, Dis = MP-SP

Given Profit= 1160 rs.

So,CP = 27000 rs.

Answer:

103

Step-by-step explanation:

57° + 46° =103°

This shows that the third angle in the triangle is 180°-103°=77°

Therefore the largest exterior angle is 180°-77°=103°

Answer: The input force (effort) on the rope is 20 N.

Step-by-step explanation:

In a frictionless pulley system, the tension in the rope is constant throughout. Therefore, the force applied to the rope on one side of the pulley system is equal to the force exerted on the other side of the system.

In this problem, we know that the weight of the block is 20 N. This means that there is a force of 20 N acting downwards on one side of the pulley system.

Since the pulley system is frictionless, the tension in the rope is also 20 N. Therefore, the force applied to the rope on the other side of the pulley system (i.e., the input force or effort) must also be 20 N in order to balance the weight of the block.

So the input force (effort) on the rope is also 20 N.

Net rendering is a method of rendering a computer-generated animation or image on multiple computers over a network.

Net rendering is a method of rendering a computer-generated animation or image on multiple computers over a network. This technique allows a user to take advantage of the computing power of multiple computers to render a scene. To do this, the user would divide the scene into several parts, assigning each part to a different computer. The computers would then render each part of the scene independently, and then the results are combined into a single image. This process can significantly reduce the time required to render a scene, as the workload is distributed over multiple computers. For example, if it would normally take a single computer 10 minutes to render a scene, net rendering could reduce that time to 2 minutes.

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A 2-liter container costs R0.032 per milliliter, which is less than a 750-milliliter bottle, which costs R0.037 per milliliter.

a volumetric measurement using the metric system. One litre is equivalent to 1,000 milliliters. Additionally known as cc, mL, and cubic centimetre.

To evaluate which option is the most cost-effective, we need to calculate the cost per milliliter of each bottle of cooking oil.

For the 750ml bottle, the cost per milliliter is:

R28 / 750ml = R0.037 per ml

For the 2-liter bottle, the cost per milliliter is:

R63 / 2000ml = R0.032 per ml

Therefore, the 2-liter bottle is the more cost-effective option, as it has a lower cost per milliliter than the 750ml bottle. The cost per milliliter of the 2-liter bottle is R0.032, which is cheaper than the cost per milliliter of the 750ml bottle, which is R0.037.

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The coordinate matrix LFE of L relative to the ordered bases E and F is

[tex]\left(\begin{array}{ccc}3&1&10\\3&3&2\\0&3&3\\0&0&3\end{array}\right)[/tex].

Since here L is a linear transformation from a vector space of dimension 3 to a vector space of dimension 4, the coordinate matrix of L relative to the given ordered bases must be a (4×3) matrix,

Linear transformation is given by,

L(P(t)) = 5p"(t) + 1p' (t) + 3p(t) + 3tp(t)

The given basis is IP² is E = (C1, C2, C3) where, e1(t) = 1, e2(t) = t, e3(t) = t².

Also the given basis of IP³ is (f1, f2, f3, f4) where, f1(t) = 1, f2(t) = t, f3(t) = t², f4(t) = t³.

Now to find the coordinate matrix,

Now,

L(e1(t)) = 5.0 + 1.0 + 3.1 + 3t.1

= 3 + 3t

= 3f1(t) + 3f2(t) + 0.f3(t) + 0.f4(t)

L(e2(t)) = 5.0 + 1.1 + 3.t + 3t.t

= 1 + 3t + 3t²

L(e3(t)) = 5.2 + 1.2t + 3.t² + 3t.t²

= 10 + 2t + 3t² + 3t³

Now writing the coefficients as a column vector we get,

[tex]\left(\begin{array}{ccc}3&1&10\\3&3&2\\0&3&3\\0&0&3\end{array}\right)[/tex]

The coordinate matrix LFE of L relative to the ordered bases E and F is

[tex]\left(\begin{array}{ccc}3&1&10\\3&3&2\\0&3&3\\0&0&3\end{array}\right)[/tex].

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The area of the circle will decrease by 51% if the diameter increases by 40%. Then the new diameter will be 1.4 times the original diameter.

Let's assume the original diameter is d and the original area of the circle is A.

Then, the new diameter will be 1.4d and the new area of the circle can be calculated as follows:

New area = pi * (New diameter/2)²= pi * (1.4d/2)² = pi * (0.7d)² = 0.49 * pi * d²

Therefore, the new area is 0.49 times the original area.

To calculate the percentage increase in area, we can use the following formula:

Percentage increase = (New value - Old value) / Old value * 100%

In this case, the old value is the original area A and the new value is the new area, which is 0.49*A. Therefore,

Percentage increase = (0.49A - A) / A * 100%

= -0.51A / A * 100%

= -51%

Therefore, the area of the circle will decrease by 51% if the diameter increases by 40%.

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The probability of selecting another black marble is 3/7. As a result, the probability of drawing two black marbles in a row without replacement

(a) P(two red marbles) with replacement:The probability of drawing a red marble from a jar with five red marbles and four black marbles is 5/9, as there are five red marbles and nine total marbles. As a result, the probability of selecting two red marbles in a row with replacement is:P(two red marbles with replacement) = (5/9) × (5/9) = 25/81without replacement:When the first marble is removed, there are now only eight marbles remaining in the jar. Because there are only four black marbles in the jar, the probability of drawing a red marble is now 5/8. Therefore, the probability of selecting two red marbles in a row without replacement is:P(two red marbles without replacement) = (5/9) × (5/8) = 25/72(b) P(two black marbles)with replacement:For the first draw, there are four black marbles in the jar and a total of nine marbles. Therefore, the probability of drawing a black marble on the first draw is 4/9. Since the first marble was not removed, there are now eight marbles in the jar, including three black ones, and there are a total of nine marbles. Therefore, the probability of selecting another black marble is 3/9 or 1/3.

The probability of drawing two black marbles in a row with replacement is:P(two black marbles with replacement) = (4/9) × (1/3) = 4/27without replacement:Since the first marble was removed, there are only eight marbles in the jar, and there are four black ones. Therefore, the probability of selecting a black marble is 4/8 or 1/2. When the first black marble is removed, there are only seven marbles left, including three black ones. Therefore, the probability of selecting another black marble is 3/7. As a result, the probability of drawing two black marbles in a row without replacement is:P(two black marbles without replacement) = (4/9) × (3/7) = 12/63(c) P(one red and one black marble)with replacement:When one red and one black marble are selected with replacement, there are nine marbles in the jar for each draw. The probability of selecting one red and one black marble in a row is:P(one red and one black marble with replacement) = 2 × (5/9) × (4/9) = 40/81without replacement:Since there are five red and four black marbles in the jar, the probability of selecting a red marble first is 5/9. Once the red marble has been drawn and removed, there are only eight marbles remaining, including four black ones. As a result, the probability of selecting a black marble is 4/8 or 1/2.

As a result, the probability of drawing one red and one black marble without replacement is:P(one red and one black marble without replacement) = (5/9) × (4/8) + (4/9) × (5/8) = 20/36 + 20/36 = 10/18 = 5/9(d) P(red on the first draw and black on the second draw)with replacement:There are nine marbles in the jar for each draw. The probability of selecting a red marble first is 5/9. When the red marble is returned to the jar, there are still nine marbles in the jar, but now there are only four black marbles. The probability of selecting a black marble on the second draw is 4/9. As a result, the probability of drawing a red marble first and a black marble second with replacement is:P(red on the first draw and black on the second draw with replacement) = (5/9) × (4/9) = 20/81without replacement:Since there are five red and four black marbles in the jar, the probability of selecting a red marble first is 5/9. Once the red marble has been drawn and removed, there are only eight marbles remaining, including four black ones. As a result, the probability of selecting a black marble is 4/8 or 1/2. As a result, the probability of drawing a red marble first and a black marble second without replacement is:P(red on the first draw and black on the second draw without replacement) = (5/9) × (4/8) = 5/18

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As a result, the percentage of adults who selected math is different from the percentage of kids who did.

As a number out of 100, a percentage is a method to express a proportion or a fraction. It is symbolized by the number %. If there are 25 boys in a class of 100 pupils, for instance, then there are 25% of boys in the class. It is a helpful method to compare quantities and to express changes in values over time.

given

120 80

Total    200

Women Overall Party A Party B

70 60

Overall    130

Therefore, there are 130 ladies in the group.

b) The chart indicates that 70 women plan to support Party A.

Thus, the percentage of adults who selected English was 40% of 48, which is equal to 0.4 times 48 and 19.2 when rounded to the closest whole number.

b) Reeshma is not accurate. The percentage of adults who selected math is 35%, while for children it is 40%, according to the pie chart.

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The complete question is:-   complete the two-way table, which shows the voting intentions of a group of men and women. a How many women are in the group?

Men

Party A Party B 120

Total    200

Women   130

Total       380

b How many women intend to vote for Party A?

2 A group of 48 adults are asked what their favourite subject was at school. They can choose from

maths, English and science.

A group of 32 school children are asked the

same question.

Answer:

[tex](x + 4)(2x - 5) = 0[/tex]

explanation:

[tex]x \times 2x = 2 {x}^{2} [/tex]

[tex]( - 5 \times x) + (4 \times 2x) = 3x[/tex]

[tex] (- 5) \times 4 = - 20[/tex]

We can reduce the width of the confidence interval by increasing the sample size, reducing the confidence level and decreasing the mean (A, D, and F)

A confidence interval is an estimate of the interval that has a specified probability of including an unknown population parameter.

The purpose of a confidence interval is to estimate the true value of the population parameter being measured, such as a mean, a standard deviation, or a proportion.

In general, a wider confidence interval indicates more uncertainty about the estimate, while a narrower confidence interval suggests more precision in the estimate.

We want narrower confidence intervals to demonstrate more precision, as this allows us to draw more reliable conclusions about population parameters.

We cannot reduce the width of the confidence interval by increasing the sample size, increasing the confidence level or increasing the mean.

Thus, the correct options are a, d, and f.

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