Solve for x. Round to the nearest tenth of a degree, if necessary

Answer:

the cost of the tire=341.4$

Answer:

130

Step-by-step explanation:

65/50*100= 130

Answer:

[tex]36 + 35 = 71[/tex]

Step-by-step explanation:

[tex]3 + 5 + 4 = 12 \\ \\ 3 \times 3 = 9 \\ 5 \times 3 = 15 \\ 4 \times 3 = 12 \\ 9 + 15 + 12 = 36[/tex]

Answer:71 is correct

Step-by-step explanation:

3+5+4=12

3*3=9

5*3=15

4*3=12

9+5+12=36

36+35=71

Answer:

I think this is right for the 2nd problem

Step-by-step explanation:

a1=7+(3)(1)

Step 1: Simplify both sides of the equation.

a1=7+(3)(1)

a=7+3

a=(7+3)(Combine Like Terms)

a=10

a=10

Answer:

a=10

Answer:  [tex]\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)[/tex]

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

From there, we can then say the following:

[tex]\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}[/tex]

Answer:

A

Step-by-step explanation:

The area (A) of a rectangle is calculated as

A = length × breadth

   = (2x - 5)(x + 4) ← expand using FOIL

   = 2x² + 8x - 5x - 20

  = 2x² + 3x - 20 → A

Use the law of cosines, which says

189² = 215² + 123² - 2×215×123 cos(∠P)

==>   cos(∠P) = 25,633/52,890

==>   ∠P ≈ 61.06°

Answer:

y = -1/5x - 3

Step-by-step explanation:

Answer:

100km

Step-by-step explanation:

Time taken to travel to Bangi:

x/80 hours

15min = 1/4hrs

Time taken to travel back:

x/80 - 1/4

x= x/(x/80-1/4)

x^2-100x=0

x(x-100)=0

x=0 (rejected) or x=100

Answer:

B. 100km

Step-by-step explanation:

Brainliest please

Answer:

The inequality is -3<x<3

Step-by-step explanation:

(-3,3)

Answer:

7 pots of coffee (If you want to be precise its 6 2/3)

Step-by-step explanation:

So basically you need 10 cups of coffe in fifteen minutes, so 60/15=4 then time 10. so 40 is how much coffee you need in a hour, but we are solving the pot so 40/6= 6 2/3. but it says how many pots so we round it up so its 7. (Unless you wanna be precise)

Answer:

-60 and -28

Step-by-step explanation:

-60 + 42= -18

CHECK:

-42-18=-60

-56+-28=-84

CHECK:

-84+28=-56

Hope this helps <3 Need thanks? Comment /hearthelp

Answer:

-60

-28

Step-by-step explanation:

x +42 = -18

Subtract 42 from each side

x+42-42 = -18-42

x = -60

-56 +y = -84

Add 56 to each side

y = -84+56

y = -28

9514 1404 393

Answer:

  1/sec(x) · 1/tan(x)

Step-by-step explanation:

The breakup can be accomplished any of several ways.

  [tex]\dfrac{1}{\sec(x)\tan(x)}=\dfrac{1}{\sec(x)}\times\dfrac{1}{\tan(x)}=\dfrac{\cos(x)}{1}\times\dfrac{\cos(x)}{\sin(x)}[/tex]

Answer:

30 quarts

Step-by-step explanation:

4 quarts = 1 gallon

7.5 gallons * 4 quarts/ 1 gallon = 30 quarts

Answer:

5.30

Step-by-step explanation:

Total cost = flat fee + cost per mile * number of miles

              c(m)  = 3.50 + .60m

Let m=3

c(3)  = 3.50 + .60(3)

    = 3.50 + 1.80

    =5.30

Answer:

B: $5.30

Step-by-step explanation:

Each mile is $0.6, to get the result for 3 miles we would need to multiply $0.6 by 3. $0.60 * 3 = $1.8. Finally we would need to add the 3.50 to $1.8 resulting in $5.30

Answer:

Ty = √k  * Tx

The orbital period of Y has to be be multiplied by √k .   or . k∧1/2

Step-by-step explanation:

The general equation:

T² = A³

is for the case of planet X

Tₓ² = Aₓ³

In the case of planet Y

Ty² = k * Aₓ³ .     and   Aₓ³ = Tₓ²

By substitution:

Ty² =  k *Tₓ²

Ty = √k  * Tx

Answer:

D: K^3/2

Step-by-step explanation:

Just took the test and this is right

Answer:

3/12 as a decimal is 0.25

2/9 as a decimal is 0.2 reapeted

Answer:

Answer written below

Step-by-step explanation:

Divide 3 by 12 and 2 by 9 using long division solve like normal long division if your divisor is bigger than your dividend add a zero on top and add a zero to the dividend.

Decimal form of  3/12:0.25

Decimal form of  2/9:0.22223

Answer:

Step-by-step explanation:

15x-6y=48

-6y=48-15x

y=-8+(15/6)x

y=(5/2)x-8

Answer:

19

Step-by-step explanation:

Add 7 onto 12 to find answer.

Answer:

b = 19

Step-by-step explanation:

b = 12 + 7

Simplify 12+7 to 19.

Answer:

2ax(y-2ay^2+3a^2x)

Step-by-step explanation:

2axy-4a^2xy^2+6a^3x^2

Given data

we have the following expression

2axy-4a^2xy^2+6a^3x^2

let us factor this expression

we have

2ax(y-2ay^2+3a^2x)

The common factor is 2ax

And the factorized expression is 2ax(y-2ay^2+3a^2x)

Answer:

8

Step-by-step explanation:

By power of a point, (x-2)(x+13) = (x-3)(x+16). Solving, we find that x=11, so FG= 11-3 = 8

Answer:

3.88

Step-by-step explanation:

1. Subtract 5.74 from both sides of the equation

9.62-5.74=3.88

[tex]6 \sqrt{7} (1 - x)[/tex]

Answer:

x=4

Step-by-step explanation:

(x-1+5)×5=(2+x+4)×4

or, 5×(x+4)=4×(x+6)

or, 5x+20=4x+24

or, 5x-4x=24-20

or, x=4

Answer:

Omg why are you soo beautiful? I love it

Answer:

0.36

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

product of 18 and -3=18*-3= -54

positive difference=52-29=23

(18x-3)+56+(52-29)

= -54 + 56 + 23

=25

Using the domain concept, it is found that the domain of the function is: x is an element of all real numbers such that [tex]x \neq (-\frac{3}{2}, 4)[/tex], second option.

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The function is:

[tex]f(x) = \frac{2x}{2x^3 - 5x^2 - 12x} = \frac{2x}{x(2x^2 - 5x - 12)} = \frac{2}{2x^2 - 5x - 12}[/tex]

The points outside the domain are the zeros of [tex]2x^2 - 5x - 12[/tex], which we find solving a quadratic equation.

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

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[tex]2x^2 - 5x - 12[/tex] is a quadratic equation with [tex]a = 2, b = -5, c = -12[/tex].

[tex]\Delta = b^{2} - 4ac = (-5)^2 - 4(2)(-12) = 121[/tex]

[tex]x_{1} = \frac{-(-5) + \sqrt{121}}{2(2)} = 4[/tex]

[tex]x_{2} = \frac{-(-5) - \sqrt{121}}{2(2)} = -\frac{6}{4} = -\frac{3}{2}[/tex]

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The domain is: x is an element of all real numbers such that [tex]x \neq (-\frac{3}{2}, 4)[/tex], second option.

A similar problem is given at https://brainly.com/question/13136492

Answer:

Step-by-step explanation:

Using the domain concept, it is found that the domain of the function is: x is an element of all real numbers such that , second option.

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The domain of a function is all possible values that the input value x can assume.

The domain of a fraction is all real values of x except the zeros of the denominator.

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The function is:

The points outside the domain are the zeros of , which we find solving a quadratic equation.

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots  such that , given by the following formulas:

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is a quadratic equation with .

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The domain is: x is an element of all real numbers such that , second option.

A similar problem is given at brainly.com/question/13136492