Solve for x. Round to the nearest tenth, if necessary.

Answer:

The number of FM listereners are 24000.

Step-by-step explanation:

Let the listeners of FM are p and thus the istereners of AM are 5p.

According to the question,

p + 5 p = 144000

6 p = 144000

p = 24000

The number of FM listereners are 24000.

Answer: The quotient of 28 and 4 minus the sum of a number and 7

Step-by-step explanation:

Answer:

Step-by-step explanation:

5.2*9= 46.8

Do you want to know how to find the answer? :/

Answer:

A

Step-by-step explanation:

4x+5=33

then I solved for x and plugged in the numbers

Answer:

A

Step-by-step explanation:

4×+5=33

true.

this the true answer correct answer in first one

Answer:

$725

Step-by-step explanation:

First, find how much money she made from selling 65 cups:

65(15)

= 975

Subtract the $250 that she spent on the bag of grapes:

975 - 250

= 725

So, her profit was $725

Answer:

$35000

Step-by-step explanation:

A = P(1+rt)

A = 25000*(1+4%*10)

A = 35000

BRAINLIEST PLEASEEEEEEEEEEE

Answer:

60162.3214286

Step-by-step explanation:

that's just what my calculator said

i believe it's y-intercept!

to be honest i was never taught why it was the y-intercept, i was just told that it was. hope this helps!

Answer:

16/8 + 24

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]Mean = \frac{Sum \ of \ all \ the \ data}{number \ of \ data}\\\\= \frac{3.8+5.1+4.1+3.8+3.3+3.6}{6}\\\\=\frac{23.7}{6}\\\\= 3.95[/tex]

Mean = 3.95

B) To find the median, arrange the data in ascending order

3.3 ;  3.6 , 3.8  ; 3.8  ; 4.1  ; 5.1

As number of data is even, median = Average of (n/2)th term and (n/2)th term +1

= Average of 3 and 4th term

[tex]= \frac{3.8+3.8}{2}\\\\= 3.8\\[/tex]

Median  = 3.8

C) 3.8 occurs two times.

So, Mode = 3.8

d) 14.6 is above the mean. So, if we add a data above the mean, then the mean will increase

e) If April (3.8)  is deleted from chart, Mean will increase. If we remove a data below the mean, then mean will increase

If April is deleted from chart,  there will be no change in median.

Still median will be 3.8 only

Answer:

area of parallelogram=base *height

Answer:

area =36cm²

Step-by-step explanation:

area of parallelogram= b×h

Answer:

B

Step-by-step explanation:

[tex]2xy + 3xt - 7yt = 0[/tex]

[tex]3xt - 7yt = - 2xy[/tex]

Factor out t

[tex]t(3x - 7y) = - 2xy[/tex]

Divide by 3x-7y

[tex]t = - \frac{2xy}{3x - 7y} [/tex]

But since x and y are positive, the answer is positive

[tex]t = \frac{2xy}{3x - 7y} [/tex]

Answer:

1. LM < PN

2. AD < DC

3. m<CAB < m<CBA

4. m<1 = m<2

Step-by-step explanation:

Recall: an angle measure is relative to the length of the opposite side. That is, the longer the side opposite to an angle, the larger the measure of that angle and vice versa.

1. LM is opposite to <LNM,

PN is opposite to <NLP

m<LNM is less than m<NLP, therefore,

LM < PN

2. AD is opposite to <ABD

DC is opposite to <DBC

m<ABD is less than m<DBC, therefore,

AD < DC

3. m<CAB is opposite to CB

m<CBA is opposite to CA

CB is less than CA, therefore,

m<CAB < m<CBA

4. The side opposite to <1 is congruent to the side opposite to <2.

Therefore,

m<1 = m<2

Answer:

C.  y axis

Step-by-step explanation:

y axis is the answer

Answer:

s + l > 300

40 * s + 90 * l > 1500

Step-by-step explanation:

Let's say the amount of small bags is equal to s and the amount of large bags is equal to l.

The total amount of bags is equal to the sum of the small bags and large bags, as there can only be small or large bags. Therefore, the total amount of bags is equal to s + l. As the total amount of bags is greater than 300, we can write

s + l > 300

Next, the total number of packets of crackers exceeds 1500. We can find the total number of packets based on the amount of small and large bags. Because each small bag holds 40 packets, we can say that the amount of packets in small bags is equal to 40 * s. Similarly, the total amount of packets in large bags is equal to 90 * l. Therefore, the total amount of packets is equal to

40 * s + 90 * l

and since the total number of packets is greater than 1500, we can say

40 * s + 90 * l > 1500

Answer: $32

Step-by-step explanation:

Since the boutique was having a 20% storewide sale and Erica bought 2 dresses which originally cost $80 each, therefore the sale for each dress will be:

= $80 - (20% × $80)

= $80 - (0.2 × $80)

= $80 - $16

= $64

Therefore, on each dress Erica saves $16. The amount of savings enjoyed will then be:

= $16 × 2

= $32

Answer:

well I'm not gonna explain it but

#1 is C or the 3rd one (DOMIAN)

#2 is B or the second one (RANGE)

Answer:

DOMAIN OF THE FUNCTION :-

all real numbers

RANGE :-

all real numbers greater than or equal to - 2

as we the graph's vertex is at -2 so basically -2 is the lowest value of the function.

Answer:

y=2x

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0).

1) Determine the slope (m)

The slope is the rate of change, or the number of units the line moves up divided by the number of units the line moves to the right.

Looking at the graph, we can see that for every 1 space the line travels to the right, the line travels 2 spaces up. This makes the slope of the line 2. Plug this into [tex]y=mx+b[/tex]:

[tex]y=2x+b[/tex]

2) Determine the y-intercept (b)

When x=0 on the graph, y=0. Therefore, the y-intercept is 0. Plug this into [tex]y=2x+b[/tex]:

[tex]y=2x+0\\y=2x[/tex]

I hope this helps!

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

Step-by-step explanation:

[tex]thank \: you[/tex]

Answer and explanation:

Keira could get or look up an electronic copy of the book online. Once she has an electronic copy(pdf for instance) of the book, she can count number of e's in her book using the PDF reader or any software extension(good number of tools online) that would do just that.

Factors for Keira to consider:

How many lines and words are there on average per page; how many words are there per line?

How many e's are there manually counting for at least 5 pages.

Problems Keira might have in collecting data:

If book is physical and not an electronic copy, Keira may have to go through a tedious task of counting manually. She could make a rough estimation based on a few pages counted but she would need more accurate figures which requires the tedious task of counting e 's manually

Answer:

17.5

Step-by-step explanation:

as the triangles are similar, when oriented in the same direction they have the same angles, and the lengths of all sides of DEF are the lengths of the sides of ABC but multiplied by the same scaling factor f for all sides.

so, we see that

A ~ D

B ~ E

C ~ F

and therefore

AB ~ DE

BC ~ EF

CA ~ FD

that means

DE = AB × f

EF = BC × f

FD = CA × f

we know DE and AB.

so,

4 = 10 × f

f = 4/10 = 2/5

and now we know

EF = 7 = BC × f

BC = 7/f = (7/1) / (2/5) = (5×7)/(2×1) = 35/2 = 17.5

Answer:

17.5

Step-by-step explanation:

Answer:

Y= –4X+3

Step-by-step explanation:

Aight, check this out. the X and Ys are gonna form a linear equation.

Y=aX+b

3=a(0)+b===> b=3, so there you got for b

–1=a(1)+3===> a= –4

and the final touch

Y= –4X+3

Answer:

let

diagonal 1=6cm

diagonal 2=10cm

Area of rhombus=½*diagonal 1*diagonal 2=½*6*10

=30cm²

Answer:

Area of rhombus is 30cm².

Step-by-step explanation:

A rhombus having diagonals 6cm and 10cm . Find the area of rhombus.

Solution :-

Let us assume that

Finding the area of rhombus

Using Formula :-

Area of rhombus = ½ × [tex]diagonal_1[/tex]×[tex]diagonal_2[/tex]

Substitute the values of both diagonals.

Area of rhombus = ½ × 6cm × 10cm

Multiply the numbers

Area of rhombus = ½ × 60cm²

Divide we get ,

Area of rhombus = 30 cm

Answer:

Her investment will increase by 551.54 dollars

Step-by-step explanation:

So we know that the exponential function formula is f(x)=a(1+r)^x

So knowing that we can input values

So now we have f(x)=400(1+0.055)^6

Since it is annual we will only have the interest yearly so that changes are equation to look like this f(x)=400(1+0.055/1)^6

So next we have to add 1 and 0.055 which is 1.055

So we input that into the equation so now we have f(x)=400(1.055/1)^6

Now we have to do (1.055/1) to the power of six, so we get 1.37884280676

Now we have to 1.37884280676 times 400,  which would be 551.537122705.

Assuming they want to the nearest 100th it would be 551.54

So the answer is 551.54 dollars

Hopefully, that helped. If I made any mistake or I am incorrect feel free to correct me. :)

Answer:

13.7 units

Step-by-step explanation:

Hi there!

The dotted lines and the hypotenuse of the green triangle create a new right triangle, with one of its acute angles measuring 17 degrees and its hypotenuse measuring 47 units.

Given this information and that we must solve for the side opposite the given angle, we can use the sine ratio:

[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]

Plug in known information

[tex]sin17=\frac{x}{47}\\47*sin17=x\\13.7=x[/tex]

Therefore, the value of x when rounded to the nearest tenth is 13.7 units.

I hope this helps!

Answer:

2One-fifteenth

Step-by-step explanation:

[tex]3\frac{13}{15} - 1\frac{4}{5}[/tex]

[tex]2\frac{13 - 12}{15}[/tex]

2 [tex]\frac{1}{15}[/tex]

Answer:

7

Step-by-step explanation:

Answer:

[tex]{ \tt{sum = \frac{a(r {}^{n - 1} )}{n - 1} }} \\ 27 = \frac{a(r {}^{2 - 1} )}{2 - 1} \\ { \bf{27 = ar - - - (i)}} \\ \\ 54 = \frac{a( {r}^{3 - 1} )}{3 - 1} \\ { \bf{108 = a {r}^{2} - - - (ii) }} \\ { \tt{(ii) \div (i) : }} \\ r = \frac{108}{27} \\ { \bf{common \: ratio = 4}} \\ { \bf{first \: term = \frac{27}{4} }}[/tex]