Answer:
x = 1/5(k-14)
Step-by-step explanation:
5x + 14 = k
Subtract 14 from each side
5x+14-14 = k-14
5x = k-14
Divide by 5
5x/5 = 1/5(k-14)
x = 1/5(k-14)
Can someone help me with this math homework please!
9514 1404 393
Answer:
7/3-3y = 7/3x - 3Step-by-step explanation:
1) The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1)
m = (4 -(-3))/(3 -0) = 7/3
__
2) The y-intercept is the point where x=0:
(x, y) = (0, -3) . . . . . y = -3
__
3) Then the slope-intercept equation is ...
y = mx + b . . . . . . . line with slope m and y-intercept b
y = 7/3x -3
please me in the math
Find the H.C.F
[tex] {x}^{2} - 4 \\ {x}^{3} + 8 \\ {x}^{2} + 5x + 6[/tex]
it so simple
Step-by-step explanation:
Solution
First equation x ² - 4
= (x+2) (x-2)
Second equation = x ³ +8 + = x³+2^3
= (x-2) (x² + x₁2 +2²) = (x-2) (x² + 2x+4)
3 Third equation = x ² + 5x + 6
= x² + 6x= x +6 = x(x+6)-1(x+6)
(x-1) (x+6)
H.C. F= x-2
Given m||n, find the value of x.
+
mm
(6x+4)
(4x-14)
Answer:
Submit Answer
attempt out of 2
Answer:
x = 19
Step-by-step explanation:
6x+4 + 4x - 14 = 180
10x - 10 = 180
10 X = 190
x = 19
Can someone help me with this math homework please!
Answer:
Below
Step-by-step explanation:
From the graph the first local minimum is -16.18
The local maximum is 3.75
The second local minimum is -3.
Answer:
Over the interval (-3,0), the local minimum is -16.18Over the interval [0,3], the local maximum is -3.75Over the interval [0,3], the minimum is -3----------------------
Hope it helps..
Have a great day!!
what is 3^-8 x 3^-4 x 3^-2
Answer:
Value of given expression is 3⁻¹⁴
Step-by-step explanation:
Given expression:
3⁻⁸ x 3⁻⁴ x 3⁻²
Find:
Value of given expression
Computation:
⇒ 3⁻⁸ x 3⁻⁴ x 3⁻²
⇒ 3[⁻⁸⁻⁴⁻²]
⇒ 3⁻¹⁴
Value of given expression is 3⁻¹⁴
expand this question (x+5)(x-3)
state the dimensions of the matrix. identify the indicated element
Answer:
D; 2 * 3; -4
Step-by-step explanation:
The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column
In a row, we have 2 elements, in a column , we have 3 elements
So the matrix is of 2 * 3 dimension
a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4
a line has slope 3 and y-intercept 4
Answer:
y = 3x+4
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = 3x+4
simplify: 5 (6 - ab) + 2 (-7 + 3ab)
Answer:
30-5ab-14+6ab
16-ab ans
Answer:
[tex] \boxed{ab + 16} [/tex]
Step-by-step explanation:
5 (6 – ab) + 2 (-7 + 3ab)
[distribution property]
(6)(5) – (ab)(5) + (-7)(2) + (3ab)(2)
30 – 5ab – 14 + 6ab
[group like terms]
(6ab – 5ab) + (30 – 14)
ab + 16
Line r is parallel to line c.
Answer:
I think ∆5 is the correct Ans
Is this true or false
Answer:
I say it's TRUE
Step-by-step explanation:
I hope this help you
find the range. 130,131,132,134,135136,137,138,139,141,142,143,144,146,148,146,149,158,169
Answer:
The answer is 12
Step-by-step explanation:
The range is the difference between the lowest and highest values. In this case, this means 142 - 130 which equals 12.
Answer:
12
Step-by-step explanation:
Range = Largest number - Smallest number
Larger number = 142 ; Smallest number = 130
142-130 = 12
Range = 12
Suppose f(x)=x^3 what is the graph of f(x+3)
Answer:
[tex]f(x + 3) = {(x + 3)}^{3} [/tex]
Shifted left with x-intercept at (-3,0) and the y-intercept at (0,27)
Help please…
If (tan^30-1/tan0-1)-sec^20+1=0, find cot0
Answer:
dl5fgtrrfhrruf ofender fkufgj jjgglr
1. What is the sum of 3/4 and 4/5?
Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0
Answer:
[tex]{ \tt{ {x}^{2} + {y}^{2} - 6x - 2y + 4 = 0 }} [/tex]
Center:
[tex]{ \tt{(3, \: 1)}}[/tex]
Radius:
[tex]{ \tt{radius = \sqrt{ {g}^{2} + {f}^{2} - c } }} \\ = \sqrt{36 + 4 - 4} \\ = 6 \: units[/tex]
A block is being dragged along a horizontal surface by a constant horizontal force of size 45 N. It covers 8 m in the first 2 s and 8.5 m in the next 1 s. Find the mass of the block.
Answer: 15kg
Can anyone please explain this sum with proper working?
Answer:
Solution: To determine mass of the block we can use second Newton' law \vec F=m\vec a
F
=m
a
. The force and acceleration according the problem is directed along a horizontal surface, and we can omit the vector sign in Newton's law. The force we know F=45NF=45N, thus we should deduce the acceleration. The problem does not specify the initial speed at which time began to count, so for the first time interval, we may write the kinematics equation in the form
(1) S_1=v_1\cdot t_1+a\frac {t_1^2}{2}S
1
=v
1
⋅t
1
+a
2
t
1
2
, where S_1=8m, t_1=2s S
1
=8m,t
1
=2s , other quantities we don't know. The similar equation we can write for next time interval
(2) S_2=v_2\cdot t_2+ a\frac{t_2^2}{2}S
2
=v
2
⋅t
2
+a
2
t
2
2
. where S_2=8.5m, t_2=1s S
2
=8.5m,t
2
=1s
Note that during the first time interval, the speed of the block increased in accordance with the law of equidistant motion and it became the initial speed of the second interval, i.e.
(3) v_2=v_1+a\cdot t_1v
2
=v
1
+a⋅t
1
Substitute (3) to (2) we get
(4) S_2=(v_1+a\cdot t_1)\cdot t_2+ a\frac{t_2^2}{2}=v_1\cdot t_2+a\cdot t_1\cdot t_2+a\frac{t_2^2}{2}S
2
=(v
1
+a⋅t
1
)⋅t
2
+a
2
t
2
2
=v
1
⋅t
2
+a⋅t
1
⋅t
2
+a
2
t
2
2
From equation (1) and (4) we can exclude unknown quantity v_1v
1
, then remain only one unknown aa. For determine aa we dived (1) by t_1t
1
, (4) by t_2t
2
to find the average speed at time intervals and subtract (1) from (4).
(5) \frac {S_2}{t_2}-\frac {S_1}{t_1}=v_1+a\cdot t_1 +a\frac {t_2}{2}-(v_1+a\frac{t_1}{2})=a\frac{t_1+t_2}{2}-
t
2
S
2
−
t
1
S
1
=v
1
+a⋅t
1
+a
2
t
2
−(v
1
+a
2
t
1
)=a
2
t
1
+t
2
− For acceleration we get
(6) a=2\cdot ( {\frac{S_2}{t_2}-\frac{S_1}{t_1})/(t_1+t_2)}=2\cdot \frac{(8.5m/s-4m/s)}{3s}=3ms^{-2}a=2⋅(
t
2
S
2
−
t
1
S
1
)/(t
1
+t
2
)=2⋅
3s
(8.5m/s−4m/s)
=3ms
−2
For mass from second Newton's law we get
(7) m=\frac{F}{a}=\frac{45N}{3ms^{-2}}=15kgm=
a
F
=
3ms
−2
45N
=15kg
Answer: The mass of the block is 15 kg
Question 6 of 10
How much would $500 invested at 6% interest compounded monthly be
worth after 5 years? Round your answer to the nearest cen
(0) - P(144
A $674,43
B. $886,41
C, 5669.11
D. $512,68
9514 1404 393
Answer:
A. $674.43
Step-by-step explanation:
The account balance is given by ...
A = P(1 +r/12)^(12t) . . . . . principal P invested at annual rate r for t years
A = $500(1 +0.06/12)^(12·5) = $500(1.005^60)
A ≈ $674.43
can someone help me with the question?
Determine whether the equation represents direct, inverse, joint, or combined variation.
y = 4x^3z^3
Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus, 5 p=p=p, equals
Given:
The given equation is:
[tex]16-3p=\dfrac{2}{3}p+5[/tex]
To find:
The value of p.
Solution:
We have,
[tex]16-3p=\dfrac{2}{3}p+5[/tex]
Multiply both sides by 3.
[tex]3(16-3p)=3\left(\dfrac{2}{3}p+5\right)[/tex]
[tex]48-9p=2p+15[/tex]
Isolating the variable terms, we get
[tex]48-15=2p+9p[/tex]
[tex]33=11p[/tex]
Divide both sides by 11, we get
[tex]\dfrac{33}{11}=p[/tex]
[tex]3=p[/tex]
Therefore, the required solution is [tex]p=3[/tex].
Answer:
p=3
Step-by-step explanation:
i got it right on khan
There is a bag filled with 4 blue, 3 red and 5 green marbles.
A marble is taken at random from the bag, the colour is noted and then it is
replaced.
Another marble is taken at random.
What is the probability of exactly 1 red?
Answer:
25%
Step-by-step explanation:
4+3+5=12
3/12 ×100=25
The cost price of a box and a pen is Rs 120. The box is sold at 10% profita the pen is sold at 10% loss. If the selling price of the box is Rs 52 more than of the pen, calculate the profit or loss percent in the whole.
Answer:
3.803% Profit
Step-by-step explanation:
First let us calculate total sales, then calculate the total cost, and then divide the two.
Sale: 120*1.1=132 and 52*.9=46.8
Cost: 120 and 52
Profit equation:
[tex]\frac{Net sales-COGS}{Net Sales} =Profit[/tex]
[tex]\frac{(132+46.8)-(120+52)}{(132+46.8)}[/tex]
Simplify:
[tex]\frac{6.8}{178.8} =.03803[/tex] or 3.803% Profit
What is the perimeter of the rectangular narrow on the aircraft carrier HMS Queen Elizabeth
Answer:
dddjshsbs zhzusushwbsgzyzhsbssbs s hsbd d dhd ssbshebebs shyshs s sbshss s s
Step-by-step explanation:
shshshsnsnsjzj shsjs s sjsn s s snsnsbzbznnz ssjs s snsnsmkzkxnz
tanA × cosecA = secA
Step-by-step explanation:
L.H.S
tanA * cosecA
=sinA/cosA * 1/sinA
now cancel sinA and sinA
then,
1/cosA
= secA
= RHS
hence proved
Fill the empty slots by dragging tiles from the left to show the next step for sloving the equation solve the two step equation negative nine and a mumber plus zero point four equals to four
Step-by-step explanation:
gjlhcohuguo
y.krgkyfjfhcxhhhxhhxfucuchhcjvgjjgvjvkvkx
If triangle LMQ is similar to triangle LNP, calculate the length of segment LP.
Answer:
LP = 15
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
[tex]\frac{LM}{LN}[/tex] = [tex]\frac{LQ}{LP}[/tex] , substitute values
[tex]\frac{4}{10}[/tex] = [tex]\frac{LQ}{LQ+QP}[/tex]
[tex]\frac{2}{5}[/tex] = [tex]\frac{LQ}{LQ+9 }[/tex] ( cross- multiply )
5LQ = 2(LQ + 9) = 2LQ + 18 ( subtract 2LQ from both sides )
3LQ = 18 ( divide both sides by 3 )
LQ = 6
Then
LP = LQ + QP = 6 + 9 = 15
Complete table of values
Step-by-step explanation:
here's the answer to your question
A cash register at a store contains $277 bills. There are six more $5 bills than $10 bills. The number of $1bills is two more than 24 times the number of $10 bills. How many bills of each kind are there
Answer: See explanation
Step-by-step explanation:
Your question isn't well written, the store contains $227 and not $277.
let c be the number of $1 bills
let f be the number of $5 bills
let t be the number of $10 bills.
Therefore, the equation will be:
1c + 5f + 10t = 227
Since there are six more $5 bills than $10 bills, therefore,
f = t+6
Also, the number of $1 bills is two more than 24 times the number of $10 bills and this will be:
c = 24t + 2
Now, we substitute the equation for f and c into the main equation and this will be:
1c + 5f + 10t = 277
1(24t + 2) + 5(t + 6) + 10t = 227
24t + 2 + 5t + 30 + 10t = 227
39t + 32 = 227
39t = 227 - 32
39t = 195
t = 195/39
t = 5
Therefore, there are 5 $10 bills
Since c = 24t + 2
c = 24(5) + 2
c = 120 + 2
c = 122
Therefore, there are 122 $1 bills
Since f = t+6
f = 5+6
f = 11
Therefore, there are 11 $5 bills.
Find the measure of the missing angle using the triangle angle sum theorm.
Answer:
65°
Step-by-step explanation:
The sum of angles in a triangle =180
53°+62°+?°=180°
115°+?°=180°
?°=180°-115°
Rate the answer If you love everything I did n explanation
Answer:
65 degrees
Step-by-step explanation:
Angles in a triangle add up to 180, so 180 - 53 - 62 = 65.