Solve 3x-4>11 if the domain of x is {1,2,3,4,5,6,7,8}

Answer:

d

Step-by-step explanation:

a. (2/5)(-8/9)(-1/3)(-2/7)= - 32/945

b. (-2/5)(8/9)(-1/3)(-2/7) = -32/945

c. 2/5 * 8/9 * 1/3 * - 2/7 = - 32/945

d. -2/5 * - 8/9 * 1/3 * 2/7 = 32/945

Answer:

D

Step-by-step explanation:

32/945 is the final answer

Step-by-step explanation:

-5x - 4y= -117x + 3y = 18

-5x +117x = 3y + 4y = 18

112x = 7y = 18

Answer:

8 x^-2

Step-by-step explanation:

2 sqrt(x) * 4x ^ -5/2

Rewriting

2 x^1/2  * 4x ^ -5/2

2*4 = 8

x^1/2 * x^ -5/2  

We know a^b * a^c = a^(b+c)

x^ 1/2 * x^ -5/2 = x^ (1/2 -5/2 ) = x^ (-4/2) = x^-2

8 x^-2

Answer:

93

Step-by-step explanation:

the answer is 93 no -93 i think so

Answer:

[tex]4.\\\text{E. }x=5, x=-6,\\\\5.\\\text{A. }x=7, x=-3\\\\\text{18.}\\\text{D. No mistakes.}[/tex]

Step-by-step explanation:

For [tex]a=|b|[/tex], there are two cases:

[tex]\begin{cases}a=b,\\a=-b\end{cases}[/tex]

Question 4:

Given [tex]5|2x+1|=55[/tex],

Divide both sides by 5:

[tex]|2x+1|=11[/tex]

Divide into two cases and solve:

[tex]\begin{cases}2x+1=11,2x=10, x=\boxed{5}\\-(2x+1)=11,2x+1=-11, 2x=-12, x=\boxed{-6}\end{cases}[/tex]

Therefore, the solutions to this equation are [tex]\boxed{\text{E. }x=5, x=-6}[/tex].

Question 5:

Given [tex]\frac{1}{2}|4x-8|-7=3[/tex],

Add 7 to both sides:

[tex]\frac{1}{2}|4x-8|=10[/tex]

Multiply both sides by 2:

[tex]|4x-8|=20[/tex]

Divide into two cases and solve:

[tex]\begin{cases}4x-8=20,4x=28, x=\boxed{7}\\-(4x-8)=20, 4x-8=-20, 4x=-12, x=\boxed{-3}\end{cases}[/tex]

Therefore, the solutions to this equation are [tex]\boxed{\text{A. }x=7, x=-3}[/tex]

Question 18:

There are no mistakes in the solution shown. The answer properly isolates the term with absolute value with no algebraic mistakes. Following that, the answer divides the equation into both absolute value cases and solves algebraically correctly. Therefore, the correct answer is [tex]\boxed{\text{D. No mistakes.}}[/tex]

Answer:

one side length has to be equal in both triangles.

Answer:

To prove that two triangles with three congruent, corresponding angles are congruent, you would need to have at least one set of corresponding sides that are also congruent. You could then use ASA or AAS congruence theorems or rigid transformations to prove congruence.

Step-by-step explanation:

Convenience sampling.

Answer:

20 < L < 24

Step-by-step explanation:

We know that in any given triangle, the length of two sides is always greater than the length of the third side.

Since the sail is a triangle having length of one side as 22 feet and the length of another side as 2 feet, and let L be the length of the third side.

It follows from our triangle rule of sides above that

22 + 2 > L  (1)

22 + L > 2   (2)and

L + 2 > 22   (3)

It follows that from (1)

22 + 2 > L  

⇒  24 > L (4)

It follows that from (2)

22 + L > 2

⇒ L > 2 - 22

⇒ L > - 44  (5) and

It follows that from (3)

L + 2 > 22

⇒ L > 22 - 2

⇒ L > 20  (6)

Since from (5) and (6),

L > -44 and L > 20

and 20 > -44 ⇒ L > 20

⇒ 20 < L (7)

From (4) 24 > L ⇒ L < 24 (8)

Combining (7) and (8), we have

20 < L < 24

So, the possible range of values of the third side are 20 < L < 24

Answer:

at x = 11

0 =-4.5X +49.5

x = 49.5/4.5

x = 11

Step-by-step explanation:

x1 y1  x2 y2

1 45  3 36

(Y2-Y1) (36)-(45)=   -9  ΔY -9

(X2-X1) (3)-(1)=    2  ΔX 2

slope= -4  1/2    

B= 49  1/2    

Y =-4.5X +49.5    

Answer:

irrelevant is the answer for it doesn't belong

Answer:

1/2

slope = Δy/Δx

start at (-1,3)  to get to the line from there you can go down 1 ( Δy = -1)

and left 2 (Δx = -2)

-1/-2 = 1/2

Step-by-step explanation:

Answer

Mrs. Click's Garden is 6/5 or 1 1/5 square meters.

Explanation

Mrs. Click's has a rectangular garden. To find the area of a rectangle, you multiply the width by the length. To find the area of Mrs. Click's Garden, you multiply 4/5 by 3/2.

To multiply fractions, you multiply the numerator by the denominator.

4×3 is 12 and 5×2 is 10. You get the fraction 12/10, which can be simplified to 6/5, or 1 1/5.

Answer:

ST = 17 and WY = 32

Step-by-step explanation:

3

SV is a perpendicular bisector and divides Δ RST into 2 congruent triangles with

ST = SR , that is

7x - 4 = 3x + 8 ( subtract 3x from both sides )

4x - 4 = 8 ( add 4 to both sides )

4x = 12 ( divide both sides by 4 )

x = 3

Then

ST = 7x - 4 = 7(3) - 4 = 21 - 4 = 17

-------------------------------------------------------------------

4

Δ WXY and Δ WXZ are congruent ( both have 3 congruent angles ), then

WZ = WY , that is

9x - 13 = 6x + 2 ( subtract 6x from both sides )

3x - 13 = 2 ( add 13 to both sides )

3x = 15 ( divide both sides by 3 )

x = 5

Then

WY = 6x + 2 = 6(5) + 2 = 30 + 2 = 32

Answer:

[tex]8x^{4}[/tex]

3n-10

(a÷5)+12

Step-by-step explanation:

Numbers listed as in the picture.

70) 8 * [tex]x^{4}[/tex]= [tex]8x^{4}[/tex]

71) 3 * n -10= 3n-10

72) 12+ a/5= (a÷5)-12

Answer:

45°

Step-by-step explanation:

80 + 55=135

Every type of triangle has 180 degrees.

180-135=45 degrees.

Answer: [tex]56\ kmph,\quad 50\ kmph[/tex]

Step-by-step explanation:

Given

Two cars are 600 km apart moving towards each other

Difference in their speed is 6 kmph

After 4.5 hr, they are 123 km apart that is, they covered a distance of [tex]600-123=477\ km[/tex] in 4.5 hours

Suppose their speeds is [tex]v_1\ \text{and}\ v_2[/tex]

[tex]\therefore v_1-v_2=6\quad \ldots(i)[/tex]

Also, distance traveled is given by

[tex]\Rightarrow 477=[v_1+v_2]4.5\\\Rightarrow v_1+v_2=106\quad \ldots(ii)[/tex]

Solve, (i) and (ii) , we get [tex]v_1=56\ kmph\ \text{and}\ v_2=50\ kmph[/tex]

I don't answer the grammar but if you asked how many kids in total (not counting duplicate people that signed up for both) then 1073 student registered for the courses

I saw that this is from 2 weeks ago so it's probaly too late to answer... if you ever have trouble multiplying exponents use symbolab it's an online calculator that's really good (i use it on all my math exams :)

Answer:

Solutions given:

Velocity ratio V.R =5

effort =500N

efficiency =80%

magnitude of load=?

mechanical advantage [M.A ]

we have

efficiency =M.A/V.R*100%

80=M.A./5*100

80/100*5=M.A

M.A.=4

again

we have

M.A =load/effort

4=load/500

load=500*4

load=2000N

Answer:

31 degrees

Step-by-step explanation:

the side with the length of 29 can be seen as the radius of a circle.

and the sin value of an angle is the distance of a point on that circle from the x-axis. as the standard sin function is for the standard circle with radius 1, we need to multiply this by the actual radius.

15 = sin(?)×29

sin(?) = 15/29 = 0.5172...

? = 31.14... degrees ≈ 31 degrees

Answer:

Step-by-step explanation:

If AD is an altitude, then by definition it drops from the vertex angle (the top angle) and meets the base at a right angle, which measures 90 degrees. That means that 17x + 73 is a right angle:

17x + 73 = 90 and

17x = 17 so

x = 1

Answer:

y = 100,000 (1 + 0.04) ²⁰

Step-by-step explanation:

Here:

100,000 = original amount.

0.04 = rate (a percent)

and

20 = number of times you need to run the simulation.

Answer:

sry, i am doing this for points

Answer:

The answer is "A point on the parabola  and Focus".

Step-by-step explanation:

[tex]= \sqrt{(x - x)^2 + (y- (-p))^2} = \sqrt{(x-0)^2+ (y-p)^2} \\\\= \sqrt{(0)^2 + (y+p))^2} = \sqrt{(x)^2+ (y-p)^2} \\\\= \sqrt{(y+p))^2} = \sqrt{(x)^2+ (y-p)^2} \\\\= (y+p) = (x)+ (y-p) \\\\= y+p = x+ y-p \\\\=2p=x\\\\=x=2p[/tex]

Whenever the focus and also the guideline are utilized in determining the parabolic formula, two distances have indeed been equal.

The distance from the direction, as well as a parabolic point, was equal to the distance from the center to a parabolic point.

Answer:

The distance between the directrix and a point on the parabola is set equal to the distance between the focus and the same point on the parabola.

Step-by-step explanation:

Hope this helps! :)

Answer:

Length of Sarah rope    = 6 m

Length of Amanda's rope  = 4 m

Length of Mary's rope  = 7 m

Step-by-step explanation:

Let the length of Sarah rope = x

Length of Amanda's rope= x - 2

Length of Mary's rope = (x - 2 ) + 3 = x - 2 + 3 = x + 1

Length of rope = 17 m

x + x - 2 + x + 1 = 17

Combine like terms

x + x + x - 2 + 1 = 17

       3x  - 1 = 17

Add 1 to both sides

3x = 17 + 1

3x = 18

Divide both sides by 3

x = 18/3

x = 6

Length of Sarah rope = x  = 6 m

Length of Amanda's rope= x - 2 = 6 - 2 = 4 m

Length of Mary's rope =   x + 1 = 6 + 1 = 7 m

Answer:

The correct answer is 6x^2 + 3x - 18

Answer

Conditions for similar polygons. We say two figures are similar if they have the same shape, but not necessarily the same size. If they also have the same size, we say they are congruent. ... If two figures are similar, then they are also congruent.

Answer:

3.8; 4

Step-by-step explanation:

In this exercise, you're are required to find the missing values by performing some arithmetic calculations.

For the first part;

Let the missing value be X

Translating the word problem into an algebraic expression, we have;

[tex] X = 2000 * 1.9 * 10^{-6} [/tex]

[tex] X = 3.8 * 10^{-3} [/tex]

For the second part;

Let the missing value be Y.

[tex] 3.8 * 10^{-3} = Y * 9.5 * 10^{-4} [/tex]

[tex] X = \frac {3.8 * 10^{-3}}{9.5 * 10^{-4}} [/tex]

[tex] X = 4 [/tex]

Therefore, the complete sentence would be written as follows;

[tex] 3.8 * 10^{-3} [/tex] is 2000 times greater than [tex] 1.9 * 10^{-6} [/tex]. It is also 4 times greater than [tex] 9.5 * 10^{-4} [/tex]

Answer:

#1 is f.

#2 is d.

#3 is a.

#4 is b.

#5 is c.

#6 is g.

#7 is e.

Step-by-step explanation:

The digit "9" is in the ten's place because it is two numbers/spaces left from the decimal. If you make all the other digits "0", you'll be left with a value of 90.

The digit "1" is in the one's place because it is one number/space left from the decimal. Applying the same concept of making all the other digits "0", you'll be left with a value of 1.

The type of digits to the right of the decimal, starting from left to right, are the tenths place, hundredths place, thousandths place, ten-thousandths place, and millionths. Remember and know those digit types based on their position away from the decimal. The value will be there for you to see afterward.

[tex]\rightarrow\sf \sqrt{27} + 7 \sqrt{5} : \sqrt{2 } \\ = \sf \sqrt{9(3)} + 7 \sqrt{5} : \sqrt{2 } \\ = \sf \sqrt{ {3}^{2} } \times 3 + 7 \sqrt{5} : \sqrt{2} \\ \rightarrow \large\boxed{\sf{\red{3 \sqrt{3} + 7 \sqrt{5} : \sqrt{2} }}}[/tex]

[tex]\large\boxed{\sf{\red{3 \sqrt{3} + 7 \sqrt{5} : \sqrt{2} }}}[/tex]

[tex]\color{red}{==========================}[/tex]

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