so de fanga gu se si gage humang we sapa shata phoni we heo sang pai​

Answer:

Decanitrogen is molecular

Explanation:

Answer:

Dec a nitrogen is Molecular

Explanation:

hey mate i hope it will help you...!

Answer:

(a): The theoretical yield of silicon is 72.33 kg.

(b): The percent yield of the reaction is 91.25 %.

Explanation:

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]       .....(1)

For [tex]SiO_2[/tex]:

Given mass = 155.0 kg = 155000 g          (Conversion factor: 1 kg = 1000 g)

Molar mass = 60 g/mol

Putting values in equation 1:

[tex]\text{Moles of }SiO_2=\frac{155000g}{60g/mol}=2583.3mol[/tex]

For carbon:

Given mass = 78.2 kg = 78200 g

Molar mass = 12 g/mol

Putting values in equation 1:

[tex]\text{Moles of carbon}=\frac{78200g}{12g/mol}=6516.67mol[/tex]

The chemical equation for the reaction of silicon dioxide and carbon follows:

[tex]SiO_2+2C\rightarrow Si+2CO[/tex]

By stoichiometry of the reaction:

1 mole of [tex]SiO_2[/tex] reacts with 2 moles of carbon

So, 2583.3 moles of [tex]SiO_2[/tex] will react with = [tex]\frac{2}{1}\times 2583.3=5166.4mol[/tex] of carbon

As the given amount of carbon is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, [tex]SiO_2[/tex] is considered a limiting reagent because it limits the formation of the product.

By stoichiometry of the reaction:

1 mole of [tex]SiO_2[/tex] produces 1 mole of silicon

So, 2583.3 moles of [tex]SiO_2[/tex] will produce = [tex]\frac{1}{1}\times 2583.3=2583.3mol[/tex] of silicon

Since the molar mass of silicon = 28 g/mol

Putting values in equation 1:

[tex]\text{Mass of Si}=2583.3mol\times 28g/mol=72332.4g=72.33 kg[/tex]

Hence, the theoretical yield of silicon is 72.33 kg.

The percent yield of a reaction is calculated by using an equation:

[tex]\% \text{yield}=\frac{\text{Measured value}}{\text{Theoretical value}}\times 100[/tex]              ......(2)

Given values:

Measured value of silicon = 66.0 kg

Theoretical value of silicon  = 72.33 kg

Putting values in equation 1:

[tex]\% \text{yield}=\frac{66.0kg}{72.33kg}\times 100\\\\\% \text{yield}=91.25 \%[/tex]

Hence, the percent yield of the reaction is 91.25 %.

Answer:

combine harvester, or a combiner.

Answer:

e) C5H10O3

Explanation:

According to the information given in this question;

50.84% represents C

8.53% represents H

[100% - (50.84 + 8.53)]

= 100 - 59.37

= 40.63% of Oxygen (O)

This percentage means that;

Carbon = 50.84g

Hydrogen = 8.53g

Oxygen = 40.63g

By dividing by their respective atomic masses, we convert to moles:

C = 50.84g ÷ 12 = 4.24mol

H = 8.53g ÷ 1 = 8.53mol

O = 40.63g ÷ 16 = 2.54mol

Next we divide by the smallest no of the values (2.54mol)

C = 4.24 ÷ 2.54 = 1.669

H = 8.53 ÷ 2.54 = 3.358

O = 2.54 ÷ 2.54 = 1

To get a simple whole number ratio, we multiply the results by 3

C = 1.669 × 3 = 5.007

H = 3.358 × 3 = 10.074

O = 1 × 3 = 3

Simple whole number ratio of carbon, hydrogen and oxygen is 5:10:3. Hence, the empirical formula is C5H10O3.

Answer:

(Basic )

Real

These are formed in the front side of the mirror.

Virtual

These are assumed to be formed at the backside of the mirror.

Type of lens used

Converging(real)

Diverging(virtual)

Image reception

Image can be appeared on a screen.(Real)

Image appears to be on the mirror or lens itself.

Interaction of light rays Actual Imaginary(Virtual)

Appearance of image

Inverted(Real)

Erect(Virtual)

Formed by

Concave mirror and convex lens.(Real)

Plane, convex mirror and concave lens.(Virtual)

Example

Image on the theater screen.(Real)

Reflection of any object or body on plane mirror.(Virtual)

Hsvhpsvuwgycwhusvywgogwitcsuovsigsviyscyisvyos

Answer:

none

Explanation:

the correct option would be Ar 3d3 4s2

Answer:

d. All of the above

Explanation:

d. All of the above

Answer:

[tex]1.74molNO_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:

[tex]80g*\frac{1mol}{46g}\\\\1.74molNO_2[/tex]

Regards!

Explanation:

If 50.0 grams of Zinc are reacted with 50.0 grams of Hydrogen Chloride ... 50.09 Zn x 1 mol Zn , Imol ZnCl2 , 136.4g. ... If a decomposition reaction produces a 75.0% yield for the oxygen by mass (128.0 grams were.

Answer:

10/3

Explanation:

Hope this helps

Answer:

The compound formula for the ammonia is

N

H

3

. It is a colorless gas. It is the result of the chemical reaction between nitrogen and hydrogen gas. The chemical reaction between the gases is shown below:

N

2

+

3

H

2

→

2

N

H

3

Answer:

pH = 11.3

Explanation:

From the question given above, the following data were obtained:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

The pH of a solution is defined by the following equation:

pH = –Log [H₃O⁺]

Thus, with the above formula, we can obtain the pH of the solution as follow:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

pH = –Log [H₃O⁺]

pH = –Log 4.950×10¯¹²

pH = 11.3

dont mind me here for the points

Answer:

oxygen is add to ATP providing energy to the cell

Answer:

B

Explanation:

Explanation:

hope the picture make sense :)

Answer:

Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

[tex]Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3[/tex]

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

[tex]0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2[/tex]

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

[tex]0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2[/tex]

And the resulting percent yield:

[tex]Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%[/tex]

Regards!

Answer:

A. phosphate group

Explanation:

I got it right in class!

Hope this Helps!! :))

Answer:

42000km

Explanation:

Average Speed (v) can be calculated using the formula as follows:

Average speed = distance (d) ÷ time (t)

According to this question, a space shuttle travels around the Earth at a constant speed of 28000 km/hr in 90 minutes.

Since 60 minutes = 1 hr

90 minutes = 90/60

= 3/2 or 1.5hours.

Using speed = distance/time

Distance (km) = speed × time

Distance = 28000 km/hr × 1.5hr

Distance = 42000km

Answer: C

Explanation:

Answer:

C.

Explanation:

:)

Answer:

A (True)

Explanation:

Because ibuprofen has a chiral carbon center (carbon bonded to 4 distinct groups of atoms).

This means that a mixture of ibuprofen can rotate plane-polarized light equally in both the clockwise and counterclockwise direction.

Answer:true

Explanation: ibuprofen is commonly used for most pain, aches ect

Answer: The frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is [tex]5.49 \times 10^{14} s^{-1}[/tex].

Explanation:

Given: Wavelength = 546 nm [tex](1 nm = 10^{-9} m)[/tex] = [tex]546 \times 10^{-9} m[/tex]

The relation between frequency and wavelength is as follows.

[tex]\nu = \frac{c}{\lambda}[/tex]

where,

[tex]\nu[/tex] = frequency

c = speed of light = [tex]3.0 \times 10^{8} m/s[/tex]

[tex]\lambda[/tex] = wavelength

Substitute the values into above formula as follows.

[tex]\nu = \frac{c}{\lambda}\\= \frac{3.0 \times 10^{8} m/s}{546 \times 10^{-9} m}\\= 5.49 \times 10^{14} s^{-1}[/tex]

Thus, we can conclude that the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is [tex]5.49 \times 10^{14} s^{-1}[/tex].

The question is incomplete, the complete question is:

A solution of permanganate is standardized by titration with oxalic acid. To react completely with 0.0018 mol of oxalic acid required 28.18 mL of permanganate solution. The unbalanced chemical equation for the reaction in acidic solution is:

[tex]\mathrm{MnO}_{4}^{-}(aq)+\mathrm{H}_{2}\mathrm{C}_{2}\mathrm{O}_{4}(aq)\stackrel{\mathrm{Acidic}}{\longrightarrow}\mathrm{Mn}^{2+}(aq)+\mathrm{CO}_{2}(\mathrm{g})[/tex]

Determine the concentration of the permanganate solution in molarity.

Answer: The molarity of permanganate solution is 0.026 M

Explanation:

The balanced chemical equation follows:

[tex]2MnO_4^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow 2Mn^{2+}+8H_2O(l)+10CO_2(g)[/tex]

Given values:

Moles of oxalic acid = 0.0018 moles

By the stoichiometry of the reaction:

If 5 moles of oxalic acid reacts with 2 moles of permanganate solution

So, 0.0018 moles of oxalic acid will react with = [tex]\frac{2}{5}\times 0.0018mol=0.00072mol[/tex] of permanganate solution

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)

Given values:

Moles of permanganate solution = 0.00072 moles

Volume of solution = 28.18 mL

Putting values in equation 1, we get:

[tex]\text{Molarity of permanganate solution}=\frac{0.00072\times 1000}{28.18}\\\\\text{Molarity of permanganate solution}=0.026M[/tex]

Hence, the molarity of permanganate solution is 0.026 M

Answer: B

Explanation: im pretty sure my teacher mentioned something about N--h bonds are non polar

Answer:

C

Explanation:

Answer:

[tex]m_{CO_2}=75.6gCO_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out mandatory for us to calculate the reacting moles of both C and O2 because we are given grams and pressure, temperature and volume, respectively:

[tex]n_C=36gC*\frac{1molC}{12gC}=3.0molC \\\\n_{O_2}=\frac{3.0atm*14L}{0.08206\frac{atm*L}{mol*K}*298K}=1.72molO_2[/tex]

Thus, since C and O2 react in a 1:1 mole ratio, we infer C is in excess, and the grams of CO2 can be calculated with the moles of O2:

[tex]m_{CO_2}=1.72molO_2*\frac{1molCO_2}{1molO_2}*\frac{44.01gCO_2}{1molCO_2} \\\\ m_{CO_2}=75.6gCO_2[/tex]

Best regards!

Explanation:

the answer is clay as seen from the picture

Answer:

How many grams C2H6 in 1 mol? The answer is 30.06904. We assume you are converting between grams C2H6 and mole. You can view more details on each measurement unit

Answer:

1.40M = [N2O4]

Explanation:

Based on the reaction:

2NO2(g) ⇄ N2O4(g)

Kc is defined as:

Kc = 5.0 = [N2O4] / [NO2]²

Where [] are the concentrations in equilibrium of each gas

As the equilibrium concentration of NO2 is 0.53M:

5.0 = [N2O4] / [0.53]²

5.0 = [N2O4] / [0.2809]

5.0*0.2809 = [N2O4]

Answer:

Answer: There are 1.53 moles present in   molecules of water in a beaker.

Explanation:

According to the mole concept, there are  molecules present in 1 mole of a substance.

So, number of moles present in  molecules are calculated as follows.

Thus, we can conclude that there are 1.53 moles present in   molecules of water in a beaker.

Explanation: