Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region
Answer:
Question 16 = 22
Question 17 = 20 cm²
Step-by-step explanation:
Concepts:
Area of Square = s²
s = sideArea of Triangle = bh/2
b = baseh = heightDiagonals of the square are congruent and bisect each other, which forms a right angle with 90°
Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.
Solve:
Question # 16
Step One: Find the total area of two squares
Large square: 5 × 5 = 25
Small square: 2 × 2 = 4
25 + 4 = 29
Step Two: Find the area of the blank triangle
b = 5 + 2 = 7
h = 2
A = bh / 2
A = (7) (2) / 2
A = 14 / 2
A = 7
Step Three: Subtract the area of the blank triangle from the total area
Total area = 29
Area of Square = 7
29 - 7 = 22
-----------------------------------------------------------
Question # 17
Step One: Find the length of PT
Given:
PR = 4 cmRT = 6 cmPT = PR + RT [Segment addition postulate]
PT = (4) + (6)
PT = 10 cm
Step Two: Find the length of S to PT perpendicularly
According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal
Length of Diagonal = 4 cm
4 ÷ 2 = 2 cm
Step Three: Find the area of ΔPST
b = PT = 10 cm
h = S to PT = 2 cm
A = bh / 2
A = (10)(2) / 2
A = 20 / 2
A = 10 cm²
Step Four: Find the length of Q to PT perpendicularly
Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.
Length of Diagonal = 4 cm
4 ÷ 2 = 2 cm
Step Five: Find the area of ΔPQT
b = PT = 10 cm
h = Q to PT = 2 cm
A = bh / 2
A = (10)(2) / 2
A = 20 / 2
A = 10 cm²
Step Six: Combine area of two triangles to find the total area
Area of ΔPST = 10 cm²
Area of ΔPQT = 10 cm²
10 + 10 = 20 cm²
Hope this helps!! :)
Please let me know if you have any questions
HELPASAP (15 points)
A circle with an arc length of ____ centimeters is intercepted by a central angle of 3pi/4 radians has a radius of ____ centimeters.
1st Blank Options: 12pi, 4pi, 2pi
2nd Blank Options: 3, 16, 24
Margaret took a trip to Italy. She had to convert US dollars to euros to pay for her expenses there. At the time she was traveling, the conversion rate was represented by the function , where n is the number of dollars and E(n) is the equivalent value in euros. Later, she traveled to Dubai and converted her remaining euros into the local currency, UAE dirhams. At that time, the conversion rate was represented by the function , where x is the number of euros and D(x) is the equivalent value in dirhams. Which function can be used to convert n dollars directly to dirhams?
The conversion rate US dollars to Euros is represented with the function:
E(n)=0.72n
n- number of dollars
E(n) - Euros as a function of US dollars
The conversion rate Euros to Dirhams is :
D(x)=5.10x
x- number of Euros
D(x)- Dirhams as a function of Euros
We are trying to find D(x) in terms of n.
D(x) = 5.10x
x can be rewritten as E(n)
D(x) = 5.10(E(n))
D(x) = 5.10(E(n))
D(x) = 5.10(0.72n)
D(x) = 3.672n
According to this the following statement is true:
A) (D x E)(n) = 5.10(0.72n)
The length of a constantan wire P is twice of the constantan wire Q and the ratio of the diameter of wire P to
wire Q is 1:3. Given that the resistance of the wire varies directly as the length and inversely as the square of the
diameter, find the resistance ratio of wire P to wire Q.
Answer:
Hello,
9/2
Step-by-step explanation:
Using "la loi de Pouillet", i don't know the name in USA
[tex]R=\rho*\dfrac{l}{S} \\\\\rho: resistivity\\\\l: length\\\\S:section\ of \ the\ wire\\\\R_1=\rho*\dfrac{l_1}{S_1} \\S_1=\pi*d_1^2*\dfrac{1}{4} \\\\\\l_2=2*l_1\\d_2=3*d_1\\\\S_2=\pi*d_2^2*\dfrac{1}{4} =\pi*(3*d_1)^2*\dfrac{1}{4}=9*S_1\\\\\\\dfrac{R_1}{R_2} =\dfrac{\rho*\dfrac{l_1}{S_1}}{\rho*\dfrac{l_2}{S_2}} \\\\=\dfrac{\rho*\dfrac{l_1}{S_1}}{\rho*\dfrac{2*l_1}{9*S_1}} \\\\\\\boxed{\dfrac{R_1}{R_2} =\dfrac{9}{2}}[/tex]
i’ve came so far and i’m almost there.. please help!!
Answer:
m = -1/3
Step-by-step explanation:
To get the slope of the line, we identify two points on the line and use the slope formula
We can have the points (-2,3) and (1,2)
We have the slope formula as;
m = (y2-y1)/(x2-x1)
m = (2-3)/(1 + 2) = -1/3
17
x
3
8
Find the unknown side length, x. Write your answer in simplest radical form.
A 15
B. 5/10
C2/70
D. 4 37
==========================================================
Explanation:
It helps to add point labels. Let's place point A at the very top point of the triangle. Then point B will be at the 90 degree angle. Point C is the far left point. Lastly, point D is on segment BC such that DC = 3.
Since BC = 8 and CA = 17, we can use the pythagorean theorem to get...
(AB)^2 + (BC)^2 = (AC)^2
(AB)^2 + (8)^2 = (17)^2
(AB)^2 + 64 = 289
(AB)^2 = 289-64
(AB)^2 = 225
AB = sqrt(225)
AB = 15
Now focus on triangle ABD and apply the pythagorean theorem again to find side AD
(AB)^2 + (BD)^2 = (AD)^2
AD = sqrt( (AB)^2 + (BD)^2 )
AD = sqrt( (AB)^2 + (BC-CD)^2 )
AD = sqrt( (15)^2 + (8-3)^2 )
AD = sqrt(250)
AD = sqrt(25*10)
AD = sqrt(25)*sqrt(10)
AD = 5*sqrt(10) .... answer is choice B
please help SO CONFUSED
Answer:
SOH-CAH-TOA
[tex]h = \sqrt{ 9^{2} +5^{2} }[/tex]
~~~~~~~~~~
H= [tex]\sqrt{106}[/tex]
O= 5
A= 9
~~~~~~~~~~~~~~~~
Sin = [tex]\frac{5}{\sqrt{106 } }[/tex]
Cos= [tex]\frac{9}{\sqrt{106 } }[/tex]
Tan = [tex]\frac{5}{9 }[/tex]
Step-by-step explanation:
Each side of a pentagon is 10 cm greater than the previous side. If the perimeter of this pentagon is 500 cm, find the lengths of the sides.
Answer: See explanation
Step-by-step explanation:
The perimeter of a pentagon is gotten through the summation of its five sides. Let the first side be represented by x. Since each side of a pentagon is 10 cm greater than the previous side, then the sides will be:
First side = x
Second side = x + 10
Third side = x + 10 + 10 = x + 20
Forth side = x + 30
Fifty side = x + 40
Therefore,
x + (x + 10) + (x + 20) + (x + 30) + (x + 40) = 500
5x + 100 = 500
5x = 500 - 100
5x = 400
x = 400/5
x = 80
Therefore, the lengths will be:
First side = x = 80cm
Second side = x + 10 = 80 + 10 = 90cm
Third side = x + 20 = 80 + 20 = 100cm
Forth side = x + 30 = 80 + 30 = 110cm
Fifty side = x + 40 = 80 + 40 = 120cm
HURRY PLEASEE!!!! TAKING AN EXAM !! AND ITS TIMED!!! WILL GIVE BRAINLIEST!!
which rule represents the translation from the pre image ∆abc to ∆a'b'c'?
(x,y)-->(x+7,y+6)
(x,y)-->(x+7,y-6)
(x,y)-->(x-6,y+7)
(x,y)-->(x+6,y+7)
Answer:
B (x+7, y-6)
Step-by-step explanation:
It goes right 7 and down 6
Answer:
(x,y) --> (x+7, y-6)
Step-by-step explanation:
Good luck with your exam! :DD
Write the equation of a line in slope-intercept form that has a slope of -0.5 and passes through the point (-5, 1.5)
When this open-ended cylinder is opened out, it forms a rectangle with a width of 25 cm. What is the area of the rectangle?.
Answer:
Just want the points
Step-by-step explanation:
which of the following equations is not a function?
a.) 5y^2 = x
b.) 1/2y + 9 = x^2 + 2x + 1
c.) y = 1/2x + 9
d.) 8x + 4y = 0
please help with these two questions!!
6√5 + 3√6 = 6√5 + 3√6 [cannot be simplified]
; roots do not contain any perfect squares, and the roots are not similar.
6√5(3√6) = 18√30 [can be simplified]
; although roots do not contain any perfect squares, the product rule can be applied to create a singular expression.
simplify the following
[tex]simplify \: the \: follwing \: \\ logx \: x9[/tex]
please I need help
Answer:
9
Step-by-step explanation:
Using the rules of logarithms
log[tex]x^{n}[/tex] = nlogx
[tex]log_{b}[/tex] b = 1
Then
[tex]log_{x}[/tex] [tex]x^{9}[/tex]
= 9[tex]log_{x}[/tex] x
= 9
What is the length of the hypotenuse in the right triangle shown below?
45°
45
6
Answer:
option A
Step-by-step explanation:
let the hypotenuse be x
take 45 degree as reference angle and use cos rule
cos 45 = adjacent/hypotenuse
1/[tex]\sqrt{2[/tex] = 6/x
do cross multiplication
6*[tex]\sqrt{2[/tex] = x *1
6[tex]\sqrt{2}[/tex] = x
Answer:
Answer is a
Step-by-step explanation:
Thats what i got
Solve each of the following:
a) x² + 4x – 77 = 0
b) x(x + 4) = -2(3x + 8)
Please show your work
Answer:
a.) x=7 or x=-11
b.) x=−2 or x=−8
Step-by-step explanation:
a) x² + 4x – 77 = 0
Step 1: Factor left side of equation.
(x−7)(x+11)=0
Step 2: Set factors equal to 0.
x−7=0 or x+11=0
x=7 or x=−11
b.) x(x + 4) = -2(3x + 8)
Step 1: Simplify both sides of the equation.
x^2+4x=−6x−16
Step 2: Subtract -6x-16 from both sides.
x^2+4x−(−6x−16)=−6x−16−(−6x−16)
x^2+10x+16=0
Step 3: Factor left side of equation.
(x+2)(x+8)=0
Step 4: Set factors equal to 0.
x+2=0 or x+8=0
x=−2 or x=−8
Answer:
a) {-11, 7}.
b) {-8, -2}
Step-by-step explanation:
a) x^2 + 4x - 77 = 0
To factor this we need 2 numbers whose product is -77 and sum is + 4.
They are + 11 and - 7, so:
( x + 11)(x - 7) = 0
x + 11 = 0 or x - 7 = 0
x = -11, 7.
b) x(x + 4) = -2(3x + 8)
x^2 + 4x = -6x - 16
x^2 + 4x + 6x + 16 = 0
x^2 + 10x + 16 = 0
(x + 2)(x + 8) = 0
x = -8, -2.
If p varies inversely as q and p =8 when q=10,find p when q=4
Answer:
20
Step-by-step explanation:
When two numbers vary inversely, they always multiply to the same product, in this case, it is 80, because it is 8 x 10(product of two known values of p and q). This means, for q = 4, we can write:
p * 4 = 80
This means that p is equal to 20.
The value of p is 20 when q=4
What is directly proportional and inversely proportional relationship?Let there are two variables p and q
Then, p and q are said to be directly proportional to each other if
p = kq
where k is some constant number called constant of proportionality.
When two numbers vary inversely, then the will always multiply to the same product,
Here it is 80, because it is 8 x 10
Then product of two known values of p and q).
This means, for q = 4, we can write:
p x 4 = 80
This means that p is 20.
Learn more about directly inversely proportional relationship variable here:
https://brainly.com/question/13082482
#SPJ2
50 POINTS PLEASE HELP
Given the list of measures of EXTERIOR angles (missing one) of a polygon, find the missing angle:
a. ___, 92°, 28°, 55°, 75°, 55°
b. ___, 71°, 69°, 40°, 62°
c. ___, 120°, 38°, 80°
d. ___, 90°, 60°, 40°, 30°, 60°, 30°
Answer:
Step-by-step explanation:
The measures of the exterior angles of all polygons add up to 360. So all we have to do is subtract the given values from 360 and we will have the missing angle.
a. 55
b. 118
c. 122
d. 50
HELPPPP, which expression is it?
Answer: D
Step-by-step explanation:
formula=V=(π)r2h
A 4.0kg brick is sliding on a surface. The coefficient of kinetic friction between the surfaces is 0.25. What is the size of the force of friction?
a. ON b. 1 N
c. 10 N
d. 4 N
Answer:
Choice C. 10N
Step-by-step explanation:
[tex]F_{k} =U_{k} *F_{N}\\F_{k} =.25*[(4kg*10m/s2)] : [40N][/tex]
[tex]F_{k} =10N[/tex]
Ilhan needs to write in function notation and evaluate this equation at the given value of the
independent variable. What answer should she get? 6x + y = 3; x=3
Answer:
it should be the second one I hope this help
An exam starts at 10:10 and lasts for 75 minutes what time does the exam end pls help i will give brainliest
Given:
An exam starts at 10:10 and lasts for 75 minutes.
To find:
The time when the exam end.
Solution:
We have,
Starting time = 10:10
Exam duration = 75 minutes
First we will divide the 75 minutes in two parts 50 minutes and 25 minutes.
We know that 50 minutes after 10:10 is 11:00 and 25 minutes after 11:00 is 11:25. So,
10:10 + 75 minutes = 10:10 + 50 minutes +25 minutes)
= (10:10 + 50 minutes) +25 minutes
= 11:00 +25 minutes
= 11:25
Therefore, the exam ends at 11:25.
12. (05.02 LC) Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = 7 over q and tan y° = 7 over r, what is the value of sec y°? (4 points) sec y° = q over r sec y° = 7r sec y° = 7q sec y° = r over q
Answer:
[tex]sec~y=\frac{q}{r}[/tex]
Step-by-step explanation:
[tex]tan ~y=\frac{7}{r} \\\\\frac{sin~y}{cos~y} =\frac{7}{r} \\\\sin~y=\frac{7}{r} cos~y\\sin ~y=\frac{7}{q} \\\frac{7}{q} =\frac{7}{r} cos~y\\sec~y=\frac{7}{r} \times \frac{q}{7} =\frac{q}{r}[/tex]
The tangent is equal to the product of the sine and secant. The value of sec y is q over r, then the correct option is A.
What is a right-angle triangle?It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function. The Pythagoras is the sum of the square of two sides is equal to the square of the longest side.
If sin y = 7/q and tan y = 7/r.
Then the value of sec y will be
We know that the identity
[tex]\sec x =\dfrac{\tan x}{\sin x}[/tex]
Then we have
[tex]\rm \sec y = \dfrac{7/r}{7/q} \\\\\\\sec y = \dfrac{q}{r}[/tex]
The value of sec y is q over r.
More about the right-angle triangle link is given below.
https://brainly.com/question/3770177
2/3 of a number is 11 work out half the number
Answer:
33/4
Step-by-step explanation:
Let n = number
2/3 * n = 11
Multiply each side by 3/2
3/2 * 2/3 n = 11 * 3/2
n = 33/2
We want to find 1/2 of n
1/2 * 33/2 = 33/4
On a tuesday a magician said i made my wife disappear 31 days ago what day of the week did he make her disappear
Answer:
Saturday.
Step-by-step explanation:
To answer the above question, we must recognise that Tuesday appears once every 7 days.
If today is Tuesday, 31 days ago will be obtained as follow:
31/7 = 4 remainder 3
Thus
31 = (7 × 4) + 3
31 = (28) + 3
Thus, the 28th day is Tuesday. If we count 3 days back from Tuesday, the day will be Saturday.
Therefore, the magician made his wife disappear on Saturday.
Solve the inequality and write the solution in interval notation:
x-6/x+5 <0
(-5, 6)
[-5, 6)
(-infinity,-5) U [6,infinity)
(-infinity,-5] U (6,infinity)
Answer:
A
Step-by-step explanation:
Firstly x cannot be -5 because the expression on th left would be undefined so it's only between choices a and c.
Create a number line with makes the expression on left 0 and undefined...so at 6 and -5 this happens.
-------(-5)--------(6)---------
Let's test the 3 intervals by choosing a value from that interval to see if all numbers from that interval will make the expression on left less than 0.
Number before -5 is -6:
(-6-6)/(-6+5)=-12/-1=12 >0 so this interval is not a part of our solution.
Number between -5 and 6 is 0:
(0-6)/(0+5)=-6/5<0 so this interval is a part of our solution
Number after 6 like 7:
(7-6)/(7+5)=1/12>0 so this interval is not a part of our solution.
The winner is everything between-5 and 6 so answer is A.
Instructions: Find the missing side. Round your answer to the nearest tenth.
36
Х
71°
Answer:
x = 12.4
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan 71 = 36/x
x tan 71 = 36
x = 36/tan 71
x=12.39579
To the nearest tenth
x = 12.4
What is the tangent ratio of angle B?
a. tan= BC/AB
b. tan= AC/AB
c. tan= AC/BC
d. tan= BC/AC
Answer:
C
Step-by-step explanation:
tanB = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{AC}{BC}[/tex] → C
What is the solution to the equation?
3 + V3x – 5= x
Answer: (D) 7
Step-by-step explanation:
Solve the following inequality: |x + 1| <_3
<_ = greater than or equal to
Answer:
x <= -4 or x >= 2
Step-by-step explanation:
so, it actually says
|x+1| >= 3
so, then, this is valid for all x >= 2 (then x+1 is 3 or higher), and for all x <= -4 (then x+1 is -3 or lower, and |x+1| is still 3 or higher)