Answer:
10
Step-by-step explanation:
Given the following
<X = 60°
I = 90°
IX = 5(Adjacent)
Required
SX (HYPOTENUSE
According to SOH CAH TOA
Cos theta = adj/hyp
Cos 60 = 5/SX
SX = 5/cos 60
SX = 5/(1/2).
SX =5×2
SX = 10
The perimter of a rectangle is 34 units. Its width is 6.5 units. Write an equation to determine the length (l) if the rectangle
Answer:
Step-by-step explanation:
P=2(w)+2(l)
34=2(6.5)+2(l)
34=13+2(l)
21=2(l)
10.5=l
3. The simple interest on $6,000 for 4 years is $1,680. *
Suppose a quadratic equation is given as follows:
(k – 1)x² + x + 1 = 0
Select all values of k for which the above equation has two real and unequal roots
0
.25
0.5
0.75
1
1.25
1.5
1.75
Answer:
k>1.25
Step-by-step explanation:
The given quadratic equation is :
(k – 1)x² + x + 1 = 0
We need to find all values of k for which the above equation has two real and unequal roots.
For a quadratic equation ax²+bx+c=0, for real and unequal roots,
b²-4ac>0
Here, a = (k-1), b = 1 and c = 1
Put all the values,
1²-4×(k-1)1>0
1-4k+4>0
5-4k>0
k>1.25
S, k can take values more than 1.25. Hence, it can take values 1.5, 1.75.
Hello if you're able to answer this question help me and provide work as well, Thank you.
Answer:
answer is no. a -1/8 for sure
1 squared + 1= 2 sqaured - 2
2 sqaured + 2 = 3 squared - 3
3 squared + 3= 4 squared - 4
a) make a conjecture about this pattern. write your conjecture in words
b) generalise your conjecture for this pattern
c) prove that your conjecture is true
Answer:
It would be the letter B :)
What is the equivalent recursive definition for an = 12+ (n - 1)3?
A. a1 = 3, An = An-1 + 12
B. a1 = 12, An = 30n-1
C. a1 = 12, Un = On-1 +3
D. a1 = n, an= 1201-1+3
Answer:
[tex]A_1 = 12[/tex]
[tex]A_n = A_{n-1} + 3[/tex]
Step-by-step explanation:
Given
[tex]A_n =12+(n-1)3[/tex]
Required
Write as recursive
We have:
[tex]A_n =12+(n-1)3[/tex]
Open bracket
[tex]A_n =12+3n-3[/tex]
[tex]A_n =12-3+3n[/tex]
[tex]A_n =9+3n[/tex]
Calculate few terms
[tex]A_1 =9+3*1 = 9 + 3 = 12[/tex]
[tex]A_2 =9+3*2 = 9 + 6 = 15[/tex]
[tex]A_3 =9+3*3 = 9 + 9 = 18[/tex]
The above shows that the rule is to add 3.
So, we have:
[tex]A_1 = 12[/tex]
[tex]A_n = A_{n-1} + 3[/tex]
The following hypothetical data represent a sample of the annual numbers of home fires started by candles for the past several years.
5640, 5090, 6590, 6380, 7165, 8440, 9980
The population has a standard deviation equal to 1210. Assuming that the data is from a distribution that is approximately normal, construct a 90 % confidence interval for the mean number of home fires started by candles each year
Answer:
(6290.678 ; 7790.742)
Step-by-step explanation:
Given the data :
5640, 5090, 6590, 6380, 7165, 8440, 9980
The sample mean, xbar = Σx / n = 49285 / 7 = 7040.71
The 90% confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * σ/√n
Since the σ is known, we use the z- distribution
Zcritical at 90% confidence = 1.64
Hence,
Margin of Error = 1.64 * 1210/√7
Margin of Error = 750.032
90% confidence interval is :
7040.71 ± 750.032
Lower boundary = 7040.71 - 750.032 = 6290.678
Upper boundary = 7040.71 + 750.032 = 7790.742
(6290.678 ; 7790.742)
An item was marked down 64% from its original price, x. The amount discounted was $30. Which equation can be
used to find the original price?
0.64(x) = 30
0.64(30) = x
30 +0.64 = x
x + 0.064 = 30
Answer:
0.64(x) = 30
Step-by-step explanation:
Hope that's correct.
what is the mean mark of 847 ÷ 30?
Answer:
Step-by-step explanation:
1. The cardboard costs 0.002 cents per square mm but glue for each box is also 1 cent per box
2. The plastic costs 0.003 cents per square mm. No glue is necessary. It’s sealed by heat.
Which packaging costs less money?
Please write out the steps in explanation on how to solve these
1836-1347 and 4865-3956
Please help will give brainliest answer
D none of the above
as it should be ([tex]\sqrt[5]{x}[/tex])^4
NO LINKS!!!
What is the volume of this solid?
220 cubic units.
Answer:
Solution given:
for small cylinder
r=1
and for large cylinder
R=5+1=6
height for both [h]=2
Now
Volume of solid=πR²h-πr²h=πh(R²-r²)
=3.14*2(6²-1²)=219.8 =220 units ³.
Small cylinder is r=1
Large cylinder is R= 5+1 =6
Height (h) =2
Volume of solid,
→ πR²h-πr²h
→ πh(R²-r²)
→ 3.14 × 2(6²-1²)
→ 219.8
→ 220 cubic units
You buy items costing $1900 and finance the cost with a fixed installment loan for 24 months at 8% simple interest per year.
1. What is the finance charge?
2. What is your monthly payment?
* Please explain how you got the answer*
9514 1404 393
Answer:
$304$91.83Step-by-step explanation:
1. The finance charge is found from the simple interest formula;
I = Prt
where P is the principal amount, r is the annual rate, and t is the number of years.
24 months is 2 years, so the interest charged is ...
I = $1900×0.08×2 = $304
The finance charge is $304.
__
2. The monthly payment will be the total amount due, divided by the number of months.
payment = ($1900 +304)/24 = $2204/24 ≈ $91.83
The monthly payment is $91.83.
A tank with capacity of 600 gal of water originally contains 200 gal of water with 100 lb of salt in solution. Water containing 1 lb of salt per gallon is entering at a rate of 3 gal/min, and the mixture is allowed to flow out of the tank at a rate of
Answer:
Step-by-step explanation:
From the information given:
Tank's Capacity = 600 gal
Original content of water = 200 gal
Salt solution = 100 lb
In the tank:
Suppose x(t) = amount of salt at time (t); &
V(t) = volume of water
Then,
V(t) = 200 + t
and [tex]x'(t) = 3 - \dfrac{2x(t)}{200+t}[/tex]
From the above linear equation, the integrating factor can be computed as:
[tex]x(t) = \Bigg(e^{\int \dfrac{2}{200+t}} \Bigg)^{dt}[/tex]
[tex]= e^{2 \ log (200+t)}[/tex]
= (200 + t)²
The general solution can now be expressed as:
[tex]x(t) = \dfrac{1}{(200+t)^2}\Bigg( \int 3(200+t)^2 \ dt +C\Bigg)[/tex]
We know that C = integrating factor, thus taking the integral:
[tex]x(t) = \dfrac{(200+t)^3 +C}{(200+t)^2}[/tex]
At the initial condition, x(0) = 100
∴
[tex]100= \dfrac{(200)^3 +C}{(200)^2}[/tex]
C = ((200)²×100) - 200³
C = -4 × 10⁶
Hence, at any time t, the amount of salt is:
[tex]x(t) = \dfrac{(200+t^2) - 4\times 10^6}{(200+t)^2}[/tex]
If ∠1 = 3x, ∠2 = 5x + 18, and s ⊥ r, find m∠1.
I hope it will help you.
Answer:
x = 9
Step-by-step explanation:
angle <1 and angle <2 is complementary and their sum is 90 degrees
3x + 5x + 18 = 90 add like terms
8x + 18 = 90 subtract 18 from both sides
8x = 72 divide both sides by 8
x = 9 to find the measure of angle <1 replace x with the value we found
help me out pleaseeee
Answer:
The correct option is (b).
Step-by-step explanation:
The solution of the given polynomial is :
[tex](-\dfrac{1}{3},4)[/tex]
x = 1/3 and y = -4
i.e.
Sum of roots = (1/3-4) = -11/3
Product of roots = (1/3)(-4) = -4/3
The quadratic equation is as follows :
[tex]x^2+(\text{sum of roots})x+\text{Product of roots}=0[/tex]
Put all the values,
[tex]x^2+\dfrac{-11}{3}x+\dfrac{-4}{3}=0\\\\3x^2-11x-4=0[/tex]
So, the correct option is (b).
Consider the expression below. Assume the variable m represents an integer. 6m(3m + 21) Enter an expression in the box that uses the variable m and makes the equation true. (Simplify your answer completely. If no expression exists, enter DNE.) 6m(3m + 21) = 9 Given that m represents an integer, is 6m(3m + 21) divisible by 9?
Answer:
[tex](a)\ 6m(3m + 21) = 9(2m^2 + 14m)[/tex]
(b) Yes, it is divisible by 9
Step-by-step explanation:
Given
[tex]6m(3m + 21)[/tex]
Solving (a): Complete the blanks
[tex]6m(3m + 21) = 9 [\ ][/tex]
Expand the bracket
[tex]6m(3[m + 7]) = 9 [\ ][/tex]
[tex]6m*3(m + 7) = 9 [\ ][/tex]
Express 6m as 2m * 3
[tex]2m*3*3(m + 7) = 9 [\ ][/tex]
[tex]2m*9(m + 7) = 9 [\ ][/tex]
Rewrite as:
[tex]9 * 2m(m + 7) = 9 [\ ][/tex]
Multiply the bracket by 2m
[tex]9 * (2m^2 + 14m) = 9 [\ ][/tex]
Divide both sides by 9
[tex]2m^2 + 14m = [\ ][/tex]
Hence, the bracket will be filled with: [tex]2m^2 + 14m[/tex]
So:
[tex]6m(3m + 21) = 9(2m^2 + 14m)[/tex]
Solving (b): Is [tex]6m(3m + 21)[/tex] divisible by 9?
In (a), we have:
[tex]6m(3m + 21) = 9(2m^2 + 14m)[/tex]
The leading factor "9" implies that the expression is divisible by 9
3p(2p - 9) - 2p(-9 + p)
Answer:
4p² - 9p
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Algebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
3p(2p - 9) - 2p(-9 + p)
Step 2: Simplify
[Distributive Property] Distribute 3p: 6p² - 27p - 2p(-9 + p)[Distributive Property] Distribute -2p: 6p² - 27p + 18p - 2p²[Subtraction] Combine like terms (p²): 4p² - 27p + 18p[Addition] Combine like terms (p): 4p² - 9pExplain why in a drawer containing only two different colors of socks one must draw only three socks to find a matching pair
For the sequence an = an-1 + an-2 and ai = 2, a2 = 3,
its first term is
its second term is
its third term is
its fourth term is
its fifth term is
Answer:
[tex]a_1 = 2[/tex]
[tex]a_2 = 3[/tex]
[tex]a_3 = 5[/tex]
[tex]a_4 = 8[/tex]
[tex]a_5 = 13[/tex]
Step-by-step explanation:
Given
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_1 = 2[/tex]
[tex]a_2 = 3[/tex]
Solving (a): The first term
This has already been given as:
[tex]a_1 = 2[/tex]
Solving (b): The second term
This has already been given as:
[tex]a_2 = 3[/tex]
Solving (c): The third term
This is calculated as:
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_3 = a_{3-1} +a_{3-2}[/tex]
[tex]a_3 = a_2 +a_1[/tex]
[tex]a_3 = 3 +2[/tex]
[tex]a_3 = 5[/tex]
Solving (d): The fourth term
This is calculated as:
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_4 = a_{4-1} +a_{4-2}[/tex]
[tex]a_4 = a_3 +a_2[/tex]
[tex]a_4 = 5+3[/tex]
[tex]a_4 = 8[/tex]
Solving (e): The fifth term
This is calculated as:
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_5 = a_{5-1} +a_{5-2}[/tex]
[tex]a_5 = a_4 +a_3[/tex]
[tex]a_5 = 8+5[/tex]
[tex]a_5 = 13[/tex]
Solve the solution as an ordered pair
X + 9 = y
X = 4y - 6
Answer:
-10, -1
Step-by-step explanation:
See Image below:)
A company that manufactures vehicle trailers estimates that the monthly profit for selling its midsize trailer is represented by function p, where t is the number of trailers sold. p(t)= -25t^3+625t^2-2500t Use the key features of function p to complete these statements. The company makes a profit when it sells _____trailers. The maximum profit of approximately $____ occurs when it sells approximately____ trailers.
Answer:
The answer is below
Step-by-step explanation:
The profit equation is given by:
p(t)= -25t³+625t²-2500t
The maximum profit is the maximum profit that can be gotten from selling t trailers. The maximum profit is at point p'(t) = 0. Hence:
p'(t) = -75t² + 1250t - 2500
-75t² + 1250t - 2500 = 0
t = 2.3 and t = 14.3
Therefore t = 3 trailers and t = 15 trailers
p(15) = -25(15³) + 625(15²) - 2500(15) = 18750
Therefore the company makes a maximum profit of approximately $18750 when it sells approximately 15 trailers.
Answer:
See below
Step-by-step explanation:
Since t is number of trailers, the domain includes only those values greater than 0.
On the relevant domain, the graph crosses the x-axis at the points (5,0) and (20,0). Between these points, the value of p(t) is positive. So the company makes a profit when it sells between 5 and 20 trailers.
On the positive interval between these points, the graph reaches a relative maximum when t roughly equals 14 and p(t) roughly equals $19,000.
So the maximum profit of approximately $19,000 occurs when it sells approximately 14 trailers.
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters. How much work is done in stretching the spring from 30 centimeters to 60 centimeters?
Answer:
The work done is 202.50Nm
Step-by-step explanation:
Given
[tex]F =450N[/tex]
[tex]x_1 = 30cm[/tex]
[tex]x_2 = 60cm[/tex]
Required
The work done
First, we calculate the spring constant (k)
[tex]F = kx_1[/tex]
[tex]450N = k *30cm[/tex]
[tex]k = \frac{450N}{30cm}[/tex]
[tex]k =15N/cm[/tex]
So:
[tex]F = kx_1[/tex]
[tex]F(x) = 15x[/tex]
The work done using Hooke's law is:
[tex]W =\int\limits^a_b {F(x)} \, dx[/tex]
This gives:
[tex]W =\int\limits^{60}_{30} {15x} \, dx[/tex]
Rewrite as:
[tex]W =15\int\limits^{60}_{30} {x} \, dx[/tex]
Integrate
[tex]W =15 \frac{x^2}{2}|\limits^{60}_{30}[/tex]
This gives:
[tex]W =15 *\frac{60^2 - 30^2}{2}[/tex]
[tex]W =15 *\frac{2700}{2}[/tex]
[tex]W =15 *1350[/tex]
[tex]W =20250N-cm[/tex]
Convert to Nm
[tex]W =\frac{20250Nm}{100}[/tex]
[tex]W =202.50Nm[/tex]
Choose which two numbers the following will fall between: *
V156 PLEASE HELP ME FASTTTTT
[tex]\sf\purple{A.\:Between \:12\:and\:13.}[/tex] ✅
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex] \sqrt{156} \\ = 12.4899 \\ = 12.49[/tex]
Therefore, [tex] \sqrt{156} [/tex] will fall in between 12 and 13.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]
A rectangular prism has a base area of 2 square feet and a height of 5 feet. What
is the volume of the prism in cubic feet?
10
15
12
11
Submit
Katy runs a day care center . So far this year , the enrollment has consisted of 2 toddlers and 8 children of other ages . Considering this data, how many of the next 20 children to enroll should you expect to be toddlers?
Answer:
You should expect 4 of the next 20 children to enroll to be toddlers.
Step-by-step explanation:
This question is solved by proportions.
So far:
We have that of 2 + 8 = 10 children, 2 are toddlers, so the proportion of toddlers is 2/10 = 0.2.
How many of the next 20 children to enroll should you expect to be toddlers?
0.2 out of 20, so: 0.2*20 = 4
You should expect 4 of the next 20 children to enroll to be toddlers.
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
Let n represent the interger l, the three consective intergers are represented by
[tex]n[/tex]
[tex]n + 2[/tex]
[tex]n + 4[/tex]
The second one represent
[tex](n + 2) {}^{2} + 76 =( n + 4) {}^{2} [/tex]
Simplify both sides
[tex]n {}^{2} + 4n + 4 + 76 = {n}^{2} + 8n + 16[/tex]
[tex] {n}^{2} + 4n + 4 = {n}^{2} + 8n - 60[/tex]
[tex]4n + 4 = 8n - 60[/tex]
[tex]4n + 64= 8n[/tex]
[tex]64= 4n[/tex]
[tex]n = 16[/tex]
The intergers are 16,18,20
The product of two consecutive negative integers is 600. What is the value of the lesser integer?
–60
–30
–25
–15
Answer:
-25
Step-by-step explanation:
-24×(-25)=600
Hope this helps! :)
Answer: It's -25
edg 2023
the sumof 8pq and -17 pq is
Answer:
= -9pq
Step-by-step explanation:
=8pq + (-17pq)
=8pq-17pq
= -9pq
