Situation:
You invest $4,000 in an account that
pays an interest rate of 5.5%,
compounded continuously.
Calculate the balance of your account after 15
years. Round your answer to the nearest
hundredth.

Answers

Answer 1

Answer:

[tex]{ \bf{A=(P + \frac{r}{100} ) {}^{n} }} \\ { \tt{ = (4000 + \frac{5.5}{100} ) {}^{15} }} \\ \\ { \tt{ = \: 1.074 \times {10}^{54} \: dollars}}[/tex]


Related Questions

how do you get rid of the fractions

Answers

Answer:

x = - 12/11

Step-by-step explanation:

Multiply by LCM (or LDC if you like that term better)

2 & 3 LCM = 6

6(3/2) x  + 6(1/3)x  + 5*6 = 3*6

9x + 2x + 30 = 18

11x = - 12

x = - 12/11

The graph of a linear function is given below. What is the zero of the function?

Answers

Answer:

Need to see the problem, but the "zero of the function" is the x value when y=0.

Substitute '0' for y.

Solve for x

Answer: D

Step-by-step explanation:

A team wishes to purchase 10 shirts of the same color. A store sells shirts in 3 different colors. What must the inventory of the store be in order to conclude that there are at least 10 shirts in one of the three colors?

Answers

Answer:

30

Step-by-step explanation:

Question 24 plz show ALL STEPS

Answers

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

a) The first 5 partial sums are listed in the table in the attachment.

__

b) Sigma notation makes use of the general term shown:

  [tex]\displaystyle\sum_{n=1}^\infty{\frac{3^n+(-2)^n}{6^n}}[/tex]

__

c) The sum appears to be close to 3/4. (For large n, a calculator cannot evaluate the terms of the series--they are too small.) The attachment shows the 100th sum to be rounded to 3/4 (from 12 significant digits).

kabura bought a piece of cloth 3 metres long. The material shrunk by 1% after washing. What was the new length of the cloth​

Answers

Answer:

2.97m

Step-by-step explanation:

1% of 3m =1/100×3=0.03

0.03m of cloth was shrunk,

So, New lenght : 3-0.03=2.97m

Which best describes the relationship between the line that passes through the points (-6,5) and (-
2,7) and the line that passes through the points (4, 2) and (6, 6)?

Answers

Answer:

Slope passes through (-6, 5) and (-2, 7)

[tex]m_1=\frac{y_2-y_1}{x_2-x_1} =m_1=\frac{7-5}{-2+6}[/tex]

[tex]m_1=\frac{2}{4} =\frac{1}{2}[/tex]

Slope passes through (4, 2) and (6, 6)

[tex]m_2=\frac{6-2}{6-4}[/tex]

[tex]\frac{4}{2} =2[/tex]

[tex]m_1\times m_2 \neq -1[/tex] [tex]m_1\neq m_2[/tex]

Answer:- A) neither perpendicular nor parallel.

OAmalOHopeO



What is the image point of (4, -6) after a translation right 5 units and up 4 units?

Answers

Answer:

(9,-2)

Step-by-step explanation:

5 is the x coordinate, and 4 is the y coordinate. When you go right a certain amount of units, you add those units to your x coordinate. If you were to go left a certain amount of units, you'd subtract them. Since we're going right, 5 + 4 = 9. When you go up a certain amount of units, you add those units to you y coordinate. If you were to go down a certain amount of units, you'd subtract them.  Since we're going up, -6 + 4 = -2. So, x = 9 and y = -2, or (9,-2)

What is the 11th term of this geometric sequence?: 16384, 8192, 4096, 2048

Answers

Answer:

16

Step-by-step explanation:

1) Find out r of the sequence. The first term(a1) is 16384, the second term (a2) is 8192.

8192=16384*r. r= 0.5

2) Use the rule that an=a1*r^(n-1)

a11=a1*r^10

a11= 16384*((0.5)^10)= 16384/ (2^10)=16.

MY NOTES Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) f(x) = 2x2 − 4x + 3, [−1, 3

Answers

Answer:

b)  [tex]c=1[/tex]

Step-by-step explanation:

From the question, we are told that:

Function

[tex]F(x)=2x^2-4x+9[/tex]

Given

Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.

Generally, the Function above is a polynomial that can be Differentiated and it is continuous

Where

-F(x) is continuous at (-1,3)

-F(x) Can be differentiated at (-1.3)

-And F(-1)=F(3)

Therefore

F(x) has Satisfied all the Requirements for Rolle's Theorem

Differentiating F(x) we have

[tex]F'(x)=4x-4[/tex]

Equating F(c) we have

[tex]F'(c)=0[/tex]

[tex]4(c)-4=0[/tex]

Therefore

[tex]c=1[/tex]

An object is moving at a speed of 5 kilometers every 4.5 hours. Express this speed in miles per minute

Answers

Answer:

Step-by-step explanation:

1 km = 0.621 mi

1 hr = 60 min

(5 km)/(4.5 hr) × (0.621 mi)/km × (1 hr)/(60 min) = (0.0115 mi)/min

What is the slope of the line through (-9,6)(−9,6)left parenthesis, minus, 9, comma, 6, right parenthesis and (-6,-9)(−6,−9)left parenthesis, minus, 6, comma, minus, 9, right parenthesis?

Answers

Answer:

Step-by-step explanation:

Slope of line through (-9,6) and (-6,-9) = (-9 - 6)/(-6 - (-9)) = (-15)/(3) = -5

point-slope equation for line of slope -5 that passes through (-9,6):

y-6 = -5(x+9)

Answer:

1/2

Step-by-step explanation:

because i answered it on khan academy and it was right

Slope=  

Run

Rise

=  

Change in x

Change in y

start text, S, l, o, p, e, end text, equals, start fraction, start text, R, i, s, e, end text, divided by, start text, R, u, n, end text, end fraction, equals, start fraction, start text, C, h, a, n, g, e, space, i, n, space, end text, y, divided by, start text, C, h, a, n, g, e, space, i, n, space, end text, x, end fraction

Hint #22 / 3

\begin{aligned} \text{Slope}&=\dfrac{9-6}{-3-(-9)} \\\\ &=\dfrac{3}{6} \\\\ &=\dfrac{1}{2} \end{aligned}  

Slope

 

=  

−3−(−9)

9−6

 

=  

6

3

 

=  

2

1

 

 

Hint #33 / 3

The slope is \dfrac{1}{2}  

2

1

start fraction, 1, divided by, 2, end fraction.

[tex]Solve. Clear fraction first.6/5 + 2/5 x = 89/30 + 7/6 x + 1/6[/tex]

Answers

Step-by-step explanation:

we have denominators 5, 6 and 30.

the smallest number that is divisible by all 3 is clearly 30.

so, we have to multiply everything by 30 to eliminate the fractions.

180/5 + 60/5 x = 89 + 210/6 x + 30/6 =

36 + 12x = 89 + 35x + 5

-58 = 23x

x = -58/23

Solve for
x
Round to the nearest tenth, if necessary.

Answers

9514 1404 393

Answer:

  x = 5.0

Step-by-step explanation:

The tangent relation is helpful:

  Tan = Opposite/Adjacent

  tan(50°) = x/4.2

  x = 4.2·tan(50°) ≈ 5.0054 . . . . multiply by 4.2

  x ≈ 5.0

What is the value of p?

A. 125°
B. 45°
C. 35°
D. 550

Answers

Answer:

C- 35 °

Step-by-step explanation:

Interior angle adjacent to 90° angle = 90° (supplementary angles of a line segment).

Interior angle adjacent to 125° angle = 55° (supplementary angles of a line segment).

Sum of two interior angles of the triangle = 55+90 = 145°

∠p = 180° - 145° = 35°

C. 35° if you take the adjacent angle of 125° and subtract this from 180° you are left with 55°. Add this to the other 90° and you get 145°. You can then take 180°-145° to get 35°.

***URGENT***
PLEASE HELP ME ASAP, ITS DUE TODAY!!!
............................................................

T is the point on AB such that AT:TB = 5: 1. Show that ot is parallel to the vector a + 2b.

Answers

Step-by-step explanation:

SO, OT is parallel to the vector a+2b

did from six times a certain number the result is 96 what is the number​

Answers

Answer:

The number is 16

Step-by-step explanation:

Number : x

Procedure and resolution:

6x = 96

x = 96/6

x = 16

Good Luck!
6x= 96
6/6x=96/6
X= 16

a day? 6. If 18 pumps can raise 2150 tonnes of water in 50 days, working 8 hours a day, how much water will be raised in 60 days by 16 out of which 10 are working 9 hours a day and the rest 7 hours a day?

Answers

Given, 18 pumps----2170 tonnes----10*7 hrs.
So, 16 pumps-------2170 tonnes----10*7*18/16 hrs.
And, 16 pumps-------1736 tonnes----10*7*(18/16)*(1736/2170)hrs. = 63 hrs.

So, no. of days req.= 63/9 = 7 days

I need help ASAP please and thank you

Answers

9514 1404 393

Answer:

  C. 4 +√(x+5)

Step-by-step explanation:

The sign between the terms changes to form the conjugate. The radical contents are unchanged.

The conjugate of 4 -√(x+5) is 4 +√(x+5).

_____

Additional comment

The utility of a conjugate is that the product of a number and its conjugate is the difference of two squares. The squares are intended to remove an undesirable feature of the number, its imaginary part or its irrational part, for example. Here, the product of the number and its conjugate would be ...

  (a -b)(a +b) = a² -b²

  4² -(√(x+5))² = 16 -(x +5) = 11 -x . . . . no longer contains a root

find the surface area of the prism HURRY

Answers

Answer:

Does the answer help you?

A plot of land in the shape of a horizontal ellipse has a pole at each focus. The foci are 16 feet from the center. If the plot of land is 40 feet across one axis, how long is it across the other axis?

a. 34 feet
b. 46 feet
c. 24 feet
d. 30 feet

Answers

Answer: 24 feet

Step-by-step explanation: i just guessed it on pluto and got it right. please leave a like if it worked

The length of another axis for the given ellipse will be around 25.6125 feet so none of the options will be correct.

What is an ellipse?

a regular oval form produced when a cone is cut by an oblique plane that does not intersect the base, or when a point moves in a plane so that the sum of its distances from two other points remains constant.

In another word, an ellipse is a curve that becomes by a point moving in such a way that the sum of its distances from two fixed points is a closed planar curve produced.

General equation of an ellipse

(x 2 / a 2 )+ (y2 / b 2 )= 1

Given that

the plot of land is 40 feet across one axis

so  2a = 40 feet

a = 20 feet

The foci are 16 feet from the center so

c = 16

Now we know that

c = √(b² - a²)  

c² = b² - a²

16² = b² - 20²

b = 25.6125  

So, the length of the minor axis will be around 25.6125 feet.

To learn more about ellipse,

https://brainly.com/question/14281133

#SPJ2

Which of the following would increase the width of a confidence interval for a population​ mean? Choose the correct answer below. A. Increase the level of confidence B. Decrease the sample standard deviation. C. Increase the sample size D. All of the above

Answers

Answer:

A. Increase the level of confidence

Step-by-step explanation:

The margin of error is given by:

The margin of error is:

[tex]M = \frac{Ts}{\sqrt{n}}[/tex]

In which T is related to the level of confidence(the higher the level of confidence, the higher T is), s is the standard deviation of the sample and n is the size of the sample.

Increase the width:

That is, increasing the margin of error, as the width is twice the margin of error, the possible options are:

Increase T -> increase confidence level.

Increase s -> Increase the standard deviation of the sample.

Decrease n -> Decrease the sample size.

Thus, the correct answer is given by option A.

A plane flying horizontally at an altitude of 3 mi and a speed of 460 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 4 mi away from the station (Round your answer to the nearest whole number.) 368 X mi/h Enhanced Feedback Please try again. Keep in mind that distance - (altitude)2 + (horizontal distance)? (or y = x + n ). Differentiate with respect to con both sides of the equation, using the Chain Rule, to solve for the given speed of the plane is x.

Answers

Answer:

[tex]\frac{dy}{dt}=304mi/h[/tex]

Step-by-step explanation:

From the question we are told that:

Height of Plane [tex]h=3mi[/tex]

Speed [tex]\frac{dx}{dt}=460mi/h[/tex]

Distance from station [tex]d=4mi[/tex]

Generally the equation for The Pythagoras Theorem is is mathematically given by

[tex]x^2+3^2=y^2[/tex]

For y=d

[tex]x^2+3^2=d^2[/tex]

[tex]x^2+3^2=4^2[/tex]

[tex]x=\sqrt{7}[/tex]

Therefore

[tex]x^2+3^2=y^2[/tex]

Differentiating with respect to time t we have

[tex]2x\frac{dx}{dt}=2y\frac{dy}{dt}[/tex]

[tex]\frac{dy}{dt}=\frac{x}{y}\frac{dx}{dt}[/tex]

[tex]\frac{dy}{dt}=\frac{\sqrt{7}}{4} *460[/tex]

[tex]\frac{dy}{dt}=304.2614008mi/h[/tex]

[tex]\frac{dy}{dt}=304mi/h[/tex]

Two coins are tossed. Assume that each event is equally likely to occur. ​a) Use the counting principle to determine the number of sample points in the sample space. ​b) Construct a tree diagram and list the sample space. ​c) Determine the probability that no tails are tossed. ​d) Determine the probability that exactly one tail is tossed. ​e) Determine the probability that two tails are tossed. ​f) Determine the probability that at least one tail is tossed.

Answers

Answer:

(a) 4 sample points

(b) See attachment for tree diagram

(c) The probability that no tail is appeared is 1/4

(d) The probability that exactly 1 tail is appeared is 1/2

(e) The probability that 2 tails are appeared is 1/4

(f) The probability that at least 1 tail appeared is 3/4

Step-by-step explanation:

Given

[tex]Coins = 2[/tex]

Solving (a): Counting principle to determine the number of sample points

We have:

[tex]Coin\ 1 = \{H,T\}[/tex]

[tex]Coin\ 2 = \{H,T\}[/tex]

To determine the sample space using counting principle, we simply pick one outcome in each coin. So, the sample space (S) is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

The number of sample points is:

[tex]n(S) = 4[/tex]

Solving (b): The tree diagram

See attachment for tree diagram

From the tree diagram, the sample space is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

Solving (c): Probability that no tail is appeared

This implies that:

[tex]P(T = 0)[/tex]

From the sample points, we have:

[tex]n(T = 0) = 1[/tex] --- i.e. 1 occurrence where no tail is appeared

So, the probability is:

[tex]P(T = 0) = \frac{n(T = 0)}{n(S)}[/tex]

This gives:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Solving (d): Probability that exactly 1 tail is appeared

This implies that:

[tex]P(T = 1)[/tex]

From the sample points, we have:

[tex]n(T = 1) = 2[/tex] --- i.e. 2 occurrences where exactly 1 tail appeared

So, the probability is:

[tex]P(T = 1) = \frac{n(T = 1)}{n(S)}[/tex]

This gives:

[tex]P(T = 1) = \frac{2}{4}[/tex]

[tex]P(T = 1) = \frac{1}{2}[/tex]

Solving (e): Probability that 2 tails appeared

This implies that:

[tex]P(T = 2)[/tex]

From the sample points, we have:

[tex]n(T = 2) = 1[/tex] --- i.e. 1 occurrences where 2 tails appeared

So, the probability is:

[tex]P(T = 2) = \frac{n(T = 2)}{n(S)}[/tex]

This gives:

[tex]P(T = 2) = \frac{1}{4}[/tex]

Solving (f): Probability that at least 1 tail appeared

This implies that:

[tex]P(T \ge 1)[/tex]

In (c), we have:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Using the complement rule, we have:

[tex]P(T \ge 1) + P(T = 0) = 1[/tex]

Rewrite as:

[tex]P(T \ge 1) = 1-P(T = 0)[/tex]

Substitute known value

[tex]P(T \ge 1) = 1-\frac{1}{4}[/tex]

Take LCM

[tex]P(T \ge 1) = \frac{4-1}{4}[/tex]

[tex]P(T \ge 1) = \frac{3}{4}[/tex]

A certain freezing process requires that room temperature be lowered from 35oC at the rate of 6oC every hour. What will be the room temperature 8 hours after the process begins?​

Answers

Answer:

-13 degrees celcius.

Step-by-step explanation:

6 degrees are lowered every hour. 6*8 = 48 degrees, 48 degrees are lowered.

35-48 is -13. The room temperature will be -13 eight hours after the process begins.

please help me with this
Evaluate -8 × |2|.

Answers

Answer:

-16

Step-by-step explanation:

The absolute value of 2 is 2 so -8*2=-16

b) solve by factorisation
[tex]x { }^{2} + x - 72 = 0[/tex]

Answers

QUESTION:- SOLVE EQUATION BY FACTORISATION

EQUATION:-

[tex] {x}^{2} + x - 72 = 0[/tex]

ANSWER:-

[tex] {x}^{2} + x - 72 = 0\\{x}^{2} + 9x - 8x - 72 = 0 \\ x(x + 9) - 8(x +9) = 0 \\ (x - 8)(x + 9) = 0 \\ [/tex]

NOW FOR VALUE OF X ->

[tex]x - 8 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x + 9 = 0\\ x = 8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 9[/tex]

convert the following to decimal fractions 99 by 5 ​

Answers

Answer:

divide 99 by 5

99/5= 19.8

Jean can swim 100 meters in 1.86 minutes. Sean can swim the same distance in 2.12 minutes.

Answers

please where is the question

Greatest to least just need some help will help ty(please don’t give wrong answer)

Answers

Answer:

try 91.78, 91.58, 91.26, 363.4

Step-by-step explanation:

Hello hello sis happy birthday dear sis happy birthday birthday happy birthday to you sis happy birthday dear sis dear happy birthday dear sis dear dear friend love love miss mommy mommy hello sis dear happy birthday dear sis dear dear sis sis happy birthday dear sis dear happy birthday dear sis dear dear sis sis happy birthday dear sis dear dear sis sis happy birthday dear sis dear dear

salifye pizza charges a base pizza of $12.77 for large plus 7.44 additional topping.
a) Find a function that models the price of a pizza with toppings.
Find the inverse of the function. What does−1 represent?
If a pizza costs $20.20, how many toppings does it have?

Answers

Answer:

Sharjah Call Girls +971529238486 | Call Girls In Sharjah

Step-by-step explanation:

Sharjah Call Girls and our group are very a good deal satisfied to participate withinside the boom of the leisure field. Lots of customers are touring Sharjah now no longer handiest for playing the splendor of the town however additionally to the sensual entertainments our profiles.

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