Answers
Related Questions
A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0.5 kilograms. The company wishes to test the hypothesis H0: µ = 12 against H1: µ < 12 using a random sample of n = 4 specimens. Calculate the P-value if the observed statistic is Xbar (average) = 11.25. Suppose that the distribution of the sample mean is approximately normal.
Answers
Answer:
The p-value of the test is 0.0013.
Step-by-step explanation:
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
12 is tested at the null hypothesis:
This means that [tex]\mu = 12[/tex]
Standard deviation of 0.5 kilograms.
This means that [tex]\sigma = 0.5[/tex]
Sample of n = 4 specimens. Observed statistic is Xbar (average) = 11.25.
This means that [tex]n = 4, X = 11.25[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{11.25 - 12}{\frac{0.5}{\sqrt{4}}}[/tex]
[tex]z = -3[/tex]
P-value:
Probability of finding a sample mean belo 11.25, which is the p-value of z = -3.
Looking at the z-table, z = -3 has a p-value of 0.0013, thus the this is the p-value of the test.
Identify the level of measurement (nominal, ordinal, or interval-ratio) of each of the following variables: (1) How satisfied a person is with his or her employment benefits, measured as very satisfied, somewhat satisfied, neither satisfied nor dissatisfied, somewhat dissatisfied, or very dissatisfied. (2) The number of times someone has shoplifted in her or his life. (3) The number of times someone has voted in a public election measured as 0-1 times, 2-3 times, or 4 or more times. (4) The type of attomey a criminal defendant has attrial, measured as privately retained or publicly funded.
Answers
Solution :
Nominal variable
A nominal variable is defined as a variable which is used to [tex]\text{nam}e \text{ or label or categorize some particular attributes }[/tex] which are being measured.
An ordinal variable is the one in which the order matters, but the difference between any two orders does not matter.
In interval ratio variable is defined as the variable where the difference between any two values is meaningful.
The level of measurement for each of the following are :
1) Variables that are categorized in categories so that it is ordinal data.
2) Data scaled with the two categories her or his, so it is a nominal data.
3) Number of votes categorized in the intervals so it is Interval type data.
4) nominal data.
When randomly selecting adults, let M denote the event of randomly selecting a male and let B denote the event of randomly selecting someone with blue eyes. What does P(M|B) represent? Is P(M|B) the same as P(B|M)?
Answers
Answer:
See explanation
Step-by-step explanation:
Given
[tex]M \to[/tex] randomly selecting a male
[tex]B \to[/tex] randomly selecting someone with blue eyes
Solving (a): Interpret P(M|B)
The above implies conditional probability
The interpretation is: the probability of selecting a male provided that a person with blue eyes has been selected
Solving (b): is (a) the same as P(B|M)
No, they are not the same.
The interpretation of P(B|M) is: the probability of selecting a person with blue eyes provided that a male has been selected
3. Tell whether each statement is true or false Explain how you know a) LCM (7, 18) - LCM (14.18) b) LCM (5,8) - LCM (10,8) c) The GCF of any two prime numbers is 1 and the number itself.
Answers
Step-by-step explanation:
ok for a. the both are 126
and for b. the both are 30
for c. i believe its true
What is the smallest 6-digit palindrome (a number that reads the same forward and
backward) divisible by 99?
Answers
Answer:
108801
Step-by-step explanation:
Well, you should first add 99 to 99999 which is 10098. And since it's not a palindrome you need to keep adding 99 to the sum until you reach one.
----------------------------------
This is with a calculator
Btw, I used calculator soup.com for it.
100089, 100188, 100287, 100386, 100485, 100584, 100683, 100782, 100881, 100980, 101079, 101178, 101277, 101376, 101475, 101574, 101673, 101772, 101871, 101970, 102069, 102168, 102267, 102366, 102465, 102564, 102663, 102762, 102861, 102960, 103059, 103158, 103257, 103356, 103455, 103554, 103653, 103752, 103851, 103950, 104049, 104148, 104247, 104346, 104445, 104544, 104643, 104742, 104841, 104940, 105039, 105138, 105237, 105336, 105435, 105534, 105633, 105732, 105831, 105930, 106029, 106128, 106227, 106326, 106425, 106524, 106623, 106722, 106821, 106920, 107019, 107118, 107217, 107316, 107415, 107514, 107613, 107712, 107811, 107910, 108009, 108108, 108207, 108306, 108405, 108504, 108603, 108702, 108801, 108900, 108999, 109098, 109197, 109296, 109395, 109494, 109593, 109692, 109791, 109890
Recall the creative calligraphy case we discussed in class. Suppose you have received a rush order of 55 invitations that have to be created in the next (four hour) work session. What is the most time You (i.e. not Susie) can spend writing on the card and envelope for each invitation and still fill the order
Answers
Answer:
About 4 minutes and 3 seconds
Step-by-step explanation:
If I have 55 invitations to be created in four hours.
4 hours × 60 =240 minutes
240/55= 4.36 minutes
So if I spend 4 minutes and 3 seconds on an invitation, I should be able to fill the order.
You and a friend were invited to a
party. You both were asked to bring
pizzas and chips. Your friend brought
three pizzas and four bags of chips
and spent $48.05. You brought five
pizzas and two bags of chips and
spent $67.25. What is the cost of
each? Answer should be in (Pizza, Chips)
Answers
Answer:
Pizza = 12.35
Chips = 2.75
Step-by-step explanation:
Let :
Pizza = x
chips = y
3x + 4y = 48.05 - - - (1)
5x + 2y = 67.25 - - - (2)
Multiply (1) by 5 and (2) by 3
15x + 20y = 240.25
15x + 6y = 201.75
Subtract :
20y - 6y = 240.25 - 201.75
14y = 38.50
y = 38.50/ 14
y = 2.75
Put y = 2.75 in (1)
3x + 4(2.75) = 48.05
3x + 11 = 48.05
3x = 48.05 - 11
3x = 37.05
x = 37.05 / 3
x = 12.35
Pizza = 12.35
Chips = 2.75
The following table shows the distribution of people in a tennis tournament, and one
person is to be selected at random.
Find the probability that the selected person is a female.
Express your answer as a decimal, rounded to the nearest hundredth.
Under Age 35
Male 8 Female 18
35 years and older
Male 11 Female18
Answers
Answer:
36/55
Step-by-step explanation:
Total 55 persons, total females 36.
The probability that the selected person is a female from the given table is gotten as; 0.65
What is the Probability?
From the given table we see that;
Males under 35 years = 8
Females under 35 years = 18
Males 35 years and older = 11
Females 35 years and older = 18
Thus;
Total number of people = 8 + 18 + 11 + 18
Total people = 55
Thus, probability that the selected person is a female is;
P(female) = (18 + 18)/55
P(female) = 36/55
P(female) = 0.65
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Uma pizzaria oferece em seu cardápio 12 sabores de pizza. Se um cliente pretende pedir 3 pizzas, então o número de maneiras que ele pode realizar esse pedido é;
•364
•220
•440
•1320
Answers
Answer:
Step-by-step explanation:
Partindo do pressuposto de que você pode ter coberturas duplas e triplas do mesmo item, o cálculo é relativamente simples. Para calcular as combinações possíveis; deve-se multiplicar as coberturas disponíveis pelo número total de coberturas permitidas. Este cálculo é semelhante a como olhamos para diferentes sistemas de contagem de base. Normalmente contamos com decimais (base 10), portanto, o número de combinações, se usar 3 dígitos, seria calculado por 10 x 10 x 10.
10x10 = 100
100x10 = 1000 combinações (0 a 999)
Sua pergunta sobre coberturas de pizza é a mesma, mas assumindo um sistema de numeração de base 12, então 12x12x12 ou 12³
Portanto, 1.728 combinações incluindo 0 (sem coberturas?) E também incluindo 12 ocasiões em que todas as 3 coberturas seriam iguais. Se esses cenários de pessoas forem restritos de modo que você só possa ter coberturas duplas máximas, etc., então essas combinações devem ser removidas (subtraídas do total de combinações permitidas).
Espero ter ajudado você a entender os princípios, então você deve ser capaz de trabalhar a partir disso, de muitas outras soluções semelhantes
Give two examples of subtraction of fractions ( between 0-1) with different denominators.
SHOW ALL STEPS
Answers
Answer:
3/4-1/2=1/4 4/5-3/15
Step-by-step explanation:
3/4-1/2
=3/4-2/4
=1/4
4/5-3/15
=4/5-1/5
=3/5
PLEASE ANSWER ILL MARK !!
Answers
Step-by-step explanation:
a) Use sine law:
[tex]\dfrac{g}{\sin 60} = \dfrac{17\:m}{\sin 49}[/tex]
Solving for g,
[tex]g = \left(\dfrac{\sin 60}{\sin 49}\right)(17\:m)=19.5\:m[/tex]
b) Use the cosine law here:
[tex]q^2 = (11\:\text{cm})^2 + (16\:\text{cm})^2 \\ - 2(11\:\text{cm})(16\:\text{cm})\cos 29[/tex]
Solving for q,
[tex]q = 8.3\:\text{cm}[/tex]
Evaluate for x=2 and y=3: x^2y^-3/x^-1y
Answers
Answer:
8/81
Step-by-step explanation:
It's most efficient to simplify the quotient algebraically before inserting the values of the variables x and y.
The given expression reduces to x³ / y^4.
Substituting 2 for x and 3 for y, we get:
(2)³ 8
--------- = ---------- (Agrees with first given possible answer)
(3)^4 81
1-0.4^n>=0.99 howwwwwwwwwwwwwwwwwwwwwwwwww
Answers
Answer:
n>=6
Step-by-step explanation:
1-0.4ⁿ>=0.99
1-0.99>=0.4ⁿ
0.4ⁿ<=0.01
Apply log10:
Log10(0.4ⁿ)<=log10(0.01)
n×log10(0.4)<=log10(0.01)=-2
Because log10(0.4)=-0.39794 is negative we get:
n>=5.028.
Since n is integer, we have n>=6
In a survey, 250 adults and children were asked whether they know how to
swim. The survey data are shown in the relative frequency table.
Can swim
Cannot swim
Total
0.34
Adults
Children
0.06
0.48
0.12
Total
What percentage of the people surveyed can swim?
O A. 18%
B. 82%
C. 48%
D. 34%
Answers
Answer:
B - 82%
Step-by-step explanation:
.34+.48
The percentage of people who can swim is 82%.
Option B is the correct answer.
What is a percentage?
The percentage means the required value out of 100.
It is calculated by dividing the required value by the total value and multiplying it by 100.
The percentage change is also calculated using the same method.
In percentage change, we find the difference between the values given.
Example:
Required percentage value = a
total value = b
Percentage = a/b x 100
We have,
The relative frequency table shows the proportion of people in each group who can and cannot swim.
To find the percentage of people who can swim, we need to add up the proportion of adults who can swim (0.34) and the proportion of children who can swim (0.48).
Percentage of people who can swim
= (0.34 + 0.48) x 100%
= 82%
Therefore,
The percentage of people who can swim is 82%.
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Find dy/dx of the function y = √x sec*-1 (√x)
Answers
Hi there!
[tex]\large\boxed{\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) + \frac{1}{2|\sqrt{x}|\sqrt{{x} - 1}}}[/tex]
[tex]y = \sqrt{x} * sec^{-1}(-\sqrt{x}})[/tex]
Use the chain rule and multiplication rules to solve:
g(x) * f(x) = f'(x)g(x) + g'(x)f(x)
g(f(x)) = g'(f(x)) * 'f(x))
Thus:
f(x) = √x
g(x) = sec⁻¹ (√x)
[tex]\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) + \sqrt{x} * \frac{1}{\sqrt{x}\sqrt{\sqrt{x}^{2} - 1}} * \frac{1}{2\sqrt{x}}[/tex]
Simplify:
[tex]\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) + \sqrt{x} * \frac{1}{2|x|\sqrt{{x} - 1}}[/tex]
[tex]\frac{dy}{dx} = \frac{1}{2\sqrt{x}}sec^{-1}(\sqrt{x}) + \frac{1}{2|\sqrt{x}|\sqrt{{x} - 1}}[/tex]
Answer:
[tex]\displaystyle y' = \frac{arcsec(\sqrt{x})}{2\sqrt{x}} + \frac{1}{2|\sqrt{x}|\sqrt{x - 1}}[/tex]
General Formulas and Concepts:
Algebra I
Exponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Rule [Root Rewrite]: [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]Calculus
Derivatives
Derivative Notation
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Arctrig Derivative: [tex]\displaystyle \frac{d}{dx}[arcsec(u)] = \frac{u'}{|u|\sqrt{u^2 - 1}}[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = \sqrt{x}sec^{-1}(\sqrt{x})[/tex]
Step 2: Differentiate
Rewrite: [tex]\displaystyle y = \sqrt{x}arcsec(\sqrt{x})[/tex]Product Rule: [tex]\displaystyle y' = \frac{d}{dx}[\sqrt{x}]arcsec(\sqrt{x}) + \sqrt{x}\frac{d}{dx}[arcsec(\sqrt{x})][/tex]Chain Rule: [tex]\displaystyle y' = \frac{d}{dx}[\sqrt{x}]arcsec(\sqrt{x}) + \bigg[ \sqrt{x}\frac{d}{dx}[arcsec(\sqrt{x})] \cdot \frac{d}{dx}[\sqrt{x}] \bigg][/tex]Rewrite [Exponential Rule - Root Rewrite]: [tex]\displaystyle y' = \frac{d}{dx}[x^\bigg{\frac{1}{2}}]arcsec(\sqrt{x}) + \bigg[ \sqrt{x}\frac{d}{dx}[arcsec(\sqrt{x})] \cdot \frac{d}{dx}[x^\bigg{\frac{1}{2}}] \bigg][/tex]Basic Power Rule: [tex]\displaystyle y' = \frac{1}{2}x^\bigg{\frac{1}{2} - 1}arcsec(\sqrt{x}) + \bigg[ \sqrt{x}\frac{d}{dx}[arcsec(\sqrt{x})] \cdot \frac{1}{2}x^\bigg{\frac{1}{2} - 1} \bigg][/tex]Simplify: [tex]\displaystyle y' = \frac{1}{2}x^\bigg{\frac{-1}{2}}arcsec(\sqrt{x}) + \bigg[ \sqrt{x}\frac{d}{dx}[arcsec(\sqrt{x})] \cdot \frac{1}{2}x^\bigg{\frac{-1}{2}} \bigg][/tex]Rewrite [Exponential Rule - Rewrite]: [tex]\displaystyle y' = \frac{1}{2x^\bigg{\frac{1}{2}}}arcsec(\sqrt{x}) + \bigg[ \sqrt{x}\frac{d}{dx}[arcsec(\sqrt{x})] \cdot \frac{1}{2x^\bigg{\frac{1}{2}}} \bigg][/tex]Rewrite [Exponential Rule - Root Rewrite]: [tex]\displaystyle y' = \frac{1}{2\sqrt{x}}arcsec(\sqrt{x}) + \bigg[ \sqrt{x}\frac{d}{dx}[arcsec(\sqrt{x})] \cdot \frac{1}{2\sqrt{x}} \bigg][/tex]Arctrig Derivative: [tex]\displaystyle y' = \frac{1}{2\sqrt{x}}arcsec(\sqrt{x}) + \bigg[ \sqrt{x}\frac{1}{|\sqrt{x}|\sqrt{(\sqrt{x})^2 - 1}} \cdot \frac{1}{2\sqrt{x}} \bigg][/tex]Simplify: [tex]\displaystyle y' = \frac{arcsec(\sqrt{x})}{2\sqrt{x}} + \frac{1}{2|\sqrt{x}|\sqrt{x - 1}}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
If the domain of a function that is translated down 3 is (0, 4), (-5, 8), (4, -2), what is the range?
A. (0, 1), (-5, 5), (4, -5)
B. (3, 4), (-2, 8), (7, -2)
C. (-3, 4), (-8, 8), (1, -2)
D. (0, 7), (-5, 11), (4, 1)
Answers
Given:
The domain of function that is translated down 3 is (0, 4), (-5, 8), (4, -2).
To find:
The range of the function.
Solution:
If a function is translated 3 units down, then
[tex](x,y)\to (x,y-3)[/tex]
Using this rule, we get
[tex](0,4)\to (0,4-3)[/tex]
[tex](0,4)\to (0,1)[/tex]
Similarly,
[tex](-5,8)\to (-5,5)[/tex]
[tex](4,-2)\to (4,-5)[/tex]
The range of the given function is (0, 1), (-5, 5), (4, -5).
Therefore, the correct option is A.
The running trail in the local park is 2.826 miles long. If the park board were planning to extend the trail by 1.46 miles, what would the new length of the running trail be?
Answers
Answer:
4.286
Step-by-step explanation:
you really need help with this ? you cannot just use your calculator ? that would have been faster than putting that question in here ...
remember, similar to the number positions in front of the decimal point, it is equally important to add the same positions after the decimal point.
we have 10th, 100th, 1000th, 10000th, 100000th, ... no end possible.
so we have
2.826 miles
and need to add 1.46 miles
2.826
1.46
----------
4.286
and the line of thinking goes from right to left
nothing plus 6 is 6
6 plus 2 is 8
4 plus 8 is 12, so we write 2 and carry over the 1
1 plus 2 plus 1 carry over is 4
if it helps, you can always add zeroes at the end of any digits after the decimal point, as you can also add zeroes in front to the digits before the decimal point to make both numbers have the same length and their decimal points are perfectly aligned.
our addition could have also looked like
2.826
1.460
with the same result
overall, if this is truly helping you, an example of using both leading and tailing zeroes could be
4278.9472081
0021.6380000
---------------------
4300.5852081
A boy had 3 apples and lost one, how many does he have now
Answers
Step-by-step explanation:
i would love to say 2 but the word had shows that he does not have 3 apples anymore so the answer is either
0 or -1
The number of apples left after taking the 1 apple from 3 apples by a person is 2 apples.
What is subtraction?Subtraction stands for the resultant number, which exists acquired by taking the difference of a number from another number.
Let a number be subtracted from the number b. Then the consequent number after subtracting b from a will be,
d = b - a
Here, (a, b) exists the real numbers.
It exists given that there exist 3 apples. 1 apple stand was taken. Let's assume after taking the 3 apples, that there exist x apples remaining.
As there exist a total of 3 apples and 1 apple stand taken, then to estimate the number of apples left, we must subtract 1 apple from 3 apples.
Therefore, the total apples left exist,
x = 3 - 1
x = 2
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You bought a car that was $25500 and the value depreciates by 4.5% each year.
How much will the car be worth after 5 years?
How much after 8 years?
Answers
Answer:
(a) 20256.15625
(b) 17642.78546
Step-by-step explanation:
(a) There's a formula for this problem y = A(d)^t where, A is the initial value you are given, d is the growth or decay rate and t is the time period. So, in this case, as the car cost is decreasing it is a decay problem and we can write the formula as such; y = A(1-R)^t
So, in 5 years the car will be worth, 25500(1-4.5%)^5 or 20256.15625 dollars
(b) And after 8 years the car will be worth 25500(1-4.5%)^8 or 17642.78546 dollars.
Suppose that the probability distribution for birth weights is normal with a mean of 120 ounces and a standard deviation of 20 ounces. The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is [ Select ] 68%. The probability that a randomly selected infant has a birth weight between 110 and 130 is [ Select ] 68%.
Answers
Answer:
The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is 68%.
The probability that a randomly selected infant has a birth weight between 110 and 130 is 38%.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 120 ounces and a standard deviation of 20 ounces.
This means that [tex]\mu = 120, \sigma = 20[/tex]
The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is
p-value of Z when X = 140 subtracted by the p-value of Z when X = 100.
X = 140
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{140 - 120}{20}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a p-value of 0.84
X = 100
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 120}{20}[/tex]
[tex]Z = -1[/tex]
[tex]Z = -1[/tex] has a p-value of 0.16
0.84 - 0.16 = 0.68
The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is 68%.
The probability that a randomly selected infant has a birth weight between 110 and 130
This is the p-value of Z when X = 130 subtracted by the p-value of Z when X = 110.
X = 130
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{130 - 120}{20}[/tex]
[tex]Z = 0.5[/tex]
[tex]Z = 0.5[/tex] has a p-value of 0.69
X = 110
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{110 - 120}{20}[/tex]
[tex]Z = -0.5[/tex]
[tex]Z = -0.5[/tex] has a p-value of 0.31
0.69 - 0.31 = 0.38 = 38%.
The probability that a randomly selected infant has a birth weight between 110 and 130 is 38%.
Need help putting the answer in
Answers
Step-by-step explanation:
We can rewrite the given equation as
[tex]x^2 + \frac{1}{5}x - \frac{12}{25} = (x + \frac{4}{5})(x - \frac{3}{5})[/tex]
As a check, let's multiply out the factors:
[tex](x + \frac{4}{5})(x - \frac{3}{5}) = x^2 - \frac{3}{5}x + \frac{4}{5}x - \frac{12}{25}[/tex]
[tex]= x^2 + \frac{1}{5}x - \frac{12}{25}[/tex]
and this is our original equation.
An 8-oz bottle of hair spray costs $4.46. Find the unit price in cents per ounce
Answers
Answer:
55.75 cents per ounce
Step-by-step explanation:
Take the cost and divide by the number of ounces
We want cents per ounce so change dollars to cents
446 / 8
55.75 cents per ounce
How's The online class？
Answers
Answer:
weak
Step-by-step explanation:
i dont be having fun at all
The principal P is borrowed at a simple interest rate are for a period of time T. Find the loans future value A, or the total amount due at time T
Answers
Answer:
The total amount due after five years is $57,000.
Step-by-step explanation:
Recall that simple interest is given by the formula:
[tex]\displaystyle A=P(1+rt)[/tex]
Where A is the final amount, P is the principal amount, r is the rate, and t is the time (in years).
Since we are investing a principal amount of $38,000 at a rate of 10.0% for five years, P = 38000, r = 0.1, and t = 5. Substitute:
[tex]\displaystyle A=38000(1+(0.1)(5))[/tex]
Evaluate. Hence:
[tex]\displaystyle A=\$ 57,000[/tex]
The total amount due after five years is $57,000.
Which of the following is equivalent to
5v13^3
Answers
Answer:
13⅗ is the answer of your quest
13 3/5.
$2900 at 13% for 30 years. i need simple interest and compounding interest
Answers
Answer:
Step-by-step explanation:
simple:
2900(1+.13*30)=14210
Compounding
[tex]2900(1+.13)^{30}=113436.1041[/tex]
Answer:
113436.1041
Step-by-step explanation:
2900 ( 1 +0.13 ) ^ 30
Formula : amount ( 1 + percentage ) ^ years
Which describes the transformations applied in the figure above?
1. A clockwise rotation of 180 degrees about the origin.
2. A counterclockwise rotation of 270 degrees about the origin.
3. A counterclockwise rotation of 90 degrees about the origin.
4. A clockwise rotation of 270 degrees about the origin.
Answers
Answer:
2. A counterclockwise rotation of 270 degrees about the origin.
Step-by-step explanation:
Point A before the transformation:
Before the transformation, point A was at (-2,2).
After the transformation, point A' is (2,2).
Point B:
Before the transformation, point B was at (-6,-3)
After the transformation, point B' is (-3,6).
Transformation rule:
From the transformations of points A and B, we get that the transformation rule is (x,y) -> (y,-x), which is a counterclockwise rotation of 270 degrees about the origin., and the correct answer is given by option 2.
Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width.
Answers
Answer:
eh width = 103.5 inches
Step-by-step explanation:
x = width
Length = (x/2 - 5 )*6
so 384=x+3x-30
414=4x
x=414/4=103.5 inches
I’m stuck please help .
Answers
Answer:
me too
Step-by-step explanation:
me too
Sally bought five books.Their mean price was 3.25. The total cost for four books was 11.75.what was the cost of the fifth book
Answers
Answer:
$4.50
Step-by-step explanation:
Use the mean formula: mean = sum of elements / number of elements
Let x represent the cost of the fifth book, and solve for x:
mean = sum of elements / number of elements
3.25 = (11.75 + x) / 5
16.25 = 11.75 + x
4.5 = x
So, the cost of the fifth book was $4.50
