Simplify: 41a-2b + 3c) + 11a

9514 1404 393

Answer:

  ₱6400

Step-by-step explanation:

Let 'b' represent the amount invested in scheme B. Then 13900-b is the amount invested in scheme A. The total interest for 2 years is then ...

  14%(13900-b)(2) +11%(b)(2) = 3508

  1946 -0.03b = 1754 . . . . . . divide by 2, simplify

  -0.03b = -192 . . . . . . . . . subtract 1946

  b = 6400 . . . . . . . . . . . divide by -0.03

The amount invested in scheme B was ₱6400.

Answer:

Pretty sure it's 0.528

Answer:

C. 9

Step-by-step explanation:

Start plugging in the number 2

3(2)^2+3(2)-9

6^2+6-9

12+6-9

18-9

9

9514 1404 393

Answer:

Step-by-step explanation:

Let L represent the length of the rectangle. Then the width is W=5+3L, and the perimeter is ...

  P = 2(L+W)

  240 = 2(L +(5 +3L))

  120 = 5 +4L

  115 = 4L

  115/4 = L = 28.75 . . . . cm

  W = 5+3L = 5 +3(28.75) = 91.25 . . . . cm

The length and width of the rectangle are 28.75 cm and 91.25 cm.

Answer:

6x+24=10

4x=24

x=6

OAmalOHopeO

Answer:

Step-by-step explanation:

OK, Since angle B and angle K are equal and the line segment CE is a bisector,So the shape is divided into two equal triangular parts.

therefore angle E divide into two equal part(angles) ;then: 6x+24=10x--->4x=24--->x=6

9514 1404 393

Answer:

  all of them (A, B, C, D)

Step-by-step explanation:

Two unique points define a line. Any pair of unique points will always be collinear (reside on the same line).

Each of the points listed, together with (2, 1), will define a line. The two points will be collinear.

Answer:

a) 0.1295

b) The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).

Step-by-step explanation:

Question a:

112 out of 865, so:

[tex]\pi = \frac{112}{865} = 0.1295[/tex]

Question b:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 865, \pi = 0.1295[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 - 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1071[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 + 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1519[/tex]

The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).

Answer:We know the total amount of money invested. $17818

x+y=17818,

We know that the difference in interest earned by the two accounts is $490.33

0.11*x-0.06*y=490.33

x=17818-y

We substitute for x

0.11*(17818-y)-0.06*y=490.33

We multiply out

1959.98-0.11y-0.06*y=490.33

We combine like terms.

1469.65=0.17*y

Isolate y

y=1469.65/0.17

y=8645 at 6%

Calculate x

x=17818-8645

x=9173 at 11%

Check

0.11*9173-0.06*8645=490.33

interest earned at 11%=1009.03

interest earned at 6%=518.70

1009.03-518.7=490.33

490.33=490.33

Since this statement is TRUE and neither amount is negative then all is well.We know the total amount of money invested. $17818

x+y=17818,

We know that the difference in interest earned by the two accounts is $490.33

0.11*x-0.06*y=490.33

x=17818-y

We substitute for x

0.11*(17818-y)-0.06*y=490.33

We multiply out

1959.98-0.11y-0.06*y=490.33

We combine like terms.

1469.65=0.17*y

Isolate y

y=1469.65/0.17

y=8645 at 6%

Calculate x

x=17818-8645

x=9173 at 11%

Check

0.11*9173-0.06*8645=490.33

interest earned at 11%=1009.03

interest earned at 6%=518.70

1009.03-518.7=490.33

490.33=490.33

Since this statement is TRUE and neither amount is negative then all is well.

Let X be a random number selected from the interval. Then the probability density for the random variable X is

[tex]f_X(x)=\begin{cases}\dfrac1{10-6.35}=\dfrac1{3.65}\approx0.2740&\text{if }6.35\le x\le 10\\0&\text{otherwise}\end{cases}[/tex]

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute

P(|X - 8| < 0.25) + P(|X - 10| < 0.25)

… = P(7.75 < X < 8.25) + P(9.75 < X < 10.25)

… = P(7.75 < X < 8.25) + P(9.75 < X < 10)

(since P(X > 10) = 0)

… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)

… = 0.2055

Step-by-step explanation:

A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.

There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.

Problem 8. (Continues previous problem.) A type I error occurs if (Q12)

Problem 9. (Continues previous problem.) A type II error occurs if (Q13)

Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)

Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)

Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)

Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)

Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)

(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.

Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)

Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)

Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)

9514 1404 393

Answer:

  (a) 5.82 cm (correctly shown)

  (b) 10.53 cm

Step-by-step explanation:

a) The length BC can be found from the law of sines:

  BD/sin(C) = BC/sin(D)

  BC = BC·sin(C)/sin(D) = (6 cm)sin(48°)/sin(50°) ≈ 5.82 cm

__

b) The angle ABD is the sum of the angles shown:

  angle ABD = 50° +48° = 98°

We know the lengths BA and BD and the included angle ABD, so we can use the law of cosines to find AD.

  AD² = BA² +BD² -2·BA·BD·cos(98°)

  AD² ≈ 8² +5.82² -2(8)(5.82)(-0.139173) ≈ 110.8411

  AD ≈ √110.8411 ≈ 10.53 . . . . cm

Answer:

1006

Step-by-step explanation:

Take proportion, p = 62%

n = (Z² * pq) / M.E²

Margin error = 0.03

p = 62% = 0.62

q = 1 - p = 1 - 0.62 = 0.38

Zcritical at 95% = 1.96

n = (1.96² * (0.62*0.38)) / 0.03²

n = 0.90508096 / 0.0009

n = 1005.6455

n = 1006

Sample size = 1006

9514 1404 393

Answer:

  all real numbers

Step-by-step explanation:

The arrows on the ends of the curve indicate that the graph extends to infinity horizontally. The domain is the horizontal extent, so is all real numbers.

__

Additional comment

Apparently, y=-7 is a horizontal asymptote, so the range is y > -7.

Answer:

Hi! There's no picture, but we don't need that to find the answer. Parallel lines always have the same slope. I suppose you're saying that the green and red line are parallel -- so, the red line's slope is also -2.

-2 <--

Hope this helps!! Have a nice day & please mark brainliest if you don't mind!

Answer:

AE = 18

Step-by-step explanation:

The triangles must be similar so we can use ratios

2x+4         12

--------  = ---------

x+8          10

Using cross products

(2x+4)10 = 12 (x+8)

20x +40 = 12x+96

Subtract 12x from each side

20x-12x +40 = 12x-12x +96

8x +40 = 96

Subtract 40 from each side

8x = 96-40

8x = 56

Divide by 8

x = 56/8

x = 7

AE = 2x+4 = 2(7) +4 = 14+4 = 18

Answer:

[tex]5 \sqrt{2 } [/tex]

Step-by-step explanation:

In a 45 45 90 triangle, the hypotenuse is equal to

[tex]x \sqrt{2} [/tex]

where x is the length of a leg of the triangle

Answer:

i thank its 4000

Step-by-step explanation:

please mark this answer as brainlist

Answer:b. (8,-1) is a solution to one equation but not the other, so it is a solution to the system

Step-by-step explanation:

27. Which statement is true about the system

x+3y=11

y=r-7

a. (8,-1) is a solution to both equations, so it is a solution to the system

b. (8,-1) is a solution to one equation but not the other, so it is a solution to the system

C. (8,-1) is a solution to one equation but not the other so it is not the solution to the system

d. (8,-1) is not a solution to either equation, so it is not a solution to the system​

Answer:

-1/8

Step-by-step explanation:

(-2)^-3

We know that a^-b = 1/a^b

1/(-2)^3

We know (-2)^3 = -8

1/(-8)

-1/8

Answer:

saya tidak tahu !)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!qjjjjbugg7yhhuhhhuhgy fundes per grallahegeuebevhehehnjķßùèò395oìùýþŕèwqàďhĺ

Answer:

Onetta can salect a sandwich and a salad in 78 different ways.

Step-by-step explanation:

Since Onetta goes to the food court to get a salad and sandwich for lunch, and the Daily Deli has 8 varieties of sandwiches and 3 salads, while Better Bites has 2 varieties of sandwiches and 7 salads, and the Lunch Spot has 5 varieties of sandwiches and 8 salads, to determine the number of ways Onetta can select a sandwich and a salad, the following calculation must be performed:

8 x 3 + 2 x 7 + 5 x 8 = X

24 + 14 + 40 = X

78 = X

Therefore, Onetta can salect a sandwich and a salad in 78 different ways.

We need to find the number of buttons the company produced per day

The company produced 772 buttons per day

Total bottons produced in a week = 5404

There are 7 days in a week

If the factory produced same number of buttons every day of the week

Then,

Buttons produced per day = Total bottons produced in a week / Total number of days in a week

= 5404 / 7

= 772 buttons

The company produced 772 buttons per day

Read more: https://brainly.com/question/24368335

Answer:

3. 100% = 1

3/4 = 0.75

Now, 0.75 is halfway between 0.5 and 1, so Chris is correct.

4. 10% = 10/100 = 0.1

3/5 = 0.6

Now, 0.2 is not halfway between 0.1 and 0.6, so Emily is wrong.

Answer:

3 đúng 4 wrong

Step-by-step explanation:

100%=1

giữa 0, 5 và 1 =(0,5+1)/2=3/4

10%= 0,1

giữa  0,1 và  3/5 =(0,1+3/5)/2=  0,35  #0,2

Answer:

37.5%

Step-by-step explanation:

A=P(1+r)^t

363=192*(1+r)^2

1.375=1+r, r=0.375=37.5%

Answer:

The solutions are x = -4 and x = 4.

Step-by-step explanation:

Solving a quadratic equation:

We have to find x for which [tex]y = 0[/tex].

In this question:

[tex]y = 16 - x^2[/tex]

So

[tex]16 - x^2 = 0[/tex]

[tex]x^2 = 16[/tex]

[tex]x = \pm \sqrt{16}[/tex]

[tex]x = \pm 4[/tex]

The solutions are x = -4 and x = 4.

Answer:

B Trevor isn't correct because -2i must also be a root

Step-by-step explanation:

A Trevor is correct.

B Trevor is not correct because –2i must also be a root.

C Trevor is not correct there cannot be an odd number of roots.

D Trevor is not correct because there cannot be both rational and complex roots.

statements^^^^^^

The statement that f(x) must be a polynomial with degree 3 is not necessarily true based on the given roots.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

Since one of the roots is complex (2i), it follows that the coefficients of f(x) must be complex as well, and therefore f(x) must be a polynomial with complex coefficients.

However, it is possible for f(x) to have a higher degree than 3.

For example,

The polynomial (x + 7)(x - 2i)(x + 2i)(x - 7) has degree 4 and has the given roots of -7, 2i, and 7. Therefore, f(x) could be a polynomial with degree 4 or higher.

Thus,

The statement that f(x) must be a polynomial with degree 3 is not necessarily true based on the given roots.

Learn more about functions here:

https://brainly.com/question/28533782

#SPJ2

The statement that best compares the variability of the quiz scores for Class A and Class B is A; The scores on the quiz for Class A have more variability than the scores for Class B.

Suppose we're measuring something whose values are numeric. For each value of that thing we observe, we plot a dot above that value in the number line. Thus, the total number of dots in the dot plot tells us the total number of observations of the values of that thing we did.

LEt suppose if we observed the value 'x', then we will make a dot above 'x'. If there is already a dot over 'x', then we will make a new dot over that dot.

The dot plot is skewed to the right due to majority of the data occur to the right of the dot plot.

An outlier is a number that is way smaller or way larger than that of other numbers in a data set. Outliers usually occur with a frequency of one.

For Class A the dots are spread out more.

For Class B, the dots are more grouped together.

Here, Looking at the dot plot, it can be seen that the numbers that range from 16 to 21 have only one dot.

The statement that best compares the variability of the quiz scores for Class A and Class B is A; The scores on the quiz for Class A have more variability than the scores for Class B.

To learn more about outliers, please check: brainly.com/question/27197311

SPJ2

Answer:

12

Step-by-step explanation:

(10/y + 13) -3

Let y=5

(10/5 + 13) -3

PEMDAS says parentheses first

(2 +13) -3

15 -3

12