Select the two values of x that are roots of this equation 2x^2+5x-3=0

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Answer:

  (b)  It means that the results that Tessa obtained are too unusual to be explained by chance alone

Step-by-step explanation:

The test for statistical significance is a comparison of the result to the probability that it occurred by chance. The probability of a chance occurrence is usually set at 1% or 5%. The lower the percentage, the less likely a chance occurrence is, and the more difficult showing statistical significance becomes.

Answer:

24

Step-by-step explanation:

To find the range, you must subtract the lowest value from the highest value in the data set. If you organize the set from least to greatest, 72 is the lowest, and 96 is the highest.

So, 96 - 72 = 24, which is the range.

Answer:

Step-by-step explanation:

Um where is the diagrahm

Answer:

√3 x^5y

First, let's do √3

√3=1.7

1.7 • x^5 • y

if you want

1.7 • X^4• x• y.

There are tons of equivalent's!

9514 1404 393

Answer:

  12

Step-by-step explanation:

In base-5 arithmetic, ...

  41 -24 = 12

_____

If we use : to separate columns with different place value, this can be looked at a couple of ways.

Subtraction by addition

  2 : 4 + 0 : 2 = 3 : 1 . . . . . make the 1s place match

  3 : 1 + 1 : 0 = 4 : 1 . . . . . . make the 5s place match

The total amount added was 0:2 +1:0 = 1:2.

Subtraction using borrowing

  4 : 1 - 2 : 4 = (4-1) : (5+1) - 2 : 4

  = (4-1-2) : (5+1)-4 = 1:2

Answer:

There are 256 pairs in all.

Answer:

A. 2x + 1

Step-by-step explanation:

f(x) = 2x + 7

g(x) = x - 3

To find f(g(x)), substitute x = x - 3 into f(x) = 2x + 7

Thus:

f(g(x)) = 2(x - 3) + 7

f(g(x)) = 2x - 6 + 7

Add like terms

f(g(x)) = 2x + 1

Answer:

usai964s46s694s4o6s64694s946649s469 opps

Answer:

[tex](x,y)=(7,5)[/tex]

Step-by-step explanation:

Megan's equation will be:

[tex]20x+35y=315[/tex]

[tex]x+y=12[/tex]

Substitute [tex]x=12-y[/tex] in the first equation:

[tex]20(12-y)+35y=315[/tex]

[tex]15y=75[/tex]

[tex]y=75/15[/tex]

[tex]y=5[/tex]

Find x:

[tex]x=12-5[/tex]

[tex]x=7[/tex]

Where x and y represent 30-second and 60-second ads sold, we find that Meghan's sales were:

[tex](x,y)=(7,5)[/tex]

hope this helps....

The function has the characteristics is (b) y= (2x^2 - 8) / (x^2 - 9)

The features are given as:

The function that has the above features is (b).

This is proved as follows:

y= (2x^2 - 8) / (x^2 - 9)

Set the denominator not equal to 0, to determine the domain

x^2 - 9 ≠ 0

Add 9 to both sides

x^2 ≠ 9

Take the square roots

x ≠ ±3 --- domain

Replace ≠ with =

x = ±3 --- vertical asymptote

Set the numerator to 0

2x^2 - 8 = 0

Divide through by 2

x^2 - 4 = 0

This gives

x^2 = 4

Take the square roots

x = 2 ---- horizontal asymptote

Hence, the function has the characteristics is (b) y= (2x^2 - 8) / (x^2 - 9)

Read more about functions at:

https://brainly.com/question/4138300

#SPJ1

Answer:

[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]

Step-by-step explanation:

Given

[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]

[tex]P(1) = 2[/tex]

Required

The solution

We have:

[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]

[tex]\frac{dP}{dt} = (Pt)^\frac{1}{2}[/tex]

Split

[tex]\frac{dP}{dt} = P^\frac{1}{2} * t^\frac{1}{2}[/tex]

Divide both sides by [tex]P^\frac{1}{2}[/tex]

[tex]\frac{dP}{ P^\frac{1}{2}*dt} = t^\frac{1}{2}[/tex]

Multiply both sides by dt

[tex]\frac{dP}{ P^\frac{1}{2}} = t^\frac{1}{2} \cdot dt[/tex]

Integrate

[tex]\int \frac{dP}{ P^\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]

Rewrite as:

[tex]\int dP \cdot P^\frac{-1}{2} = \int t^\frac{1}{2} \cdot dt[/tex]

Integrate the left hand side

[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} = \int t^\frac{1}{2} \cdot dt[/tex]

[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]

[tex]2P^{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]

Integrate the right hand side

[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{1}{2} +1 }}{\frac{1}{2} +1 } + c[/tex]

[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{3}{2}}}{\frac{3}{2} } + c[/tex]

[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex] ---- (1)

To solve for c, we first make c the subject

[tex]c = 2P^{\frac{1}{2}} - \frac{2}{3}t^\frac{3}{2}[/tex]

[tex]P(1) = 2[/tex] means

[tex]t = 1; P =2[/tex]

So:

[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1^\frac{3}{2}[/tex]

[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1[/tex]

[tex]c = 2\sqrt 2 - \frac{2}{3}[/tex]

So, we have:

[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex]

[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + 2\sqrt 2 - \frac{2}{3}[/tex]

Divide through by 2

[tex]P^{\frac{1}{2}} = \frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3}[/tex]

Square both sides

[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]

Answer:

2.5, 2.05, 0, -5, -15

Step-by-step explanation:

for negative numbers the bigger is worth less

Hello!

[tex]\large\boxed{(x + 2)(x + 3)}[/tex]

x² + 5x + 6

Find two numbers that add up to 5 and multiply to 6. We get:

2, 3

Therefore:

(x + 2)(x + 3)

Answer:

The answer is C.

as for C . the value of f(x) increases by 7 and so the graph goes up by units 7.

OR

g(x) = |x| + 7

we know that |x| is f(x), so :-

g(x) = f(x) + 7

and since f(x) is plot on y- axis the graph climbs the y axis by 7 units

*The graph shifts right or left for the other functions*

Answer:

[tex]\frac{28}{n}[/tex]

Step-by-step explanation:

Answer:

85 mi

Step-by-step explanation:

Let d = the distance in miles traveled

Let M = the time in hours for Maria to travel d miles

[tex]m+\frac{3}{4} =[/tex] time in hours for Ricky to travel d miles

(Note that [tex]\frac{3}{4}[/tex] hrs = 45 min)

----------------------

Maria's equation:

d = 51m

Ricky's equation:

d = 24 · [tex](m+\frac{3}{4} )[/tex]

----------------------

Substitution:

51m = 24 · [tex](m+\frac{3}{4} )[/tex]

51m = 24m + 45

6m = 10

m = [tex]\frac{5}{3}[/tex]

----------------------

d = 51m

d = 51 · [tex](\frac{5}{3})[/tex]

d = 85

----------------------

The distance traveled is 85 mi

If it takes Ricky, traveling at 24 mph, 45 minutes longer to go a certain distance than it takes Maria traveling at 51 mph, the distance traveled is 85 miles

Speed is the ratio of distance traveled to time taken. Mathematically:

Distance = Speed/Time

According to the given question:

Set up the Maria equation:

d = 51m

Set up Ricky's equation:

d = 24 · (m+3/4)

Substitute

51m = 24 · (m+3/4)

51m = 24m + 45

6m = 10

m = 5/3

Determine the required distance

d = 51m

d = 51 · 5/3

d = 85

Hence the distance traveled is 85 mile

Learn more on distance and speed here: https://brainly.com/question/26046491

Answer:

42%

Step-by-step explanation:

to find percentages, you move the decimal point twice to the right

Answer:

7 : 8

Step-by-step explanation:

that is the procedure above

Answer:

Paedtricians claim isn't true.

Step-by-step explanation:

The hypothesis :

H0 : σ = 7

H0 : σ > 7

The test statistic ; χ² :

χ² = [(n - 1) * s²] ÷ σ²

n = 25 ; s = 4.3, σ = 7

χ² = [(25 - 1) * 4.3²] ÷ 7²

χ² = [(24 * 4.3²] ÷ 49

χ² = 443.76 / 49

χ² = 9.056

At α = 0.01 ; critical value = 42.980

Since critical value > test statistic, we fail to reject the null, H0.

Answer:

i cant see the image

Step-by-step explanation:

Answer:

Y' = - 1

Step-by-step explanation:

Y' = - 2x +3

So y' (2,2) =-2*2 +3= - 1

Answer:

36

Step-by-step explanation:

(h · f)(x) = h(f(x))

h(f(x)) = h(2x+8)

h(f(x))= 3(2x+8) - 6

h(f(x)) = 6x + 24 - 6

h(f(x))= 6x + 18

If x = 3

h(f(x))= 6(3) + 18

h(f(x))= 18 + 18

h(f(x))= 36

Hence (h · f)(3) = 36

Answer:

Joe's wife must drive at a rate of 45km/hour.

Step-by-step explanation:

We are given that Joe leaves home and bikes at a speed of 30km/hour. Joe's wife leaves home five minutes later by car, and we want to determine her speed in order for her to catch up to Joe in 10 minutes.

Since Joe bikes at a speed of 30km/hour, he bikes at the equivalent rate of 0.5km/min.

Then after five minutes, when his wife leaves, Joe is 5(0.5) or 2.5 km from the house. He will still be traveling at a rate of 0.5km/min, so his distance from the house can be given by:

[tex]2.5+0.5t[/tex]

Where t represents the time in minutes after his wife left the house.

And since we want to catch up in 10 minutes, Joe's distance from the house 10 minutes after his wife left will be:

[tex]2.5+0.5(10)=7.5\text{ km}[/tex]

Let s represent the wife's speed in km/min. So, her speed times 10 minutes must total 7.5 km:

[tex]10s=7.5[/tex]

Solve for s:

[tex]\displaystye s=0.75\text{ km/min}[/tex]

Thus, Joe's wife must drive at a rate of 0.75km/min, or 45km/hour.

Answer:

8/15

Step-by-step explanation:

Answer:

8/15

Step-by-step explanation:

when you divide 8/15 its 0.53

Answer:

Step-by-step explanation:

Here,

<6 + 125° = 180° [Co-interior angles]

=> <6 = 180 - 125

=> <6 = 55° (Ans)

9514 1404 393

Answer:

  y = 2

Step-by-step explanation:

Subtracting the second equation from the third gives ...

  (2z +3x) -(2z -2x) = (-6) -(-6)

  5x = 0

  x = 0

Using this in the third equation, we have ...

  2z +0 = -6

  z = -3

And substituting these values into the first equation, we have ...

  5y -3(0) -4(-3) = 22

  5y = 10 . . . . . subtract 12

  y = 2

__

The solution to the system is (x, y, z) = (0, 2, -3).

Answer:

Step-by-step explanation:

a.

(1.36 L)/(10 hr) = (0.136 L)/(hr)

Flow rate = (0.136 L)/(hr) × (1000 mL)/L = (136 mL)/(hr)

136 mL × (27 mg)/(100 mL) = 36.72 mg

Delivery rate = (36.72 mg)/(hr)

b.

(136 mL)/(hr) × (13 gtt)/(mL) = (1868 gtt)/(hr)

c.

10 hr × (36.72 mg)/)hr) = 367.2 mg

Hello,

answer C (11,-23)

[tex]\left\{\begin{array}{ccc}3a+b&=&10\\-4a-2b&=&2\end{array}\right.\\\\\\\left\{\begin{array}{ccc}6a+2b&=&20\\-4a-2b&=&2\end{array}\right.\\\\\\\left\{\begin{array}{ccc}3a+b&=&10\\2a&=&22\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&11\\b&=&10-3*11\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&11\\b&=&-21\end{array}\right.\\[/tex]

Answer: C. (11,-23)

Step-by-step explanation:

Answer:

m>-7

Step-by-step explanation:

expand

-10m+15-4<81

-10m+11<81

collect like terms

-10m<81-11

-10m<70

m>-7