Select the false statement
A. Vertical angles are always congruent
B.Vertical angles are sometimes complimentary
C.Two right angles are always supplementary
D. Angles that form a linear pair are sometimes supplementary. Plz answer ASAP

Answer:

a = 50

b = 50

c = 80

d = 50

e = 130

Step-by-step explanation:

e = 180 - (25 + 25)   {Angle sum property & It is an isosceles triangle}

    = 180 - 50 = 130

a +e = 180  {Linear pair}

a + 130 = 180

a = 180 - 130

a = 50

d =a   {Vertically opposite angles}

d = 50

c = 180 -(50+ 50 )     {Angle sum property & It is an isosceles triangle}

c = 180 -100

c = 80

a+b + c = 180  {Straight angles}

50 + b + 80 = 180

  b + 130 = 180

          b = 180 - 130

          b = 50

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Short answer: to solve this problem, follow directions.

Let c and p represent numbers of cakes and pies produced daily. Then the constraints are ...

  2c +3p ≤ 108 . . . . . . . . available hours of preparation time

  1c +0.5p ≤ 20 . . . . . . . available hours of decoration time

  p ≥ 0, c ≥ 0 . . . . . . . . . negative numbers of cakes or pies cannot be produced

__

It works well to let a graphing calculator do this.

The feasible region is the doubly-shaded area with vertices ...

  (0, 0), (0, 36), (3, 34), (20, 0)

__

Profit is $25 per cake and $12 per pie, so is ...

  p = 25c +12p

__

The attached table shows the profit for the various mixes of cakes and pies in the feasible region. The most profit is had by production of cakes only.

The maximum profit is $500 per day for production of 20 cakes.

_____

Additional comment

We have used x for cakes and y for pies in the attachment, because those are variables that the Desmos calculator prefers.

As is sometimes the case, the production point giving maximum profit leaves one of the resources (preparation time) only partially utilized.

Answer:

Hello,

Step-by-step explanation:

[tex]g(-9)=2\Longrightarrow\ g^{-1}(2)=-9\\\\y=h(x)=3x-4\\x=3y-4\\\\y=\dfrac{x+4}{3} \\\\h^{-1}(x)=\dfrac{x+4}{3}\\\\h(h^{-1}(x))=(h^{-1}o\ h)(x)=1_\pi(x) \ (identical\ permutation\ of\ plane) \\\\h(h^{-1}(2))=2[/tex]

Answer:

2.6

Step-by-step explanation:

We'll use the Pythagoras theorem to solve this, which states that in a right angle triangle:

h^2 = a^2 + b^2

4^2 = 3^2 +b^2

16= 9 +b^2

16-9= b^2

7= b^2

(take square root in both sides)

b= 2.65

round to nearest 10th = 2.6

answer by Gauthmath

Answer:

Missing side is 2.6

3^2 + x^2 = 4^2

9 + x^2 = 16

-9            -9

x^2 = 7

([tex]\sqrt{x}[/tex])^2 = [tex]\sqrt{7}[/tex]

x = 7

Find the approximation o the square root of 7 in fractions then carry out the long division.

Or

Approx. is 2 3/5 which equals 2 6/10 which equals 2.6

Answer:

Part A: A = 8

B = 20

C = 28

D = 35  

E = 37

F = 72

G = 43

H = 57

I = 200

Part B: 18.5%

Part C:

D = People who do not like Orange Juice

B = People who do not like Apple Juice

I use the values of B and D because these are the values that represent dislike for that juice, and also because adding them together creates a value for not liking either juice.

D = 35

B = 20

So there is a greater dislike for Orange Juice.

Step-by-step explanation:

Answer:

70 days

Step-by-step explanation:

that is the procedure above

Answer:

Hello,

m=2

(0,-3) True

(1,-1) True

(1.5,0) True

(-2,-2) False

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}y&=&mx-6\\8x-4y&=&12\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&mx-6\\y&=&2x-3\\\end{array}\right.\\\\\\The\ slope\ must\ be\ the\ same:\ m=2\\\\\\\begin{array}{c|c}&y=2x-3\\---&--------\\x&y\\0&2*0-3=-3\\1&2*1-3=-1\\1.5&2*1.5-3=0\\-2&2*(-2)-3=-7\\\end{array}[/tex]

Answer:

-2/5

Step-by-step explanation:

The diagram is missing and so i have attached it.

Answer:

Next step is;

to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.

Step-by-step explanation:

A perpendicular line is to be drawn to line GH through point A.

The steps are;

1. Identification of the two end points of the line which has been done.

2. Place one leg of the compass at point G and draw a small arc above the line GH. This has been done.

3. Without changing the span of the compass, place the same leg of the compass at point H and draw another small arc above the line GH to intersect the previously drawn small arc.

4. Make use of a straight object to connect the point of intersection of the two small arcs to the point A.

This line is the perpendicular line to GH.

In the figure attached, they have just finished point 2 I wrote above. Thus, the next step is point 3.

Answer:

to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.

Step-by-step explanation:

Let the cost of a lamp = x

6 lamps would cost 6x

He bought 3 lamps at 3x plus Thad 950 left.

3 lamps plus the 950

Would be the same amount as 6 lamps:

Set up an equation and solve for x:

3x + 950 = 6x

Subtract 3x from both sides:

950 = 3x

Divide both sides by 3:

X = 316.67

Each lamp was $316.67

Multiply the price of a lamp by 6:

316.67 x 6 = 1900

He had $1900

Answer: $1900

Step-by-step explanation:

Mr Lim had enough money to buy 6 similar lamps. However he only bought 3 such lamps. That means he had only spent half of his money (6-3=3).

So, if he take money remaining with him = x = $950

Amount of money he first had = 2x =$950×2 = $1900

Answer:

1

5

4

2

3

Step-by-step explanation:

1 combines the sets A and B. that symbol there stands for U like "union". so, all values of x, where x is either < 1 or >= 5.

2 is again a union. A and C are combined. C contains only one element : x=5.

3 is again a union. B and C are combined. but the element of C (x=5) is already part of B (x>=5), so the union does not change anything, the result is simply B again.

4 is doing a "cross section" between the sets A and B. only elements that are in both sets are in the result. but x < 1 and x >= 5 don't have any elements in common. so, the result is an empty set.

5 is again a cross section. the only shared element between B and C is x=5.

Answer:

A. 45%

Step-by-step explanation:

34/75=45 = 45%

Answer:

(1,2) is ordered pair to (-4,2).

Step-by-step explanation:

(1,2)

hora khoi thaha vayena hai

Answer:

[tex]a) \: \: 7x[/tex]

[tex]b) \: \: 12 {x}^{2} - 5x[/tex]

[tex]c) \: \: - 3x + 4[/tex]

Step-by-step explanation:

[tex]a) \: \: 4x+7x−3x−x \\ 11x−3x−x \\ 8x−x \\ 7x[/tex]

[tex]b) \: \: 7 {x}^{2} −6x+5 {x}^{2} +x \\ 12 {x}^{2} −6x+x \\ 12 {x}^{2} - 5x[/tex]

[tex]c) \: \: 9−4x−5+x \\ −4x+4+x \\ −3x+4[/tex]

Answer:

1 hour 33 minutes

Step-by-step explanation:

distance/speed= time

d =800/600

d=1.33

The aeroplane takes 1.33 hours to traverse a distance of 800 km.

Speed is the rate at which an object's position changes, measured in meters per second. For example, if an object starts at the origin, and then moves three meters in three seconds, its speed is one meter per second. The equation for speed is simple: distance divided by time

Given here: An airplane flies a distance of 800 km with an average speed of 600 km/h

Thus the time taken by the aeroplane to cover that distance is

t=800/600

t=4/3

t=1.33 hours

Hence, The aeroplane takes 1.33 hours to traverse a distance of 800 km.

Learn more about the speed of an object here:

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Answer:

C. 30

Step-by-step explanation:

We have a list of names that need to be sorted in a specific order. For this, we will use a permutation. This can be found on a scientific calculator, however, I'll be using the equation.

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

n = total number of objects

r = number of objects selected

In this instance, n will equal 6 since we have 6 different names to choose from and r will equal 2 since we are picking two names. Enter the values into the equation and evaluate.

[tex]_6P_2=\frac{6!}{(6-2)!}=30[/tex]

Therefore, there are 30 possible two-part names.

Answer:

here,

3x-3x=

[tex] {x}^{2} - {x}^{2} [/tex]

x=0

Answer:

Step-by-step explanation:

let the height of the room(h) = x

Length(l) = 3*x = 3x

length = 2 * breadth

breadth(b) = length /2 = 3x/2

Cost of whitewashing the 4  walls = ₹ 7200

Area of 4 walls = 7200 ÷ 50 = 144 m²   ------(I)

Area of walls = 2lh + 2bh

                      = 2*3x*x + 2  *[tex]\frac{3x}{2}[/tex] * x

                       = 6x² + 3x²

                        = 9x²

9x² = 144    {From (I)}

x²  = 144/9

x²  = 16

x = [tex]\sqrt{16}=\sqrt{4*4}[/tex]

x = 4 m

height = 4 m

length = 3*4 = 12m

Breadth = [tex]\frac{3}{2}*4=3*2=6 \ m[/tex]

Area of floor = l*b

                    = 12 * 6

                    = 72 m²

Cost of carpeting the floor = 72 * 325 = ₹ 23400

Answer:

The answer is 7.5

Answer:

The forms are:

Given:

Use point slope form:

Convert it to slope-intercept form:

Convert it to standard form:

-2a(a - d) + 2a(2a - 3d)

(-2a * a) + (-d * -2a) + (2a * 2a) + (2a * -3d)

-2a^2 + 2ad + 4a^2 - 6ad

(4a^2 - 2a^2) + (2ad - 6ad)

2a^2 - 4ad

---The above expression is simplified, though not fully. The below expression is fully simplified.

2a(a - 2d)

Hope this helps!

Answer:

[tex](x-4)^2+(y)^2=9[/tex]

Step-by-step explanation:

The general format for the equation of a circle is the following:

[tex](x-n)^2+(y-m)^2=a[/tex]

This circle will have a radius of ([tex]\sqrt{a}[/tex]), moreover, this circle will have its center at point [tex](n,m)[/tex]. Please note that its center is shifted (n) units to the right of the origin, and (m) units up. Apply this knowledge to the given problem.

The circle in the given problem has its center at (4, 0). Therefore the following can be stated,

[tex]n=4\\\\m =0[/tex]

Since one knows the center of the circle is at (4, 0), and (the circle has (4, 3) on its circumference, the distance between the coordinates will produce the radius of the circle. The following formula can be used to find the distance between two points on a number line,

[tex]D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

Where ([tex](x_1,y_1)[/tex]) and ([tex](x_2,y_2)[/tex]) are the points one is trying to find the distance between. Substitute the given points into the formula and solve for the distance between them.

[tex]D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

[tex]D=\sqrt{(4-4)^2+(3-0)^2}[/tex]

Simplify,

[tex]D=\sqrt{(4-4)^2+(3-0)^2}[/tex]

[tex]D=\sqrt{(0)^2+(3)^2}[/tex]

[tex]D=\sqrt{0+9}[/tex]

[tex]D=\sqrt{9}[/tex]

[tex]D=3[/tex]

The parameter (a) is equal to ([tex]D^2[/tex]) are per the format of the equation, thus one must do the following to find the value of (a):

[tex]a = D^2[/tex]

[tex]a=3^3[/tex]

[tex]a = 9[/tex]

Substitute all of the information into the general formula for the equation of a circle, then simplify,

[tex](x-n)^2+(y-m)^2=a[/tex]

[tex](x-4)^2+(y-0)^2=9[/tex]

[tex](x-4)^2+(y)^2=9[/tex]

Answer:

The answer is 12

Step-by-step explanation:

You see its because.

Answer:

?=12

Step-by-step explanation:

Using the Thalès's theorem:

[tex]\dfrac{6}{6+4}=\dfrac{?}{20} \\\\?*10=6*20\ (cross\ products)\\\\?=\dfrac{6*20}{10} \ dividing\ by\ 10\\\\?=12[/tex]

Answer:

170

Step-by-step explanation:

17/7

Multiply the top and bottom by 10

17*10/ 7*10  =170/70

The fraction with the indicated denominator 70 is [tex]\frac{170}{70}[/tex].

The given fraction is[tex]\frac{17}{7}[/tex].

Convert the fraction with a denominator of 70.

To do this, multiply the numerator and denominator by 10:

[tex]\frac{17}{7} \times \frac{10}{10}[/tex]

[tex]=\frac{17 \times 10}{7 \times 10}[/tex]

[tex]=\frac{170}{70}[/tex]

Hence, the fraction with the indicated denominator 70 is [tex]\frac{170}{70}[/tex].

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Answer:

0.625

Step-by-step explanation:

:) i hope this helps.

Answer:

27, 18

Step-by-step explanation:

Here's why

9514 1404 393

Answer:

  7.56 cm

Step-by-step explanation:

The volume is given by the formula ...

  V = 1/3b²h . . . . where b is the base edge length, and h is the height.

Here we have V = 144 cm³, and b = h. Filling in these values and solving for h, we get ...

  144 cm³ = 1/3h³

  432 cm³ = h³

  h = ∛432 cm ≈ 7.55953 cm

The height of the pyramid is about 7.56 cm.

Answer:

[tex]7.56cm[/tex]

Step-by-step explanation:

Given that,

base length = Height

so,

[tex]volume = \frac{1}{3} {b}^{2} h \\ [/tex]

We can also write this as( according to this question)

[tex]v = \frac{1}{3} \times {b}^{2} \times b \\ v = \frac{ {b}^{3} }{3} [/tex]

let's solve

[tex]v = \frac{ {b}^{3} }{3} \\ 144 = \frac{ {b}^{3} }{3} \\ 144 \times 3 = {b}^{3} \\43 2 = {b}^{3} \\ \sqrt[3]{432} = b \\ b = 7.55[/tex]

[tex]base = height = 7.55cm \\ [/tex]

= 7.56cm