Select the correct answer.
Which chemical can you use to assist with your motor fuel needs?
O A.
ethylene glycol
OB.
ethanol
O c.
butanol
OD.
pentanol
O E.
propranolol
Reset
Next

Answers

Answer 1
The answer is either b or e search it up and you will know the answer by definition
Answer 2

Answer: Ethanol

Explanation:


Related Questions

If most wildfires are suppressed (all fires are put out) for many years, how does the risk of wildfire in the area change in the future?

There will be a higher risk of wildfires
There will be a lower risk of wildfires
There is no difference in risk

Explain your answer.

Answers

Answer:

there is no difference in risk

Explanation:

even though they put out the fires, if they don't get rid of the source from which the wildfires comes from then wildfires wont stop coming

A wedge would be best described as
A wheel and axle used to cTeate a rotary motion
A lever arm fixed to a shaft
A triangle shaped tool that functions as an inclined plane
A rectangular shaped tool that functions as a pulley

Answers

The answer is

C. A triangle shaped tool that functions as an incline ld plane

Answer:

A rectangular shaped tool that functions as a pulley.

Explanation:

i beleive

Five identical keys are suspended from a balance, which is held horizontally as shown. The two keys on the left are attached to the balance 6 cm from the pivot and the three keys on the right are attached 5 cm from the pivot. What will happen when the person lets go of the balance beam?

Answers

Answer:

movement in clockwise direction.

Explanation:

The following parameters or information are given from the question above, they are:

[1]. There are two identical keys, [2]. two out of the five keys are attached to 6cm from the pivot, [3]. three keys out of the five keys on the right are attached 5 cm.

Therefore, considering the moment of force, the two keys on the left = 2 × 6 = 12.

Also, considering the moment of force, the 3 keys on the right = 3 × 5 = 15.

Therefore, we have more weight on the right keys. So, in order to balance the force there must be movement in clockwise direction.

a cantilever beam 1.5m long has a square box cross section with the outer width and height being 100mm and a wall thickness of 8mm. the beam carries a uniform load of 6.5kN/m along the entire length and, in the same direction, a concentrated force of 4kN at the free end. (a) determine the max bending stress (b) determine the max transervse shear stress (c) determine the max shear stress in the beam

Answers

Answer:

a) 159.07 MPa

b) 10.45 MPa

c) 79.535 MPa

Explanation:

Given data :

length of cantilever beam = 1.5m

outer width and height = 100 mm

wall thickness = 8mm

uniform load carried by beam  along entire length= 6.5 kN/m

concentrated force at free end = 4kN

first we  determine these values :

Mmax = ( 6.5 *(1.5) * (1.5/2) + 4 * 1.5 ) = 13312.5 N.m

Vmax = ( 6.5 * (1.5) + 4 ) = 13750 N

A) determine max bending stress

б = [tex]\frac{MC}{I}[/tex]  =  [tex]\frac{13312.5 ( 0.112)}{1/12(0.1^4-0.084^4)}[/tex]  =  159.07 MPa

B) Determine max transverse shear stress

attached below

   ζ = 10.45 MPa

C) Determine max shear stress in the beam

This occurs at the top of the beam or at the centroidal axis

hence max stress in the beam =  159.07 / 2 = 79.535 MPa  

attached below is the remaining solution

Determine the size of memory needed for CD recording of a piece of music, which lasts for 26 minutes, is done with a 20-bit Analog-to-Digital Converter (ADC) in stereo (2 channels), at the rate of 44.1 kSa/s, with the compression factor 6 (allow 10% error margin).

Answers

Answer: the size of memory needed for the CD recording is 28.7 MB

Explanation:

so in the case of stereo, the bitrate is;

⇒ 26 × 60 × 44.1 × 10³ × 2

=   137592 × 10³  

for 10 bit

⇒ 137592 × 10³ × 10

= 1375920 × 10³ bits

now divide by 8 (convert to bytes)

⇒ (1375920 × 10³) / 8

= 171,990,000 BYTE

divide by 1000 (convert to kilobytes)

= 171,990,000 / 1000

= 171,990 KILOBYTES

now Given that, the compression ratio is 6      

so  

171,990 / 6

= 28665 KB

we know that. 1 MB = 1000 KB

x MB = 28665 KB

x MB = 28665 / 1000

⇒ 28.665 MB ≈ 28.7 MB

Therefore the size of memory needed for the CD recording is 28.7 MB

4.
error occurs when the measurement we think we see is not the
measurement being indicated by the instrument.
A. Positioning
B. Operator bias
C. Instrument
D. Observational

Answers

Answer: observational error

Explanation:

An Error occurs when the measurement is actually done by the Observational approach. Thus, the correct option is D.

What is an ideal method of measurement?

The ideal methods of measurement are subdivided into two methods: They are as follows:

Direct measurement method.Indirect measurement method.

The Direct measurement method involves the utilization of instruments such as micrometers, vernier calipers, coordinate measuring machines, etc. In this method, the unknown quantity is directly compared with the standard quantity.

In the Indirect measurement method, the physical parameter of the quantity is measured with the help of the direct method.

Positioning of the required quantity, operator-biased measurement, and the utilization of instruments for estimating the measurement of any unknown value are generally favored in order to eliminate the chances of errors.

Therefore, an Error occurs when the measurement is actually done by the Observational approach. Thus, the correct option is D.

To learn more about Errors in Measurement, refer to the link:

https://brainly.com/question/475573

#SPJ2

A plate and frame heat exchanger has 15 plates made of stainless steel that are 1 m tall. The plates are 1 mm thick and 0.6 m wide and are spaced 4.8 mm apart. The exchanger is used to cool water. The volume flow rate of this water is 0.011 m3/s, and its inlet temperature is 30 C. Raw water is the cooling medium. It enters the exchanger at 6 C with a volume flow rate of 0.02 m3/s. Calculate the outlet temperatures.

Answers

Answer:

14.506°C

Explanation:

Given data :

flow rate of water been cooled = 0.011 m^3/s

inlet temp = 30°C + 273 = 303 k

cooling medium temperature = 6°C  + 273 = 279 k

flow rate of cooling medium = 0.02 m^3/s

Determine the outlet temperature

we can determine the outlet temperature by applying the relation below

Heat gained by cooling medium = Heat lost by water

= ( Mcp ( To - 6 )  =  Mcp ( 30 - To )

since the properties of water and the cooling medium ( water ) is the same

= 0.02 ( To - 6 ) = 0.011 ( 30 - To )

= 1.82 ( To - 6 ) = 30 - To

hence To ( outlet temperature ) = 14.506°C

The purpose of pasteurizing milk is to A. Kill pathogens B. Break down milk fat C. Add vitamins and minerals D. Prevent spoilage by sunlight

Answers

Answer:

The answer is A

Explanation:

The correct answer is A

4. The process of heating milk to kill microorganisms that cause spoilage and disease without affecting its nutritional value is called
A. Homogenization
B. Pasteurization
C. Boiling
D. Poaching

Answers

Answer:

I think the answer is C. Boiling but I'm not 100% sure.

​Write 83,120 in expanded form using powers of 10.

Answers

Answer:

8*10000+3*1000+1*00+2*10+2

Explanation:

An astronomer of 65 kg of mass hikes from the beach to the observatory atop the mountain in Mauna Kea, Hawaii (altitude of 4205 m). By how much (in newtons) does her weight change when she goes from sea level to the observatory?

Answers

Answer:

[tex]0.845\ \text{N}[/tex]

Explanation:

g = Acceleration due to gravity at sea level = [tex]9.81\ \text{m/s}^2[/tex]

R = Radius of Earth = 6371000 m

h = Altitude of observatory = 4205 m

Change in acceleration due to gravity due to change in altitude is given by

[tex]g_h=g(1+\dfrac{h}{R})^{-2}\\\Rightarrow g_h=9.81\times(1+\dfrac{4205}{6371000})^{-2}\\\Rightarrow g_h=9.797\ \text{m/s}^2[/tex]

Weight at sea level

[tex]W=mg\\\Rightarrow W=65\times 9.81\\\Rightarrow W=637.65\ \text{N}[/tex]

Weight at the given height

[tex]W_h=mg_h\\\Rightarrow W_h=65\times 9.797\\\Rightarrow W_h=636.805\ \text{N}[/tex]

Change in weight [tex]W_h-W=636.805-637.65=-0.845\ \text{N}[/tex]

Her weight reduces by [tex]0.845\ \text{N}[/tex].

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