Expressions that are equivalent to 3 to the fourth power are 81, 3³, and 9².
To calculate 3 to the fourth power, you need to multiply 3 by itself four times. That is, 3 x 3 x 3 x 3. The result is 81, which is one of the equivalent expressions. Another equivalent expression is 3³. This is because 3³ is equal to 3 to the third power, which is equal to 3 x 3 x 3 = 27. Multiplying 27 by 3 gives 81. Finally, 9² is also an equivalent expression because 9² is equal to 81. Therefore, the three equivalent expressions of 3 to the fourth power are 81, 3³, and 9².
Expressions that are equivalent to 3 to the fourth power are 81, 3³, and 9².To calculate 3 to the fourth power, you need to multiply 3 by itself four times. That is, 3 x 3 x 3 x 3. The result is 81, which is one of the equivalent expressions.Another equivalent expression is 3³. This is because 3³ is equal to 3 to the third power, which is equal to 3 x 3 x 3 = 27. Multiplying 27 by 3 gives 81. Finally, 9² is also an equivalent expression because 9² is equal to 81.Therefore, the three equivalent expressions of 3 to the fourth power are 81, 3³, and 9².
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a number z is few then 3/4 answer
Answer:
[tex]\sf z - \dfrac{3}{4}[/tex]
Step-by-step explanation:
Algebraic expression:Subtract 3/4 from z.
[tex]\sf z - \dfrac{3}{4}[/tex]
for all values of x, f(x)=2x-3 and g(x)=x^2+1 find fg(x)
fg(x) is 2x³ - 3x² + 2x - 3.To find fg(x), we need to multiply f(x) and g(x).
The given functions are f(x) = 2x - 3 and g(x) = x² + 1.
We know that (f · g)(x) = f(x) · g(x).
So, (f · g)(x) = (2x - 3)(x² + 1)
(f · g)(x) = 2x³ - 3x² + 2x - 3.
Hence, the value of fg(x) is 2x³ - 3x² + 2x - 3
Given f(x) = 2x - 3 and g(x) = x² + 1
We have to find fg(x) = f(x)g(x)
= (2x - 3)(x² + 1)
We will use the distributive law of multiplication to multiply the given two functions.
(2x - 3)(x² + 1)= 2x(x² + 1) - 3(x² + 1)
Expanding further, we get the following:
2x³ + 2x - 3x² - 3=2x³ - 3x² + 2x - 3
Therefore,
fg(x) = 2x³ - 3x² + 2x - 3.
So, we get the value of fg(x) as 2x³ - 3x² + 2x - 3.
We have found that fg(x) is 2x³ - 3x² + 2x - 3 by multiplying f(x) = 2x - 3 and g(x) = x² + 1.
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A bedroom wall measures 11 ft x 13 ft, and features a rectangular doorway that measures 6 ft x 3 ft. How many square of paint will be needed to cover the wall only?
The wall area that needs to be painted, excluding the doorway, is 125 square feet.
The total area of the wall is obtained by multiplying its length and width:
Total area = 11 ft * 13 ft = 143 square feet.
The area of the doorway is given by multiplying its length and width:
Doorway area = 6 ft * 3 ft = 18 square feet.
To find the area of the wall that needs to be painted, we subtract the area of the doorway from the total area:
Painting area = Total area - Doorway area = 143 square feet - 18 square feet = 125 square feet.
Therefore, you will need 125 square feet of paint to cover the wall only.
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An airplane moves velocity of (200 km/Hr) for (45 min) then changes its velocity to (240 km/Hr) for (35 min) calculate the average velocity of the airplane during its journey
The average velocity of an airplane during its journey when it moves at a velocity of 200 km/hour for 45 minutes and changes its velocity to 240 km/hour for 35 minutes can be calculated as follows:The first step is to convert the time from minutes to hours.
We can do this by dividing the number of minutes by 60 (since there are 60 minutes in an hour).So, time taken to move at a velocity of 200 km/hr for 45 minutes = 45/60 = 0.75 hoursTime taken to move at a velocity of 240 km/hr for 35 minutes = 35/60 = 0.583 hoursNow we can find the total distance traveled by the airplane. We can do this by multiplying the velocity of the airplane with the time it traveled at that velocity.Distance traveled at 200 km/hr = 200 x 0.75 = 150 kmDistance traveled at 240 km/hr = 240 x 0.583 = 139.92 kmTotal distance traveled by the airplane = 150 + 139.92 = 289.92 km.
The average velocity of the airplane during its journey can now be found by dividing the total distance traveled by the total time taken to travel that distance. Total time taken = 0.75 + 0.583 = 1.333 hours Average velocity of the airplane = Total distance traveled.
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Let x = a bi and y = c di and z = f gi. Which statements are true? Check all of the boxes that apply. X y = y x (x × y) × z = x × (y × z) x – y = y – x (x y) z = x (y z) (x – y) – z = x – (y – z).
The true statements are: - (x × y) × z = x × (y × z) and - (x – y) – z = x – (y – z)
Let's evaluate each statement:
1. X y = y x:
This statement is generally not true for complex numbers. Multiplication of complex numbers is not commutative, so in most cases, X y is not equal to y x.
2. (x × y) × z = x × (y × z):
This statement is true. The associative property holds for multiplication of complex numbers. The order of multiplication does not affect the final result.
3. x – y = y – x:
This statement is generally not true for complex numbers. Subtraction of complex numbers is not commutative, so in most cases, x - y is not equal to y - x.
4. (x y) z = x (y z):
This statement is true. The associative property holds for multiplication of complex numbers. The order of multiplication does not affect the final result.
5. (x – y) – z = x – (y – z):
This statement is true. The associative property holds for subtraction of complex numbers. The order of subtraction does not affect the final result.
To summarize, the true statements are:
- (x × y) × z = x × (y × z)
- (x – y) – z = x – (y – z)
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In general, as the unit price of a commodity increases, the demand for that commodity decreases. Also, as a commodity's unit price increases, the manufacturer normally increases the supply. The point where supply is equal to demand is called the equilibrium point. Find the number of DVDs and the price per DVD when supply equals demand.
Therefore, at the equilibrium point, the number of DVDs will be 510.71 and the price per DVD will be $18.85 (rounded to the nearest cent).
The equilibrium point is the point at which supply and demand are equal. At this point, the price and quantity demanded will be stable. When a commodity's unit price increases, demand decreases, while the manufacturer usually increases the supply. The point at which supply and demand are equal is known as the equilibrium point. The quantity demanded and the price per DVD can be calculated when supply equals demand.
When supply is equal to demand, we can equate both equations as:
S = Dwhere S is supply and D is demand.
S = -0.05P + 600 ... equation 1
D = 0.3P - 60 ... equation 2
We will now solve the above equations for P, which is the price per DVD.
S = D-0.05P + 600 = 0.3
P - 60-0.05P - 0.3
P = -60 - 600-0.35
P = -660
P = 660/0.35
= 1885.71 cents
= 18.85 dollars (rounded to the nearest cent)
Now that we know the price per DVD, we can calculate the quantity demanded by inserting P into one of the above equations. Using equation 1:
S = -0.05(1885.71) + 600S
= 510.71
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A population of 1000 alligators has a birthrate of 400 per year. Each year, 150 alligators die, and 150 leave the population to look for new territory, but 30 alligators arrive from other territories to join the population. What is the annual population growth rate per thousand animals
The annual population growth rate per thousand animals in this scenario is 130.
In the given population of 1000 alligators, the birthrate is 400 per year. This means that 400 new alligators are born each year. However, there are also factors that decrease the population. Each year, 150 alligators die and 150 leave the population to search for new territory. On the other hand, 30 alligators arrive from other territories to join the population.
To calculate the annual population growth rate per thousand animals, we can subtract the total number of deaths and departures (150 + 150) from the total number of births and arrivals (400 + 30). This gives us a net increase of 130 alligators.
To calculate the growth rate per thousand animals, we divide the net increase (130) by the initial population size (1000) and multiply the result by 1000. This gives us a growth rate of 130/1000 * 1000 = 130.
Therefore, the annual population growth rate per thousand animals in this scenario is 130.
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Is regular n-gon PQRST. , PR is drawn, and measure of angle QPR=QRP=20. What is the name of the polygon
The polygon described in this scenario is a regular pentagon. In the given diagram, the vertices of the pentagon are labeled as P, Q, R, S, and T. The line segment PR is drawn within the pentagon, and it is mentioned that the angle QPR and QRP both measure 20 degrees.
A line segment PR is drawn within the polygon, and the measure of both angles QPR and QRP is 20 degrees. Based on this information, we can determine that the polygon in question is a regular pentagon.
A regular polygon is defined as a polygon where all sides have the same length and all angles have the same measure. In the case of a regular pentagon, it specifically has five sides and five angles. The given information confirms that the angles QPR and QRP both measure 20 degrees, satisfying the criteria for a regular polygon.
By identifying the polygon as a regular pentagon, we can understand its fundamental properties, such as equal side lengths and equal angles. The name "regular" emphasizes the uniformity of the polygon's sides and angles, while "pentagon" specifies that it consists of five sides.
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find (f ∘ g)(x) when f(x) = x^2 +5x +4 and g(x) = 1/x+4
The required answer is [tex][4x² + 36x + 85]/(x + 4)².[/tex]
Given [tex]f(x) = x² + 5x + 4[/tex]and g(x) = 1/(x + 4).
We are to find (f ∘ g)(x)
Formula used:
The composition of two functions f(x) and g(x) is given by (f ∘ g)(x) = f(g(x))
To solve the above problem, we substitute g(x) in place of x in f(x).
Hence,[tex](f ∘ g)(x) = f(g(x)) = f(1/(x + 4))f(g(x)) = g(x)² + 5g(x) + 4[/tex]
Putting the value of g(x) we get,
[tex]f(g(x)) = g(x)² + 5g(x) + 4= [1/(x + 4)]² + 5[1/(x + 4)] + 4= [1/(x + 4)][1/(x + 4)] + 5/(x + 4) + 4= (1/(x + 4))(1/(x + 4) + 5/(x + 4) + 4)= [1 + 5(x + 4) + 4(x + 4)²]/(x + 4)²= [4x² + 36x + 85]/(x + 4)²[/tex]
Therefore, [tex](f ∘ g)(x) = [4x² + 36x + 85]/(x + 4)².[/tex]
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which statement is true about this comparison
0.739 > 0.7380
The statement that is true about this comparison is that they differ in the thousandths place, with 0.739 being greater than 0.7380.
The statement that is true about the comparison
0.739 > 0.7380
is that they differ in the thousandths place. The difference between the two numbers is
0.001 or 1/1000,
which is why we can say that they differ in the thousandths place. This difference is very small, but it is enough to make
0.739 greater than 0.7380.
The comparison between
0.739 and 0.7380
is true in that the former is greater than the latter by a small margin. The two numbers differ in the thousandths place, with 0.739 having a value of
0.739 and 0.7380
having a value of 0.738.
The difference between the two values is
0.001 or 1/1000,
which is very small.
However, this difference is enough to make 0.739 greater than 0.7380.
Therefore, the statement that is true about this comparison is that they differ in the thousandths place, with
0.739 being greater than 0.7380.
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Plane 1 travels 450 miles south in 2 hours with a very strong tailwind. Plane 2 travels 525 miles north in 3 hours, this time against the same wind speed, with an air speed 3 times faster than plane 1.
- Plane 1 travels at a speed of 225 mph.
- Plane 2 has an airspeed of 3 times faster than Plane 1, which is 3 * 225 mph = 675 mph.
- The wind speed is 500 mph.
Let's analyze the information provided:
Plane 1:
- Distance traveled: 450 miles
- Direction: South
- Time taken: 2 hours
Plane 2:
- Distance traveled: 525 miles
- Direction: North
- Time taken: 3 hours
- Airspeed: 3 times faster than Plane 1
We can calculate the speed of Plane 1 and the wind speed by dividing the distance traveled by the time taken.
Plane 1's speed = Distance / Time = 450 miles / 2 hours = 225 miles per hour (mph)
Let's assume the speed of the wind is W mph.
For Plane 2, since it is traveling against the wind, we need to consider the effect of the wind on its speed. The effective speed of Plane 2 against the wind can be calculated as the airspeed of Plane 2 minus the wind speed.
Effective speed of Plane 2 = Airspeed of Plane 2 - Wind speed = 3 * Plane 1's speed - W
Now we can use the formula: Speed = Distance / Time to calculate the wind speed.
For Plane 2:
Effective speed of Plane 2 = Distance / Time = 525 miles / 3 hours = 175 mph
175 mph = 3 * 225 mph - W
W = 3 * 225 mph - 175 mph
W = 675 mph - 175 mph
W = 500 mph
The wind speed is calculated to be 500 mph.
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what is the mean for 5,5,5,4,4,2,2what is the mean for 7, 5, 1, 2, 8, 3, 3what is the mean for 8, 4, 2, 8, 7what is the mean for 3, 3, 7, 6, 3, 3, 3, 5, 4
The mean for the first set of numbers is 4. The mean for the second set of numbers is 4. The mean for the third set of numbers is 5. The mean for the fourth set of numbers is 4.11.
To calculate the mean, we sum up all the numbers in the set and divide the sum by the total count of numbers.
For the first set of numbers (5, 5, 5, 4, 4, 2, 2), the sum is 27. There are 7 numbers in the set, so the mean is 27/7 = 4.
For the second set of numbers (7, 5, 1, 2, 8, 3, 3), the sum is 29. There are 7 numbers in the set, so the mean is 29/7 = 4.
For the third set of numbers (8, 4, 2, 8, 7), the sum is 29. There are 5 numbers in the set, so the mean is 29/5 = 5.
For the fourth set of numbers (3, 3, 7, 6, 3, 3, 3, 5, 4), the sum is 37. There are 9 numbers in the set, so the mean is 37/9 = 4.11 (rounded to two decimal places).
Therefore, the mean for the respective sets of numbers are 4, 4, 5, and 4.11.
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The price of a nine minute phone call is $3. 15 what is the price of a 12 minute phone call
The cost of a 12-minute phone call is $4.20.
The cost of a nine-minute phone call is $3.15. To find the cost of a 12-minute phone call, we must first determine the cost per minute. We can do this by dividing the cost of a nine-minute call by 9 minutes, which gives us the cost per minute.
3.15 ÷ 9 = $0.35 (cost per minute) Now that we know the cost per minute, we can find the cost of a 12-minute phone call by multiplying the cost per minute by the number of minutes. 12 × $0.35 = $4.20 Therefore, the price of a 12-minute phone call is $4.20.
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Sharon made a scale drawing of a triangular park. Her scale are 1 unit =1 meter. What is the area of the triangular park in square meters
The area of the triangular park in square meters is given by (b * h) / 2, where "b" represents the base in meters and "h" represents the height in meters.
To find the area of the triangular park in square meters, we need the measurements of the triangular park in the scale drawing. Since the scale is 1 unit = 1 meter, the measurements in the scale drawing represent the actual measurements in meters.
To determine the area of the triangular park in square meters, we need the base and height of the triangle in meters.
Let's assume that in the scale drawing, the base of the triangular park is represented by a certain number of units, and the height is represented by another number of units.
If we denote the base of the triangular park as "b" units and the height as "h" units in the scale drawing, then the actual measurements in meters would also be "b" meters for the base and "h" meters for the height.
The formula for the area of a triangle is:
Area = (1/2) * base * height
Substituting the actual measurements in meters, we have:
Area = (1/2) * b meters * h meters
Area = (1/2) * b * h square meters
Area = (b * h) / 2 square meters
Therefore, the area of the triangular park in square meters is given by (b * h) / 2, where "b" represents the base in meters and "h" represents the height in meters.
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What x-values are solutions of x3 + 5x2 − x − 7 = x2 + 6x + 3? Simplify the polynomial and find the zeros to find the intersection points. Enter your answers in increasing order.
To find the x-values that are solutions of the equation
[tex]x^3 + 5x^2 - x - 7 - (x^2 + 6x + 3)[/tex], we first need to simplify the equation and find the zeros.
By subtracting x^2 + 6x + 3 from both sides of the equation, we get:
[tex]x^3 + 5x^2 - x - 7 - (x^2 + 6x + 3) = 0[/tex]
[tex]x^3 + 5x^2 - x - 7 - x^2 - 6x - 3 = 0\\x^3 + 4x^2 - 7x - 10 = 0[/tex]
Now, to find the zeros of this polynomial, we set it equal to zero and factor it if possible:
[tex]x^3 + 4x^2 - 7x - 10 = 0[/tex]
By trying different values, we can find that x = -2 is a zero of the polynomial. Therefore, (x + 2) is a factor of the polynomial.
Using synthetic division or long division, we can divide the polynomial [tex]x^3 + 4x^2 - 7x - 10 = 0[/tex] by (x + 2):
[tex]| (x^3 + 4x^2 - 7x - 10) ÷ (x + 2) |= x^2 + 2x - 5[/tex]
Now, we can factor the quadratic equation x^2 + 2x - 5:
(x + 2)(x - 1) = 0
Setting each factor equal to zero and solving for x, we get:
x + 2 = 0 --> x = -2
x - 1 = 0 --> x = 1
Therefore, the x-values that are solutions to the equation x^3 + 5x^2 - x - 7 = x^2 + 6x + 3 are x = -2 and x = 1. The intersection points of the two polynomials occur at these x-values.
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a:b = 1:5
a:c = 2:1
how many times is b bigger than c
b is 10 times bigger than c. the ratio A:b is equivalent to the ratio a:c multiplied by 5: A:b = (a:c) * 5
To determine how many times b is bigger than c, we need to compare their respective ratios.
Given:
A:b = 1:5
a:c = 2:1
To make a comparison, we can find the relative sizes of b and c by considering the ratios they have with other variables.
From the ratio A:b = 1:5, we can rewrite it as A:b = 2:10 (multiplying both sides by 2).
Comparing the ratios A:b and a:c, we can see that the ratio A:b is equivalent to the ratio a:c multiplied by 5:
A:b = (a:c) * 5
Substituting the given ratios, we have:
2:10 = (2:1) * 5
Now, we can compare the values of b and c directly:
b = 10
c = 1
Therefore, b is 10 times bigger than c.
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For the standard normal probability distribution, the area under the probability density function to the left of the mean is:.
The area under the probability density function to the left of the mean for the standard normal distribution is 0.5.
The standard normal distribution, also known as the Z-distribution, is a bell-shaped distribution with a mean of zero and a standard deviation of one. The area under the curve of a probability density function represents the probability of an event occurring. Since the mean of the standard normal distribution is at the center of the distribution, the area to the left of the mean is symmetrically equal to the area to the right of the mean. Therefore, the area under the probability density function to the left of the mean is 0.5 or 50%. This means that there is a 50% probability of observing a value less than the mean in a standard normal distribution.
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What is the slope of a line perpendicular to the line whose equation is
4x — 6y = –24. Fully simplify your answer.
The slope of a line perpendicular to the line given by the equation 4x - 6y = -24 is -3/2.
To find the slope of a line perpendicular to the line given by the equation 4x - 6y = -24, we first need to put this equation in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
Rearranging the given equation, we get:
4x - 6y = -24
-6y = -4x - 24
y = (2/3)x + 4
So the slope of the original line is m = 2/3.
For a line that is perpendicular to this line, the slope will be the negative reciprocal of the original slope. That is, if the original slope is m, then the slope of the perpendicular line will be -1/m.
So for the line given by the equation 4x - 6y = -24, the slope of a line perpendicular to it is:
-1/m = -1/(2/3) = -3/2
Therefore, the slope of a line perpendicular to the line given by the equation 4x - 6y = -24 is -3/2.
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For the past `12` school days, Mai has recorded how long her bus rides to school take in minutes. The times she recorded are shown below. `9`, `12`, `6`, `9`, `10`, `7`, `6`, `12`, `9`, `8`, `10`, `10` Find the mean for Mai's data.
The mean for Mai's data is 8.9167.
To find the mean of the data given by Mai for the past 12 school days, we need to add all the values together and then divide by the total number of values.
Here is the solution: Given data are: 9, 12, 6, 9, 10, 7, 6, 12, 9, 8, 10, 10
To find: The mean for Mai's data
To calculate the mean, we will add up all the values and then divide by the total number of values.
Mean (average) = sum of values / total number of values
Sum of values = 9 + 12 + 6 + 9 + 10 + 7 + 6 + 12 + 9 + 8 + 10 + 10= 107
Total number of values = 12
Therefore, Mean (average) = sum of values / total number of values
= 107 / 12
= 8.9167 (rounded to four decimal places)
Hence, the mean for Mai's data is 8.9167.
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A 3-gallon bottle of bleach costs $15.60. What is the price per quart?
We know that the bottle contains 3 gallons of bleach. More than 250 quarts can be produced from 3 gallons. Let's find out how many quarts there are in a gallon.1 US gallon is equivalent to 4 US quarts.
So 3 gallons equal 12 quarts. Hence, More than 250 quarts can be obtained from 3 gallons, since more than 250 is greater than 12.Therefore, we can find the price per quart by dividing the total cost by the total number of quarts: Price per quart = Total cost ÷ Total number of quarts Since the cost of a 3-gallon bottle of bleach is $15.60, the cost of 1 gallon would be $15.60 ÷ 3 = $5.20.The cost of one quart is $5.20 ÷ 4 = $1.30.Therefore, the price per quart is $1.30.
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Directions: Find the missing side lengths. Leave your answers as radicals in simplest form.
There's no specific diagram or context mentioned in your question. Thus, I'm giving a general answer to the question. Please provide more information for a specific answer.
The Pythagorean theorem is a fundamental geometric principle that relates the lengths of the sides of a right triangle. It states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
So, the given question asks us to find the missing side lengths.
Since we don't have any further information on the given question, let's assume that the given triangle is a right triangle. Let the two given sides of a right triangle be a and b, and the missing side be c.
According to the Pythagorean theorem,
[tex]`a^2 + b^2 = c^2`[/tex]
Thus, [tex]`c = \sqrt(a^2 + b^2)`[/tex]
Here, `sqrt()` is used to represent the square root function. Therefore, we have to take the square root of `a² + b²` to find the length of the missing side.
Answer: [tex]`c = \sqrt(a^2 + b^2)`[/tex]
Leave your answers as radicals in the simplest form.
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Consider the function
h(x) = 1/2x– 3 with a restricted domain of {-2,0, 2, 10}.
What is the range of the function?
The range of the function is {-7, -3/2, -2, 2}.Hence, the correct option is the last option.
The range of the function is a set of all possible values of a function. It is the set of all output values of a function. In the given function, h(x) = 1/2x– 3 with a restricted domain of {-2,0, 2, 10}.Here is the solution;
As per the question, the given function is (x) = 1/2x– 3 with a restricted domain of {-2,0, 2, 10}.Now, let us find the range of the function; Let's find the value of the function at each of the domain points. x h(x)-2 h(-2) = -4-3 = -7 0 h(0) = -3/2 2 h(2) = -2 10 h(10) = 2
Therefore, the range of the function is {-7, -3/2, -2, 2}.Hence, the correct option is the last option.
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James, Gilbert, Matthew, and Simon ran in a relay race. Their times are
listed in the chart below.
James
2/3
Gilbert
11/12
Matthew
5/6
Simon
7/12
1. Find the difference between the fastest boy’s time and the slowest
boy’s time
The difference between the fastest boy's time and the slowest boy's time can be found by comparing their respective times and calculating the difference.
To determine the fastest and slowest times among James, Gilbert, Matthew, and Simon, we examine their recorded times: 2/3, 11/12, 5/6, and 7/12.
To compare these fractions, we need to find a common denominator. In this case, the least common multiple of the denominators 3, 12, 6, and 12 is 12.
Converting the fractions to have a denominator of 12, we get:
James: 2/3 = 8/12
Gilbert: 11/12 (already in terms of 12)
Matthew: 5/6 = 10/12
Simon: 7/12 (already in terms of 12)
Now, we can clearly see that the fastest time is 8/12 (James) and the slowest time is 11/12 (Gilbert).
To find the difference between these two times, we subtract the slowest time from the fastest time:
8/12 - 11/12 = -3/12 = -1/4
Therefore, the difference between the fastest boy's time and the slowest boy's time is -1/4, or in other words, the fastest boy is 1/4 of a unit of time faster than the slowest boy.
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Find the measure of each angle to the nearest tenth of a degree.
tan X=0. 2962
Now we know that;tan x = Opposite/Adjacent side of the angle x tan x = Opposite/Adjacent sideTherefore, the Opposite side = tan x * Adjacent sideHere, we have only the value of tan x.
Thus, we need the value of any one side to find the other side value. But, we don't have the value of any of the sides. So, we will take an arbitrary value of one of the sides, suppose 1.We know that tan x = Opposite/Adjacent sideNow, we have Adjacent side = 1Therefore, tan x = Opposite/1Opposite side = tan xNow, Opposite side = 0.2962 (from the given equation)
Therefore, the measure of the angle can be found using the tangent ratio formula.tan x = Opposite/Adjacenttan x = 0.2962/1tan x = 16.92°Thus, the measure of the angle x to the nearest tenth of a degree is 16.9°.Therefore, the answer is, the measure of angle x is 16.9° to the nearest tenth of a degree.
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what is the circumference of a cylinder with the diameter of 6cm and height of 12cm
The diameter of a cylinder is given as 6 cm and the height as 12 cm. We can use the formula of the circumference of a cylinder to calculate the circumference. We know that the circumference of a circle is πd, where d is the diameter of the circle.
Now, the circumference of a cylinder is nothing but the perimeter of its circular base. Therefore, the circumference of a cylinder is 2πr where r is the radius of the circular base. In this question, the diameter is given as 6 cm, which means the radius will be half of it. Hence the radius of the circular base will be 6/2 = 3 cm. The height of the cylinder is given as 12 cm, which means the circumference will be the perimeter of the circular base times the height of the cylinder. The circumference will be:2πr = 2π(3) = 6π cm. The circumference of a cylinder with the diameter of 6 cm and height of 12 cm is 6π cm.
The circumference of a cylinder with the diameter of 6 cm and height of 12 cm is 6π cm. The diameter of a cylinder is given as 6 cm and the height as 12 cm. We can use the formula of the circumference of a cylinder to calculate the circumference. We know that the circumference of a circle is πd, where d is the diameter of the circle. Now, the circumference of a cylinder is nothing but the perimeter of its circular base. Therefore, the circumference of a cylinder is 2πr where r is the radius of the circular base. In this question, the diameter is given as 6 cm, which means the radius will be half of it. Hence the radius of the circular base will be 6/2 = 3 cm. The height of the cylinder is given as 12 cm, which means the circumference will be the perimeter of the circular base times the height of the cylinder. The circumference will be:2πr = 2π(3) = 6π cm. The circumference of a cylinder with the diameter of 6 cm and height of 12 cm is 6π cm, where π is pi and is equal to approximately 3.14.
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Is the following event Independent or Dependent:Yolanda grabs 2 red checkers, replacing between.
The correct answer is that the event you described is dependent.
When Yolanda grabs 2 red checkers and replaces them between each draw, the outcome of the first draw affects the probability of the second draw. This is because replacing the checkers means that the probability of drawing a red checker remains the same for each individual draw, but the overall probability changes after each draw.
Let's break it down:
In the first draw, Yolanda has a certain probability of drawing a red checker.
After the first draw, if Yolanda indeed drew a red checker, there is one less red checker in the pool and the total number of checkers has decreased.
In the second draw, Yolanda now has a different probability of drawing a red checker compared to the first draw because the pool of available checkers has changed.
Therefore, the outcome of the first draw affects the probability of the second draw, making the event dependent.
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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 14 fect and a height of 13 fect. Container B has a diameter of 12 feet and a height of 18 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. After the pumping is complete. what is the volume of the empty portion of Container B, to the nearest tenth of a cubic foot?
The volume of the empty portion of Container B is given as follows:
34.6 ft³.
How to obtain the volume of the cylinder?The volume of a cylinder of radius r and height h is given by the equation presented as follows:
V = πr²h.
(the radius is half the diameter).
Hence the volume of Container A is given as follows:
V = π x 7² x 13
V = 2001.2 ft³.
The volume of container B is given as follows:
V = π x 6² x 18
V = 2035.8 ft³.
Then the volume of the empty portion of Container B is given as follows:
2035.8 - 2001.2 = 34.6 ft³.
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The perimeter of a rectangle is 22cm and the length of each side is a natural number. How many different areas in centimeter squared can the rectangle have?
option B is the correct answer.
The perimeter of a rectangle is 22 cmLet the length of the rectangle be 'l' and the breadth be 'b'As per the question, the perimeter of the rectangle is given by;Perimeter = 2(l + b) => 2(l + b) = 22 => l + b = 11.As we know that the area of a rectangle is given by;Area = l × b
Therefore, the different areas of the rectangle are; l × b1 × (11 - 1) = 10 cm²2 × (11 - 2) = 18 cm²3 × (11 - 3) = 24 cm²4 × (11 - 4) = 28 cm²5 × (11 - 5) = 30 cm²6 × (11 - 6) = 30 cm²7 × (11 - 7) = 28 cm²8 × (11 - 8) = 24 cm²9 × (11 - 9) = 18 cm²10 × (11 - 10) = 10 cm²Hence, there are only 8 different areas of the rectangle i.e., 10 cm², 18 cm², 24 cm², 28 cm², 30 cm².
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Alexa is designing a paper airplane whose final shape, when viewed from the top or bottom, is a trapezoid. A sketch of her plane, viewed from the top, is shown on the left.
A trapezoid has a base of 6 centimeters, a height of 3 centimeters, and a top side length of 2 centimeters
The dimensions of one of the identical triangular pieces of the paper airplane are A. 2 cm base, 3 cm height
How to find the dimensions ?From the given information, the paper airplane is designed in the shape of a trapezoid when viewed from the top. The trapezoid has a base of 6 centimeters, a height of 3 centimeters, and a top side length of 2 centimeters.
When we divide the trapezoid along the height, we get two congruent triangles. These triangles have the same shape and size, making them identical. The height of the triangle corresponds to the same height as the trapezoid, which is 3 centimeters.
Therefore, the dimensions of one of the identical triangular pieces of the paper airplane are a base of 2 centimeters and a height of 3 centimeters.
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Full question is:
Alexa is designing a paper airplane whose final shape, when viewed from the top or bottom, is a trapezoid. A sketch of her plane, viewed from the top, is shown on the left.
What are the dimensions of one of the identical triangular pieces of the plane?
2 cm base, 3 cm height
3 cm base, 3 cm height
3 cm base, 4 cm height
3 cm base, 6 cm height
Edgar cannot sleep because he is terribly worried about his research paper. So edgar decides to get out of bed and continue working on the paper. Although he stays up to nearly 3 a. M. , he is relieved that it is done and easily falls off to sleep. In the future, edgar will be more likely to finish his work before going to bed so that he can avoid the worry and sleeplessness. Such behavior is an example of.
To sum up, Edgar's behavior is an example of positive reinforcement as he has learned to associate finishing his work before going to bed with positive consequences.
Edgar's behavior is an example of a learning process known as operant conditioning. Operant conditioning is the concept that we learn to associate our behavior with its consequences, either positive or negative. We are motivated by rewards, such as praise, and punishments, such as criticism, that we experience as a result of our behavior.
In Edgar's case, his relief and ability to fall asleep after completing his research paper can be considered a reward. Thus, he has been conditioned to associate finishing his work before going to bed with positive consequences. This learning process is an example of positive reinforcement.
Positive reinforcement, in which a positive stimulus is used to encourage a desired behavior, is the most effective way to promote good behavior and discourage undesirable behavior. Positive reinforcement can take many forms, including praise, recognition, and tangible rewards.
By contrast, negative reinforcement, which involves removing an unpleasant stimulus, can also be used to encourage a desired behavior, but it is not as effective as positive reinforcement in the long term.
To sum up, Edgar's behavior is an example of positive reinforcement as he has learned to associate finishing his work before going to bed with positive consequences.
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