School is almost over pls help

Answer:

259.2 cm³

Step-by-step explanation:

The volume of the dilated image is

(3/5)³ × 1200= 27/125 × 1200

= 259.2 cm³

Answer:

the quotient is 2

Step-by-step explanation:

4/1=4

4/2=2

Answer:

y=179x

Y=105x+2046

Step-by-step explanation:

Answer:

Step-by-step explanation:

The graph of f(x) = –x^2 + 5 is that of an upside-down parabola with vertex (0, 5) and x-intercepts (-√5, 0) and (+√5, 0).  Plot the vertex (0, 5) and then draw a smooth curve through it and through the x-intercepts.

The function f(x) = -x2+5 is thus represented by the quadratic functions in the first graph.

A quadratic function has the formula f(x) = ax2 + bx + c, with a, b, and c being integers and a not equal to zero.  Parabolas can have openings that are upward or downward, different "widths" or "steepnesses," but they all share the same fundamental "U" shape.

here calculation

The function provided is f(x) =  -x2+5

.... (1) (1)

We must locate the function's graph.

The quadratic function's vertex form is f(x)= a(x-h)2 + k.... (2)

When we compare (1) and (2), we obtain

h=0 , k=5

It denotes that the function's vertex is (0,5).

The values list is

x           y

-2            1

-1            4

0            5

1            4

2           1

Place all ordered pairings on a coordinate plane, and then use a free-hand curve to link them.

The function f(x) = -x2+5 is thus represented by the quadratic functions in the first graph.

To know more about quadratic functions visit:-

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The exact value of cos(13π/8) is 1/2 [tex]\sqrt{2-\sqrt{2} }[/tex].

Trigonometriic ratios are the ratios of the sides of a right angled triangle. sin , cos, tan, sec, cosec, cot are some of the trigonometric ratios. Sin is the ratio of perpendicular and hypotenuse, cos is the ratio if base and hypotenuse, tan is the ratio of perpendicular and base, secant is the ratio of hypotenuse and base, cosecant is the ratio of hypotenuse and perpendicular, cot is the ratio of base and perpendicular.

We have to find the value of cos (13π/8).

We have to use formula which is following:

cos[tex]Θ[/tex]=[tex]\sqrt{1/2(1+cos 2Θ}[/tex]

=[tex]\sqrt{1/2(1+cos(2*13 π/8)}[/tex]   (π=[tex]π[/tex])

=[tex]\sqrt{1/2(1+cos(3 π+π/4)}[/tex]

=[tex]\sqrt{1/2(1-cos(π/4)}[/tex]

=[tex]\sqrt{1/2(1-1/\sqrt{2} }[/tex]

=[tex]\sqrt{\sqrt{2}-1/2\sqrt{2} }[/tex]

=1/2[tex]\sqrt{2-\sqrt{2} }[/tex]

Hence the value of cos (13π/8) is [tex]1/2\sqrt{2-\sqrt{2} }[/tex].

Learn more about trigonometric ratios at https://brainly.com/question/24349828

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Answer:

The answer is "Option B".

Step-by-step explanation:

Please find the complete question in the attached file.

The Horizontal stretch [tex]=(\frac{1}{6 \ x})\\\\[/tex]

Translation by 5 units right[tex]=( \frac{1}{6\ x})-5[/tex]

Answer:

its A i used his answer and got it wrong

Answer:

12 ft

Step-by-step explanation:

we know the areas of the 2 top squares.

the area of a square is simply the square of its side length.

=>

81 ft² means side length is 9 ft.

225 ft² means side length is 15 ft.

these are also 2 of the sides of the right triangle.

the third side we get by using Pythagoras :

c² = a² + b²

with c being the side opposite of the 90 degree angle.

so,

225 = 81 + x²

as x is also the third side of the triangle.

=> 144 = x²

x = 12 ft

Answer:

The answer is below

Step-by-step explanation:

Given that k(x) = -125x² +670x - 125, where x is the charge per cone and P = k(x) is the weekly profit

a) The maximum profit is at P'(x) = 0. Therefore we have to find the derivative of the profit equation and equate it to 0.

P'(x) = k'(x) = 0

k'(x) = -250x + 670 = 0

-250x + 670 = 0

250x = 670

x = $2.68

P = k(2.68) = -125(2.68²) + 670(2.68) - 125 = $772.8

Hence the maximum profit is $772.8 when the price of each ice cream cone is $2.68

b) At break even, the profit is 0. Hence P= k(x) = 0

-125x² + 670x - 125 = 0

x = 5.17 or x = 0.19

Therefore to break even, the price of the ice cream cone needs to be $0.19 or $5.17

c) g(x) = k(x - 2)

g(x) = -125(x - 2)² + 670 (x -2) - 125

Maximum profit is at g'(x) = 0

g'(x) = -250(x-2) + 670

-250(x-2) + 670 = 0

-250x + 500 + 670 = 0

250x = 1170

x = 4.68

g(4.68) = -125(4.68 - 2)² + 670(4.68 -2) - 125 = $772.8

Therefore function g has the same maximum value as function k

y=23x+143 hope this helps

Answer:

y = -5x+14

Step-by-step explanation:

slope formula

y-y divided by x-x

4-(-1) / 2-3

5/-1 or -5

substitute into y = mx + b

4 = -5(2) + b

b = 14

Answer:

348 kiwis

Step-by-step explanation:

Jamie is packing Kiwie fruits into a tray

Each tray holds 58 kiwis

He can put 6 trays in a crate

Hence when the craye is full the number of kiwis it will contain can be calculated as follows

°= 58×6

= 348 kiwis

Answer:

−7.361097448

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information:

ΔG° = -30.5 kJ/mol

By applying the following equation to calculate the value of K.

ΔG° =-RT㏑K

making ㏑ K  the subject of the formula:

[tex]\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}[/tex]

where;

Temperature at 25° C = (25 + 273)K

= 298K

R = 8.3145 J/mol.K (gas cosntant)

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}[/tex]

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }[/tex]

㏑K = 12.309

[tex]K = e^{12.309}[/tex]

K = 221682.17

K = 2.22 × 10⁵

b) The reaction for the metabolism of glucose is given as:

[tex]C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}[/tex]

From the above expression, let calculate the Gibbs free energy by using the formula:

[tex]\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}[/tex]

[tex]\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)][/tex]

At standard conditions;

The values of corresponding compounds are substituted into the equation above:

Thus,

[tex]\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -3786 +911 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875000 \ J/mol[/tex]

Now, the no of ATP molecules generated = [tex]\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}[/tex]

= (-2875000 J/mol ) / -30500 J/mol

= 94.26

≅ 94 ATP molecules generated

Answer:

A) 60

Step-by-step explanation:

P = 5+5+11+9+(5+11)+(9+5)

P = 60

Answer:

A. 60 m

Step explanation:

Perimeter for the small cube

5+5+5+5=20

Perimeter for the rectangle

9+9+11+11=40

Add 20 plus 40 to find the perimeter for the whole shape

20+40=60

Hope this helps

Answer:

Step-by-step explanation:

Step 1: 360÷30(exterior angle)= 12 sides

Step 2: (12-2)×180= 1800 (sum of the interior angles of the polygon)

Test: 1800÷ 12 sides= 150 ( 1 interior angle)

Answer:

4.2 hours

Step-by-step explanation:

Answer:

2821.51

73425.64

28124.24

4124.24

Step-by-step explanation:

Effective rate: .058/2 = .029

This question is kind of ambigous and I'll make the assumption that there is no payment at time 0

[tex]175000=x\frac{(1+.029)^{2*18}-1}{.029}\\x=2821.511[/tex]

interested earned:

175000-2821.51*36= 73425.64

2.)

Same assumption as question 1 (there is no payment at time 0)

effective rate: .063/12= .00525

[tex]400(\frac{(1+.00525)^{60}-1}{.00525})=28124.24[/tex]

Interest earned: 28124-400*60=4124.24

Answer:

First problem: monthly payment $2741.99; interest earned $76,288.36

Second problem: amount in account $28,271.90; interest earned $4271.90

Step-by-step explanation:

First problem:

You open an account with a deposit. The deposit is the first monthly payment. This means that this is an annuity in which you pay at the beginning of the pay period. That makes it into an "annuity due."

[tex] A = \dfrac{F}{\frac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

where A = periodic payment,

F = future value

i = interest rate per compounding period, n = number of compounding periods

[tex]A = \dfrac{175000}{\frac{(1 + \frac{0.058}{2})^{2 \times 18} - 1}{\frac{0.058}{2}} \times (1 + \frac{0.058}{2})}[/tex]

[tex] A = 2741.99 [/tex]

Interest earned:

[tex] 2 \times 18 \times 2741.99 - 175000 = 76288.36 [/tex]

Second problem:

Once again, the account starts with a deposit of the monthly payment, so this is also an annuity due, meaning the payments occur at the beginning of each compounding period. Here, we are given the monthly payment, an d we need to find the future value.

[tex] F = A \times \dfrac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

[tex] F = 400 \times \dfrac{(1 + \frac{0.063}{12})^{5 \times 12} - 1}{\frac{0.063}{12}} \times (1 + \frac{0.063}{12})} [/tex]

[tex] F = 28271.90 [/tex]

The interest earned is:

[tex] 28271.90 - 12 \times 5 \times 400 = 4271.90 [/tex]

Answer:

Y = -0.3587+0.09118X

92 %

Step-by-step explanation:

Using technology to fit the data between the variables, test score and hours of sleep; we obtain the linear model :

Ŷ = -0.3587+0.09118X

Where, x = test score ; y = hours of sleep

To obtain the test score of a student who sleep foe 8 hours using the model :

Y = 8

Ŷ = -0.3587+0.09118X

8 = -0.3587+0.09118X

8 + 0.3587 =0.09118X

8.3587 = 0.09118X

X = 8.3587 / 0.09118

X = 91.672515

X = 92 ( approximately)

Answer:

1865.16 m^2

Step-by-step explanation:

first let 's find radius of a circle

radius=diameter/2

=18/2

=9 m

area of a cylinder=2πrh+2πr2

=2*3.14*9*24 + 2*3.14*(9)^2

=1356.48 + 2*3.14*81

=1356.48 + 508.68

=1865.16 m^2

Answer:

1866.11 m²

Step-by-step explanation:

Formula = 2πrh + 2πr²

Surface area = 2 * 3.14 * 9 * 24 + 2*3.14* 81 ≈ 1866.11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

Step-by-step explanation:

Answer:

108

Step-by-step explanation:

c = b + 56

c + b = 160

Substitute for c

(b + 56) + b = 160

2b + 56 = 160

2b = 104

b = 52

c = 52 + 56 = 108

Answer: No

Step-by-step explanation: if you mean the measure of a is 3, the measure of b is 9 and the measure of c is 5, c being the hypotenuse then the answer is no because the the sides of a and b must be less than the measure of c. If 5 wasn’t the hypotenuse then the answer would be different.

(KEEP IN MIND THAT IF 9 IS THE HYPOTENUSE THEN THE ANSWER IS YES)

Hope this helps! :)

Answer:

[tex]t - 3.2 \le 7.5\\[/tex]

Step-by-step explanation:

Given

Represent as inequality

Taking the statement one at a time

So, the inequality is:

[tex]t - 3.2 \le 7.5\\[/tex]

Answer: The company will recognize commission expense in the amount of $2,400 in December

Step-by-step explanation:

Based on the information given in the question, the company will recognize commission expense in the amount of $2,400 in December.

A commission is regarded as a fee which is paid to a salesperson by a company in exchange for completing a sale.

It should be noted that in the accrual basis of accounting, commission should be recorded in the same period as when the sale generated was generated.

Answer:

b. The company will recognize commission expense in the amount of $2,400 in December.

Step-by-step explanation:

Based on the information given the statements that is true will be: THE COMPANY WILL RECOGNIZE COMMISSION EXPENSE IN THE AMOUNT OF $2,400 IN DECEMBER reason been that each salesperson were paid a commission in the amount of $800 for each cycle sold, which is 3 cycles during the month of December.

Calculation to determine the Commission Expense

Commission Expense=$800*3 cycles

Commission Expense=$2,400

Therefore The company will recognize commission expense in the amount of $2,400 in December.

Answer:

demographic

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

(-3, -1) and (1, 3)

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex]{ \tt{y = x + 2 - - - (a)}} \\ { \tt{ {x}^{2} + {y}^{2} = 10 - - - (b) }} \\ substitute \: for \: y \: in \: (b) : \\ { \tt{ {x}^{2} + {(x + 2)}^{2} = 10 }} \\ { \tt{ {x}^{2} + {x}^{2} + 4x + 4 = 10 }} \\ { \tt{2 {x}^{2} + 4x - 6 = 0}} \\ { \tt{ {x}^{2} + 2x - 3 = 0 }} \\ { \boxed{ \bf{x = 1 \: and \: - 3}}} \\ in \: (a) : \\ y = x + 2 \\ { \boxed{ \bf{y = 3 \: and \: - 1}}}[/tex]