Answer:
27
Step-by-step explanation:
The centroid divide a median in two parts, with ratio 1/3 and 2/3.
In particular the part between the centroid and the point where the median touches the side is 1/3 of the median.
We can build this proportion:
ST : 1/3 = IT : 3/3
9 : 1/3 = IT : 1
IT = 9 * 3 = 27
What is the slope-intercept form is?
TRIANGLES please help!! :)
Answer:
A
Step-by-step explanation:
First, the list of congruence theorems are:
SSS
SAS
ASA
AAS
HL
SSA is not on the list, so we can cross that out
Next, ASA implies that two angles are congruent, but we only know that one pair of angles (the right angles) are congruent, so we can cross that out
After that, the angle is not connecting the congruent sides, so D is not an option
Finally, we know that the longest sides (AD / AC) are congruent to each other, one other pair of legs/sides are congruent, and the triangles are both right triangles. Therefore, we can apply HL here
Solve the system by substitution
y= 5x− 22
y= 4x− 17
(show your work pls)
Answer:
i think 5 is the answer not sure check with other helpers or brainer
Step-by-step explanation:
help plsssssssssssssssssssss
Answer:
Question 10:
Answer: b.
[tex]{ \tt{f(x) = 5 {x}^{2} + 9x - 4}} \\ { \tt{g(x) = - {8x}^{2} - 3x - 4 }}[/tex]
(f + g)x, add f(x) and g(x):
[tex]{ \tt{(f + g)x = (5 - 8) {x}^{2} + (9 - 3)x - 4 - 4}} \\ { \tt{(f + g)x = - 3 {x}^{2} + 6x - 8}}[/tex]
Question 11:
Answer: a.
In relation with solution of question 10, same procedure:
[tex]{ \tt{(f - g)x = - 3 {x}^{3} + (1 - 2) {x}^{2} + ( - 3 - 4)x + 9 - ( - 9)}} \\ { \tt{(f - g)x = - 3 {x}^{3} - {x}^{2} - 7x + 18 }}[/tex]
Dividing with powers of 10
Use the properties of logarithms to prove log, 1000 = log2 10.
Given:
Consider the equation is:
[tex]\log_81000=\log_210[/tex]
To prove:
[tex]\log_81000=\log_210[/tex] by using the properties of logarithms.
Solution:
We have,
[tex]\log_81000=\log_210[/tex]
Taking left hand side (LHS), we get
[tex]LHS=\log_81000[/tex]
[tex]LHS=\dfrac{\log 1000}{\log 8}[/tex] [tex]\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right][/tex]
[tex]LHS=\dfrac{\log (10)^3}{\log 2^3}[/tex]
[tex]LHS=\dfrac{3\log 10}{3\log 2}[/tex] [tex][\because \log x^n=n\log x][/tex]
[tex]LHS=\dfrac{\log 10}{\log 2}[/tex]
[tex]LHS=\log_210[/tex] [tex]\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right][/tex]
[tex]LHS=RHS[/tex]
Hence proved.
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =
Answer:
4c² + 11cd + 5d
Step-by-step explanation:
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
-4c² + 7cd + 8d - 3d + 8c² + 4cd (opening bracket)
8c²-4c²+7cd + 4cd + 8d - 3d
= 4c² + 11cd + 5d
he manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 3.1 minutes. The population standard deviation is known to be 0.5 minute. We want to test to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes. Refer to Exhibit 9-2. At a .05 level of significance, it can be concluded that the mean of the population is _____. a. significantly less than 3 b. significantly greater than 3.18 c. significantly greater than 3 d. not significantly greater than 3
please help
yuffytdgtutidrysryrdf
Answer:
19 + 1 + 9 + 1
put any of those in the slots
Answer:
19 + 1 + 9 + 1
peace
A rectangular swimming pool. Measures 16m by 20m. A path of uniform width is built around the pool. If the area of path is 100m^2, find the width of the path, giving your answer correct to 2 decimal places.
Answer:
not sure but good luck
Step-by-step explanation:
:))))
Over what interval is the function in this graph constant?
Answer:
hjjjnnnhjjjjj
Step-by-step explanation:
answer is d
Can anyone help with this question? The population of a small industrial town was 12 910 in 2000. Each year, the population decreases by an average of 5%. Estimate the population in the year 2020. Round to the nearest whole number.
Answer:
Population of town in 2020 = 4626 (Approx.)
Step-by-step explanation:
Given:
Population of town in 2000 = 12,910
Decrease rate = 5% = 0.05 yearly
Find:
Population of town in 2020
Computation:
Number of year = 20 years
Population of town in 2020 = Population of town in 2000[1-r]ⁿ
Population of town in 2020 = 12,910[1-0.05]²⁰
Population of town in 2020 = 12,910[0.95]²⁰
Population of town in 2020 = 12,910[0.3584]
Population of town in 2020 = 4625.944
Population of town in 2020 = 4626 (Approx.)
Answer:
The population is 4628.
Step-by-step explanation:
Population in 2000 = 12910
Rate of decrease = 5 %
Time, t = 2020 - 2000 = 20 years
Let the population is P.
Use the formula
[tex]P = Po\left ( 1-\frac{r}{100} \right )^t\\\\P = 12910\left ( 1-0.05 \right )^2\\\\P = 4628[/tex]
6. Which of the following equations has a slope of -2 and passes
through the point (3,-4).
O) y=-2x - 4
O) y=-2x + 2
O) y = -2x+3
O) y = -2x - 1
Answer:
y=-2x+2
Step-by-step explanation:
substitute either the x or y value into the equations, if you substitute x=3 and get back y=-4, the equation is correct
PLEASE I NEED HELP!!
Find the value of x
Answer:
y=4sqrt 3 X=8sqr 3
Step-by-step explanation:
4/y=y/12 y^2=48 y= sqrt 48= sqrt 4 * sqrt 3 * sqrt 4 = y = 4sqrt 3 then X
(4sqrt3)^2+144=x^2
48+144=192
sqrt 192
8sqrt3
plz help me to do this
A 90 ° angle is divided into 2 angles.
Find the size of the angles.
5x+10 and 6x-41
Answer:
So required ans is 5*11+10=65 6x-41=25
Step-by-step explanation:
You can do as,
5x+10+6x-41=90
11x-31=90
11x=31+90
11x=121
x=121/11
x=11
Consider two parabolas: One has equation 1 ( 4)( 4) 2 y x x =−+ . The other has the same xintercepts, but goes through the point (2,−12) How far apart are the vertices of the two parabolas
Answer:
Following are the responses to the given question:
Step-by-step explanation:
[tex]\to y=(\frac{1}{2})(x-4)(x+4)\\\\\to y=(\frac{1}{2}) (x^2-16)\\\\\to y=(\frac{1}{2})(x-0)^2-8\\\\vertex \to (0,-8)[/tex]
The general x-intercept parabola equation [tex]y=k(x-4)(x+4)[/tex]
Parabola crosses the dot (2,-12)
[tex]\to k(2-4)(2+4)=-12\\\\\to k(-2)(6)=-12\\\\\to -12k=-12\\\\\to k=\frac{-12}{-12}\\\\\to k=1[/tex]
The parabolic equation which crosses the position [tex](2,-12)[/tex] is[tex]y=(x-4)(x+4)[/tex]
[tex]\to y=(x-4)(x+4)\\\\\to y=x^2-16\\\\\to y=(x-0)^2-16\\\\vertex \to (0,-16)[/tex]
The distance among the vertices of the two parabolas:
[tex]= \sqrt{(0 - 0)^2+(-8-(-16))^2}\\\\ = \sqrt{0+(-8+16))^2}\\\\ =\sqrt{0+(8)^2}\\\\=\sqrt{(8)^2}\\\\= 8\\\\[/tex]
A parallelogram is cut out of a 12 inch by 8 inch sheet of paper there are four right triangles remnats two have the dimensions 2 inches by 9 inches and the other two have the dimensions 3 inches by 6 inches
Answer:
96 in²
36 in²
60 in²
6.51 in
Step-by-step explanation:
Given that :
Dimension of paper = 12 in by 8 in
Dimension of right triangles :
2 in by 9 in ; 3 in by 6 in
Area of sheet of paper = 12 in * 8 in = 96 in²
Area of triangle = 1/2 base * height
Therefore, area of remnant right triangle :
2 * 1/2 * 2 * 9 = 18 in²
2 * 1/2 * 3 * 6 = 18 in²
Combined area of triangle left = 18in + 18in = 36 in²
Area of parallelogram = Area of sheet - Area of triangles left
Area of parallelogram = 96in² - 36in² = 60 in²
Base, b of parallelogram = 9.22 in
Area of parallelogram = base * altitude,h
60in² = 9.22h
h = 60 / 9.22 = 6.51 in
what is the value of x?
Explanation:
The adjacent angle to the right of the (6x+1) angle is 180-(6x+1). Simply subtract it from 180 to get its supplementary counterpart.
The three inner angles of any triangle must add to 180, so,
(inner angle 1) + (inner angle 2) + (inner angle 3) = 180
[ 180-(6x+1) ] + (79) + (2x+10) = 180
180 - 6x - 1 + 79 + 2x + 10 = 180
(-6x+2x) + (180-1+79+10) = 180
-4x+268 = 180
-4x = 180 - 268
-4x = -88
x = -88/(-4)
x = 22
Answer:
x = 22
Step-by-step explanation:
2x + 10 + 79 = 6x + 1
Think alternate interior angles
2x + 10 + 79 makes up one of the alternate interior angles
6x + 1 is the other.
Combine like terms.
Subtract 2x both sides.
Subtract 1 from both sides.
Divide by 4 both sides.
The domain of {(x, y): y = 2x2 + 1 ls
Answer:
y>1
Step-by-step explanation:
does anyone know this?
Answer:
The volume is approximately 50 m^3
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
The radius is 1/2 of the diameter r = 8/2 = 4
V = pi ( 4)^2 (1)
V = 16 pi
Letting pi be approximated by 3.14
V = 3.14 * 16
V = 50.24
The volume is approximately 50 m^3
HELPPPP MEEEE OUTTTT!!!
Answer:
Solution given:
Relationship between base and hypotenuse is given by Cos angle
Cos Angle(?)=base/hypotenuse
Angle{?}=Cos-¹(40/58)
Angle{?}=46°
The indicated angle is 46°
Can someone help me with this math homework please!
Answer:
10
Step-by-step explanation:
f ( 1 ) = 18
First term ( a ) = 18
f ( n + 1 ) = f ( n ) - 2
When, n = 1
f ( 1 + 1 ) = f ( 1 ) - 2
f ( 2 ) = 18 - 2
f ( 2 ) = 16
f ( 2 ) - f ( 1 )
= 16 - 18
= - 2
Common difference ( d ) = - 2
f ( 5 )
= a + 4d
= 18 + 4 ( - 2 )
= 18 - 8
= 10
If the base of a triangle is 3 and its height is 4, then its area is 6. This triangle has an area of 6, so its base is 3 and its height is 4
Valid or invalid
9514 1404 393
Answer:
invalid
Step-by-step explanation:
There is more than one set of dimensions that will give a triangle with an area of 6. The fact that the area is 6 implies nothing about the dimensions (except that their product is 12).
The converse is invalid.
Answer:
The first sentence is valid but the second one is invalid.
Step-by-step explanation:
You can't say just because the area of the triangle is 6, its base is 3 and its height is 4, it might have a base of 1 and a hight of 12 so there are more than one answers for the second one.
Feel free to message me if you still have questions :)
Who know how to do this??
Answer:
Step-by-step explanation:
With some research I found that the medians (QK, RJ, and SI) are broken into 2:1 ratios.
So what this means is that QD is twice as long as DK.
QD = 2DK
QD = 2 * 6.5
QD = 13
write 2^60 as an exponent with a base of 16
Recall that 2⁴ = 16. So you have
2⁶⁰ = 2⁴ˣ¹⁵ = (2⁴)¹⁵ = 16¹⁵
The graph of a function f(x) is shown below:
What is the domain of f(x)? (1 point)
integers from - 1< x <2
integers from -3 < y < 3
integers from -3 < y <3
integers from -1 < x < 2
Answer:
It's all integers x such that -1<=x<=2.
Step-by-step explanation:
The domain is the x values for which the relation exists.
Lets read from left to right.
First point I see from left exists at x=-1, next one at x=0, then x=1, and finally at x=2.
So it's all integers x such that -1<=x<=2.
*<= means less than or equal to
The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.
Answer:
[tex]a+b+c=10[/tex]
Step-by-step explanation:
We are given that the graph of the equation:
[tex]y=ax^2+bx+c[/tex]
Passes through the three points (0, 5), (1, 10), and (2, 19).
And we want to find the value of (a + b + c).
First, since the graph passes through (0, 5), its y-intercept or c is 5. Hence:
[tex]y=ax^2+bx+5[/tex]
Next, since the graph passes through (1, 10), when x = 1, y = 10. Substitute:
[tex](10)=a(1)^2+b(1)+5[/tex]
Simplify:
[tex]5=a+b[/tex]
The point (2, 19) tells us that when x = 2, y = 19. Substitute:
[tex](19)=a(2)^2+b(2)+5[/tex]
Simplify:
[tex]14=4a+2b[/tex]
This yields a system of equations:
[tex]\begin{cases} 5 = a + b \\ 14 = 4a + 2b\end{cases}[/tex]
Solve the system. We can do so using elimination (or any other method you prefer). Multiply the first equation by negative two:
[tex]-10=-2a-2b[/tex]
Add the two equations together:
[tex](-10)+(14)=(-2a+4a)+(-2b+2b)[/tex]
Combine like terms:
[tex]4 = 2a[/tex]
Hence:
[tex]a=2[/tex]
Using the first equation:
[tex]5=(2)+b\Rightarrow b=3[/tex]
Therefore, our equation is:
[tex]y=2x^2+3x+5[/tex]
Thus, the value of (a + b + c) will be:
[tex]a+b+c = (2) + (3) + (5) = 10[/tex]
reciprocal of. 0×7/11
Answer:
it doesn't exist
Step-by-step explanation:
the expression 0×7/11 is equivalent to 0. 1/0 isn't possible, so its reciprocal doesn't exist.
Which of the following statements does not prove that ABCD is a parallelogram.
Given: A(-4, 7), B(3,0), C(2,-5) and D(-5, 2).
Answer:
answer A
Step-by-step explanation:
A=(-4,7)
C=(2,-5)
midpoint = U=((-4+2)/2, (7+(-5))/2)=(-1,1))
B=(3,0)
D=(-5,2)
midpoint = V=((3+(-5))/2,(0+2)/2)=( -1,1)
Diagonals have the same middle, the quadrilater is a parallogram.