Answer:
Rs.92.95
Step-by-step explanation:
Given the following :
Metres of cloth purchased = 24.5m
Metres of ribbon = 13.5m
Cost of cloth per metre = Rs.85.40
Cost of Ribbon per metre = Rs.8.50
Total amount given to shopkeeper = Rs. 2300
how much money will he get back?
Total cost of cloth:
Cost per metre * number of metres
85.40 * 24.5 = Rs. 2092.30
Total cost of Ribbon :
Cost per metre * number of metres
8.50 * 13.5 = Rs. 114.75
Total cost of goods purchased :
Rs. (2092.30 + 114.75) = Rs. 2,207.05
Amount of change :
Rs. (2300 - 2207.05) = Rs.92.95
What type of number is that? Multiple answers.
Answer:
A & C
Step-by-step explanation:
-9 is a whole number is rational
Please answer quickly, what is the measure of c
===================================================
Explanation:
The only given number here is the 20 degree angle. So we'll start with that. This is an inscribed angle, which doubles to 2*20 = 40, and this is the measure of the arc the inscribed angle cuts off (inscribed angle theorem). Consequently, it means that central angle b is also 40 degrees.
With b = 40, we can see that c = 180-b = 180-40 = 140. This is because b+c = 180 as the two angles are supplementary.
Answer:
140 degrees
Step-by-step explanation:
If the given angle is 20 degrees then the other unknown angle would also be 20 degrees because this triangle is an isosceles triangle. 20+20+20=180 proving the triangle sum theorem.
complete the square to solve
f(x)=x^2+6x-7
PLEASE HELP DO TODAY IN A FRW MINUTESSS
27
A radioactive substance decays at an annual rate of
13 percent. If the initial amount of the substance is
325 grams, which of the following functions i
models the remaining amount of the substance. In
grams, 1 years later?
A) f(t) = 325(0.877'
B) f(t) = 325(0.13)
C) f(t) = 0.87(325)
D) (t) = 0.13(325)
Answer:
the answer
Step-by-step explanation:
D) 0.13 (325)
HOPE THIS HELPS!
do you need the workout?
Need help and will mark brainlist and thank You
In a circle whose center is O, arc AB contaisn 100 degrees. Find the number of degrees in angle ABO?
Answer:
40
Step-by-step explanation:
Angles ABO, BAO, and AOB are the angles of isosceles triangle AOB. The angles at A and B are equal, so we have ...
AOB +2ABO = 180° . . . . . sum of angles in the triangle
100° +2ABO = 180° . . . . . . use the given value
50° +ABO = 90° . . . . . . . . divide by 2; next, subtract 50°
∠ABO = 40°
20 points! Thank you :)
Answer:
[tex]\Large \boxed{x=-2 \ \mathrm{and} \ x=3}[/tex]
Step-by-step explanation:
The quadratic expression is given.
[tex]2x^2-2x-12=0[/tex]
Factor the left side of the equation.
[tex]2(x+2)(x-3)=0[/tex]
Set the factors equal to 0.
[tex]x+2=0[/tex]
[tex]x=-2[/tex]
[tex]x-3=0[/tex]
[tex]x=3[/tex]
The two solutions work in the original equation. The solutions make the equation true.
The quadratic expression:
[tex]2 {x}^{2} - 2x - 12[/tex]
★ By split middle term,we get
[tex]2 {x}^{2} - 6x + 4x - 12[/tex]
[tex]2x(x - 3) + 4( x - 3)[/tex]
[tex](2x + 4) (x - 3)[/tex]
[tex]2x + 4 = 0 \: \: and \: \: x - 3 = 0[/tex]
[tex]2 x = - 4 \: \: and \: \: x = 3[/tex]
[tex]x = - 2 \: \: and \: \: x = 3[/tex]
Therefore , the two solution of given quadratic equations is -2 and 3.
the fastest land dwelling creature is the cheetah. fact or
opinion
Answer:
True.
Step-by-step explanation:
Cheetahs can reach speeds of 109.4–120.7 km/h (68.0–75.0 mph), and some have been recorded at over 80mph. The cheetah can accelerate from 0 to 96.6 km/h (60.0 mph) in under three seconds, though endurance is limited.
The second fastest land animal is the Pronghorn antelope at 98kph (60mph).
Answer:
It is a Fact because it can run 70mph or 112kph
f(x) = -7x^2+8x+2f(x)=−7x 2 +8x+2
Answer:5
Step-by-step explanation:
max drove 460 miles in 8 hours at a constant speed. How long would it take him to drive 661.25 miles at that speed? speed=d/t Time =d/s
Answer:
x = 11.5 hours
Step-by-step explanation:
Set up a proportion:
[tex]\frac{460}{8}[/tex] = [tex]\frac{661.25}{x}[/tex]
661.25/460 = 1.4375
Multiply 8 by 1.4375 to find x:
8(1.4375) = 11.5
x = 11.5 hours
Let f (x) = x – 4 and g(x) = 6 - x
Evaluate g(f(10)).
G(f(10))
First solve f(x) by replacing x with 10:
F(x) = x-4 = 10-4 = 6
Now replace x in g(x) with 6
G(x) = 6-x = 6-6 = 0
So g(f(10)) = 0
Plz help Solve: y-17= -37
Answer:
-20
Step-by-step explanation:
First thing you do is set up your equation:
y-17= -37
+17 +17 Next you add 17 to both sides
------------- Follow your integer rules
y= -20
We can check this by putting it back into the solution
-20-17= -37 Integer Rules
You use KCC aka Keep Change Change
= -20+ -17= -37
Find the area of the shape shown below.
12
5
5
units
Answer:
42.5 units²
Explenation:
The area of the square on the left is 5×5=25.
At the top you do 12-5=7 to find the length of the tringle.
Than it is 7×5=35 than this divided by two, so 17.5.
You add both areas 25+17.5=42.5
Answer:
42.5 square units
Step-by-step explanation:
Separate shape into a square and a triangle
Calculate the area of the square (5*5=25 square units)
Calculate the are of the triangle (7*5/2=35/2= 17.5 square units)
Add together (17.5+25=42.5 square units)
solve for x 13(x-3)=39
Answer:
x=6
Step-by-step explanation:
13(x-3)=39
Divide each side by 13
13/13(x-3)=39/13
x-3 = 3
Add 3 to each side
x-3+3 = 3+3
x = 6
Answer:
x=6
Step-by-step explanation:
expanding we get
13x-39=39
13x=39+39
13x=78
x=78/13
x=6
Special right triangles
Answer: please find the attached files
Step-by-step explanation:
A unit circle formula and special triangle of 45, 30 and 60 degrees can be used to solve the problem.
Please find the attached files for the solution
In right triangle ΔABC (m∠C = 90°), point P is the intersection of the angle bisectors of the acute angles. The distance from P to the hypotenuse is equal to 4 in. Find the perimeter of △ABC if AB = 12 in.
Answer:
the perimeter of ΔABC is 32in
Step-by-step explanation:
We know that intersection point of the angle bisectors refers to the incenter of the triangle,.
Given tmthe radius of 4inch for the centre of the incircle.
One of the properties of the incircle is that the distances (d) from vertex C to the nearest touchpoints are equal and have the value
In an incircle , the distances (d) along vertex C and touchpoints have equal value and can be expressed as
d = 1/2(a +b -c)
And a, b, c represent lengths of the sides
We were given the hypotenuse (c) as 12 in, with the radius of 4inch for the
distance from the right-angle vertex C to the incircle touchpoints .
We can determine the sum a+b as
4 = (1/2)(a+b -12) .
4/(1/2)= (a+b -12)
8= (a+b -12)
20=a+b
Which is the addition of length of the two legs of the triangle.
We can determine the perimeter which is the addition of the leg lengths as well as the hypotenuse length.
perimeter = 20 in + 12 in = 32 in
Therefore, the perimeter of ΔABC is 32in
if the sum of two angles is 200 grade and their difference is 20 degree. Find the angle?
Step-by-step explanation:
Formulate an equation to solve for this one.
- I did x+x-20= 200
x represents the larger angle between the two triangles.
x-20 represents the smaller triangle which the problem states is 20 degrees smaller.
- if you solve the equation I gave you above you will get your answer. x= 110
your angles should be 110 and 90. You can check by adding those numbers which will equal to 200.
Hope this helps!
Convert 1.2 radians to an
angle in degrees
Answer:
Below
Step-by-step explanation:
Let x be the measure in degrees
● x/180 = 1.2/Pi
Cross multiply the values
● x*Pi = 180×1.2
● x = 216/Pi
Take Pi = 3.14
● x = 68.78 wich is approximatively 69°
(2.05 MC) Triangle PQR is transformed to Triangle P'Q'R'. Triangle PQR has vertices P(4,0), Q(0,-4) and R(-8,-4). Triangle P'Q'R' has vertices P'(1,0), Q'(0,-1), and R'(-2,-1). Part A: What is the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' Part B: Write The Coords of triangle P"Q"R" obtained after P'Q'R' is reflected about the y-axis Part C: Are the two Triangles PQR and P"Q"R" congruent?
Answer:
Part A: The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4
Part B:
P''(-1, 0)
Q''(0, -1)
R''(2, -1)
Part C:
The two Triangles PQR and P''Q''R'' are not congruent
Step-by-step explanation:
The coordinates of triangle PQR are;
P(4, 0)
Q(0, 4)
R(-8, -4)
The coordinates of triangle P'Q'R' are;
P'(1, 0)
Q'(0, -1)
R'(-2, -1)
Part A:
The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' can be found from the ratio of the respective coordinates as follows;
The ratio of the x, and y coordinates of the points are;
P'/P = x'/x = 1/4, y'/y =0/0
R'/R = x'/x = -2/-8 = 1/4, y'/y =-1/-4 = 1/4
Therefore, the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' = 1/4
Part B: For reflection across the y-axis, we have;
Pre-image (x, y) becomes the image, (-x, y)
Therefore, we have;
Reflection of P'(1, 0) about the y-xis becomes P''(-1, 0)
Reflection of Q'(0, -1) about the y-xis becomes Q''(0, -1)
Reflection of R'(-2, -1) about the y-xis becomes R''(2, -1)
Part C:
The two Triangles PQR and P''Q''R'' are similar but they are not congruent as the dimensions of PQR are larger than the dimensions of the sides of triangle P''Q''R''.
(A) The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4
(B) Coordinates of Δ P"Q"R"
P" (-1,0)
Q"(0,-1)
R"(2,-1)
(C) Triangles PQR and P"Q"R" are not congruent.
Given
ΔPQR is transformed into ΔP'Q'R'
Coordinates of P, Q, R are
P (4,0),
Q(0,-4)
R(-8,-4)
Coordinates of P'Q'R' are
P'(1,0)
Q'(0,-1)
R'(-2,-1)
(A) By Distance formula we can find the distance between P Q and P'Q'
Distance formula = [tex]D= \sqrt{(X_2-X_1)^2+(Y_2-Y_1)^2 }[/tex]
Where D = Distance between two points [tex](X_1.Y_1) \; and\; (X_2.Y_2)[/tex]
from distance formula we can write that
[tex]PQ = \sqrt{(0-4)^2+ (-4-0)^2} }\\[/tex]
PQ = [tex]4\sqrt{2}[/tex]
Similarly
P'Q'= [tex]\sqrt{2}[/tex]
PQ /P'Q' = 4
hence the scale factor of dilation is 1/4 (Compression)
(B )The Coordinates of Reflection about y axis can be written for a point
[tex](x,y ) \; as \; (-x,y)[/tex]
So the Coordinated of Δ P"Q"R" can be written as
P" (-1,0)
Q"(0,-1)
R"(2,-1)
(C) ΔPQR and ΔP"Q"R" are similar triangles but they are not congruent because their sides are not equal in size.
For more information please refer to the link below
https://brainly.com/question/12413243
In a bag of M&MS there are 4 green, 6 yellow and 8 blue candies. What is the probability of drawing a blue then a green if you replace the candy after the draw?
Answer:
8/81
Step-by-step explanation:
8/18 x 4/18 = 32/324 = 8/81
The probability of drawing a blue and then a green and replacing the candy after the draw is 8/81.
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Probability = Number of favorable outcomes / Number of sample
It is given that in a bag of M&MS there are 4 green, 6 yellow, and 8 blue candies.
The probability for blue = 8/18
The probability for green = 4/18
The probabilities of drawing a blue then green if you replace the candy after the draw will be calculated as below:-
Probability = 8/18 x 4/18
Probability = 32/324
Divide the number 32 by 324 to get the probability.
Probability = 8/81
Therefore, the probability of drawing a blue and then a green and replacing the candy after the draw is 8/81.
To know more about probability follow
https://brainly.com/question/24756209
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To bake 12 cookies, I use 2 quarts of milk. There are 2 pints in a quart. How many pints of milk do I need to bake 3 cookies?
Answer:
1 pint
Step-by-step explanation:
You need 2 * 2 = 4 pints to make 12 cookies. Since 3 cookies is 1/4 of 12 cookies, you would need 1/4 * 4 = 1 pint of milk to make 3 cookies.
Answer:
1 pint
Step-by-step explanation:
12c=4p
divide both sides by 4
3 cookies needs 1 pint!!!!
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
Una profesora compra 28 manzanas para compartir con sus estudiantes; al día siguiente revisa la cesta con las frutas y ve que se le han dañado 2/7 del total de manzanas que había comprado. Para reponer las frutas dañadas ella debe comprar
Answer:
La profesora debe comprar 8 manzanas para reponer la cesta de frutas.
Step-by-step explanation:
La profesora debe reponer la cesta de frutas por la cantidad de manzanas que se encuentran dañadas. La cantidad de manzanas dañadas es igual a las dos séptimas partes del total de manzanas. Es decir:
[tex]x = \frac{2}{7} \times (28\,manzanas)[/tex]
[tex]x = \frac{56\,manzanas}{7}[/tex]
[tex]x = 8\,manzanas[/tex]
La profesora debe comprar 8 manzanas para reponer la cesta de frutas.
a. Give Tommy your estimate of 0.27 probability in ratio form.
Answer:
0.27 expressed in ratio form is 27:100
Step-by-step explanation:
Before we give Tommy the estimate of 0.27 probability in ratio form, we shall need to turn 0.27 to fraction
Mathematically, that would be 27/100
Now expressing this in ratio form, we will have 27:100
If the average of 5, 8, b, 9 and 4 is 7. Find the value of b.
A. 9 B. 8 C. 7 D. 5
So our set of numbers is 5,8,b,9,4 . And we know the average is 7. So first, you have to add all the numbers in the set : 5+8+9+4 which gives you 26. We also know that to get the average of a set of numbers you have to add all the numbers and divide that sum by the how many numbers you have, in thsi case we have 5 numbers including b . So our equation now is : 26+b÷5=7. And if you plug in 9 for b you get 26+9÷5=7 and 26+9÷5 does equal 7 so therefore A is your answer
I need Help please answer :((
Answer:
Second option is the correct answer
[tex] {3}^{ - 4} [/tex]
Step-by-step explanation:
[tex] {3}^{ - 8} . {3}^{4} = {3}^{ - 8 + 4} = {3}^{ - 4} [/tex]
Answer:
The answer is D because you multiply the exponents so -8 times 4 is -32
Hope this helps and plz mark branliest!
Step-by-step explanation:
Please help. Calculate the area of the shaded region in each figure use 3.14 for π and round to the nearest 10th if necessary
3y=-2x+1593 divide each side by 3
Answer:
y = -2x/3 + 531
Step-by-step explanation:
Which expression is equivalent 6+7n+4+8n?
Answer: 5(2+3n)
Step-by-step explanation:
Answer:
15n + 10 should be your answer.
Step-by-step explanation:
A.) 170
B.) 300
C.)280
D.)155
Please help me
Answer:
Step-by-step explanation:
The formula for this is
∠G = 1/2(arcEH - arcHF)
We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF
Filling in the formula with what we have:
[tex]5x-10=\frac{1}{2}(195-(8x+17))[/tex]
which simplifies down a bit to
[tex]5x-10=\frac{1}{2}(195-8x-17)[/tex] which simplifies down a bit more to
[tex]5x-10=\frac{1}{2}(178-8x)[/tex] Multiply both sides by 2 to get rid of the fraction and get:
2(5x - 10) = 178 - 8x which of course simplifies to
10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:
18x = 198 so
x = 11. Now we can find the measure of arcHF:
arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.
arcEH + arcHF = arcEHF so
195 + 105 = arcEHF so
arcEHF = 300°
I WANT TO PASS HIGH SCHOOL PLEASE HELP
Given that the quadrilateral EFGH is a trapezoid, m∠H = 62° and m∠HEG = 64° calculate m∠FEG
Answer:
m∠FEG == 54°
Step-by-step explanation:
you should know that m∠FEG is equal m∠EGH. this is because sides HE and FG are equal this also means opposite angles of this sides (m∠FEG and m∠EGH) are equal.
first find the measure of m∠EGH from triangle EHG.
m∠H + m∠HEG + m∠EGH= 180°
62° + 64° + m∠EGH = 180°
m∠EGH=180° - 126°
m∠EGH=54°
due to the fact that sides HE and FG are equal thus opposite angles of sides HE and FG are also equal.
m∠FEG = m∠EGH = 54°
m∠FEG =54°
