Round 31.24 to 1 decimal place

Round 5.275 to 2 decimal place

Round 0.56489 to 3 decimal place

Answer:

Red: 13/41

Yellow: 19/41

Blue: 9/41

Step-by-step explanation:

yes friend and your answe is wring

Given:

The data values are:

21, 32, 17, 24, 15, 30, 28 and 26.

To find:

The first quartile, third quartile, and interquartile range.

Solution:

We have,

21, 32, 17, 24, 15, 30, 28, 26

Arrange the data values in ascending order.

15, 17, 21, 24, 26, 28, 30, 32

Divide the data set in two equal parts.

(15, 17, 21, 24), (26, 28, 30, 32)

Divide each parenthesis in two equal parts.

(15, 17), (21, 24), (26, 28), (30, 32)

Now, the first quartile is:

[tex]Q_1=\dfrac{17+21}{2}[/tex]

[tex]Q_1=\dfrac{38}{2}[/tex]

[tex]Q_1=19[/tex]

The third quartile is:

[tex]Q_3=\dfrac{28+30}{2}[/tex]

[tex]Q_3=\dfrac{58}{2}[/tex]

[tex]Q_3=29[/tex]

The interquartile range is:

[tex]IQR=Q_3-Q_1[/tex]

[tex]IQR=29-19[/tex]

[tex]IQR=10[/tex]

Therefore, the first quartile is 19, third quartile is 29 and the interquartile range is 10.

Answer:

The maximum angle is 84.3 degree.

Step-by-step explanation:

Sides of a triangle is

a = 6 , b = 11, c = 12

The maximum angle is opposite to c.

So,

[tex]a =6, b =11, c = 12 \\\\cos C =\frac{a^2+b^2-c^2}{2 ab}\\\\cos C =\frac{36+121-144}{2\times 6\times 11}\\\\cos C = \frac{13}{132}\\\\cos C = 0.0985\\\\C =84.3^o[/tex]

Answer:

The person above got it wrong its 84

Step-by-step explanation:

got it wrong on edge

Answer:

-3

Step-by-step explanation:

This is a quadratic equation. Therefore, one way we can solve this is by using the quadratic formula, [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex] and [tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex].

a, b, and c represent the coefficients in our equation [tex]x^2-5x-24=0[/tex]. a represents the coefficient of the term with degree of 2, which is 1. b represents the coefficient of the term with degree of 1, which is -5. c represents the coefficient of the term with degree of 0, which is -24.

Let us plug them in the equation! Let us start with this one: [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{5+\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5+\sqrt{25+96} }{2} =\\\frac{5+\sqrt{121} }{2} =\\\frac{5+11}{2} =\\\frac{16}{2} =\\8[/tex]

Oops! We are looking for the other solution. Let us plug in the values in this equation instead: [tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{5-\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5-\sqrt{25+96} }{2} =\\\frac{5-\sqrt{121} }{2} =\\\frac{5-11}{2} =\\\frac{-6}{2} =\\-3[/tex]

I hope this helps! Let me know if you have any questions :)

Answer:

scale factor: 2

translation: (x+2, y+7)

Step-by-step explanation:

Answer:

choose B is the greatest variablity

Answer:

Step-by-step explanation:

3 roots

namely -7/9,-1/4.-4/3

Answer:

3 x 5 is the gcf of 45 and 75. gcf(45,75) = 15.

Step-by-step explanation:

hope this helped! yw :}

Step-by-step explanation:

Translation: (x,y)↦( 9, -12)

Scale factor: 2

Translation:

(x,y)↦( 9, -12 )

Scale factor:

2 is the required answer.

Answer:

13/16

Step-by-step explanation:

The pan is divided into 16 bars. His family eats half and then another 5/8. What the question is asking you to do, is to count how many green bars there are left in the pan.

Hope this Helps!

-kiniwih426

Answer:

Mean= 44.2

Median=45

Mode=6

Range=50

Step-by-step explanation:

Mean= (10x1 +30x2 + 40x3 +50x2 +60x4)/12

= 530/12

=44.17

=44.2

Median= 40+50 /2

=45

Mode= 6

Range= 60-10

=50

Answer:

XY=6

Step-by-step explanation:

13-7=6

Answer:

XY = 6

Step-by-step explanation:

We know that the whole line (XZ) is equal to 13, and we know that YZ + XY is equal to XZ.

XZ = XY + YZ

13 = XY + 7

6 = XY

Hope this helped :)

Answer:

7 boys

Step-by-step explanation:

We must find the median of the data given. A median is the "middle number" of a set of numbers ordered in increasing value.

Step 1, ordering the numbers:

We will start by ordering the numbers from smallest to largest. We have:

2, 2, 6, 8, 9, 12

Step 2, finding the "middle number":

Well...notice how there is an even amount of numbers in the data set. We can't exactly find one "middle number". We can however, narrow the list down to two "middle numbers."

We have 6 and 8.

Step 3, taking the average:

To find the median, we will take the average of the two "middle numbers."

[tex]\frac{6+8}{2} =\\\frac{14}{2}=\\\fbox{7}[/tex]

The median is 7 boys.

I hope this helps! Let me know if you have any questions :)

Answer:

B. [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

Step-by-step explanation:

No. of students from first grade = 15

No. of students from second grade = 5

There are 5 rows of seats

Each row contains 5 seats

Total seats = 25

No. of ways for second-grade students to occupy the first row (i.e first 5 seats) = [tex]^{5} P_{5}[/tex]

Remaining seats = 20

So, now we are left with 15 first grade students  

So, No. of ways for first-grade students occupy remaining seats = [tex]^{20} P_{15}[/tex]

Using the counting rule principle,

No. of ways for the students can be seated if all of the second-grade students occupy the first row = [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

So, Option B is the correct answer

Hence, no. of ways for the students can be seated if all of the second-grade students occupy the first row is ×

There are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

A permutation in math is the number of ways in which a set of data or objects can be ordered or arranged, where the order matters.

Given that, a school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second-grade travel in the bus.

Since you have to place all first-grade students in the first three rows,

Therefore,

For the 15 first-graders of the first three rows (15 seats), we have ¹⁵P₁₅ since all 15 places have to be occupied by all 15 first-graders.

Then we have 10 remaining seats left to be assigned to the 5 second-graders = ¹⁰P₅

We then multiply the permutation numbers of those two arrangements to get the total ways:

¹⁵P₁₅ x ¹⁰P₅

Hence there are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

Learn more about permutation click;

https://brainly.com/question/30649574

#SPJ7

Answer:

20

Step-by-step explanation:

L times W

length times width

so 5 x 4 = 20

Answer:

(b) She should have rounded –8.02 to –8

Step-by-step explanation:

Given

See attachment for long division

Required

Her error

Ignoring the minus sign,

Her approximation is as follows:

[tex]-71.81 \approx 72[/tex]

[tex]-8.02 \approx 9[/tex]

Her approximation of -8.02 is wrong

Because:

[tex]-8.02 \approx 8[/tex]

Hence (b) is correct

B (she should have rounded –8.02 to –8)

Step-by-step explanation:

Just got it right on e d g e u n i t y 2021!

The Answer is:

C.) (x+2)(x+3)

Answer:

(x-2)(x+3)

Step-by-step explanation:

1. Start by setting up the synthetic division. The numbers 1, -4, -11, and 30 go on the inside on the division. To get the number on the outside, set x-5 equal to 0. solve and get 5.

2. bring the one down. multiply the one and the five and place the number you get underneath the -4 in the next column. From there, add the two numbers in the column.

3. After adding those two numbers, put the number you get (which should be 1) directly below the 5. Now multiply that number and the 5 again.

4. Repeat these steps until you fill the spaces under the next two columns. If you do it correctly, the number at the bottom of the very last column should be 0. This zero is known as the remainder. The remainder is not needed to complete this problem.

 Now that you have finished synthetic division, it is time to set up the new equation you got.

5. The 1 on the bottom left will be your [tex]x^{2}[/tex] value, the next 1 will be your x value, and the -6 will be your c. You should get the equation [tex]x^{2} + x -6[/tex]

6. From here, factor the polynomial. The factors must add up to the middle value (1) and multiple to c (-6). The factors -2 and 3 add up to 1 and multiply to -6

Therefore, your answer will be (x-2)(x+3)

Answer:

58cm2

Step-by-step explanation:

put it in section and them slove

so area of triangle = b×h÷2= 6×3/2=9cm2

area of terpizium = 5(4+6)/2=25cm2

area of triangle = 8×6÷2=20cm2

add all these together You get 58cm2

hope this helps :)

Answer: 4'6 2'4

Step-by-step explanation:

Answer:

I'm not seeing the options clearly so I'll answer the entire question then perhaps you can get your answer from that

Step-by-step explanation:

Formula for finding volume of rectangular prism =

Area or rectangle x Height

(L x B) x H

[tex] = (8 \times 3) \times 5 \\ = (24) \times 5 \\ = 120 {cm}^{3} [/tex]

I hope it helped?

Answer:

C    The mean or median

Step-by-step explanation:

Answer: -5/4

Step-by-step explanation: Cosecant is hypotenuse divided by the opposite side. The hypotenuse is 5 units, while the opposite side is 4 units. The answer has to be negative because the opposite side is below y=0.

Answer:

y-8x+7=0

Step-by-step explanation:

slope(m)=8

using slope intercept form of equation of staright line we get

y=mx+b

y=8*x+b

y-8x=b ................  eq(i)

since the line include the point (2,9) it satisfies the euation,

here x=2 and y=9

equation: y-8x=b

9-8*2=b

9-16=-b

-7=b

substituting the value of b in eq(i) we get

y-8x=-7

y-8x+7=0   is a required equation of the line.

Answer:

[tex]6^{-5}[/tex]

Step-by-step explanation:

lmk if its right :)

Answer:

Here we have the sequence:

0.5, 1, 2, 4, 8,...

A) we want to write the term to term rule.

We can see that each term is twice the one before, like:

2*0.5 = 1

2*1 =  2

2*2 = 4

2*4 = 8

etc.

So the term to term rule is just:

n-th term equals twice the previous term, or:

[tex]A_n = 2*A_{n-1}[/tex]

b) We can just construct the 7th term with the known ones:

We know that:

A₅ = 8

A₆ = 2*A₅ = 2*8 = 16

A₇ = 2*A₆ = 2*16 = 32

A₇ = 32

c) As each term in our sequence (unless for the first two ones) is a multiple of 2, we know that no odd number can be a term of this sequence.

1527 is an odd number, so this number can not be in the sequence.