Answer:
2025 cm
Step-by-step explanation:
Given the length of pieces - 45 cm, 75 cm and 81 cm
To find the length of the rope we have to find the L.C.M. of 45, 75 and 81 :
3 | 45, 75, 81
| ________________
3 | 15, 25, 27
|________________
3 | 5, 25, 9
|________________
3 | 5, 25, 3
|________________
5 | 5, 25, 1
|________________
5 | 1, 5, 1
|________________
| 1, 1, 1
L.C.M. = 3 × 3 × 3 × 3 × 5 × 5
= 2025 cm
So, the least length of the rope should be 2025 cm which can be cut into a whole number of pieces of length 45 cm, 75 cm and 81 cm.
which polygon will NOT tessellate a plane?
Step-by-step explanation:
the answer is regular octagon
i think
Which graph corresponds to the following inequality? -2x-3y<6
Answer:
A) It’s the First graph
Step-by-step explanation: hope this helps!
The graph corresponds to the inequality -2x - 3y < 6 is option A.
How to find the value of x?To estimate the value of x and y, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.
Given: -2x - 3y < 6
then -2x - 3y = 6
Put the value of y = 0, then
[tex]$-2x-3*0=6[/tex]
-2x = 6
x = -6/2 = -3 and
-2x - 3y = 6
Put the value of x = 0, then
[tex]$-2*0-3y=6[/tex]
-3y = 6
y = -6/3 = -2
The value of x = -3 and y = -2.
Therefore, the correct answer is option A.
To learn more about inequality refer to:
https://brainly.com/question/12170562
#SPJ2
I need help ASAP please
Answer:
yes how can I help you???
Which one and what do I put in the box(s)
Answer:
Option A i the right option.
First blank is 110-[tex]10\sqrt{61}[/tex] or 10(11-[tex]\sqrt{61}[/tex])
Second blank is 31.898
Let me know if anything didn't make sense.
Step-by-step explanation:
So a diagonal through a rectangle makes two triangles. The question wants to know how much walking is saved walking down the diagonal vs walking along two sides that make the diagonal. in this case the two non diagonal sides walked are 60 paces and 50 paces.
A diagonal through a rectangle specifically makes a right triangle, so to find the diagonal we can use the pythagorean theorem.
c^2 = 60^2 + 50^2
c = [tex]\sqrt{60^2 + 50^2}[/tex]
c = [tex]\sqrt{6100} = 10\sqrt{61}[/tex]
if you don't get how to simplify a radical like that let me know.
Anyway, looking at the answers you can see right away the second option says no approximation is necessary. Well, you need to approximate square root of 61, so we can say the second answer is not right. So now we need to know what to fill in for option 1.
it wants the distance saved, well we know the distance of the diagonal is [tex]10\sqrt{61}[/tex] Hopefully you can see the disctance walking the two other sides is just adding them up so 50+60=110.
Now, to find the difference, that is subtraction. So subtract the smaller number from the larger number. You do need to remember with a right triangle, the sum of the to non diagonal (hypotenuse) sides are always longer than said hypotenuse. so that's 110-[tex]10\sqrt{61}[/tex]. That is the exact form. Or you could use 10(11-[tex]\sqrt{61}[/tex]) They are the same.
Then just plug that into a calculator for a decimal approximation.
The number of dollars in x quarters
Answer:
There are four quarters in one dollar, so 4x quarters in x dollarsAn article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from soil. Out of 155 seeds planted in soil containing 3% mushroom compost by weight, 74 germinated. Out of 155 seeds planted in soil containing 5% mushroom compost by weight, 86 germinated. Can you conclude that the proportion of seeds that germinate differs with the percent of mushroom compost in the soil
Solution :
Let [tex]p_1[/tex] and [tex]p_2[/tex] represents the proportions of the seeds which germinate among the seeds planted in the soil containing [tex]3\%[/tex] and [tex]5\%[/tex] mushroom compost by weight respectively.
To test the null hypothesis [tex]H_0: p_1=p_2[/tex] against the alternate hypothesis [tex]H_1:p_1 \neq p_2[/tex] .
Let [tex]\hat p_1, \hat p_2[/tex] denotes the respective sample proportions and the [tex]n_1, n_2[/tex] represents the sample size respectively.
[tex]$\hat p_1 = \frac{74}{155} = 0.477419[/tex]
[tex]n_1=155[/tex]
[tex]$p_2=\frac{86}{155}=0.554839[/tex]
[tex]n_2=155[/tex]
The test statistic can be written as :
[tex]$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}[/tex]
which under [tex]H_0[/tex] follows the standard normal distribution.
We reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance, if the P-value [tex]<0.05[/tex] or if [tex]|z_{obs}|>Z_{0.025}[/tex]
Now, the value of the test statistics = -1.368928
The critical value = [tex]\pm 1.959964[/tex]
P-value = [tex]$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$[/tex]
[tex]$=2 \times 0.085667$[/tex]
= 0.171335
Since the p-value > 0.05 and [tex]$|z_{obs}| \ngtr z_{critical} = 1.959964$[/tex], so we fail to reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the [tex]\text{proportion}[/tex] of the seeds that [tex]\text{germinate differs}[/tex] with the percent of the [tex]\text{mushroom compost}[/tex] in the soil.
Circled one I need help with thank you!!
Formula-
If a set has “n” elements, then the number of subset of the given set is 2n and the number of proper subsets of the given subset is given by 2n-1. Consider an example, If set A has the elements, A = {a, b}, then the proper subset of the given subset are { }, {a}, and {b}
Symbol that can be used-
The symbol "⊆" means "is a subset of". The symbol "⊂" means "is a proper subset of".
Hope it helps you... pls mark brainliest if it helped you.
$88 tickets to the San Francisco 49ers game are offered at a 15%
discount. What is the sale price?
Answer:
74.80
Step-by-step explanation:
First find the discount
88 * 15%
88*.15
13.2
Subtract the discount from the original price
88-13.2
74.80
Abigail plans to repaint some classroom bookcases. She has 6/25
gallons of paint. All of the bookcases are the same size and each requires 2/3
gallon of paint. How many bookcases will the custodian be able to repaint with that amount of paint?
Answer:
Step-by-step explanation: Hello! Do
. A customer surveys the stock of gluten-free
breads sold in three different grocery stores.
At each grocery store, the customer counts
the number of different gluten-free breads
and compares it to the number of breads
that are not gluten-free. The table below
shows the results of this survey.
This is a relative frequency question. Applying the concept, we get that the relative frequency of gluten free breads sold at store A compared to those sold at all stores combined is 0.1667.
Relative frequency:
The relative frequency of a to b is given by a divided by b.
In this question:
a: Gluten free breads sold at store A
b: Gluten free breads sold at all stores combined.
2 + 7 + 3 = 12 gluten free breads sold.
2 sold at store A, so:
[tex]\frac{2}{12} = \frac{1}{6} = 0.1667[/tex]
Thus, the relative frequency of gluten free breads sold at store A compared to those sold at all stores combined is 0.1667.
Another example of a problem involving relative frequency you can check at https://brainly.com/question/20630951
Relative Frequency:
The relative frequency of gluten-free breads sold at Store A compared to those sold at all the stores combined is:
= 0.167
Data and Calculations:
Gluten-Free Breads at Different Stores
Gluten-Free Not Gluten-
Breads Free Breads
Store A 2 4
Store B 7 10
Store C 3 12
Since we are only considering Gluten-Free Breads at the three stores, we take the relevant data to calculate and compare their frequencies as follows:
Gluten-Free Relative
Breads Frequency
Store A 2 0.167 (2/12) = 17%
Store B 7 0.583 (7/12) = 58%
Store C 3 0.250 (3/12) = 25%
Total Gluten-free 12 1 = 100%
Thus, the relative frequency of gluten-free breads sold at Store A compared to those sold at all the stores combined is 0.167.
Restate the number 4,587,902.453.
Expanded form:
Written form:
Answer:
Expanded form: 4,000,000 + 500,000 + 80,000 + 7,000 + 900 + 2 + 0.4 + 0.05 + 0.003
Word form: Four million, five hundred eighty-seven thousand, nine hundred two and four hundred fifty-three thousandths.
what is the tan invers of 3i/-1-i
z = 3i / (-1 - i )
z = 3i / (-1 - i ) × (-1 + i ) / (-1 + i )
z = (3i × (-1 + i )) / ((-1)² - i ²)
z = (-3i + 3i ²) / ((-1)² - i ²)
z = (-3 - 3i ) / (1 - (-1))
z = (-3 - 3i ) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(z) and Im(z) are negative. But arctan only returns angles between -π/2 and π/2. So we have
arg(z) = arctan((-3/2)/(-3/2)) - π
arg(z) = arctan(1) - π
arg(z) = π/4 - π
arg(z) = -3π/4
where I'm taking arg(z) to have a range of -π < arg(z) ≤ π.
Which points lie on the graph of f(x) = loggx?
Check all that apply.
Step-by-step explanation:
f(x)=log(x)
=d(log(x)/dx)
=>y=1/x
Alan's aunt gave him $95 to spend on clothes at the mall. He bought 5 shirts that cost $6 each and a pair of pants that cost $17. How much money does Alan have left to buy more clothes? (one more)
Answer:
he has 48 dollars left to spend on clothes
8-2 3/4 =
show the work
ANSWER
8-2........3/4 but you have you ADD some people dont know that 8-2= 6
and so 6/1 + 3/4 is 24/4
What is the correct way to read 43.106
Step-by-step explanation:
Forty three thousand one hundred and six
Answer:
Forty three AND one hundred six thousandths
Step-by-step explanation:
If there is a comma ( , ) between the two numbers, you are correct.
If there is a period / dot ( . ) between them, and you need to read the place values, you must read the numbers to the right of the . as decimals. Those are the "th" numbers. 1 is in the tenths place, 0 in the hundredths place and the 6 in the thousandths place.
If you are simply reading out the digit names, without assigning their value, you might say "forty three POINT one hundred six" or "forty three DOT one hundred six" or "forty three DECIMAL one hundred six".
Can someone help me? I don’t know how to solve the rest. I am struggling and I would be so happy if any of you helped me. Thank you for your help!
Erica’s family is moving away from California. They decided to have a moving sale and sell each item for 70% off the price they originally paid for it. The sofa had an original price of $799, and the love seat had an original price of $549. What is the total cost of both items after the discount?
Find the sale price by multiplying the original price by 70% then add the two prices together to get the total.
799 x 0.70 = 559.30
549 x 0.70 = 384.30
Total: 559.30 + 384.30 = $943.60
Name the indicated geometric figures for the figure shown. Be sure to use correct notation
A Name a point.
B Name a ray through Y.
C Name a line through Z.
D Name a plane.
9514 1404 393
Answer:
see below
Step-by-step explanation:
[tex]\text{A. point: }X\\\\\text{B. ray through Y: }\overrightarrow{XY}\\\\\text{C. line through Z: }\overleftrightarrow{XZ}\\\\\text{D. plane: plane } XYZ[/tex]
__
Additional comment
When you don't have the benefit of typesetting, you can refer to the geometry by name: ray XY, line XZ,
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
f(x)= sqrt of x [0,9]
c =
Answer:
9/4
Step-by-step explanation:
f(x) is continuous and differentiable on (0,9).
We want to find c using the following equation.
f'(c)=(f(9)-f(0))/(9-0)
This will require us to find f'(x) first.
f(x)=sqrt(x) is the same as f(x)=(x)^(1/2)
Using power rule to differentiate this gives f'(x)=(1/2)(x)^(1/2-1) or simplified f'(x)=(1/2)x^(-1/2) or f'(x)=1/(2x^(1/2)).
So we want to solve:
(1/2)c^(-1/2)=(f(9)-f(0))/(9-0)
Simplify denominator on right:
(1/2)c^(-1/2)=(f(9)-f(0))/9
This will require us to find f(9) and f(0).
If f(x)=sqrt(x), then f(9)=sqrt(9)=3 and f(0)=sqrt(0)=0.
So we have the following equation so far:
(1/2)c^(-1/2)=(3-0)/9
Simplify numerator on right:
(1/2)c^(-1/2)=3/9
Multiply both sides by 2:
c^(-1/2)=6/9
Raise both sides to the -2 power:
c^(1)=(6/9)^(-2)
Note c^1=c:
c=(6/9)^(-2):
Note negative exponent means to find reciprocal of base to change exponent to opposite
c=(9/6)^2
Apply the second power:
c=81/36
Reduce by dividing top and bottom by 9:
c=9/4
This means the slope of the tangent to the curve f at x=9/4 is the same value as the slope of the secant line going through points (0,0) and (9,3).
Also 9/4 is between 0 and 9... According to the theorem we were suppose to get a value c between x=0 and x=9.
Confirmation:
Slope of the secant line is (3-0)/(9-0)=3/9=1/3.
Slope of the tangent line to curve f at x=9/4.
f'(x)=(1/2)x^(-1/2)
f'(9/4)=(1/2)(9/4)^(-1/2)
f'(9/4)=(1/2)(3/2)^(-1)
f'(9/4)=(1/2)(2/3)
f'(9/4)=1/3
They are indeed equal values (talking about the 1/3 from the secant and the tangent.)
Cho hai tập hợp A={1;2;3;4},B={2;4;6;8} . Tập hợp nào sau đây bằng tập hợp A ∩B ?
Answer:
A∩B ={2;4}
Step-by-step explanation:
Chúc bạn học tốt
C 89. What is the power of 5, so that 1 its value become ? (५ को घाताङ्क 25 कति हुदा त्यसको मान 25 हुन्छ ?) .7
C 89. What is the power of 5, so that 1 its value become ?
The power is 0. because if 0 is tge powwe of any variable or letters the value becomes 1.
Find the equation of the line that contains the point (4, -2) and is perpendicular to the line y = - 2x + 5.
y = 2x - 10
y = - 2x + 6
y = - 1/2x
y = 1/2x - 4
Answer:
It's option D. y = 1/2x - 4
Step-by-step explanation:
I used Desmos to find the answer, hope the graph helps!
translate this into an expression: the quotient of a number, x, and 8, could you please explain it to me?
Answer:
x/8
Step-by-step explanation:
First, we are given "the quotient of...". This means that we are dividing something/something else. If two numbers are given in the phrase "something and something else", the first number given will be the something, and the second number will be the something else.
The first number listed is x. Therefore, we have
x/something else.
Next, we are given "and 8", so we have x/8 as our expression
In empty set, n (A) = ………
Answer:
answer is
In empty set, n(A) = { }.
2.
The reflector of a satellite dish is in the shape of a parabola with a diameter of 4 feet and a depth of 2 feet. To get the maximum reception we need to place the antenna at the focus.
a. Write the equation of the parabola of the cross section of the dish, placing the vertex of the parabola at the origin. Convert the equation into standard form, if necessary. What is the defining feature of the equation that tells us it is a parabola?
b. Describe the graph of the parabola. Find the vertex, directrix, and focus.
c. Use the endpoints of the latus rectum to find the focal width.
d. How far above the vertex should the receiving antenna be placed?
Answer:
Step-by-step explanation:
Assume the dish opens upwards. The cross-section through the vertex is a parabola. You know three points on the parabola: (0,0), (2,2), and (-2,2). Plug the points into y = ax² + bx + c to get a system of three equations where a=0.5, b=c=0.
Equation of parabola: y = 0.5x²
:::::
Vertex (0,0)
Focal length = 1/(4×0.5) = 0.5
Focus (0,0+0.5) = (0, 0.5)
Directrix y = 0-0.5 = -0.5
:::::
At endpoints of latus rectum, y = 0.5
x = ±√0.5 = ±√2/2
Focal width = 2×√2/2 = √2
:::::
Place antenna at focus, (9,2)
a coin is tossed succesively three times times . determine tje probabiliy of getting all three heads
Answer:
Answer : 1/8.
Step-by-step explanation:
Hey there!
Please see the attached picture for your answer.
Hope it helps!
Need the help thanks guys
Answer:
1/4
Step-by-step explanation:
x^2 - x
Take the coefficient of x
-1
Divide by 2
-1/2
Square it
(-1/2)^2 = 1/4
Add it
x^2 -x +1/4
Which piecewise function represents the graph?
the function that connects the point (0;1) with the point (-1;0) is the graph
Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)
Answer:
[tex](4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7[/tex]
Step-by-step explanation:
Given
[tex](4x^3y^5)(3x^5y)^2[/tex]
Required
The equivalent expression
We have:
[tex](4x^3y^5)(3x^5y)^2[/tex]
Expand
[tex](4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2[/tex]
Further expand
[tex](4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2[/tex]
Apply laws of indices
[tex](4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7[/tex]
