Romans Food Market, located in Saratoga, New York, carries a variety of specialty foods from around the world. Two of the store's leading products use the Romans Food Market name: Romans Regular Coffee and Romans DeCaf Coffee. These coffees are blends of Brazilian Natural and Colombian Mild coffee beans, which are purchased from a distributor located in New York City. Because Romans purchases large quantities, the coffee beans may be purchased on an as-needed basis for a price 10% higher than the market price the distributor pays for the beans. The current market price is $0.47 per pound for Brazilian Natural and $0.62 per pound for Colombian Mild. The compositions of each coffee blend are as follows: Blend
Bean Regular DeCaf
Brazilian Natural 75% 40%
Columbian Mild 25% 60%
Romans sells the regular blend for $3.60 per pound and the Decaf blend for $4.40 per pound. Romans would like to place an order for the Brazilian and Columbian coffee beans that will enable the production of 1000 pounds of Romans Regular coffee and 500 pound of Romans DeCaf coffee. The production cost is $0.80 per pound for the Regular blend. Because of the extra steps required to produce DeCaf, the production cost for the DeCaf blend is $1.05 per pound. Packaging costs for both products are $0.25 per pound. Formulate a linear programming model that can be used to determine the pounds of Brazilian Natural and Columbian Mild that will maximize the total contribution to profit. What is the optimal solution and what is the contribution profit?

Answers

Answer 1

Answer:

z(max) =  2996.13  $

x₁  = 968      x₂  =  430       ( quantities of regular and Decaf coffee respectevely)

Total quantity of BN = 898 pounds

Total quantity of CM =  500 pounds

Step-by-step explanation:

Cost of the beans

Brazilian natural   =  Price market + 10 %    =  0.47 + 0.047  

BN  Cost   = 0.517 $/lb

Clombian Mild      =  Price market + 10 %    =  0.62  +  0.062

CM Cost   =  0.682  $/lb

Composition of the coffee blend

Regular coffee     0.75 BN  +  0.25 CM

De Caf   coffee     0.40 BN + 0.60  CM

PRICES

Regular Roman  =  3.60  $

Decaf                   =  4.40  $

Production costs:

Regular Roman  =  0.80  $/lb

Decaf                   =  1.05  $/lb

Packaging costs:   0.25  $/Lb       both

Profit  =  Price  -  cost

Profit  of regular coffee  =  3.60 - 0.80 - 0.25 -Cost of bean

for regular coffee cost of BN + CM

BN   is :   0.75*BN cost  = 0.75*0.517  =  0.38775       and

CM  is : 0.25*0.682   =   0.1705

Profit  of regular coffee  =  1.99175  $

Profit for Decaf coffee  =  4.4 - 1.05 - 0.25 - ( 0.517*0.4 + 0.6*0.682)

Profit for Decaf coffee  =  4.4  - 1.30 - 0.616

Profit for Decaf coffee  =  2.484  $

Let´s call  x₁  pounds of regular coffee   and  x₂   pounds of Decaf coffee then:

 Objective Function is:  

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

Availability of beans for 1000 pounds of Regular coffee means:

750 pounds of BN  +  250 pounds of CM

Availability of beans for 500 pounds of Decaf coffee means

200 pounds of BN  +   300 pounds of CM

Then   750 + 200  =  900 pounds of BN

And     250 + 300 =  550  pounds of CM

Availability of beans for 1000 pounds of Decaf  coffee correspond to

0.75 *x₁  +  0.40*x₂  ≤ 900

Availability of beans for 500 pounds of Regular  coffee correspond to

0.25*x₁  +  0.60*x₂  ≤ 500

Then the model is:

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

0.75 *x₁  +  0.40*x₂  ≤ 900

0.25*x₁  +  0.60*x₂  ≤ 500

General constraints  x₁ ≥ 0      x₂ ≥   0  both integers

After 6 iterations optimal solution  ( maximum z) is

z(max) =  2996.13  $

x₁  = 968      x₂  =  430  

x₁   and  x₂  are quantities of  Regular and Decaf coffee respectively, to find out quantities of Brazilian Natural and Colombian Mild

we proceed as follows

Regular coffee is :  0.75*968 =   726 pounds of BN

Decaf coffee is :      0.40*430 =   172  pounds of BN

Total quantity of BN = 898 pounds

Regular coffee is :  0.25*968   =  242 pounds of CM

Decaf coffee is :  0.6*430  =  258 pounds of CM

Total quantity of CM =  500 pounds


Related Questions


37. Two numbers are such that their
difference, their sum and their
product are in the ratio 1:7: 24.
Find the product of the
number.

Answers

Answer:

8 and 6

Step-by-step explanation:

Two numbers are such that their difference, their sum, and their product are to

each other as 1:7:24. Their product must equal what number?

:

Two numbers a & b

Let x = the multiplier

:

a - b = 1x

a + b = 7x

a * b = 24x

:

Add the 1st two equations

a - b = x

a + b = 7x

2a = 8x

a = 4x

or

x = .25a

:

a * b = 24x

Replace 24x; a = 4x therefore:

a * b = 6a

b = 6

;

Using the 1st equation

a - b = 1x

Replace b with 6 and x with .25a

a - 6 = .25a

a - .25a = 6

.75a = 6

a =

a = 8

:

Find the multiplier

a - b = x

8 - 6 = 2

:

Check this

a - b = 2 (1*2)

a + b = 14; (7*2)

a * b = 48: (24*2)

:

The numbers are 8 and 6; their products = 48

I only need the odd numbers answered

Answers

Answer:

1.a+4=11

a=7

2.6=g+8

g=2

3.

?

4.k+8=3

k=-5

5.j+0=9

j=9

6.12+y=15

y=3

7.h-4=0

h=4

8.m-7=1

m=8

9.w+5=4

w=-2

10.b-28=33

b=61

11.45+f=48

f=3

12.n+7.1=8.6

n=1.5

Hope This Helps!!!

Monique made several batches of soup.
Each batch required 3/4 of a pound of potatoes. She used a total of 6 1/2 pounds. How many batches did she make?

Answers

Answer:

8 batches

in workings show whats left over but not counted.

As a batch its a whole number as the multiplier will usually be the fraction

and fraction / fraction should always show fraction but the whole number given with a remainder can be shown if not a whole number.

Step-by-step explanation:

6 1/2 = 6.5

and ;

3/4 of a pound = 0.75  of 1 pound

6.5 / 0.75 = 8.7         or in full workings write = 8.6666.....7

8.7/ 1 = 8 batches with 0.7 or 0.66667 left over

Answer In fraction for exam question given in fraction  8.7 = 8  batches

with  7/10 left over.

identify the system by type

Answers

Answer:

Inconsistent system

Step-by-step explanation:

Given

The attached graph

Required

The type of system

When two lines are parallel, it means they have the same slope and as such, the system has no solution.

Equations with the same slope are:

[tex]y = 2x + 6[/tex]

[tex]y = 2x- 8[/tex]

Both have a slope of 2

Such system are referred to inconsistent system.

Hence, (c) is correct.

Find, correct to the nearest degree, the three angles of the triangle with the given ven
A(1, 0, -1), B(4, -3,0), C(1, 2, 3)
o
CAB =
O
LABC =
O
LBCA =

Answers

9514 1404 393

Answer:

  ∠CAB = 86°

  ∠ABC = 43°

  ∠BCA = 51°

Step-by-step explanation:

This can be done a couple of different ways (as with most math problems). We can use the distance formula to find the side lengths, then the law of cosines to find the angles. Or, we could use the dot product. In the end, the math is about the same.

The lengths of the sides are given by the distance formula.

  AB² = (4-1)² +(-3-0)² +(0-(-1)) = 16 +9 +1 = 26

  BC² = (1-4)² +(2-(-3))³ +(3-0)² = 9 +25 +9 = 43

  CA² = (1-1)² +(0-2)² +(-1-3)² = 4 +16 = 20

From the law of cosines, ...

  ∠A = arccos((AB² +CA² -BC²)/(2·AB·CA)) = arccos((26 +20 -43)/(2√(26·20)))

  ∠A = arccos(3/(4√130)) ≈ 86°

  ∠B = arccos((AB² +BC² -AC²)/(2·AB·BC)) = arccos((26 +43 -20)/(2√(26·43)))

  ∠B = arccos(49/(2√1118)) ≈ 43°

  ∠C = arccos((BC² +CA² -AB²)/(2·BC·CA)) = arccos((43 +20 -26)/(2√(43·20)))

  ∠C = arccos(37/(4√215)) ≈ 51°

The three angles are ...

  ∠CAB = 86°

  ∠ABC = 43°

  ∠BCA = 51°

_____

Additional comment

This sort of repetitive arithmetic is nicely done by a spreadsheet.

if x can be divide by 7 and 9 without leaving a remainder, it can also divided by which number without leaving a remainder​

Answers

Answer:

all counting numbers except one

A number that can go into x would be 3

This is because 7 x 9 is 63 meaning x would be 63 and 63 divided by 3 is 21 which does NOT Leave a reminder.

Complete the following statement.

Answers

Answer:

Hello dude

[tex] - 1 \frac{21}{24} + 1 \frac{22}{24} = + \frac{1}{24} [/tex]

so it's positive

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ツ

Which rations are equivalent to 30:20? check all that apply

Answers

Answer:

3:2, 6;4 hope this helps

Answer:

C, D

Step-by-step explanation:

If you multiply both numbers of a ratio by the same number, you get an equivalent ratio.

A.  Divide both numbers by 10

40:30 = 4:3 No

B. 10:0 No

C. Multiply both numbers by 10

3:2 = 30:20 Yes

D. Multiply both numbers by 5

6:4 = 30:20 Yes

Nikola thinks that the model that reflects the growth of smartphones shipped from manufacturers to stores around the world may be logistic rather than exponential. Do you agree with Nikola

Answers

Answer:

When most people have a smartphone, that is, the variable starts getting closer to its capacity, the demand will start to have a slight decrease, until it stabilizes, so yes, Nikola is correct.

Step-by-step explanation:

Exponential model:

The variable keeps growing consistently, at a fixed rate.

Logistic model:

The variable starts growing, but as it approaches a limit, for example, the carry capacity of an environment, the growth rate starts to decrease, until the variable stabilizes at a fixed value.

Growth of smartphones shipped from manufacturers to stores around the world.

When most people have a smartphone, that is, the variable starts getting closer to its capacity, the demand will start to have a slight decrease, until it stabilizes, so yes, Nikola is correct.

a student estimates the length of a room to be 20 feet. The actual length is 20.25 feet. What is the percent error?

Answers

Answer:

Percent error=1.23%

Step-by-step explanation:

We are given that

Estimate length of room=20 feet

Actual length of room=20.25 feet

We have to find the percent error.

To find the percent error we will find the difference between the estimate length and actual length of room.

Difference=Actual length of room-Estimate length of room

Difference=20.25-20

Difference=0.25 feet

Now,

Percent error=[tex]\frac{Difference}{actual\;length}\times 100[/tex]

Percent error=[tex]\frac{0.25}{20.25}\times 100[/tex]

Percent error=1.23%

Given: x + 2 < -5.



Choose the solution set.

{x | x R, x < -3}
{x | x R, x < 3}
{x | x R, x < -7}
{x | x R, x < 7}

Answers

Answer:

C

Step-by-step explanation:

x + 2 < -5

x < - 5 - 2

x < - 7

Answer:

{x| x R, x<-7}

Step-by-step explanation:

=> x+2<-5

=> x<-5-2

=> x<-7

)
Gos
1. Select all the relations that represent a
function.
(3,2), (2,1), (3,9) (4,7)
(1,7), (2,2), (3,5) (4,8)
(2,6), (6,5), (3,2) (5,3)
(4,3), (3,3), (2,3) (1,3)
(2,2), (2,5), (2,1) (2,3)

Answers

Answer:

(1,7), (2,2), (3,5) (4,8)

(2,6), (6,5), (3,2) (5,3)

(4,3), (3,3), (2,3) (1,3)

Step-by-step explanation:

those represent functions b/c the domain of the relation is not written twice

Hope that'll help!

What is the median of the following set of values? 7, 21, 19, 15, 19, 14, 15, 19

Answers

Line them up in order first.
7, 14, 15, 15, 19, 19, 19, 21
The median is 15 and 19. OR 17, because 15+19=34/2 which equals 17.

The median of the following set of values is equals to 17.

What are median?

Median represents the middle value of the given data when arranged in a particular order. The mean is the average value which can be calculated by dividing the sum of observations by the number of observations

We are given that the median of the following set of values

7, 21, 19, 15, 19, 14, 15, 19

Line them up in order first.

7, 14, 15, 15, 19, 19, 19, 21

Here the middle value are 15 and 19.

The median is 15 and 19. OR 17,

Therefore, 15 + 19 = 34/2 which equals to 17.

Learn more about mean and median;

https://brainly.com/question/17060266

#SPJ2

PLEASE HELP ASAP! What is the value of x in the inequality start fraction seven plus two x over five end fraction minus three less than x ?

A. x greater than negative start fraction eight over three end fraction
B. x less than negative start fraction eight over three end fraction
C. x greater than start fraction eight over three end fraction
D. x less than negative start fraction three over eight end fraction

Answers

Answer:

A

Step-by-step explanation:

the first one in the picture

62. A chemist mixes 15 liters of 40 percent acid solution and 25 liters of 20 percent acid solution.
What percent of the mixture is acid?

Answers

40% of 15 L = 6 L of acid

20% of 25 L = 5 L of acid

This means the mixture contains a total of 11 L of acid, and with a total volume of 15 L + 25 L = 40 L, that means the mixture is at a concentration of

(11 L acid) / (40 L solution) = 0.275 = 27.5%

A field book is a private notepad used by a surveyor to transcribe notes and is not considered a legal document True False

Answers

Answer:

False

Step-by-step explanation:

A field book is a private notepad used by a surveyor to record measurements and notes.

Basically, the size of a field book is 200 millimeters × 120 millimeters (20 centimeters × 12 centimeters) and it's typically opened lengthwise. There are two (2) main types of field book and these includes;

I. Double-line field book.

II. Single-line field book.

As a general rule, it's best that all findings, entries (notes) and observations are recorded or made into a field book after each and every measurement have been taken by a surveyor.

In conclusion, a field book is considered to be a legal document used by surveyors to keep records of accomplished field work or work done in the field. Thus, it's not a private notepad used by a surveyor to transcribe notes.

Answer:

False

Step-by-step explanation:

A field book is a private notepad used by a surveyor to transcribe notes and is not considered a legal document is False.

On Monday, Ray had $153.75 in his bank account. On Tuesday, he withdrew $71.00 from his account. After depositing #292.50 on Wednesday, how much money did Ray have in his account

Answers

Answer:

$375.25

Step-by-step explanation:

[tex]===========================================[/tex]

Withdrew- taking out money (-)

Deposit- putting in money (+)

[tex]===========================================[/tex]

Ray started off with 153.75. He withdraws (-) 71.

[tex]153.75-71=82.75[/tex]

Then he deposits (+) 292.5.

[tex]82.75+292.5=375.25[/tex]

That's your answer!

I hope this helps ❤


What is the value of the expression [-7] + [-4]

Answers

Answer:

11

Step-by-step explanation:

I'm assuming that [.] fldenote absolute value even tho the absolute value function is represented by (|.|)

value of [-7] will be positive that us 7.

= 7 + 4

= 11

so instead of subtracting that you added so it would be 11 because two negatives make a positive

Create your own proportion problems?

Answers

Answer:

See Explanation

Step-by-step explanation:

Required

Proportion problems

An example is:

y is directly proportional to x such that: y=4 when x = 2;

Derive the equation

For direct proportions, we have:

[tex]y\ \alpha\ x[/tex]

This gives:

[tex]y = kx[/tex]

Make k the subject

[tex]k = y/x[/tex]

So:

[tex]k = 4/2 =2[/tex]

So, the equation is:

[tex]y = kx[/tex]

[tex]y = 2x[/tex]

Assume the above question is for inverse proportion

The variation will be:

[tex]y\ \alpha\ \frac{1}{x}[/tex]

This gives:

[tex]y\ = \frac{k}{x}[/tex]

Make k the subject

[tex]k =x*y[/tex]

[tex]k =2* 4 = 8[/tex]

So, the equation is:

[tex]y\ = \frac{k}{x}[/tex]

[tex]y = \frac{8}{x}[/tex]

State the final conclusion in simple nontechnical terms.
Original claim: The proportion of male golfers is less than 0.6.
Initial conclusion: Fail to reject the null hypothesis.
Which of the following is the correct conclusion?
A. There is suffficient evidence to support the claim that the proportion of male golfers is less than 0.6.
B. There is not sufficient evidence to support the claim that the proportion of male golfers is less than 0.6.

Answers

Answer:

B. There is not sufficient evidence to support the claim that the proportion of male golfers is less than 0.6.

Step-by-step explanation:

The proportion of male golfers is less than 0.6.

At the null hypothesis, we test if the proportion is of at least 0.6, that is:

[tex]H_0: p \geq 0.6[/tex]

At the alternative hypothesis, we test if the proportion is of less than 0.6, that is:

[tex]H_1: p < 0.6[/tex]

Fail to reject the null hypothesis.

This means that there is not sufficient evidence to conclude that the proportion is less than 0.6, and thus the correct answer is given by option B.

Help asap!!!!!!
A.
B.
C.
D.

Answers

Answer:

Function has a minimum value

So, f(x)=0 and f(4)=-3

f(x)= - 1/2x^2+4x-11

f(4)=-3 and f(x)=-x+4

f(4)=0

OAmalOHopeO

Find the area of the figure

Please help :)

Answers

9514 1404 393

Answer:

  66.5 cm²

Step-by-step explanation:

A horizontal line at the "knee" on the right will divide the figure into a 4 cm by 2 cm rectangle, and a trapezoid with bases 4 cm and 9 cm, and height 11-2 = 9 cm. Then the total area of the figure is ...

  A = LW + 1/2(b1 +b2)h

  A = (4 cm)(2 cm) + (1/2)(4 cm +9 cm)(9 cm) = 8 cm² +58.5 cm²

  A = 66.5 cm² . . . . area of the figure

Solve the system by substitution.
y + 4 = x
10x + 2y = 16

Answers

Answer:

(2, -2)

Step-by-step explanation:

Given system:

y + 4 = x 10x + 2y = 16

Substitute x into the second equation:

10(y + 4) + 2y = 1610y + 40 + 2y = 1612y = -24y = -2

Find x:

x = -2 + 4x = 2

Answer:

x = 2 and y = -2

Step-by-step explanation:

Given system :-

y + 4 = x

10x + 2y = 16

Solve the system by substitution:-

Let,

y + 4 = x ...(1)

10x + 2y = 16 ...(2)

Solve for y;

Substitute y + 4 as x in the eq.(2)

10( y + 4 ) + 2y = 16

Distribute 10.

10y + 40 + 2y = 16

Combine like terms.

12y + 40 = 16

Move constant to the right-hand side and change their sign.

12y = 16 - 40

Subtract 16 from -40.

12y = -24

Divide both side by 12.

12y / 12 = -24/12

Hence, y = -2

Solve for x.

Substitute the value of y in eq.(1)

-2 + 4 = x

Add -2 and 4.

Hence, 2 = x

Let f(x) = (x − 1)2, g(x) = e−2x, and h(x) = 1 + ln(1 − 2x). (a) Find the linearizations of f, g, and h at a = 0. What do you notice? How do you explain what happened?

Answers

Answer:

Lf(x) = Lg(x) = Lh(x) =  1 - 2x

value of the functions and their derivative are the same at x = 0

Step-by-step explanation:

Given :

f(x) = (x − 1)^2,  

g(x) = e^−2x ,  

h(x) = 1 + ln(1 − 2x).

a) Determine Linearization of  f, g and h  at a = 0

L(x) = f (a) + f'(a) (x-a)  ( linearization of f at a )

for f(x) = (x − 1)^2  

f'(x ) = 2( x - 1 )

at x = 0

f' = -2  

hence the Linearization at a = 0

Lf (x) = f(0) + f'(0) ( x - 0 )

Lf (x) = 1 -2 ( x - 0 ) = 1 - 2x

For g(x) = e^−2x

g'(x) = -2e^-2x

at x = 0

g(0) = 1

g'(0) = -2e^0 = -2

hence linearization at a = 0

Lg(x) = g ( 0 ) + g' (0) (x - 0 )

Lg(x) = 1 - 2x

For h(x) = 1 + ln(1 − 2x).

h'(x) =  -2 / ( 1 - 2x )

at x = 0

h(0) = 1

h'(0) = -2

hence linearization at a = 0

Lh(x) = h(0) + h'(0) (x-0)

        = 1 - 2x

Observation and reason

The Linearization is the same in every function i.e. Lf(x) = Lg(x) = Lh(x) this is because the value of the functions and their derivative are the same at x = 0

Xavier is testing different types of planting soil to determine which type is most effective in growing blueberry bushes. He purchases two different brands of planting soil from a local store. Xavier applies Brand A to an area of the yard that receives full sunlight and Brand B to another area of the yard that is in partial sunlight. He waters the area with Brand B daily; he waters the area with Brand A every other day. At the end of the study, Xavier concludes Brand A is more effective in growing blueberry bushes. Why is his conclusion not valid?

Answers

Answer:

He did not control for lurking variables and their impacts on the results of his experiment. Amount of sunlight and water received are two outside variables(or confounding variables) that may impact the growth of his plants and influence the results. He needs to apply the same amount of sunlight and water to each plant within a different planting soil in order to rule out the influence of those two variables and test the sole effect of the soil brand on the plant growth. Otherwise, it would be hard to determine whether his plant growth was because of the soil brand or the different amounts of sunlight and water received

Answer:

Invalid

Step-by-step explanation:

Xavier did not control variables or the impacts of the results. Confounding variable being sunlight and water received are two outside variables that can impact growth influence results. Within a different planting soil, Xavier will apply the same amount of sunlight & water to each plant to rule out the influence of those two variables. The test for sole effect on the plant with growth otherwise be determine. Is the plant growth because of the soil brand or the different amounts of sunlight and water received? This could and will impaired the results of this experiment, therefore, making it invalid.

what are the missing numbers ?

Answers

It is d 5,6,8,9
Cube root 8 is 2 + 7 is 9

Find the values of x for which the denominator is equal to zero for y=x^2/x^2+1 .

Answers

Answer:

Step-by-step explanation:

I assume that you mean y = x²/(x²+1), not y = x²/x²+1.

x²+1 = 0

x² = -1

x = ±√(-1) = ±i

deleted: deleted by user

Tell whether the following two triangles can be
proven congruent through SAS.
A.Yes, the two triangles are congruent
because two sides and their included
angle are congruent in both triangles.
B.No, the two triangles don't have
corresponding sides marked congruent.
C. Yes, the two triangles are congruent because they’re both right triangles.
D.No, the two triangles can only be proven congruent through SSA.

Answers

Answer:

B. No, the two triangles don't have

corresponding sides marked congruent.

To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. For each location, calculate the standard deviation and report it with two significant figures.

Answers

Answer:

[tex]\sigma_1 = 0.08[/tex] --- Location 1

[tex]\sigma_2 = 0.34[/tex] --- Location 2

Step-by-step explanation:

Given

See attachment for the given data

Required

The standard deviation of each location

For location 1

First, calculate the mean

[tex]\bar x_1 =\frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_1 =\frac{30.40+30.20+30.30+30.40+30.30}{5}[/tex]

[tex]\bar x_1 =\frac{151.60}{5}[/tex]

[tex]\bar x_1 =30.32[/tex]

The standard deviation is calculated as:

[tex]\sigma_1 = \sqrt{\frac{\sum(x - \bar x_1)^2}{n-1}}[/tex]

[tex]\sigma_1 = \sqrt{\frac{(30.40 - 30.32)^2+(30.20 - 30.32)^2+(30.30 - 30.32)^2+(30.40 - 30.32)^2+(30.30 - 30.32)^2}{5-1}}[/tex]

[tex]\sigma_1 = \sqrt{\frac{0.028}{4}}[/tex]

[tex]\sigma_1 = \sqrt{0.007}[/tex]

[tex]\sigma_1 = 0.08[/tex]

For location 2

First, calculate the mean

[tex]\bar x_2 =\frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_2 =\frac{30.10+30.90+30.20+30.70+30.30}{5}[/tex]

[tex]\bar x_2 =\frac{152.2}{5}[/tex]

[tex]\bar x_2 =30.44[/tex]

The standard deviation is calculated as:

[tex]\sigma_2 = \sqrt{\frac{\sum(x - \bar x_2)^2}{n-1}}[/tex]

[tex]\sigma_2 = \sqrt{\frac{(30.10-30.44)^2+(30.90-30.44)^2+(30.20-30.44)^2+(30.70-30.44)^2+(30.30-30.44)^2}{5-1}}[/tex]

[tex]\sigma_2 = \sqrt{\frac{0.472}{4}}[/tex]

[tex]\sigma_2 = \sqrt{0.118}[/tex]

[tex]\sigma_2 = 0.34[/tex]

Jun 29, 8:51:41 AM
Find the volume of a pyramid with a square base, where the perimeter of the base is
10.7 ft and the height of the pyramid is 9.8 ft. Round your answer to the nearest
tenth of a cubic foot.

Answers

9514 1404 393

Answer:

  23.4 ft³

Step-by-step explanation:

In terms of the perimeter of the square base, the volume of a pyramid can be found using the formula ...

  V = (1/48)P²h . . . . . where P is the base perimeter and h is the height

  V = (1/48)(10.7 ft)²(9.8 ft) ≈ 23.4 ft³

_____

Additional comment

The relevant formulas usually used are ...

  P = 4s . . . . perimeter of a square with side length s

  A = s² . . . . area of a square with side length s

  V = (1/3)Bh . . . . . volume of a pyramid with base area B and height h

Solving the perimeter equation for s, and using that result in the other formulas, we get ...

  s = P/4

  B = (P/4)² = P²/16

  V = 1/3(P²/16)h = (1/48)P²h . . . . the formula used above

Using this result saves the effort of computing the intermediate values of side length and base area.

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