rajan has two coloured ropes of lengths 720 cm and 540 cm. if he is cutting them into pieces of equal length, what is the greatest possible length of each equal piece so that there is no wastage?​

Answer:

10 inches

Step-by-step explanation:

radius = 5 inches

Diameter = radius x 2 = 5 x 2 = 10 inches

Step-by-step explanation:

At Bob's binders, the unit price = $4.20 ÷ 3

= $1.40

At Pam's Paper Place the unit price = $5.20 ÷ 4 = $1.30

the better buy is at Pam's Paper place

Answer:

The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical

Step-by-step explanation:

The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in opposite side of the axis as if we're seeing it in a mirror.

If we study it more, you will find that its symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

If you're reflecting a point (x,y) along x axis, then its abscissa will stay same but ordinates will negate. Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along y axis, the resultant image of the point will be (-x,y)

Therefore, The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

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The Sequence:

1 , 1+2 , 1+2+3 , 1+2+3+4, ...

here, every term is an AP. finding the general formula for the sum of the elements of each term is:

Sₙ = [tex]\frac{x}{2}(2a + (x-1)d)[/tex]        [where x = number of term, a = first term and d = common difference]

here, the first term is always 1 and so is the common difference.

Sₙ = [tex]\frac{x}{2}(2 +x-1)[/tex]

Sₙ = [tex]\frac{x}{2}(1 +x)[/tex] = [tex]\frac{1}{2}(x + x^{2})[/tex]

which is the formula for a general term in our series

now, we need to find the sum of the first n terms of this series

[tex]\displaystyle\sum_{x=1}^{n} [\frac{1}{2}(x + x^{2})][/tex]

[tex]\displaystyle\frac{1}{2} [\sum_{x=1}^{n} (x) + \sum_{x=1}^{n}(x^{2})][/tex]

in this formula, for the first term, it's just an AP from x = 1 to x = n

for the second term, we have a general formula [tex]\frac{n(n+1)(2n+1)}{6}[/tex]

[tex]\frac{1}{2}[\frac{n}{2}(2a + (n-1)d)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

in this AP (first term), the first term and the common difference is 1 as well

[tex]\frac{1}{2}[\frac{n}{2}(2 + n-1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex]\frac{1}{2}[\frac{n}{2}(n+1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex][\frac{n}{4}(n+1)+ \frac{n(n+1)(2n+1)}{12} ][/tex]

[tex]\frac{n}{4}(n+1) [1+\frac{(2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(3+2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(2n+4)}{3} ][/tex]

[tex]\frac{n}{2}(n+1) [\frac{(n+2)}{3} ][/tex]

[tex]\frac{n(n+1)(n+2)}{6}[/tex]

which is the sum of n terms of the given sequence

I believe this is the expression:

[tex] \displaystyle \large \boxed{ - 8 {y}^{2} }[/tex]

Since we want to evaluate it when y = -2, simply substitute y = -2 in the expression.

[tex] \displaystyle \large{ - 8 {( - 2)}^{2} }[/tex]

Any negative number squared will result in positive, refer below:

[tex] \displaystyle \large{ {( - a)}^{2} = {a}^{2} } \\ \displaystyle \large{ {( - 2)}^{2} = {2}^{2} } \longrightarrow \boxed{4} \\ [/tex]

Hence,

[tex] \displaystyle \large{ - 8(4) = - 8 \times 4} \\ \displaystyle \large \boxed{ -32}[/tex]

Answer:

-32

Step-by-step explanation:

Replace the variable y with -2 in the expression giving -8(-2)^2

Then, square -2 giving us (positive) 4

Lastly, multiply -8 with 4 and get -32 as our answer

(Hopefully this helped you! Feel free to ask again if you need more help. Tell me if the solution is unclear to you)

Answer:

5,000

Step-by-step explanation:

Solve using a weighted average like so:

{ (6 days)($34,000) + (4 days)($45,000) }/(6 days + 4 days) = $38,400

It doesn't appear as if the correct answer is listed in the choices? You can tell from the information given that the answer must be between $34,000 & $45,000!

Answer:

5d = 30

Step-by-step explanation:

1. first you need to add 5 to both sides

   d-4+5 = 2+5

2. then you need to combine like terms

   d+1 = 7

3. after that you have to multiply both sides by 5

   5(d+1) = 7(5)

4. simplify

   5d + 5 = 35

         -5     -5

   5d = 30

-9 - 9 is the same that -9 + (-9)

Answer:

[tex]5. \: \: 8 + 5(7) = 8 + 35 = 43[/tex]

I hope I helped you^_^

Answer:

This will plot as an upward  "V" with the vertex at x = 4/3, y = 5

Step-by-step explanation:

The absolute value will mean that y can only be positive. y will be at a minimin when the absolute value is zero. To determine that find the x that makes it zero, so

-3x + 4 = 0

-3x = -4

x = 4/3

which makes y = 5 (the minimin)

Answer:

2

Step-by-step explanation:

x:14 = 1:7

x/14 = 1/7

x = 14/7

=> x = 2

Answer:

Step-by-step explanation:

x-intercept(s):  

( − 4 , 0 ) , ( 6 , 0 )

y-intercept(s):  

( 0 , − 24 )

Answer:1 and 2

Step-by-step explanation:right on edge

Answer:

wheres the file or question?

Answer:

here's the answer to your question

Answer:

y-intercept is (0, -8)

Step-by-step explanation:

[tex]y = {x}^{2} + 2x - 8[/tex]

At y-intercept, x is zero

substitute x as zero:

[tex]y = {(0)}^{2} + 2(0) - 8 \\ y = 0 + 0 - 8 \\ y = - 8[/tex]

Answer:

139,999

Step-by-step explanation:

If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999

Notice that a number is only divisible by 5 if it ends in 5 or 0.

Only using this, we will find that the number is 49,999

Suppose we wanted the sum of the digits to end in 5, then we could have something like:

23

2 + 3 = 5

if we add 1, we get:

23 + 1 = 24

2 + 4 = 6

This will happen always.

instead, if we use a 0 as the last digit of the sum, we get:

For example, the simplest one:

19

we have:

1 + 9 = 10

10 is divisible by 5.

if we add 1, we get:

19 + 1 = 20

2 + 0 = 2

2 is not divisible by 5.

We have a  problem again, but this time you can see that the whole structure of the number does change. So we should keep trying with ones and nines.

Now we need to modify our number to the point we get n + 1 to be divisible by 5.

if we add a 9 to the right side of our number, we get:

199

1 + 9 + 9 = 19

clearly, not divisible by 5.

Here we need to add a 1 at the left side to make it divisible by one, so we get:

1199

1 + 9 + 1 + 9 = 20

this is divisible by 5.

now let's add 1:

1,199 + 1 = 1,200

1 + 2 = 3

3 is not divisible by 5.

Now, if you look at the two numbers we used, we can see that:

for 19, the sum of the digits + 1 gave us a 2.

for 1,199, the sum of the digits +1 gave us a 3.

then just let's add two ones and two nines.

We will get:

11,119,999

adding the digits:

1 + 1 + 1 + 1 + 9 +9 +9 +9 = 40

is divisible by 5.

Adding one to our number, we can get:

11,119,999 + 1= 11,120,000

Adding the digits:

1 + 1 + 1 + 2 + 0 + 0+ 0+ 0 = 5

divisible by 5.

Now, we can group the ones together, so instead of the number 11,119,999

we can have 49,999, which is way smaller.

Adding the digits, we get:

4 + 9 + 9 + 9 + 9 = 40

And adding one to our number, we get:

49,999 + 1 = 50,000

Adding the digits:

5 + 0 + 0 +0 + 0 = 5

So we found the smallest number n such that the sum of the digits of n is divisible by 5, and the sum of the digits of n + 1 is also divisible by 5.

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Answer:

TR = 23

Step-by-step explanation:

first we have to find TS, so we subtract 16 from 4 to get 12. then we can add 12 and 11 to get TR

Answer:

Perimeter is (8x + 4) units.

Step-by-step explanation:

[tex]{ \sf{perimeter = side + side + side}} \\ { \sf{p = (2x + 1) + (7x - 2) + (5 - x)}} \\ { \sf{p = (2x + 7x - x) + (1 - 2 + 5)}} \\ { \sf{p = 8x + 4}}[/tex]

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

We have that the Polynomial is named as a  Quintic polynomial

From the Question we are told that

Polynomial=[tex]X^4-3x^2+7x^5[/tex]

We note that the Polynomial is of degree 5 as its highest Sum of its exponent is a

Quintic polynomial

Therefore

The Polynomial is named as a  Quintic polynomial

In conclusion

For every Polynomial at degree five that is a greatest power of 5 (e^5) the accurate name for this polynomial is called a Quintic Polynomial

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Answer:

hope it helps, appreciate if you can give brainliests

Answer:

yes

Step-by-step explanation:

try using a vertical line, if you move the vertical line across the graph and the line touches the graph only at one point, than it means it is a function

Answer:

This graph represents a function

Step-by-step explanation:

By its definition, a function is a relation or a correlation between two sets (groups) of values where every input corresponds to only one output. What this means is that every input in a function can only have one output. This characteristic results in a unique property in the graph of a function, that is, the verticle line test.  The verticle line test states that when one draws a line through the graph of a function, the line can only intersect the graph in exactly one place in the function. If the line intersects the graph in more than one place, then the graph does not represent a function. In the given situation, any verticle line drawn on the graph only intersects the graph in one place, thus the graph represents a function.

Answer:

6.3 cm

Step-by-step explanation:

The distance from each centimeter is divided into 10 parts.  Point A starts at 0 and goes until right before 6.5.  The big line between each whole number signifies that you are halfway through the centimeter.  As you can see, point B is right before a big line, so can't be bigger than 6.5 nor equal.  The only option that fits this is 6.3 cm

The answer is 6.3 cm

If helpful, brainliest please !

Answer:

Distance btw (-2, -2) and (8, -6) is (10, -4)

Step-by-step explanation:

I. Give (-2, -2) is A and (8, -6) is B

                     B - A = 8 - (-2) in x

                              = -6 - (-2) in y

                    So B - A = 10, -4

II. You can prove the answer by A.value + (10, -4) = B.value

Hope that help :D

Hi ;-)

[tex]\text{A}=(-2,-2) \ \text{and} \ \text{B}=(8,-6)\\\\|AB|=\sqrt{(8-(-2))^2+(-6-(-2))^2}\\\\|AB|=\sqrt{(8+2)^2+(-6+2)^2}\\\\|AB|=\sqrt{10^2+(-4)^2}\\\\|AB|=\sqrt{100+16}\\\\|AB|=\sqrt{116}\rightarrow\boxed{|AB|=2\sqrt{29}} \ (\text{because} \ 116=4\cdot29)[/tex]

48..................

Answer:

hmm looks like you are over thinking it its just 20-8

Step-by-step explanation:

Answer:

about 48 adults , because you have to divide the 477 by 10

Step-by-step explanation:

I got this question on my test and i chose this and i got it right.

I hope this helps!! :)

Answer:

Chim is 34 years old, and Jared is 8 years old.

Step-by-step explanation:

Let c be Chim's age and j be Jared's age.

Chim's age after five years (c + 5)

is 3 times Jared's age after five years (3 * (j+5) )

#1: c + 5 = 3(j+5)

We can add Chim's age and Jared's age to get 42 (the "sum"):

#2: c + j = 42

This is a system of equations that we can solve through substitution:

c + 5 = 3(j+5)

c + j = 42

In Equation #2, we can subtract j from both sides:

c = 42 - j

Then replace c with 42 - j in the first equation

(42 - j) + 5 = 3(j+5)

47 - j = 3j + 15

32 = 4j

j = 32/4 = 8

Plug j = 8 into the second equation, then solve for c.

c + 8 = 42

c = 42 - 8 = 34

c = 34, j = 8

Check our work by plugging in c = 34 and j = 8 into the first equation:

34 + 5 = 3(8+5)

39 = 3*13

39 = 39

Plug c and j into the second equation:

34 + 8 = 42

42 = 42

Chim is 34 years old, Jared is 8 years old.