Raj went to the theatre to watch a traditional Indian dance performance with his family. The theatre had 1050 seats. There were 50% fewer $50-seats than $30-seats. 90% of the $30-seats and some $50-seats were sold. A total of $34 650 was collected. How many seats were unsold?​

The dimensions of the triangle with maximum area are a base of 11 cm and a height of 11 cm.

We are given that the sum of the base and height of a triangle is 22 cm. Let's call the base of the triangle "b" and the height "h". Then we have the equation:

b + h = 22

We want to find the dimensions of the triangle that will give us the maximum area.

The formula for the area of a triangle is A = (1/2)bh.

We can use the equation b + h = 22 to solve for one of the variables in terms of the other.

we can solve for h:

h = 22 - b

Substituting this into the formula for the area, we get:

A = (1/2)b(22 - b)

The equation 0 = 11b - (1/2)b² can be rearranged to:

(1/2)b² - 11b = 0

We can then use the quadratic formula to solve for "b"

b = 11 ± 11

So the value of b that gives us the maximum area is b = 11 cm. Substituting this back into the equation h = 22 - b, we get:

h = 22 - 11 = 11 cm

Triangle has a base of 11 cm and a height of 11 cm.

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Answer:

42x-27

Step-by-step explanation:

As per the promissory note record, the profit in pesos is 0.098%

To do this, we'll need to use a number line to help us understand the relationship between time and the interest rate.

Let's say, that the interest rate on Laura's promissory note is 5% per year. We can represent this on a number line by dividing the line into 365 equal segments, one for each day of the year.

Each segment would represent 1/365th of the total interest rate, or approximately 0.014% (5%/365).

Now, we can mark off the first 7 segments on the number line to represent the 7 days that Laura is holding the investment. The total interest she'd earn over those 7 days would be equal to the sum of the values of those 7 segments.

In this case, that would be 7 x 0.014%, or approximately 0.098%.

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Complete Question:

Laura invests $12,000 in a promissory note. 00 to 7 days what is the profit in pesos?

the original number after simplification is 5600.

A fraction is a numerical quantity representing a part of a whole or a ratio between two numbers. It is expressed as one integer, called the numerator, written above a horizontal line, and another integer, called the denominator, written below the line.  For example, the fraction 2/5 represents two out of five equal parts or 2 divided by 5,

We can start by using the fact that 14.5% can be written as a decimal fraction 0.145.

Let X be the original number we want to find.

Then we can set up the following equation:

0.145 ×X = 812

To solve for X, we can divide both sides by 0.145:

X = 812 / 0.145 = 5600

Therefore, the original number is 5600.

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Answer:

I got 162?

Step-by-step explanation:

I broke down each individual shape (7 rectangles and 2 triangles) and used each shapes surface area formula.

triangle surface area formula is 1/2*b*h, and there are 2 of the same triangles of the exact same size and 7 rectangles. 3 are same size rectangles, 2 are same size rectangles and the other 2 are different sized rectangles. Then add altogether.

The cost of one small crate of apples is $12 and the cost of one large crate of peaches is $8. The cost of 7 small cates of apples and 5 large containers of peach is $126.

The system of equations that describe the question is:

3s + 10l = 116 equation 1

11s + 20l = 292 equation 2

Where:

s = cost of one small crate of apples

l = cost of one large crate of peaches

The elimination method would be used to determine the values of s and l.

Multiply equation 1 by 2

6s + 20l = 232 equation 3

Subtract equation 3 from equation 2:

5s = 60

Divide both sides of the equation by 5

s = 60 / 5

s = $12

Substitute for s in equation 1:

3(12) + 10l = 116

36 + 10l = 116

10l = 116 - 36

10l = 80

l = 80 / 10

l = 8

Cost of 7 small crates of apples and 5 large containers of peaches = (7 x 12) + (8 x 5) = $124

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The true statement is, Parameter values can be used within the method code block. (option e).

In computer programming, methods are used to group a set of instructions together that can be executed repeatedly. Parameters are used to pass values to a method so that the method can perform specific actions based on the values passed. Let's discuss the given statements one by one to determine which ones are true.

Parameter values can be used within the method code block.

This statement is true. Parameter values can be used within the method code block to perform specific actions. The parameter values can be manipulated or combined with other values to produce the desired result.

In summary, methods can be written with any number of parameters, and parameter values can be used within the method code block to perform specific actions. The number of parameters needed will depend on the specific task the method is designed to perform.

Hence the option (e) is correct.

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Answer:

x = 10

y = -9

Step-by-step explanation:

x = -3y - 17

2x + 3y = -7

Plug in x

2 (-3y - 17) + 3y = -7

-6y - 34 + 3y = -7

-3y = 27

y = -9

Plug in the value you got for y back into the equation to find the x value

x = -3(-9) - 17

x = 10

The average rate of change for the exponential function over the interval from x = 3 to x = 5 is 12.

The average rate of change for an exponential function can be found by dividing the change in y-values over the change in x-values for the given interval.

For the interval from x = 3 to x = 5, the change in x-values is 5 - 3 = 2.

The corresponding y-values for x = 3 and x = 5 are

y = 8 and y = 32, respectively.

Therefore, the change in y-values over the interval is 32 - 8 = 24.

The average rate of change for the exponential function over the interval from x = 3 to x = 5 is:

Average rate of change = Change in y-values / Change in x-values

Average rate of change = 24 / 2

Average rate of change = 12

Hence, the average rate of change for the exponential function over the interval is 12

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Answer:

(fog)(x) = 726x^2 + 924x + 295, and (fog)(-3) = 6,817.

Using the Poisson Approximation the probability are:

a)  0.6321

b)  0.3679

c) 0.2642

The Poisson distribution is utilized to compute the likelihood of a particular amount of occurrences happening over a set period. The Poisson approximation will be used to answer the given question, and it is a form of a probability distribution that can be used to approximate the probability of particular events that occur infrequently, and it is suitable for both continuous and discrete variables.

a) The probability of having at least one student with the same birthday as Brad using the Poisson Approximation.

Let the number of other students with the same birthday as Brad be represented by x. Here, x is a discrete variable with a Poisson distribution that follows a Poisson distribution with an average of λ, which is equal to 1:

λ = average number of students having the same birthday as Brad = 1.

Using the Poisson distribution formula, the probability of having at least one student with the same birthday as Brad is given by:

P(X >= 1) = 1 - P(X = 0)

= 1 - e ^ (-λ)P(X = 0)

= (e^(-λ))(λ^0) / 0!

= e^(-λ)

= e^(-1)

= 0.3679

Therefore, the probability of having at least one student with the same birthday as Brad is:

P(X >= 1) = 1 - P(X = 0)

= 1 - 0.3679

= 0.6321

b) The probability of having exactly one student with the same birthday as Brad using Poisson Approximation

P(X = 1) = (e^(-λ))(λ^1) / 1!

= e^(-1)(1) / 1!

= e^(-1)

= 0.3679

Therefore, the probability of having exactly one student with the same birthday as Brad is:

P(X = 1)

= e^(-1)

= 0.3679

c) The probability of having at least two students with the same birthday as Brad using Poisson Approximation

P(X >= 2) = 1 - P(X < 2)

= 1 - [P(X = 0) + P(X = 1)]

= 1 - [e^(-λ)(λ^0) / 0! + e^(-λ)(λ^1) / 1!]

= 1 - [e^(-1) + e^(-1)(1) / 1!]

= 1 - [e^(-1) + e^(-1)]

= 1 - 2e^(-1)

= 0.2642

Exact probability: 1 - (364/365)^180 = 0.4406

Poisson Approximation Probability: 0.6321

The exact probability is 0.4406, which is less than the Poisson approximation probability, which is 0.6321.

This result indicates that the Poisson approximation formula overestimates the likelihood of having at least one student with the same birthday as Brad.

Exact probability: (364/365)^179(1/365) = 0.3775

Poisson Approximation Probability: 0.3679

The exact probability is 0.3775, which is quite similar to the Poisson approximation probability, which is 0.3679.

This result indicates that the Poisson approximation formula provides a reasonably precise estimate of the likelihood of having exactly one student with the same birthday as Brad.

Exact probability: 1 - [1 + 364/365 + ... + (364!/347!)/365^34] = 0.1827

Poisson Approximation Probability: 0.2642

The exact probability is 0.1827, which is less than the Poisson approximation probability, which is 0.2642.

This result indicates that the Poisson approximation formula overestimates the likelihood of having at least two students with the same birthday as Brad.

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Answer:

$12

Step-by-step explanation:

Cans : Dollars

6 cans : 9 dollars

DIVIDE BY 3

2 cans : 3 dollars

MULTIPLY BY 4

8 cans : 12 dollars

Hope this helps :)

Have a great day!

Hence, if you merely move north or east on the grid map, there are 126 distinct ways to get to the Tower of London.

A way to arrange things or elements in a particular order is through permutation. In other terms, an orderly rearranging of a set of elements is referred to as a permutation. The symbol n! indicates how many different combinations there are for a set of n elements. Factorial, denoted by an exclamation mark, signifies dividing the number by all positive integers that are less than it by one. For instance, there are 4! = 4 x 3 x 2 x 1 = 24 permutations for a set of 4 items. In several branches of mathematics, including combinatorics, probability, and statistics, permutations are used.

given

You must go 4 blocks north and 5 blocks east to reach the castle. You must make a total of 9 moves to get to the castle because you can only go north or east (4 north and 5 east). Consider this to be a combination problem in which you must select 4 of the possible 9 moves to be in the north and the remaining 5 to be in the east.

Using the combination formula, we can write:

[tex]C(9,4) = 9! / (4! * (9-4)!) = 126[/tex]

Hence, if you merely move north or east on the grid map, there are 126 distinct ways to get to the Tower of London.

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Answer:

Step-by-step explanation:

100 students all together.

50+70=120....so 20 must like both.

According to the question the value of the 5 digit in 4,597 is 9.

Digit is a numerical symbol used to represent numbers in the decimal system. It is a single symbol used to represent a number ranging from 0 to 9. Digits are used to represent numbers in all forms of mathematical calculations and equations. The most common digits used in calculations are 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. Each digit has an associated numerical value, which can be used to create larger numbers or to perform complex mathematical operations.

The answer is D) 9. The value of the 5 digit in 4,597 is 5. To find the 10 times its value, you must multiply 5 by 10, which equals 50. Therefore, the value of the 5 digit in 4,597 is 9.

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Answer:

The correct order to draw 65 agle would be:

C

A

B

D

P(0 received correctly) = P(0 sent) × P(0 received correctly | 0 sent)= [tex](2/3) × 0.8= 0.5333[/tex] (rounded to 1 decimal place)Thus, the probability that a 0 is received is 0.5333 (rounded to 1 decimal place).

0.5333

A space probe near Neptune communicates with Earth using bit strings. Suppose that in its transmissions it sends a 1 one-third of the time and a 0 two-thirds of the time. When a 0 is sent, the probability that it is received correctly is 0.8 and the probability that it is received incorrectly (as a 1) is 0.2. When a 1 is sent the probability that it is received correctly is 0.8 and the probability that it is received incorrectly (as a 0) is 0.2.The probability that a 0 is received correctly is given in the problem as 0.8, and the probability that a 0 is sent is 2/3. Therefore, the probability that a 0 is received correctly

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The rate at which the surface area of the balloon is increasing at the instant the area is 153.24 square inches and the volume is 178.37 cubic inches is 4.96 square inches per second.

The surface area of a spherical balloon and the volume of the balloon are related by the equation [tex]A³ - 36πV²[/tex], where A is in square inches and V is in cubic inches. To find the rate at which the surface area of the balloon is increasing, we can use derivatives. We start by taking the derivative of the equation [tex]A³ - 36πV²[/tex] with respect to time (t).

[tex]d/dt[A³ - 36πV²] = 3A²dA/dt - 72πVdV/dt[/tex]

Given the rate at which the balloon is being inflated with gas (dV/dt) and the area and volume of the balloon (A, V) at the given instant, we can solve for the rate at which the area is increasing (dA/dt).

[tex]dA/dt = (3A² - 72πV)dV/dt / 36πV[/tex]

Plugging in the given values for A, V, and [tex]dV/dt,[/tex]we can calculate dA/dt:

[tex]dA/dt = (3(153.24)² - 72π(178.37))(18)/(36π(178.37)) ≈ 4.96[/tex]

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The estimated probability is 0.9537 (rounded to four decimal places).Hence, the answer is 0.9537.

Question: Nine percent of men are color blind. Researchers need at least 60 men with this trait, so they randomly select 700 men. Estimate the probability that at least 60 color-blind men are in the sample. Use a TI-83, TI-83 plus, or TI-84 calculator to find the probability. Round your answer to four decimal places. Provide your answer below:

Solution:

Let the probability of the man having the trait of color blindness be p. Then, p = 0.09, and the sample size is n = 700.Mean and Variance of Binomial Distribution are:μ = np and σ² = np(1 − p)Here, p = 0.09, n = 700μ = np = 700(0.09) = 63Andσ² = np(1-p) = 700(0.09)(0.91) = 5.679Now we need to find the probability that at least 60 color-blind men are in the sample.i.e., P(X≥60)By using the Central Limit Theorem, we can approximate this binomial distribution as a normal distribution with mean μ = 63 and variance σ² = 5.679.P(X≥60) can be calculated using the following formula:P(Z≥((60-63)/√(5.679))) = P(Z≥(-1.684))Now we need to look at the z-table or use the calculator to find the value of P(Z≥(-1.684))P(Z≥(-1.684)) = 0.9537 (rounded to four decimal places)Therefore, the estimated probability is 0.9537 (rounded to four decimal places).Hence, the answer is 0.9537.

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Answer: 8/20

Step-by-step explanation:

Jackie would see a total of 81 clovers on the ninth day.

Algebra is a branch of mathematics that deals with mathematical symbols and the rules for manipulating these symbols. It involves the use of letters or symbols to represent unknown values or variables, and the use of mathematical operations such as addition, subtraction, multiplication, and division to manipulate these variables and solve equations.

Algebra is used to solve a wide variety of problems in many fields, including science, engineering, economics, and finance. It is also a fundamental tool in mathematics education, providing a basis for higher-level math courses such as calculus and linear algebra.

In algebra, equations are used to represent relationships between variables, and the goal is to find the values of the variables that satisfy the equation. Algebraic expressions, which are made up of variables and mathematical operations, can be simplified using various techniques such as factoring, combining like terms, and using the distributive property.

On the fifth day, Jackie would see nine new clovers (7 + 2) for a total of 25 three-leaf clovers. On the sixth day, she would see 11 new clovers (9 + 2) for a total of 36 three-leaf clovers. On the seventh day, she would see 13 new clovers (11 + 2) for a total of 49 three-leaf clovers. On the eighth day, she would see 15 new clovers (13 + 2) for a total of 64 three-leaf clovers. On the ninth day, she would see 17 new clovers (15 + 2) for a total of 81 three-leaf clovers. Therefore, Jackie would see a total of 81 clovers on the ninth day.

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A principal gathered data about the distance in miles that his teachers and bus drivers live from the school. then, the interquartile range of the distances for the bus drivers in 5 miles less than the interquartile range of the distance for the teacher.

Interquartile Range:

In descriptive statistics, the interquartile range (IQR) is a measure of the statistical distribution, the distribution of data. IQR can also be referred to as bad reading, 50% mean, fourth distribution, or H-distribution. It is defined as the difference between the 75th and 25th percentile of the data. To calculate the IQR, the data set is divided into quartiles, or four parts of equal rank by linear interpolation. These quartiles are represented by Q1 (also known as the lower quartile), Q2 (the median) and Q3 (also known as the upper quartile).

The lower quartile is the 25th percentile and the upper quartile is the 75th percentile, so IQR = Q3 − Q1

Basically, the interquartile range represents the width or “spread” of the collection. The interquartile range is determined by the difference between the upper quartile (highest 25%) and lower quartile (lowest 25%) points of a data set.

From the figure, we can find:

The interquartile range of the bus driver is: 20 -10 = 10

The interquartile range of the teacher is: 30 -15 = 15

Therefore,

the interval interquartile distance is bus The driver's distance was 5 miles less than the interquartile range of the teacher's distance.

Complete Question:

A principal gathered data about the distance in miles that his teachers and bus drivers live from the school .The box plots below show these data.

(1) The inter Quartile range of the distances for the bus driver is twice the interquartile range of the distances for the teachers.

(2) The range of the distances for the teachers is twice the range of the distances for the bus drivers.

(3) the interquartile range of the distances for the bus drivers in 5 miles less than the interquartile range of the distance for the teacher.

(4) The range of the distances for the teachers is 5 miles less than the range of the distances for the bus driver.

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Answer: C. The interquartile range of the distances for the bus drivers is 5 miles less than the interquartile range of the distances for the teachers.

Answer: give proper question

Step-by-step explanation:

The last two rows of the table should be completed as follows:

Input   Output

8       22.80

10      28.50

An algebraic expression is a mathematical phrase that contains numbers, variables, and operations. It is used to represent a single quantity or value, and can be written in terms of one or more variables.

The rule given is an algebraic expression, x, which is the input, multiplied by 2.85, which is the output. Using this information, we can determine the cost of 10 muffins.

To find the cost of 10 muffins, we can use the algebraic expression given. First, we will multiply 10, the number of muffins, by 2.85, the cost of one muffin. This gives us a total of 28.50. Therefore, the cost of 10 muffins is 28.50.

Using this same rule and process, we can also determine the cost of any number of muffins. For example, if we want to know the cost of 15 muffins, we can simply multiply 15 by 2.85, giving us a total of 42.75.

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The residual if the room temperature was 25°C and the cupric chloride had an etching rate of 5 μm/min is equals to the -2 μm/min.

The residual for each observation in statistics is the difference between predicted values of y (dependent variable) and observed values of y. That is Residual= observed y value − predicted y.

Here, cupric chloride is used to etch circuit boards. The linear regression equation is, y = 2 + (1/5)x

where, x = temperature in °C

y = etching rate in μm/min

Observed value of etching rate of cupric chloride = 5 μm/min for 25°C

To determine the estimated or predicted value of etching rate of cupric chloride, we substite x = 25, in the above linear equation, y = 2 + (1/5)x

=> y = 2 + (1/5)× 25

=> y = 7

So, Predicted Value = 7 μm/min

Observed Value = 5 μm/min.

Residual = Observed Value - Predicted

= 5 - 7 = -2

Hence, required value is -2 μm/min.

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Complete question:

Calculating and interpreting residuals You might need: Calculator Alexander uses cupric chloride to etch circuit boards. He recorded the room temperature, in °C, and the etching rate, in μm/min of the cupric chloride. After plotting his results, Alexander noticed that the relationship between the two variables was fairly linear, so he used the data to calculate the following least squares regression equation for predicting the etching rate from the room temperature: y = 2 + 5/x, What is the residual if the room temperature was 25°C and the cupric chloride had an etching rate of 5 μm/min. ? Show Calculator

To determine the distance traveled by Katie at different marks, we can use the formula Distance = Rate × Time.

To determine how far Katie has traveled at each mark, we can use the formula:
Distance = Rate × Time

So, the elements in the range of the function that would be used to determine how far Katie has traveled at each mark are 384 miles, 416 miles, and 448 miles.

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Frankie's dad used 2/3 of the carton of eggs for their breakfast. Two equivalent fractions are 16/24 and 24/36.

Frankie's dad used 8 out of 12 eggs from a full carton. To express this as a fraction, we can write it as 8/12. However, this fraction can be simplified by dividing both the numerator and denominator by their greatest common factor, which in this case is 4. Thus, we get:

8/12 = (8 ÷ 4)/(12 ÷ 4) = 2/3

Alternatively, we can also express this fraction in different forms. One way to do this is by multiplying both the numerator and denominator by the same number. For example, if we multiply both by 2, we get:

8/12 = (8 × 2)/(12 × 2) = 16/24

Similarly, we can multiply by 3 to get:

8/12 = (8 × 3)/(12 × 3) = 24/36

Both of these fractions are equivalent to 2/3, and we can find infinitely many other equivalent fractions by multiplying both numerator and denominator by different numbers.

In summary, when Frankie's dad made scrambled eggs using 8 eggs from a full carton of 12 eggs, he used 2/3 of the carton. This fraction can be expressed in different forms that are equivalent to 2/3 by dividing both numerator and denominator by their greatest common factor or by multiplying both numerator and denominator by the same number.

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The answers to the questions (a) the proportion who graduated in the top 25 percent of their high school class will be 0.672 and (b) the ratio in favor of having graduated in the top 25 percent of their high school class is 2:3.

(a) For first-time college students, the proportion who graduated in the top 25 percent of their high school class (rounded to three decimal places) is 0.672.

(b) For transfer students, the ratio in favor of having graduated in the top 25 percent of their high school class is 0.67:1. It is said that 0.666666666666667 proportion graduated in the top 25 percent of their high school class. This can be simplified as follows:0.666666666666667=20/30=10/15=2/3. Therefore, the ratio in favor of having graduated in the top 25 percent of their high school class is 2:3.

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The relationship between distance and travel time. It is not excessively strong or weak. In other words, the rate of change in journey time is moderate and constant with respect to distance.

positive negative moderate weak linear nonlinear relationship between distance and travel time can be described as follows:•

           Positive• Linear• Moderate

   Explain as we move from point A to point B, the distance covered and the travel time it takes to get there are positively correlated. As the distance increases, the travel time required to reach the destination also increases, resulting in a positive correlation.

          The relationship between distance and travel time is linear because the rate at which distance is covered remains constant, resulting in a straight-line relationship on a graph. It means that if distance doubles, the travel time will also double, indicating a linear relationship.

Hence, the linear relationship is also referred to as a direct relationship. On a graph, the line that represents the relationship between distance and travel time is moderate. This implies that the slope of the line is neither too steep nor too gentle.

               Thus, it is neither too strong nor too weak. In other words, the rate of change in travel time is consistent as distance changes, making it moderate.

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The five-number summary for the given data is Min = 107, Q1 = 138, M = 175, Q3 = 190, and Max = 195.

In statistics, the five-number summary is a set of descriptive statistics that provide a summary of the distribution of a dataset. The five-number summary consists of the minimum value, the first quartile (Q1), the median (M), the third quartile (Q3), and the maximum value.

To find the five-number summary for the given data on the number of calories in a hot dog for each of 17 brands of meat hot dogs, we need to order the data from smallest to largest.

107 135 136 138 139 146 147 153 172 173 175 179 182 190 191 195

The minimum value is the smallest value in the dataset, which is 107.

The first quartile (Q1) is the value that is greater than or equal to 25% of the data and less than or equal to 75% of the data. To find Q1, we take the median of the lower half of the data:

Q1 = median(107, 135, 136, 138, 139, 146, 147, 153) = 138

The median (M) is the value that is in the middle of the dataset when the data is ordered from smallest to largest. For the given data, there are 17 values, so the median is the 9th value:

M = median(107, 135, 136, 138, 139, 146, 147, 153, 172, 173, 175, 179, 182, 190, 191, 195) = 175

The third quartile (Q3) is the value that is greater than or equal to 75% of the data and less than or equal to 25% of the data. To find Q3, we take the median of the upper half of the data:

Q3 = median(172, 173, 175, 179, 182, 190, 191, 195) = 190

The maximum value is the largest value in the dataset, which is 195.

Therefore, the five-number summary for the given data is Min = 107, Q1 = 138, M = 175, Q3 = 190, and Max = 195.

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