Answer:
c = 1/4
-1-1 = -2
-3-5 = -8
Step-by-step explanation:
Which equation represents a line that passes through (2,-) and has a slope of 3?
Oy-2 = 3(x + 2)
Oy - 3 = 2(x+)
Oy+ 1 = 3(x - 2)
Oy+ < = 2(x-3)
Help?
The equation of the line is y + 1 = 3(x - 2).
The correct option is (3).
What is an equation?Equation: A statement that two variable or integer expressions are equal. In essence, equations are questions, and the motivation for the development of mathematics has been the systematic search for the answers to these questions.
As per the given data:
The line passes through the point (2, -1)
slope of the given line is 3
By using the slope intercept form of line:
y = mx + c
where m is the slope
c is the y intercept
The line passes through the point (2, -1) so substituting the point in the equation also m = 3
y = 3x + c
-1 = 3(2) + c
c = -7
The equation of the line now can be written as:
y = 3x - 7
y + 1 = 3x - 7 + 1
y + 1 = 3(x - 2)
Hence, the equation of the line is y + 1 = 3(x - 2).
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Triangle D E F is reflected across D F to form triangle E G F. The lengths of sides E F and F G are congruent. To prove that ΔDEF ≅ ΔDGF by SAS, what additional information is needed? ∠DEF ≅ ∠ DGF ∠DFE ≅ ∠ DFG DE ≅ DG DG ≅ GF
Answer:
[tex]\angle DFE = \angle DFG[/tex]
Step-by-step explanation:
Given
See attachment for complete question
Required
What makes DEF and DGF congruent
We have:
[tex]EF = GF[/tex] --- this is indicated by the single line on both sides
Also:
[tex]DF = DF[/tex] --- both triangle share same side
For SAS to be true;
2 sides and 1 angle must be equal in either triangles
So far, we have:
[tex]EF = GF[/tex] ---- S
[tex]DF = DF[/tex] ---- S
The additional to complete the proof is:
[tex]\angle DFE = \angle DFG[/tex] ---- angle between the above sides
Reflection is a type of rigid transformation which requires the turning of an object, shape or figure about a reference point or line. Therefore, the needed additional information is ∠DFE ≅ ∠ DFG. Option B.
Reflection implies turning the given triangle DEF about its side DF, so as to produce an image with the same dimensions but different orientation.
The required proof by Side-Angle-Side (SAS) implies that the relations will be in respect of two of its sides and their included angle.
So that,
GF ≅ FE (given)
DF is the common side to triangles DEF and DFG.
DFG is the included side.
Thus;
∠DFE ≅ ∠ DFG (Side-Angle-Side postulate, SAS)
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x = 4y + 3, 2x + y = -3
System of Equations
Answer:
(- 1, - 1 )
Step-by-step explanation:
Given the 2 equations
x = 4y + 3 → (1)
2x + y = - 3 → (2)
Substitute x = 4y + 3 into (2)
2(4y + 3) + y = - 3 ← distribute parenthesis and simplify left side
8y + 6 + y = - 3
9y + 6 = - 3 ( subtract 6 from both sides )
9y = - 9 ( divide both sides by 9 )
y = - 1
Substitute y = - 1 into (1) for corresponding value of x
x = 4(- 1) + 3 = - 4 + 3 = - 1
solution is (- 1, - 1 )
A new school has x day students and y boarding students.
The fees for a day student are $600 a term.
The fees for a boarding student are $1200 a term.
The school needs at least $720 000 a term.
Show that this information can be written as x + 2y ≥ 1200.
Given:
The fees for a day student are $600 a term.
The fees for a boarding student are $1200 a term.
The school needs at least $720000 a term.
To show:
That the given information can be written as [tex]x + 2y\geq 1200[/tex].
Solution:
Let x be the number of day students and y be the number of boarding students.
The fees for a day student are [tex]\$600[/tex] a term.
So, the fees for [tex]x[/tex] day students are [tex]\$600x[/tex] a term.
The fees for a boarding student are [tex]\$1200[/tex] a term.
The fees for [tex]y[/tex] boarding student are [tex]\$1200y[/tex] a term.
Total fees for [tex]x[/tex] day students and [tex]y[/tex] boarding student is:
[tex]\text{Total fees}=600x+1200y[/tex]
The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.
[tex]600x+1200y\geq 720000[/tex]
[tex]600(x+2y)\geq 720000[/tex]
Divide both sides by 600.
[tex]\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}[/tex]
[tex]x+2y\geq 1200[/tex]
Hence proved.
What is the slope of the line whose equation is y-4=5/2(x-2)?
Answer:
[tex]slope = \frac{ - 1 - 4}{0 - 2} \\ = \frac{ - 5}{ - 2} \\ = { \tt{ \frac{5}{2} }}[/tex]
Which of the following represents the factorization of the polynomial function
graphed below? (Assume it has no constant factor.)
o
A. y - (x - 1)(x+3)
B. y - (x + 1)(x+3)
O
C. y = (x - 1)(x-3)
Answer:
c: y=(x-1)(x-3)
Step-by-step explanation:
**who can help me**
Answer:
.
Step-by-step explanation:
Divisor mayor común de 28 y 48
Answer:
mcd(28,48) = 4
Para encontrar el mcd de 28 y 48:
Los factores de 28 son 28, 14, 7, 4, 2, 1.
Los factores de 48 son 48, 24, 16, 12, 8, 6, 4, 3, 2, 1.
Los factores en común de 28 y 48 son 4, 2, 1, los cuales intersectan los dos conjuntos arriba.
En la intersección de los factores de 28 ∩ factores de 48 el elemento mayor es 4.
Por lo tanto, el máximo común divisor de 28 y 48 es 4.
If A =
[tex]if \: a \: = \binom{53}{24} \: and \: b = \binom{32}{10} then \: prove \: that |ab| = |a| . |b| [/tex]
and B = Prove that |AB| = |A| . |B|
Find the coordinates of the other endpoint when given midpoint (point M) and one of the endpoints (point P). P=(3,5) and M=(-2,0)
Answer:
About Points
S = (x,y) searched point (it will be in the third quadrant )
M = (-2,0) Midpoint | SP |
P = (3,5) one end of the segment | SP |
You have to draw Cartesian.
we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .
We use the information that | SM | = | MP |
Answer : S = (-7,-5)
Step-by-step explanation:
[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad \underline{Q}(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x+3}{2}~~,~~\cfrac{y+3}{2} \right)=\stackrel{M}{(-2,0)}\implies \begin{cases} \cfrac{x+3}{2}=-2\\[1em] x+3=-4\\ \boxed{x = -7}\\[-0.5em] \hrulefill\\ \cfrac{y+3}{2}=0\\[1em] y+3=0\\ \boxed{y=-3} \end{cases}[/tex]
What is 1,485÷ 0.09 answer please let me y
Answer:
16,500
Step-by-step explanation:
Just use a calculator-simple
What do you mean "let me y"?
Answer:
the answer is 16500 or sixteen thousand five hundred
Step-by-step explanation:
:)
Can someone please help me with this?
Can someone please be generous & help I’ve been struggling all night
Answer:
Slope-intercept
y = 3/4(x) - 7
Point slope
y -5= 3/4(x - 16)
Step-by-step explanation:
In slope-intercept
We have the general slope intercept as;
y = mx + b
where m is the slope and b is the y-intercept
in this case, m = 3/4 and b = -7
So we have;
y = 3/4(x) - 7
In point-slope
we have the general form as;
y-y1 = m(x-x1)
So what we have is as follows;
y -5= 3/4(x - 16)
Where we have (x1,y1) = (16,5)
Ah what is the length of XB? I really need to learn how to solve this
Answer:
5.28
Step-by-step explanation:
we use the formula
H²=B²+P²
and we will get the answer
branliest if it is helpful
Answer:
Angle BXY
using pythogoras theory which is
hyp*2= opp*2 +adj*2
hypothenus being the longest part of the angle BX=?
Step-by-step explanation:
hyp= 4.2*2+ 3.2*2
hyp*2 =17.64 + 10.24
hyp*2 = 27.88
hyp =√27.88
hyp=5.28...Ans
note *2...square
Randy walks his dog each morning. he walks 7/12 of a mile in 7 minutes how many miles does he walks in 1 minutes
Answer:
1/12 mile
Step-by-step explanation:
We can use a ratio to solve
7/12 miles x miles
---------------- = ---------------
7 minutes 1 minute
Using cross products
7 /12 * 1 = 7x
Divide each side by 7
7/12 * 1/7 = x
1/2 = x
[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]
⠀Randy walks his dog each morning. he walks 7/12 of a mile in 7 minutes ⠀⠀⠀[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]
⠀how many miles does he walks in 1 minutes⠀⠀⠀[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]
⠀
Randy walks 7/12 miles in 7 minutes
Sooo
He walks in one minutes is
7/12 miles in 7 minutes one minutes is [tex]\sf{\dfrac{\dfrac{7}{12}}{7} }[/tex] one minute =[tex]\sf{\dfrac{7}{12}×\dfrac{1}{7} }[/tex] one minute=[tex]\sf{\dfrac{1}{12} }[/tex][tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]
Hence,
he walks in 1 minutes is 1/12 miles.
A point P(3, k) is first transformed by E¹[0, 2] and then by E²[0,3/2] so that the final image is (9, 12), find the value of k.
Hello,
The first transform E1 is the homothetie of center (0,0) and ratio=2
The second transform E2 is the homothetie of center (0,0) and ratio=3/2
P=(3,k)
P'=E1(P)= E1((3,k))=(2*3,2*k)=(6,2k)
P''=E2(P')=E2(6,2k)=(3/2*6,3/2*2*k)=(9,3k)=(9,12)
==> 3k=12
k=4
Water is filling a swimming pool at a constant rate. After 4 hours, 2 inches of water have filled the pool. Write an equation that gives the amount of water, w, after t hours.
Answer:
Step-by-step explanation:
Inches per hour is the rate we are looking for here, which will then be the slope of the linear equation. Slope is the same thing as the rate of change. While this may not seem all that important right now, it's actually a HUGE concept in higher math, especially calculus!
If the pool is filling at a rate of 2 inches per every 4 hours, then by dividing, we get that the rate is 1 inch every 2 hours, which translates to a slope of 1/2. Creating an equation with this slope:
[tex]w=\frac{1}{2}t[/tex] Let's check it. We are told that after 4 hours there are 2 inches of water in the pool. That means if we plug in 4 for t and solve for w, we should get w = 2:
[tex]w=\frac{1}{2}(4)[/tex] and
w = 2. So we're good!
Jim is designing a seesaw for a children’s park. The seesaw should make an angle of 45 degrees with the ground, and the maximum height to which it should rise is 1 meter, as shown below: What is the maximum length of the seesaw? Choices: A) 1 meter B) 1.4 meters C) 2 meters D) 0.5 meters
Answer:
B) 1.4
Step-by-step explanation:
The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.
sin(B)=opp/hyp
The maximum length of the seesaw is 1.4 meters
Trigonometric ratio
Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.
Let h represent the length of the seesaw, hence using trigonometric ratio:
sin(45) = 1 / h
h = 1.4 meters
The maximum length of the seesaw is 1.4 meters
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Write the following phrase as an expression c less than 27
A C +27
B C -27
C c/27
D 27 - C
Answer:
(D) 27 - C
Step-by-step explanation:
The "less than" means we are subtracting C from 27, so 27 - C.
Hope it helps (●'◡'●)
plz help me with this
0
Step-by-step explanation:
maybe
Answer:
1) 0 miles
2) (0,0)
3) the cars speed is missing? 3 * speed would be this answer
4) (3, "3*speed" ) something like (3,30) if car was going 10mph
Step-by-step explanation:
the area of the rectangle is 48cm^2
show that x satisfies the equation x^2 + 7x -78 = 0
Answer:
No its doesn't satisfy the equation.
[tex]{ \bf{area = 2(l + w)}} \\ { \tt{48 = 2((x + 10) + (x - 3))}} \\ { \tt{24 = 2x + 7}} \\ 2x = 17 \\ x = 8.5 \\ \\ { \bf{in : \: {x}^{2} + 7x - 78 = 0 }} \\ x = 6 \: \: and \: \: - 13[/tex]
Given statements:
If a shape is a rhombus, then the diagonals are perpendicular.
A square is a rhombus.
What is a logical conclusion from the given statements?
OA. The sides of a square are perpendicular.
OB. The diagonals of a square are perpendicular.
OC. A rhombus is a square.
OD. The diagonals of a square are not perpendicular.
Answer:
B
Step-by-step explanation:
true or false? A circle could be circumscribed about the quadrilateral below.
Answer: the answer is true
Answer:
false
Step-by-step explanation:
here the opposite angle of quadrilateral aren't supplematary the circle have no chance to be circumscribed
PLEASE HELPP ILL GIVE 20 POINTS
Answer:
C=20
Step-by-step explanation:
Use the factors of the numbers to explain why
45 x 56 = 5 x 7 x 8 x 9
Answer:
45 x 56=
2520 and
5 x 7=35*8=280*9=2520
2520=2520
Hope This Helps!!!
The volume of a cone is 329.6 cubic inches, and the height is 5.4 inches. Which of the following is the closest to the radius r of the cone, in inches?
Answer:
329.6=1/3×16.97r
5.66r=329.6/÷5.66
r=58.23
Solve |x - 5| = 7 ......
Answer:
12,-2
Step-by-step explanation:
Find the value of x.
16.2
0.03
38.5
34.8
Hi there!
[tex]\large\boxed{x = 38.5}}[/tex]
To solve, we can use right triangle trig.
We are given the value of ∠A, and side "x" is its adjacent side. We are also given its opposite side, so:
tan (A) = O / A
tan (33) = 25 / x
Solve:
x · tan(33) = 25
x = 38.49 ≈ 38.5
PLEASE HELP DESPERATE
tan=sin/cos so tan=3/5/4/5=3/4
Answer:
SOH CAH TOA
3/5 opposite over hypotenuse
4/5 adjasent over hypotenuse
tan= opposite over adjasent which is 3/4
Step-by-step explanation:
identify the maximum and minimum values of the function y=10cosx in the interval [-2pie, 2pie]. Use your understanding of transformations, not your graphing calculator.
Answer:
3 x + 2 y + z/ x + y + z , x = 2 , y = 3 , z = 1
tan ( x ) , x = − π
cot ( 3 x ) , x = 2 π /3
Step-by-step explanation: