Answers
Related Questions
Which best describes the error in finding the area of the parallelogram?
15 meters was used for the height instead of 13 meters.
15 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
The product of 8 and 15 is not 120.
The product of 8 and 15 is not 120.
The formula to use should have been A=12bh instead of A=bh.
The formula to use should have been, cap A is equal to 1 half b h instead of cap A is equal to b h.
Question 2
Correct the error.
A=
=
m2
Answers
Answer:
104
Step-by-step explanation:
What is the constant of proportionality for the data in the table?
Answers
Answer:
30
Step-by-step explanation:
find the value of 4x-6y when x=3 and y= -2
Answers
Answer:
here the answer is 24
Step-by-step explanation:
answerrrrrerrr issss hereeeeeee
Answer:
0
Step-by-step explanation:
4 multiply by x(3) = 12
6 multiply by y(2) = 12
12 -12 =0
Please help xxxxxxxx
Answers
Answer:
a. [tex]\bold{45000\times \:10^7}[/tex]b. [tex]\bold{3500}[/tex]Step-by-step explanation:
a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]
[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]
[tex]=45000\times \:10^7[/tex]
b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]
[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]
[tex]\frac{10^5}{10^2} = 10^3[/tex]
[tex]\frac{7\times \:10^3}{2}[/tex]
[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]
[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]
[tex]\frac{2^3}{2}=2^2[/tex]
[tex]7\times \:2^2\times \:5^3=3500[/tex]
Solve for n.
9 =
n
2
+ 7
n =
Answers
Answer:
9/n-2=7
We move all terms to the left:
9/n-2-(7)=0
Domain of the equation: n!=0
n∈R
We add all the numbers together, and all the variables
9/n-9=0
We multiply all the terms by the denominator
-9*n+9=0
We add all the numbers together, and all the variables
-9n+9=0
We move all terms containing n to the left, all other terms to the right
-9n=-9
n=-9/-9
n=1
Answer:
n = 1
Step-by-step explanation:
2 x 1 = 2
2 + 7 = 9
Kindly solve and explain
Answers
[tex] \frac{{12}^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = \frac{(3 \times 4) ^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = \frac{ {3}^{ \frac{1}{2} } \times {4}^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = {3}^{ (\frac{1}{2} - \frac{3}{2}) } \times 2 ^{2 \times \frac{1}{2} } \\ = {3}^{ - \frac{2}{2} } \times 2 \\ = 3 ^{ - 1} \times 2 \\ = \frac{2}{3} [/tex]
Answer:[tex] \frac{2}{3} [/tex]
Hope it helps.
Do comment if you have any query.
Juan envasa 60 bombones en cajas iguales y otros 60 en otras cajas más pequeñas, con cinco bombones menos en cada una. ¿Cuántas cajas ha llenado, si de las pequeñas hay una más que de las grandes?
Answers
Juan llenó 3 cajas grandes y 4 cajas pequeñas.
En esta pregunta debemos derivar ecuaciones algebraicas a partir de la información dada en el enunciado:
Diferencia entre cajas grandes y cajas pequeñas
[tex]m - n = 1[/tex] (1)
Donde:
[tex]m[/tex] - Cantidad de cajas pequeñas.[tex]n[/tex] - Cantidad de cajas grandes.Diferencia entre la cantidad de bombones en una caja grande y la cantidad de bombones en una caja pequeña
[tex]x-y = 5[/tex] (2)
Donde:
[tex]x[/tex] - Cantidad de bombones en una caja grande.[tex]y[/tex] - Cantidad de bombones en una caja pequeña.Total de bombones en cajas grandes
[tex]x\cdot m = 60[/tex] (3)
Total de bombones en cajas pequeñas
[tex]y\cdot n = 60[/tex] (4)
By (3) and (4) in (2):
[tex]\frac{60}{m} - \frac{60}{n} = 5[/tex]
[tex]60\cdot n - 60\cdot m = 5\cdot m\cdot n[/tex] (5)
By (1):
[tex]m = 1 + n[/tex]
(1) in (5):
[tex]60\cdot n - 60\cdot (1+n) = 5\cdot (1+n)\cdot n[/tex]
[tex]60 = 5\cdot n +5\cdot n^{2}[/tex]
[tex]5\cdot n^{2}+5\cdot n -60 = 0[/tex]
[tex]n^{2}+n-12 = 0[/tex]
[tex](n+4)\cdot (n-3) = 0[/tex]
La única raíz que encaja con el enunciado es [tex]n = 3[/tex]. Por (1) tenemos que [tex]m = 4[/tex].
Juan llenó 3 cajas grandes y 4 cajas pequeñas.
Invitamos cordialmente a ver este problema sobre sistemas de ecuaciones: https://brainly.com/question/12149981
Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =
Answers
Step-by-step explanation:
f(x) = -3x - 8
f(-3) = -3(-3) - 8
f(-3) = 9 - 8
f(-3) = 1
1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84
Answers
Answer:
4x - 12 = 84
Step-by-step explanation:
The last answer choice is correct because when you cross-multiply:
[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]you get 4x - 12 = 84.
Therefore, the last option is correct.
Answer:
D would be the answer (4x-12=84)
Step-by-step explanation:
4/7=12/x-3
=>1/7=3/x-3
=>x-3=21
Multiplying both sides by 4
4(x-3)=4x21
=>4x-12=84
Hope this helped :)
write a peacewise function for the graph
please help me
Answers
Answer:
[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]
Step-by-step explanation:
If you look at the graph you see that:
before 0, the graph has same y as it has x, or y=x.
after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.
Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.
help me please asap
Answers
Answer:
5/6
Step-by-step explanation:
2/
3
: 4/
5
= 2/
3
· 5/
4
= 2 · 5/
3 · 4
= 10/
12
= 2 · 5/
2 · 6
= 5/
6
Hope you get it right
solve pls brainliest
Answers
Answer:
first put 2 in the numerator for the first blank and 2/9 in the second blank
Step-by-step explanation:
1/3 equals 3/9 and 3/9-1/9=2/9
Answer:
[tex]\frac{3}{9}[/tex]
Step-by-step explanation:
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Prove that ~
[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]
by using first principle of differentiation ~
Answers
Answer:
METHOD I:(by using the first principle of differentiation)
We have the "Limit definition of Derivatives":
[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]
Here, f(x) = sec x, f(x+h) = sec (x+h)
Substituting these in eqn. (i)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]
sec x can be written as 1/ cos(x)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]
Taking LCM[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]
By Cosines sum to product formula, i.e.,[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]
=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]
I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]
2/ h can also be written as 1/(h/ 2)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]
We have limₓ→₀ (sin x) / x = 1.[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]
h→0 means h/ 2→0Substituting 0 for h and h/ 2
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]
sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]
Hence, we got
[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
METHOD II:(by using other standard derivatives)
[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]
sec x can also be written as (cos x)⁻¹We have a standard derivative for variables in x raised to an exponent:
[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]
Therefore,
[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]
Any base with negative exponent is equal to its reciprocal with same positive exponent[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]
The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,
while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.
The inner function that remains is cos x whose derivative is -sin x.[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]
cos²x can also be written as (cos x).(cos x)[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]
sin x/ cos x is tan x, while 1/ cos x is sec x[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]
= sec x. tan x
Hence, Proved!help!! !,
is it right or not
Answers
Answer:
No
Step-by-step explanation:
The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number
Yep!!! Your correct
- Rectangle MNOP with vertices M(-7.-2).
M(-5, -1), 0(-27), and P(-4,-8):
90° counterclockwise about the origin
Answers
Answer:
M’ = (2, -7)
N’ = (1, -5)
O’ = (7, - 2)
P’ = (8,- 4)
Step-by-step explanation:
Swap the x and y coordinates and negate the y coordinate.
M(-7, -2) swap = (- - 2, -7) = (2,-7)
N(-5, - 1) swap = (- - 1, - 5) = (1, - 5)
O(-2,-7) swap = (- -7, -2) = (7, - 2)
P(-4,-8) swap = (- - 8, - 4) = (8, - 4)
Here is a right angled triangle:
Work out the area of the triangle.
Answers
Answer:
6
Step-by-step explanation:
Answer:
The area is 6 because i add it and the divide it
HELPPP OMGGG
10, 10, 18, 18, 10, 5, 12, 13
Find the median and mean number of hours for these students.
If necessary, round your answers to the nearest tenth.
Answers
5,10,12,13,18
12 is the number in the middle so it’s your median.
Mean:Add all the numbers and then divide your answer by how many numbers there are.
10+10+18+18+10+5+12+13=96
There are 8 numbers so 96 divided by 8=12
meaning your median is also 12
50 POINTS PLS HELP ME I'LL MARK BRAINLIEST
Find a polynomial of degree n that has only the given zeros. (There are many correct answers.)
x = −3, 8; n = 3
Thank you so much!!
Answers
Answer:
Step-by-step explanation:
Here we need to find a 3rd degree polynomial that has only two distinct zeros: {-3, 8}.
Focusing on the zero x = 8 and assuming that this 8 has a multiplicity of 2, we come up with the following polynomial in which the factor x - 8 shows up twice:
f(x) = a(x - 8)(x - 8)(x + 3), or f(x) = a(x - 8)^2(x + 3)
One such polynomial is thus
f(x) = a(x - 8)^2(x + 3), where 'a' is a constant coefficient. This polynomial has a double zero at x = 8 and a third zero at x = -3.
Step-by-step explanation:
The polynomial has degree 3 and two zeros: - 3 and 8.
Since it has degree 3 it should have 3 zero's.
Two possible scenarios
1. -3 has multiplicity of two:
a(x + 3)²(x - 8) - is the factored form of the polynomial where a is the constant2. 8 has multiplicity of two:
a(x + 3)(x - 8)² - is the factored form of the polynomialSolve for x x^2 + 6x + 1 = 0
Answers
Answer:
x = -.1715 ≈ - .172 or x = -5.83
Step-by-step explanation:
x² + 6x + 1 = 0
x² + 6x = -1
Complete the square Add to both sides (1/2 of the x-term, then square it.)
x² + 6x + 9 = -1 + 9
(x + 3)(x + 3) = 8
(x + 3)² = 8
[tex]\sqrt{(x + 3)^{2}[/tex] = [tex]\sqrt{8}[/tex]
x + 3 = ± [tex]\sqrt{8}[/tex]
x = -3 ± [tex]\sqrt{8}[/tex]
x = -3 + [tex]\sqrt{8}[/tex] or x = -3 - [tex]\sqrt{8}[/tex]
x = -.1715 ≈ - .172 or x = -5.83
find the value of x. only type the “number”
Answers
Step-by-step explanation:
5x - 6 = 3x + 2
5x - 3x = 2 + 6
2x = 8
x = 8/2
x = 4
Please need help 20 points
Answers
tte corresponding angle is angle 5
Hope this helped
You want to have $200,000 when you retire in 25 years. If you can earn 3% interest rate compounded continuously, how much would you need to deposit now into the account to reach your retirement goal?
Answers
9514 1404 393
Answer:
$94,473.31
Step-by-step explanation:
The multiplier in 25 years is ...
e^(rt) = e^(0.03·25) = e^0.75 ≈ 2.117
To have an account value of $200,000 in 25 years, you need to deposit now ...
$200,000/2.117 = $94,473.31
_____
When this amount is multiplied by 2.117, the result is 200,000.
If we convert 0.14 x10^3 to scientific notation, which direction should the
decimal move and how spaces should it move?
Answers
Answer:
Move it to the right by 3 spaces.
Step-by-step explanation:
10^3 is 1000
On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140
Write two Pythagorean triplets each having one of the numbers as 5.
Answers
Answer:
3, 4, 5 and 5, 12, 13
Step-by-step explanation:
The square of the largest side is equal to the sum of the squares of the other 2 sides.
5² = 3² + 4²
13² = 5² + 12²
The 2 triplets are (3, 4, 5 ) and (5, 12, 13)
Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12
Answers
Answer:
i think it is 49:9
Step-by-step explanation:
because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9
Answer:
28:12
Step-by-step explanation:
Multiply both 7 and 3 by 4 and you get the ratio 28:12.
Write in slope-intercept form an equation of the line that passes through the given points. (0,−1),(−8,−2)
Answers
0-(-8)/-1-(-2)= 8/1 =8
8=m
-2=2(-8)+b
-2=-16+b
+16 +16
14=b
Write 2.04 × 10 ⁴ as an ordinary number
Answers
Answer:
20400
Step-by-step explanation:
its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400
The diameter of the rear tire of a bike is 34 inches. In low gear, you need to rotate the pedals 3 times to make the rear tire rotate 360° all the way around. How far will you travel in low gear each time you rotate the pedals? (Hint: find the circumference of the tire, then divide it by the number of rotations needed of the pedals.) Round the answer to the nearest hundredth. *
PLEASE DO NOT PUT INAPPROPIATE CONTENT!!!
Answers
the perimeter of this triangle is 46cm find x
Answers
Answer:
the value of x is 12
......
A person in car, travelling at 90 kilometers per hour, takes 2 seconds to go past the building on the side of the road. Calculate the length of the building in meters help
Answers
Step-by-step explanation:
very simple thought experiment :
he is going 90 km/h (90 kilometers per hour), so, he moving 90 km in 1 hour.
how far is he going in just 2 seconds ?
so, we get two ratios.
90km/1 hour = 90,000 meter / 1 hour
x meter / 2 seconds
we need to bring both ratios (they are fractions) to the same dimension of the denominators, so that we can then bring them to the same denominator.
the first is dealing with an hour.
the second one with (2) seconds.
so, how many seconds are in 1 hour ?
60 seconds per minute, 60 minutes in the hour.
60×60 = 3600 seconds.
so, now we know, the first ratio is also
90,000 meter / 3600 seconds
now we need the factor to to multiply numerator and denominator with to bring 3600 down to 2.
3600 × f = 2
f = 2/3600 = 1/1800
now we get
90,000 / 3600 × (1/1800) / (1/1800) =
(90000 / 1800) / (3600 / 1800) = 50 / 2
so, 90km/h is the same speed as 50 meter / 2 seconds.
and therefore we know, the building was 50 meters long.
