Question 5 of 10
Which of these groups of values plugged into the TVM Solver of a graphing
calculator will return the amount of a 20-year loan with an APR of 19.2%,
compounded monthly, that is paidoff with monthly payments of $510?
A. N=20; 1%=19.2; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12;
PMT:END
B. N=240; 1%=19.2; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12;
PMT:END
C. N=240; 1%=1.6; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12;
PMT:END
O D. N=20; 1%=1.6; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12; PMT:END

Answers

Answer 1

Answer:

N=240;I%=5.6=-205000;PMT=;Fv=0;P/Y=12;C/Y=12;PMT:END

Step-by-step explanation:

A P E X

Answer 2

The group of values to be plugged into TVM solver is

N=240 ; I % = 19.2% , P = -205000 , PMT= -$510, Fv =0 , P/Y =12.

We have 20  year loan then the number of periods will be

N = 20 x 12

N= 240

and, the Monthly payment is $510 then

PMT = - 510

and, Interest = 19.2%

and, PV = - 205, 000

Thus, N=240 ; I % = 19.2% , P = -205000 , PMT= -$510, Fv =0 , P/Y =12.

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Related Questions

URGENT!!!!!! 15 POINTDS

Answers

Answer:

Option C

Step-by-step explanation:

thankful that there are graphing tools. see screenshot

I’m pretty sure it’s c

Select the correct answer.
A basketball team played 15 games and won 80% of them. If the team expects to play 30 games in by all, how many more games must it win to
finish the season with a 90% winning percentage?
A.12
B.14
C.15
D.27

Answers

The answer is d 27 games
Yes, to confirm the answer is option D, 27. I got the same calculations as well. Hope this helps!

Russell is doing some research before buying his first house. He is looking at two different areas of the city, and he wants to know if there is a significant difference between the mean prices of homes in the two areas. For the 33 homes he samples in the first area, the mean home price is $168,300. Public records indicate that home prices in the first area have a population standard deviation of $37,825. For the 32 homes he samples in the second area, the mean home price is $181,900. Again, public records show that home prices in the second area have a population standard deviation of $25,070. Let Population 1 be homes in the first area and Population 2 be homes in the second area. Construct a 95% confidence interval for the true difference between the mean home prices in the two areas.

Answers

Answer:

The 95% confidence interval for the true difference between the mean home prices in the two areas is (-$29156.52, $1956.52).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

First area:

33 homes, mean of $168,300, standard deviation of $37,825. Thus:

[tex]\mu_1 = 168300[/tex]

[tex]s_1 = \frac{37825}{\sqrt{33}} = 6584.5[/tex]

Second area:

33 homes, mean of $181,900, standard deviation of $25,070. Thus:

[tex]\mu_2 = 1819000[/tex]

[tex]s_2 = \frac{25070}{\sqrt{32}} = 4431.8[/tex]

Distribution of the difference:

[tex]\mu = \mu_1 - \mu_2 = 168300 - 181900 = -13600[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqt{6584.5^2 + 4431.8^2} = 7937[/tex]

Confidence interval:

[tex]\mu \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower bound of the interval is:

[tex]\mu - zs = -13600 - 1.96*7937 = -29156.52 [/tex]

The upper bound of the interval is:

[tex]\mu + zs = -13600 + 1.96*7937 = 1956.52[/tex]

The 95% confidence interval for the true difference between the mean home prices in the two areas is (-$29156.52, $1956.52).

Domain and range problem Help

Answers

Answer:

Range y≤-1

Domain all reals

Step-by-step explanation:

The range is the output values (y)

Y is less than or equal to -1

y≤-1

The domain is the values that the input can take

the arrows on the ends of the graph tells us x can take all real numbers

The range is the span of y-values. What is the smallest possible y-value and what is the largest possible y-value?

For this problem, the y-values start at -1 and decrease infinitely. Therefore, the range is y <= -1.

The domain is the span of x-values. What is the smallest possible x-value and what is the largest possible x-value?

For this problem, the parabola will keep expanding horizontally (or to the left and right). Therefore, the range is all real numbers.

Hope this helps!

At Joe's Restaurant, 80 percent of the diners are new customers (N), while 20 percent are returning customers (R). Fifty percent of the new customers pay by credit card, compared with 70 percent of the regular customers. If a customer pays by credit card, what is the probability that the customer is a new customer?

Answers

Answer:

0.7407 = 74.07% probability that the customer is a new customer.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Pays by credit card

Event B: New customer.

Probability of a customer paying by credit card:

50% of 80%(new customers).

70% of 20%(regular customers). So

[tex]P(A) = 0.5*0.8 + 0.7*0.2 = 0.54[/tex]

Probability of a customer paying by credit card and being a new customer:

50% of 80%, so:

[tex]P(A \cap B) = 0.5*0.8 = 0.4[/tex]

What is the probability that the customer is a new customer?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.54} = 0.7407[/tex]

0.7407 = 74.07% probability that the customer is a new customer.

Help me! Thanks! Show work too! Please!

Answers

Answer:

(2, 79) (12, 24)

24-79/12-2=-55/10

m=-0.55

24=-6,6+b

30.6=b

y=-0.55x+30.6

Step-by-step explanation:

you multiply

using the equation to represent your answer

Complete the input-output table:

x 3x + 7

0
4
8
14

Answers

Step-by-step explanation:

When x = 0,

3x + 7

= 3 ( 0 ) + 7

= 0 + 7

= 7

When x = 4,

3x + 7

= 3 ( 4 ) + 7

= 12 + 7

= 19

When x = 8,

3x + 7

= 3 ( 8 ) + 7

= 24 + 7

= 31

When x = 14,

3x + 14

= 3 ( 14 ) + 14

= 14 ( 3 + 1 )

= 14 ( 4 )

= 56

HELP PLEASE BE CORRECT

Answers

Answer:

12

Step-by-step explanation:

Scale factor of 4

CD = 3

3 · 4 = 12

Length of C'D' is 12 units

Answer:

12 units

Step-by-step explanation:

The original segment CD = 3 units

Scale factor is 4.

3 x 4 = 12

QUESTION 20
The patient's weight is 245 lbs. If the patient loses 1 kg every week for 5 weeks:
a. How much will the patient weight in pounds?
b. How much will the patient weight in kilograms?

Answers

.Answer:

The answer is below

Step-by-step explanation:

The patient loses 1 kg every week for 5 weeks.

1 kg = 2.2 lbs

Therefore the patient loses 2.2 lbs every week for 5 weeks.

a) The weight of the patient after 5 weeks = 245 lbs. - (5 weeks)(2.2 lbs per week)

The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

b) The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

1 kg = 2.2 lbs.

234 lbs. = 234 lbs. * 1 kg per 2.2 lbs. = 106.36 kg

6. 2(h-8)- h= h - 16
a.8
b. -8
c. infinitely many solutions
d. no solution

i need the answer and a explanation of how to get my answer i need soon pls hurry

Answers

Answer:

c. infinitely many solutions

General Formulas and Concepts:

Pre-Algebra

Distributive Properties

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

2(h - 8) - h = h - 16

Step 2: Solve for h

[Distributive Property] Distribute 2:                                                                 2h - 16 - h = h - 16Combine like terms:                                                                                         h - 16 = h - 16[Addition Property of Equality] Add 16 on both sides:                                   h = h

Hello from  MrBillDoesMath!

Answer:    c  (infinitely many solutions)

Steps:

1) Simplify  the original  equation

       2(h-8)- h= h - 16

2.As 2 (h-8) = 2h- 16,  the equation in 1) is equivalent to  

      (2h-16) -h  = h - 16

 or

      (2h-h) - 16 = h - 16

or

      h - 16 = h -16

which is true for all values of h.

Regards,  MrB

Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

PLEASE HELPPPPPPP NEED ASAPPPPPPP WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWERRRRRR

Answers

Answer:

Here we need to solve:

[tex]\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }[/tex]

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

[tex]\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}[/tex]

Now we can multiply both sides by (y - 3)

[tex](y - 3)*(\frac{2}{y - 3} + \frac{6}{y + 3 }) = 3*(y + 3)\\2 + 6*\frac{y -3}{y + 3} = 3*(y + 3)[/tex]

Now we can multiply both sides by (y + 3)

[tex](2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)[/tex]

[tex]2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45[/tex]

First, let's see the determinant of that quadratic equation:

[tex]D = (-2)^2 - 4*3*45 = -536[/tex]

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

Answer:

y=15

Step-by-step explanation:

2. Express the number 1750 as a product of prime factors of the form:
p * qr * s

Answers

9514 1404 393

Answer:

  1750 = 2 · 5³ · 7

Step-by-step explanation:

It is often helpful to start with divisibility rules when finding prime factors of a small composite number.

The least-significant digit is even, so we know 2 is a factor.

  1750/2 = 875

The least significant digit is 5, so we know 5 is a factor.

  875/5 = 175

  175/5 = 35

  35/5 = 7

7 is a prime number, so we're done.

The factorization is ...

  1750 = 2 · 5³ · 7

PLEASE HELP

Identify the 15th term of the arithmetic sequence in which a. = 10 and ao = 20.

Answers

Answer:

The 15th term is 160

Step-by-step explanation:

The details are not clear. So, I will make the following assumptions

[tex]d = 10[/tex] ---- common difference

[tex]a_1 = 20[/tex] ---- first term

Required

The 15th term

This is calculated as:

[tex]a_{n} = a + (n - 1) * d[/tex]

Substitute 15 for n

[tex]a_{15} = a + (15 - 1) * d[/tex]

[tex]a_{15} = a + 14 * d[/tex]

Substitute values for d and a

[tex]a_{15} = 20 + 14 * 10[/tex]

[tex]a_{15} = 20 + 140[/tex]

[tex]a_{15} = 160[/tex]

Find the numerical value of the area under the normal curve given the following information:

NOT between -0.79 and 0.99 standard deviations

enter your answer as a decimal (NOT percentage) and lead with a zero...for example: 0.1234

Answers

Answer:

0.37585

once again just look up the numbers on the Z table..

in this case you want the values to the LEFT of z=-.79 and to the RIGHT of z=.99

Step-by-step explanation:

-0.79 (L)0.21476  

0.99 (R)0.16109

0.37585

The numerical value of the area under the normal curve is 0.3759 if the standard deviation value is NOT between -0.79 and 0.99.

What is a normal distribution?

It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.

We have given:

The standard deviation value = NOT between -0.79 and 0.99

= P(not between - 0.79 and 0.99)

= P( x <  -0.79) + P(x > 0.99)

= 1 - P( x < 0.79) + 1 - P(x < 0.99)

From the Z-table:

P( x < 0.79) = 0.7852

P(x < 0.99) = 0.8389

= 2 - 0.7852 - 0.8389

= 2 - 1.6241

= 0.3759

Thus, the numerical value of the area under the normal curve is 0.3759 if the standard deviation value is NOT between -0.79 and 0.99.

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SOMEONE HELP PLEASE ASAP PLES DONT LEAVE UR ANSWER AS AN IMAGE SOMETIMES I CANT SEE IMAGES. THANK YOU VERY MUCH! WILL MARK BRAINLIEST :)))

Answers

9514 1404 393

Answer:

  x = -2/5 or -1

Step-by-step explanation:

The last two terms of the expression on the left can be factored also.

  (5x+2)² +3(5x+2) = 0

And the common factor can be factored out:

  (5x+2)(5x +2+3) = 0

  5(5x +2)(x +1) = 0

Solutions to the equation make the factors zero:

  5x +2 = 0   ⇒   x = -2/5

  x +1 = 0   ⇒   x = -1

The values of x that are solutions to the equation are x = -2/5 and x = -1.

_____

Once you realize that (5x+2) is a factor, you know one solution is x = -2/5. The rest is just fluff to find the second solution. It is not required in order to answer the question.

15. What is the solution to k+(-12) = 42? (1 point)
k=-54
k=-30
k= 30
k=54

Answers

Answer:

k = 54

Step-by-step explanation:

k + (-12) = 42

Remove parenthesis and addition sign

k - 12 = 42

Add 12 to both sides

K = 54

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

k+(-12)=42

k-12=42

k=42+12

k=54

A certain manufacturing process yields electrical fuses of which, in the long run
15% are defective. Find the probability that in a random sample of size n=10, fuses
selected from this process, there will be
(i) No defective fuse
(ii) At least one defective fuse
(iii) Exactly two defective fuses
(iv) At most one defective fuse

Answers

Answer:

i) 0.1969 = 19.69% probability that there will be no defective fuse.

ii) 0.8031 = 80.31% probability that there will be at least one defective fuse.

iii) 0.2759 = 27.59% probability that there will be exactly two defective fuses.

iv) 0.5443 = 54.43% probability that there will be at most one defective fuse.

Step-by-step explanation:

For each fuse, there are only two possible outcomes. Either it is defective, or it is not. The probability of a fuse being defective is independent of any other fuse, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

15% are defective.

This means that [tex]p = 0.15[/tex]

We also have:

[tex]n = 10[/tex]

(i) No defective fuse

This is [tex]P(X = 0)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.15)^{0}.(0.85)^{10} = 0.1969[/tex]

0.1969 = 19.69% probability that there will be no defective fuse.

(ii) At least one defective fuse

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

We already have P(X = 0) = 0.1969, so:

[tex]P(X \geq 1) = 1 - 0.1969 = 0.8031[/tex]

0.8031 = 80.31% probability that there will be at least one defective fuse.

(iii) Exactly two defective fuses

This is P(X = 2). So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{10,2}.(0.15)^{2}.(0.85)^{8} = 0.2759[/tex]

0.2759 = 27.59% probability that there will be exactly two defective fuses.

(iv) At most one defective fuse

This is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.15)^{0}.(0.85)^{10} = 0.1969[/tex]

[tex]P(X = 1) = C_{10,1}.(0.15)^{1}.(0.85)^{9} = 0.3474[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.1969 + 0.3474 = 0.5443[/tex]

0.5443 = 54.43% probability that there will be at most one defective fuse.

Look at the figure below: an image of a right triangle is shown with an angle labeled y degrees If sin y° = s divided by 8 and tan y° = s divided by t, what is the value of cos y°?
cos y° = 8s
cos y° = 8t
cos y°= t / 8
cos y°=8 / t

Answers

Answer:

Cos y = t / 8

Step-by-step explanation:

Using the hints given in the question, the omitted tribagke will look like the triangle attached on the picture ;

From trigonometry :

Sin y = opposite / hypotenus

Sin y = s / 8

Opposite side = s ; hypotenus = 8

Tan y = opposite / Adjacent

Tan y = s / t

Adjacent side = t

Then ;

Cos y = Adjacent / hypotenus

Hence,

Cos y = t / 8

Answer:

the answer is :

cos y°= t / 8

Step-by-step explanation:

I promise! I got this right, and.....you are welcome.

what's a divisor a dividend and a quotient

Answers

Quotient is the correct answer

A survey sampled men and women workers and asked if they expected to get a raise or promotion this year. Suppose the survey sampled 200 men and 200 women. If 98 of the men replied Yes and 72 of the women replied Yes, are the results statistically significant so that you can conclude a greater proportion of men expect to get a raise or a promotion this year?

a. State the hypothesis test in terms of the population proportion of men and the population proportion of women.
b. What is the sample proportion for men? For women?
c. Use α= 0.01 level of significance. What is the p-value and what is your conclusion?

Answers

Answer:

a)

The null hypothesis is: [tex]H_0: p_M - p_W = 0[/tex]

The alternative hypothesis is: [tex]H_1: p_M - p_W > 0[/tex]

b) For men is of 0.49 and for women is of 0.36.

c) The p-value of the test is 0.0039 < 0.01, which means that the results are statistically significant so that you can conclude a greater proportion of men expect to get a raise or a promotion this year.

Step-by-step explanation:

Before solving this question, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Men:

98 out of 200, so:

[tex]p_M = \frac{98}{200} = 0.49[/tex]

[tex]s_M = \sqrt{\frac{0.49*0.51}{200}} = 0.0353[/tex]

Women:

72 out of 200, so:

[tex]p_W = \frac{72}{200} = 0.36[/tex]

[tex]s_W = \sqrt{\frac{0.36*0.64}{200}} = 0.0339[/tex]

a. State the hypothesis test in terms of the population proportion of men and the population proportion of women.

At the null hypothesis, we test if the proportion are similar, that is, if the subtraction of the proportions is 0, so:

[tex]H_0: p_M - p_W = 0[/tex]

At the alternative hypothesis, we test if the proportion of men is greater, that is, the subtraction is greater than 0, so:

[tex]H_1: p_M - p_W > 0[/tex]

b. What is the sample proportion for men? For women?

For men is of 0.49 and for women is of 0.36.

c. Use α= 0.01 level of significance. What is the p-value and what is your conclusion?

From the sample, we have that:

[tex]X = p_M - p_W = 0.49 - 0.36 = 0.13[/tex]

[tex]s = \sqrt{s_M^2+s_W^2} = \sqrt{0.0353^2 + 0.0339^2} = 0.0489[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error, so:

[tex]z = \frac{0.13 - 0}{0.0489}[/tex]

[tex]z = 2.66[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a difference above 0.13, which is the p-value of z = 2.66.

Looking at the z-table, z = 2.66 has a p-value of 0.9961.

1 - 0.9961 = 0.0039.

The p-value of the test is 0.0039 < 0.01, which means that the results are statistically significant so that you can conclude a greater proportion of men expect to get a raise or a promotion this year.

Hi please somebody help me with this equation with explanation thank you

Answers

Answer:

[tex]{ \tt{ \frac{1}{24} m - \frac{2}{3} = \frac{3}{4} }} \\ \\ { \tt{ \frac{1}{24} m = \frac{17}{12} }} \\ m = 34[/tex]

Step 1: Find a common denominator

---The common denominator here is 24. So, we need to transform all of the fractions to have a denominator of 24.

1/24m - 16/24 = 18/24

Step 2: Solve

1/24m - 16/24 = 18/24

1/24m = 34/24

m = 34/24 x 24/1

m = 34

Hope this helps!

A certain species of virulent bacteria is being grown in a culture. It is observed that the rate of growth of the bacterial population is proportional to the number present. If there were 3000 bacteria in the initial polulation and the number doubled after the first 60 minutes, how many bacteria will be present after 2 hours

Answers

Answer:

12000 bacteria

Step-by-step explanation:

Recall that

60 minutes = 1 hour

Given that the rate of growth of the bacterial population is proportional to the number present.

If there were 3000 bacteria in the initial population and the number doubled after the first 60 minutes

Then after 60 minutes, the number of bacteria present would be

= 3000 * 2

= 6000

In another 60 minutes, the number would have doubled again, thus the number present then would be

= 6000 * 2

= 12000

Hence after 120 minutes, the number of bacteria present is 12000. 120 minutes is same as 2 hours

What percentage is

£7 of £20?

28kg of 40kg?

plz answer both questions ​

Answers

[tex]\huge❥︎\underbrace\mathfrak\red {SoLuTiOn}✈︎[/tex]

1)

[tex] £7 \: of \: £20 \\ \\ \fbox{considering as x} \\ \\ x\%of \: 20 = 7 \\ \\ x\% = \frac{7}{20} \times 100 \\ \\ x\% = \frac{7}{ \cancel{20}} \times \cancel{ 100} \\ \\ x\% = 7 \times 5 \\ \\ x\% = 35\%[/tex]

2)

[tex]28 \: kg \: of \: 40 \: kg \\ \\ \fbox{considering as x} \\ \\ x\% 40 = 28 \\ \\ x\% = \frac{28}{40} \times 100 \\ \\ x\% = \cancel \frac{28}{4 \cancel0} \times 10 \cancel0 \\ \\ x\% = 7 \times 10 \\ \\ x\% = 70\%[/tex]

Hope This Helps You ❤️


I don’t know what this is I took a picture of it here.

Answers

Function a: exponential function
Function b: linear function
Function c: exponential function

the angle between two lines is 60 degree. if the slope of one of them is 1. find the slope of other line​

Answers

Answer:

-3.73

Step-by-step explanation:

solution:

Given:

Angle between two lines=60⁰

slope of first line=1

Or, tanA=1

Or, A= tan inverse (1)

so, A=45⁰

so, angle of inclination of first line=45⁰

Now,

angle of inclination of second line= A+ 60⁰

= 45⁰+60⁰

=105⁰

so, slope of second line = tan105.

= -3.73

7/18 - 1/3 , 1/2 - 1/5 - 1/10 and 3 1/2 - 2 5/9 please help thank you ​

Answers

1/18, 1/5,& 17/18

Hope these help!

A survey is created to measure dietary habits. The survey asks questions about each meal and snack consumed for each day of the week. The survey seems like a good representation of measuring dietary habits. This survey would be considered to have high ______ validity.

Answers

Answer:

Face validity

Step-by-step explanation:

In quantitative research in mathematics, we have four major types of validity namely;

- Content Validity

- Construct validity

- Criterion validity

- Face validity.

Now;

> Construct validity seeks to find out if the tool used in measurement is a true representation of what is really going to be measured.

> Content Validity seeks to find out whether a test covers every part of a particular subject being tested.

> Face validity seeks to find out how true a test is by looking at it on the surface.

> Criterion validity seeks to find out the relationship of a particular test to that of another test.

Now, in this question, we are told that The survey seems like a good representation of measuring dietary habits after just asking questions about each meal and snack they consumed for the week. Thus, it is a face validity because it just appears true on the surface to be a good representation but we don't know if it is effective until we go deep like content validity

Use the figure to find y.

Answers

Tanθ =sin /cos

tan θ = 5/2 / y

tan (30°) = 5/2 /y

[tex]y = \frac{5 \sqrt{3} }{2} [/tex]

y=4.33

The gross domestic product (GDP) of the United States is defined as

Answers

The gross domestic product (GDP) of the United States is defined as the market value of all final goods and services produced within the United States in a given period of time.

Answer:

the market value of all final goods and services produced within the United States in a given period of time.

a plane can fly 450 miles in the same time it takes a car to go 150 miles. if the car travels 100 mph slower than the plane, find the speed (in mph) of the plane​

Answers

Answer:

The speed of the plane is 150 miles per hour, while the speed of the car is 50 miles per hour.

Step-by-step explanation:

Since a plane can fly 450 miles in the same time it takes a car to go 150 miles, if the car travels 100 mph slower than the plane, to find the speed (in mph) of the plane the following calculation must be performed:

450 to 150 is equal to 3: 1, that is, the plane travels three times the distance of the car.

Therefore, since 100/2 x 3 equals 150, the speed of the plane is 150 miles per hour, while the speed of the car is 50 miles per hour.

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