Question 5 of 10
In the diagram below, 30 is parallel to XY. What is the value of x?
769

Question 5 Of 10In The Diagram Below, 30 Is Parallel To XY. What Is The Value Of X?769

Answers

Answer 1

Answer:

D

Step-by-step explanation:

a and 76° are corresponding angles and are congruent , then

x = 76° → D


Related Questions

The price of a technology stock has risen to $9.66 today. Yesterday's price was $9.59. Find the percentage increase. Round your answer to the nearest tenth of a percent.

Answers

Answer:

% increase = 100 x [(new price) - (original price)] / (original price)] = 100 (9.67 - 9.56) / 9.56

% increase ≅ 1.2% (to the nearest tenth)

Find x in circle O. Figure is not drawn to scale. HURRY PLEASE

Answers

Answer:

B. 23,5

Step-by-step explanation:

Given that y is directly proportional to x. If y = 30 and x= 5, write an equation that connects y with x.

Answers

Answer: y = 6x

Step-by-step explanation:

Since this is a direct proportion, we will introduce the constant of proportionality here and this will be:

y = kx

Since y = 30 and x= 5,

30 = 5 × k

30 = 5k

k = 30/5

k = 6

Therefore, the equation that connects y to x will be:

y = kx

y = 6x

The equation that connects y to x is y = 6x.

75 mm
a
60 mm
What is the length of the missing leg?

Answers

Answer:

a = 45 millimeters

Step-by-step explanation:

In order to solve this, we need to know that for right-angled triangles the following is true:

[tex]c^{2} = a^{2} + b^{2}[/tex] (where c is the hypotenuse and "a" and "b" are the legs)

From the formula above we can conlude that...

[tex]a = \sqrt{c^{2} - b^{2} }[/tex]

Now we just substitute the variable that we know and get that...

[tex]a = \sqrt{c^{2} - b^{2} }\\a = \sqrt{75^{2} - 60^{2} } \\a = \sqrt{5,625 - 3600} \\a = \sqrt{2025} \\a = 45[/tex]

Therefore a = 45millimeters.

plz any one here to follow me plz tellme any one ?​

Answers

I’ll follow you, but on what?



ig?
No hjjjjghk punctuating

. If XZ = 7x + 1 and PZ = 4x − 1, what is XP? 11
12 19 22

Answers

Answer:

XP = 11

Step-by-step explanation:

Given that XZ = 7x + 1 and PZ = 4x − 1

From the diagram, XZ = 2PZ

7x + 1 = 2(4x-1)

7x+1 = 8x - 2

7x - 8x = -2 -1

-x = -3

x = 3

Since XP = PZ

XP = 4x - 1

XP = 4(3) - 1

XP = 12-1

XP = 11

The points A, B, C and D lie on a circle centre O.
Angle AOB = 90° angle COD= 50° and angle BCD= 1239
The line DT is a tangent to the circle at D.
Find
(a) angle OCD

Answers

A I think is the answer

The measure of angle OCD from the given figure is 58°.

Given that, the points A, B, C and D lie on a circle Centre O.

What is the circle?

A circle is a two-dimensional figure formed by a set of points that are at a constant or at a fixed distance (radius) from a fixed point (center) on the plane. The fixed point is called the origin or center of the circle and the fixed distance of the points from the origin is called the radius.

Here, OC and OB are radius of a circle, then BOC is isosceles triangle

Now, ∠BOC+∠OBC+∠OCB=180°

50°+∠OBC+∠OBC=180°

⇒ 2∠OBC=130°

⇒ ∠OBC=65°

Here, ∠OCD=∠BCD-65°

⇒ x=123-65=58°

Hence, the measure of angle OCD from the given figure is 58°.

To learn more about the circle visit:

https://brainly.com/question/11833983.

#SPJ2

Brenya Estate produces a high quality tea branded Super by blending three types of tea coded A, B and C in the ration 1: 5:1. Originally Type A tea costs GHS 1,600 type B costs GHS 800 and type C costs GHS 1,700 per kg to produce. Brenya Tea Estate packs Super tea in packets of 825g each. Blending and packing costs are 40 per kg. Determine the production cost for a packet of Super tea,

Answers

Solution :

Cost of 1 kg super tea mixture

[tex]$=\frac{1(1600)+5(800)+1(1700)}{1+5+1}$[/tex]

[tex]$=\frac{1600+4000+1700}{7}$[/tex]

[tex]$=\frac{7300}{7}$[/tex]

= 1042.8

≈ 1043

Include of cost blending and packaging.

So, cost of 1 kg is 1043 + 40 = 1083

Cost of packaging of 825 gram super tea = [tex]$\frac{825}{1000} \times 1083$[/tex]

                                                                     = 893.47

Someone pls pls pls solve this!!!!!!! And pls explain how u solved it. I need this due rn ASAP!!!

Answers

35°..

can also be 145° but not in this case since the angle is less than 90°

Find the volume of the composite figure

Answers

Answer:

540m^3

Step-by-step explanation:

find volume of top + volume of bottom

bottom: l*w*h = 16*5*4 =300 m^3

top = area of side times width = area of triangle times width

area of triangle is 1/2*b*h = (6*16)/2 = 48 m^2

multiply by width = 48*5=240m^3

add top and bottom = 300+240=540m^3

a.)Would the equation be sine or cosine if the situation was someone being on a roller coaster that starts 15 ft above ground level, goes up to 45 feet above ground level, and goes down 20 feet under ground level?

b.) What would the equation be? ford monition and the terminal is in the third quadrant​

Answers

Yes ma’am yes I do have it on the back of the truck

Help me please this is due today and it’s late help help!!

Answers

Step-by-step explanation:

I know A is one because positives and negitives are oppisite but i dont know if there are more

You have $9 and earn $0.75 for each cup of orange juice you sell. Write an equation that represents the total amount $A​ (in dollars) you have after selling $j​ cups of orange juice. $A

Answers

Answer:

I believe it's   A = 0.75j + 9

Step-by-step explanation:

If x or j is the amount of cups of OJ you sell, and you earn $0.75 per cup.

0.75x

The b = 9 which adds to the total amount of money you have

0.75x+9

A is the total money you earn after you sell j cups.

I hope this helps!

Five hundred fifteen billion, eight hundred fifty-seven million, five hundred forty-nine thousand, forty-eight

Answers

Answer:

515,857,549,048

Step-by-step explanation:

I guess you are to write in numerals

Five hundred fifteen billion = 515,000,000,000

eight hundred fifty-seven million = 857,000,000

five hundred forty-nine thousand = 549,000

forty-eight = 48

Total = 515,000,000,000 + 857,000,000 + 549,000 + 48

= 515,857,549,048

Therefore,

Five hundred fifteen billion, eight hundred fifty-seven million, five hundred forty-nine thousand, forty-eight = 515,857,549,048

Jen's class 10 girls and 15 boys. The ratio of girls to boys in Ed's class is the same as the ratio of girls to boys in Jen's class. There are 24 boys in Ed's class. How many girls are in Ed's class?

Answers

Answer:

16

Step-by-step explanation:

Jen's class: 10 girls, 15 boys

ratio of girls to boys = 10:15 = 2:3 = 2x:3x

Ed's class

number of boys = 24

ratio of girls to boys = 2x:3x

3x = 24

x = 8

2x = 2(8) = 16

Answer: 16

Answer:

16

Step-by-step explanation:

Please help I’ll give brainliest

Answers

Answer:

- a + 18b

Step-by-step explanation:

2(a + 6b) - 3(a - 2b)

= 2a + 12b - 3a + 6b

= 2a - 3a + 12b + 6b

= - a + 18b (Ans)

Answer:

-a + 18b

Step-by-step explanation:

2(a + 6b) - 3(a - 2b)

Distribute the 2

2a + 12b - 3(a - 2b)

Distribute the 3

2a + 12b - 3a + 6b

Combine like terms

-a + 18b

If Albert owns x model airplanes and Maxim owns x + 13 model airplanes, then Albert and Maxim own___ model airplanes together. Albert owns ___ less model airplanes than Maxim.

Answers

Answer:

2x + 13

13

Step-by-step explanation:

Albert and Maxim own

x + (x + 13) = 2x + 13 model airplanes together

Albert owns

(x + 13) - x = 13 less model airplanes than Maxim.

Answer:

They own 2x+13 model airplanes together

Albert owns 13 less model airplanes than Maxim

A ride-share company has a fee that includes a fixed cost and a cost that depends on both the time spent travelling, in minutes, and the distance travelled, in kilometres. The fixed cost of a ride is $2.55 Judy's ride costs $16.75 and took eight minutes. The distance travelled was 10 km. Pat's ride cost $30.35 and took 20 minutes. The distance travelled was 18 km. Roy's ride took 10 minutes. The distance travelled was 15 km. Find the cost of Roy's ride.

Answers

Answer:

the cost of Roy's ride is $23.05

Step-by-step explanation:

According to the Question,

Let, Cost of per minute charge is 'x' & Cost Of Per Kilometre charge is y .

Given, A ride-share company has a fee of the fixed cost of a ride is $2.55 .And, The Total cost of the Ride depends on both the time spent on travelling(in minutes), and the distance travelled(in kilometres) .

⇒ Judy's ride costs $16.75 . but the actual cost after deducting the fixed charge is 16.75-2.55 = $14.20, took 8 minutes & The distance travelled was 10 km. Thus, the equation for the journey is 8x+10y=14.20 ⇒ Equ. 1

⇒ Pat's ride costs $30.35 . but the actual cost after deducting the fixed charge is 30.35-2.55 = $27.80, took 20 minutes & The distance travelled was 18 km. Thus, the equation for the journey is 20x+18y=27.80 ⇒ Equ. 2

Now, on Solving Equation 1 & 2, We get

x=0.4(Cost of per minute charge) & y=1.1(Cost Of Per Kilometre charge)

Now, Roy's ride took 10 minutes & The distance travelled was 15 km . Thus, the cost of Roy's Ride is 10x+15y ⇔ 10×0.4 + 15×1.1 ⇔ $20.5

Hence, the total cost of Roy's ride is 20.5 + 2.55(fixed cost) = $23.05

Question 2 of 10
A rectangle's width is 5 feet less than its length. Write a quadratic function
that expresses the rectangle's area in terms of its length.
O A. A(1) = lw
B. A(1)=12 + 51
C. All) = w(w+5)
O D. All) = 12 - 51

A rectangle's width is 5 feet less than its length. Write a quadratic function
that expresses the rectangle's area in terms of its length.
O A. A(1) = lw
B. A(1)=12 + 51
C. All) = w(w+5)
O D. All) = 12 - 51

Answers

I don’t know if you meant to post the same question twice but the answer is C

6. Is this a relation? Is this a function? Why or why not?

Answers

Answer:

the given relation is function because all elements of domain is mapped with the elements of range

It is called a function

Determine the value of a so that x1-3x3=-3 2x1+ax2-x3=-2 (i)unique solution(ii)no solution(iii)many solutions

Answers

Answer:

(i)unique solution

Explanation:

We solve for x1 thus in the first equation:

x1-3x3=-3

x1-9=-3

x1=-3+9

x1= 6

We solve for a thus in the second equation:

2x1+ax2-x3=-2

2+a2-x3=-2

a2-x3=-4

a2=-4+x3

Given(a*b)*c=a*(b*c) what property does this represent

Answers

Answer:

The associative property allows us to change groupings of addition or multiplication and keep the same value. (a+b)+c = a+(b+c) and (a*b)*c = a*(b*c).

Step-by-step explanation:

in mathematics, either of two laws relating to number operations of addition and multiplication, stated symbolically: a + (b + c) = (a + b) + c, and a(bc) = (ab)c; that is, the terms or factors may be associated in any way desired.

Answer:

Associative

Step-by-step explanation:

What is another word for zeros?​

Answers

Answer:

nothing

Step-by-step explanation:

Zero is a number without a value so nothing could be another word for it

Another word for zeros is null

The volume of 10 drops of liquid is 0.1 fluid ounces.
What is the volume of 10,000 drops

Answers

Answer:

10,000 drops would be 1 fluid ounce

Step-by-step explanation:

4g+1 5 − G−7 4 = 2g−5 10

Answers

The answer is g=-7 hope it helps

Share £35 in the ratio 4:1​

Answers

Answer:

£28 : £7

Step-by-step explanation:

sum the parts of the ratio, 4 + 1 = 5 parts

Divide the quantity by 5 to find the value of one part of the ratio

£35 ÷ 5 = £7 , then

4 parts = 4 × £7 = £28

£35 = £28 : £7 in the ratio 4 : 1

why do bank charge transaction fees ?​

Answers

Answer:

To make a profit of course

Step-by-step explanation:

it

then

yes

Possibly.

A trained stunt diver is diving off a platform that is 15 m high into a pool of water that is 45 cm deep. The height, h, in meters, of the stunt diver above the water, is modeled by h=-4.9t^2+12t+5, where t is the time in seconds after starting the dive.

a) How long is the stunt diver above 15 m?

b) How long is the stunt diver in the air?

Answers

Answer:

a) 0 seconds.

b) The stunt diver is in the air for 2.81 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

Height of the diver after t seconds:

[tex]h(t) = -4.9t^2 + 12t + 5[/tex]

a) How long is the stunt diver above 15 m?

Quadratic equation with [tex]a < 0[/tex], so the parabola is concave down, and it will be above 15m between the two roots that we found for [tex]h(t) = 15[/tex]. So

[tex]h(t) = -4.9t^2 + 12t + 5[/tex]

[tex]15 = -4.9t^2 + 12t + 5[/tex]

[tex]-4.9t^2 + 12t - 10 = 0[/tex]

Quadratic equation with [tex]a = -4.9, b = 12, c = -10[/tex]. Then

[tex]\Delta = 12^{2} - 4(-4.9)(-10) = -52[/tex]

Negative [tex]\Delta[/tex], which means that the stunt diver is never above 15m, so 0 seconds.

b) How long is the stunt diver in the air?

We have to find how long it takes for the diver to hit the ground, that is, t for which [tex]h(t) = 0[/tex]. So

[tex]h(t) = -4.9t^2 + 12t + 5[/tex]

[tex]0 = -4.9t^2 + 12t + 5[/tex]

[tex]-4.9t^2 + 12t + 5 = 0[/tex]

Quadratic equation with [tex]a = -4.9, b = 12, c = 5[/tex]. Then

[tex]\Delta = 12^{2} - 4(-4.9)(5) = 242[/tex]

[tex]x_{1} = \frac{-12 + \sqrt{242}}{2*(-4.9)} = -0.36[/tex]

[tex]x_{2} = \frac{-12 - \sqrt{242}}{2*(4.9)} = 2.81[/tex]

Time is a positive measure, so we take 2.81.

The stunt diver is in the air for 2.81 seconds.

What is the highest common factor of 65 and 56?

Answers

Highest common factor of 56&65 is 1

-5 3/4 - 3 1/2 = ? Solve please!

Answers

Answer:

-9.25

Step-by-step explanation:

-5.75 - 3.5

-9.25

[tex]\implies {\blue {\boxed {\boxed {\pink {\sf { \:- 9 \frac{1}{4} (or) \:- 9.25 }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] - 5 \frac{3}{4} - 3 \frac{1}{2} [/tex]

➺[tex] \: \frac{ - 23}{4} - \frac{7}{2} [/tex]

➺[tex] \: \frac{ - 23}{4} - \frac{7 \times 2}{2 \times 2} [/tex]

➺[tex] \: \frac{ - 23 - 14}{4} [/tex]

➺[tex] \frac{ - 37}{4} [/tex]

➺[tex] \: - 9 \frac{1}{4} [/tex]

➺[tex] \: -9.25[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

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