.Answer:
The answer is below
Step-by-step explanation:
The patient loses 1 kg every week for 5 weeks.
1 kg = 2.2 lbs
Therefore the patient loses 2.2 lbs every week for 5 weeks.
a) The weight of the patient after 5 weeks = 245 lbs. - (5 weeks)(2.2 lbs per week)
The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.
b) The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.
1 kg = 2.2 lbs.
234 lbs. = 234 lbs. * 1 kg per 2.2 lbs. = 106.36 kg
The produce of three and the sum of a number and eight
Answer:
3(x + 8)
Step-by-step explanation:
"The product of three and the sum of a number and eight".
First, note that:
1) Product means multiply.
2) Sum means addition.
With that in mind, also note the order of operations. The order of operations is defined as PEMDAS, or:
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
Also, let "a number" be denoted as the variable, x.
~
Firstly, "the sum of a number and eight": x + 8
Next, "The product of...": 3 *
Putting the two parts together will generate: 3(x + 8)
3(x + 8) is your answer.
~
so, sunny is 16 he is 132 pounds
the song my time lasts 3:33 and sunny is falling for an entire 3 minutes
the gravitational pull which is pulling sunny back down to the ground is about 10m/s²
we have the new height of the hospital, is 49312,674 meters, or 161.787 feet
upon theory, sunny died upon coming to contact with the ground if you fall head first from 100 feet you're bound to die
you can break just your legs from falling from atleast 16-18 feet so imagine that
??????
Solve the system of equations.
3x + 4y + 3z = 5
2x + 2y + 3z = 5
5x+ 6y+7z = 7
a. (x = 13, y=-6, z = -2)
b. (x = 15, y = -8, z = -4)
c. (x = 16, y = -9, z = -1)
d. (x = 14, y = -7, z = 3)
Answer:
x = 14
y = -7
z = -3
but this is none of the provided answer options !
Step-by-step explanation:
it's really easy by principle. it's just some work to do.
we try to find equations to express one variable in terms of the others.
but one thing there is : your teacher made a mistake.
the right solution is x = 14, y = -7, z = -3
your teacher made a typo at d.
but the right answer should be d.
just to give you an idea how this can be done (and also to prove that there is a mistake by the teacher):
we can directly try to transform one expression into one that describes x by y and z.
and then another to describe e.g. z by y. and then solve the third one just for y. and then we get the other 2 by these other expressions.
or we can e.g. add or subtract one equation to/from another. this is one of these cases, because we can find really simple expressions that way :
we do
5x + 6y + 7z = 7
- (3x + 4y + 3z = 5)
- (2x + 2y + 3z = 5)
---------------------------
0x + 0y + z = -3
=> z = -3
3x + 4y - 3×3 = 5
3x = -4y + 14
x = (-4y + 14)/3
2×(-4y + 14)/3 + 2y - 9 = 5
(-8y + 28)/3 + 2y = 14
-8y + 28 + 6y = 42
-2y = 14
y = -7
x = (-4×-7 + 14)/3 = (28+14)/3 = 42/3 = 14
What is the length of BC in the right triangle below?
B
00
A
15
с
A. 17
B. 60
C. 17
D. 289
Using Pythagorean Theorem
[tex]\\ \sf\longmapsto H^2=P^2+B^2[/tex]
[tex]\\ \sf\longmapsto H^2=8^2+15^2[/tex]
[tex]\\ \sf\longmapsto H^2=64+225[/tex]
[tex]\\ \sf\longmapsto H^2=289[/tex]
[tex]\\ \sf\longmapsto H=\sqrt{289}[/tex]
[tex]\\ \sf\longmapsto H=17[/tex]
BC=17The width of a rectangle is 9 less than twice its length. If the area of the rectangle is 129cm^2. What is the length of the diagonal? Give your answer to 2 decimal places.
==========================================================
Explanation:
L = x = length of the rectangleW = 2x-9 = width of the rectangle, since its 9 less than twice the lengtharea of rectangle = L*W = 129
L*W = 129
x*(2x-9) = 129
2x^2-9x = 129
2x^2-9x-129 = 0
Apply the quadratic formula. We'll use a = 2, b = -9, c = -129.
[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-9)\pm\sqrt{(-9)^2-4(2)(-129)}}{2(2)}\\\\x = \frac{9\pm\sqrt{1113}}{4}\\\\x \approx \frac{9\pm33.36165464}{4}\\\\x \approx \frac{9+33.36165464}{4}\ \text{ or } \ x \approx \frac{9-33.36165464}{4}\\\\x \approx \frac{42.36165464}{4}\ \text{ or } \ x \approx \frac{-24.36165462}{4}\\\\x \approx 10.59041366\ \text{ or } \ x \approx -6.09041364\\\\[/tex]
We ignore the negative solution because a negative length makes no sense.
The length is approximately L = 10.5904 cm.
The width is 2L-9 = 2*10.5904-9 = 12.1808 cm approximately.
As a quick check,
L*W = 10.5904*12.1808 = 128.99954432
which isn't too far off from 129. We have rounding error which is why we don't perfectly land on the target area value. If you wanted to get closer to the value 129, then use more decimal digits in the approximations of L and W.
----------------------------
If you draw a diagonal in the rectangle, then you form two identical or congruent right triangles.
Focusing on one of those triangles, we have
a = 10.5904b = 12.1808c = unknown hypotenuse = diagonal lengthApply the pythagorean theorem
a^2+b^2 = c^2
c = sqrt( a^2 + b^2 )
c = sqrt( (10.5904)^2 + (12.1808)^2 )
c = 16.1408940520653
c = 16.14
The diagonal is roughly 16.14 cm long.
WILL GIVE BRAINLIEST
Complete the equation describing how
x and y are related.
х
-3
-2
-1
0
1
2
3
y
12
8
4
0
-4
-8
-12
y = [? ]x
Answer:
[tex]y=4x[/tex]
Answer:
y = -4x
hope that helped.........
Solve x/4 > 2 Question 10 options: x ≥ 8 x < –8 x > 8 x ≤ –8
Answer:
x > 8
Step-by-step explanation:
You can start y multiplying both sides by 4 to cancel out the division by 4:
x/4 > 2
*4 *4
x > 8
Answer:
x > 8
Step-by-step explanation:
x/4 > 2
=> x > 2 × 4
=> x > 8
Find the fraction equivalent to 5/7 with: a) numerator 25 b) denominator 42
Answer:
a) 25/35
b) 30/42
Step-by-step explanation:
a)
Variable x = denominator if numerator is 25
5/7 = 25/x
5 × x = 7 × 25
5x = 175
x = 35
b)
Variable y = numerator if denominator is 42
5/7 = y/42
5 × 42 = 7 × y
210 = 7y
30 = y
25/35
30/42
To get 25/35 multiply by 5
To get 30/42 multiply by 6
What are the solutions of the equation (x + 2)2 + 12(x + 2) – 14 = 0? Use u substitution and the quadratic formula to
solve.
..... Here
This is the answer
A school sports team contains 68 students. 33 do field events, 40 do track events, 23 do swimming, 14 do both field and track events, 8 do both swimming and field events. If 15 students do field events only and 10 do both swimming and track events, how many students do a. Swimming only b. Track events only c. All three events?
Answer:
a. 9 students
b. 20 students
c. 4 students
A line passes through the point (-3, -3) and has a slope of 1/2 What is the equation of the line?
Answer:
y= 1/2x-3/2
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = 1/2x+b
Using the point for x and y we can find b
-3 = 1/2(-3)+b
-3 = -3/2 +b
-6/2 = -3/2+b
Add 3/2 to each side
-6/2 +3/2 = b
-3/2 = b
y= 1/2x-3/2
Answer:
Step-by-step explanation:
y + 3 = 1/2(x + 3)
y + 3 = 1/2x + 3/2
y + 6/2 = 1/2x + 3/2
y = 1/2x - 3/2
Given that the supply and demand function for the product type is Qd = [tex]\sqrt{260-p}[/tex],
Qs = [tex]\sqrt{p-14}[/tex]. consumer surplus ??.
2. The volume of a cube is 8 cm", find the length of one of its sides
Answer:
Step-by-step explanation:
The question has an error. Volume is expressed in cubic units. You probably mean cm³ .
Volume = 8 cm³
Length of each edge = ∛8 = 2 cm
Answer:
2cm
Step-by-step explanation:
Volume of cube=a^3 cubic units
8=a^3
a=cuberoot of 8
which is 2
I need help in math please, if you can
Answer:
Step-by-step explanation:
400*e^(.09*3)
$523.97
answer is b
Answer: Option B
$523.97
Explanation:
= 400×e^(0.09×3)
= $523.97
Must click thanks and mark brainliest
What are the first and third quartiles for the following data set?
12, 15, 18, 16, 14, 9, 12, 21
A 9 and 21
C 12 and 17
B 12 and 16
D 15 and 17
Answer:
A
Step-by-step explanation:
I guess that is it may be
Assume a random variable representing the amount of time it takes for a customer service representative to pick up has a uniform distribution between 15 and 20 minutes. What is the probability that a randomly selected application from this distribution took less than 18 minutes
Answer:
0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
The probability of finding a value above x is:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
Uniform distribution between 15 and 20 minutes.
This means that [tex]a = 15, b = 20[/tex]
What is the probability that a randomly selected application from this distribution took less than 18 minutes?
[tex]P(X < 18) = \frac{18 - 15}{20 - 15} = 0.6[/tex]
0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.
7. Ten samples of 15 parts each were taken from an ongoing process to establish a p-chart for control. a. Develop a p-Chart for 95 percent confidence (1.96 standard deviation). b. Based on the plotted data points, what comments can you make
Answer: Hello the table related to your question is attached below
answer:
a) attached below
b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )
Step-by-step explanation:
a) p-chart for 95% confidence
std = 1.96
Total defects = ∑ number of defective items in the sample = 10
number of samples = 10
sample size ( n ) = 15
The P value for the process is calculated as :
Total defects / ( number of sample * sample size )
= 10 / ( 15 * 10 ) = 10 / 150 = 0.067
standard deviation ( σ ) = [tex]\sqrt{\frac{p(1-p)}{n } } = \sqrt{\frac{0.067(1-0.067)}{15} }[/tex] = 0.065
next we determine the limits ( i.e. upper and lower )
UCL = p + zSp = 0.067 + 1.96(0.065 ) = 0.194
LCL = p - zSp = 0.067 - 1.96(0.065) = -0.060 ≈ 0 ( because LCL ≠ negative)
attached below is the required p-chart
b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )
The perimeter of a rectangular garden is 120 feet The garden is two times as long as it’s why the system of equation can be used to find the width in the length what is the length
Answer:
Step-by-step explanation:
Garden is two times as long as it is wide.
L = 2W
Perimeter is 120 feet
2L + 2W = 120
L +W = 60
(2W) + W = 60
3W = 60
W = 20 feet
L = 2W = 40 feet
The price of a car has been reduced from $16,500 to $11,055. What is the percentage decrease of the price of the car?
Answer:
33%
Step-by-step explanation:
$16,500-$11,055= $5,445
$5,445÷$16,500= 0.33 which in percentage format is 33%
HOPE THIS HELPS! MARK BRAINLIEST PLEASE!!!!!
A^2 + 2AB +B^2
habsbsjabdhjsbfhjbsdjh
solve for x : 2(x^2+9)-4=0
Answer:
no solution
Step-by-step explanation:
multiply 2 and get 2x^2+18-4=0
combine like terms
2x^2+14=0
subtract 14
2x^2=-14
there can't be a square root of a negative number so there's no solution
Answer:
x = ±i sqrt(7)
Step-by-step explanation:
2(x^2+9)-4=0
Add 4 to each side
2(x^2+9)-4+4=0+4
2(x^2+9)=4
Divide by 2
2(x^2+9)/2=4/2
(x^2+9)=2
Subtract 9 from each side
x^2 +9-9 = 2-9
x^2 = -7
Taking the square root of each side
sqrt(x^2) =sqrt(-7)
x = sqrt(-1 *7)
x = ±i sqrt(7)
Determine which type of error is most likely to arise from the following situations. a 1. the time in which individuals are contacted to take a survey occurs during work hours f 2. the last part of a newspaper article asks readers to mail or email the newspaper their opinion about universal health coverage 3. subjects are asked to recall how often they snacked between meals in the past 30 days 4. a survey to assess teachers' opinions about Common Core uses a member list for the largest teachers' union as the sampling frame a. question wording b. undercoverage c. processing error d. bad sampling method e. response error f. nonresponse g. random sampling error
Answer:
Determination of type of error arising from the situations
Situation Type of Error
1. Nonresponse
2. Bad sampling method
3. Question wording
4. Undercoverage
Step-by-step explanation:
Types of errors:
a. question wording means that the manner a question is worded elicits some particular responses, which may not accurately reflect reality.
b. undercoverage occurs when some elements of the target population is not represented on the survey frame.
c. processing error arises from data processing
d. bad sampling method is caused by the voluntariness of those who choose to respond.
e. response error is caused by a questionnaire that requires framing improvements, misinterpretation of questions by interviewers or respondents, and errors in respondents' statements.
f. nonresponse error arises as a result of incomplete information or partial response.
g. random sampling error arises from the limited sample size when compared with the population size.
The place value of 7 in 87534 is____________
Suppose (-13,2) is a point on the graph of y=f(x). What is a point that will be on the graph of y=9f(x)-5
9514 1404 393
Answer:
(x, y') = (-13, 13)
Step-by-step explanation:
At the given value of x, f(x) = 2. Then 9f(x)-5 = 9(2) -5 = 13.
The point on the scaled, translated graph will be ...
(x, y') = (-13, 13)
_____
The graph shows a function f(x) with a distinct feature (vertex) at (-13, 2). It also shows where that distinct feature moves to when the function is scaled and translated.
verify cos(a+b)/cos(a) cos(b) =1-tan(a) tan(b)
The identity as been verified/proved as:
[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]
Given that:
[tex]\frac{\cos(a + b)}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Apply cosine identity to the numerator
[tex]\frac{\cos\ a\ cos\ b - \sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Split the fraction:
[tex]\frac{\cos\ a\ cos\ b}{\cos\ a\cos b} - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Cancel out common terms
[tex]1 - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
In trigonometry, we have:
[tex]\frac{\sin \theta}{\cos \theta} = \tan \theta[/tex]
So, the equation becomes:
[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]
Hence, the identity has been verified
Read more about trigonometry identities at:
https://brainly.com/question/21055284
-27
Which of the following is equivalent to
نان-۴
?
N
O
(197)
NI
12
22
(22)
2².2
Answer:
3rd option
Step-by-step explanation:
(1/2)^-2t
= (2^-1)^-2t
= 2^2t
= (2^2)^t
Answered by GAUTHMATH
Assume x and y are two odd numbers and x/y is an integer.
Which of the following statements are true?
I. x + y is odd
2. xy is odd.
3. x/y is odd
4. x-y is odd
Answer:
Let us check these out one at a time:
1. x + y is odd. FALSE. The sum of 2 odd numbers is even.
2. xy is odd. TRUE. The product of 2 odd numbers is odd.
3. x/y is odd. TRUE. The ratio of 2 odd numbers is odd, if the ratio is an integer.
4. x - y is odd. FALSE. The difference of 2 odd numbers is even.
Only statements 2 and 3 are TRUE, so that makes (C) the correct answer.
What is 50g as a percentage of one kg?
Answer:
5 %
Step-by-step explanation:
1000 g = 1 kg
50 kg = 0.05 kg
0.05 = 5%
Therefore, 50 g as a percentage of 1kg is 5%.
Fill in the blank with a number to make the expression a perfect square.
u^2- 18u +
Answer:
u^2- 18u +81 = (u-9)^2
Step-by-step explanation:
u^2- 18u +
Take the u coefficient
-18
Divide by 2
-18/2 = -9
Square it
(-9)^2 = 81
u^2- 18u +81 = (u-9)^2
Answer:
The blank should contain 81
Step-by-step explanation:
E = u^2 - 18u + (-18/2)^2
E = (u^2 - 18u + 9^2)
E = (u - 9)^2
To be perfectly correct what you have there is a perfect square, but you need to subtract out (9/2)^2 to make it a valid statement.
E = (u - 9)^2 - 81
A hexagonal pyramid is located ontop of a hexagonal prism. How many faces are there?
A. 15
B. 24
C. 6
D. 13
Answer:
15
Step-by-step explanation:
The figure has total 15 faces, the correct option is A.
What is a Hexagon?A hexagon is a polygon with six sides.
A hexagonal pyramid has 8 faces
From (2 hexagonal base + 6 lateral surfaces)
A hexagonal prism has 7 faces
From ( A hexagonal base + 6 lateral faces)
Total faces the figure has is 8 +7 = 15
To know more about Hexagon
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