How would you write a gain of 16 points as an absolute value?
if 3x+7 Y-37 and x = 3, then Y = ?
Answer:
y = 4
Step-by-step explanation:
Given
3x + 7y = 37 ← substitute x = 3 into the equation
3(3) + 7y = 37, that is
9 + 7y = 37 ( subtract 9 from both sides )
7y = 28 ( divide both sides by 7 )
y = 4
Step-by-step explanation:
Solve for the value of r.
(7r-5)
(6r+4)°
Answer:
r = 9
Step-by-step explanation:
These are vertical angles, therefore, the measurements is the same. Set the two measurements equal to each other:
7r - 5 = 6r + 4
Isolate the variable, r. Note the equal sign, what you do to one side, you do to the other. Add 5 and subtract 6r from both sides of the equation:
7r (-6r) - 5 (+5) = 6r (-6r) + 4 (+5)
7r - 6r = 4 + 5
Simplify:
7r - 6r = 4 + 5
r = 9
9 is your value for r.
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The length of the parallel sides of a trapezium are 3cm and 1 cm, and the distance between them is 1 cm. What is its area?
Answer:
A = 2 cm²
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂ )
where h is the distance between parallel sides and b₁, b₂ , the parallel sides
Here h = 1, b₁ = 3, b₂ = 1 , then
A = [tex]\frac{1}{2}[/tex] × 1 × (3 + 1) = [tex]\frac{1}{2}[/tex] × 4 = 2 cm²
help me do this please!
Answer:
m<ABD = 37°
m<DBC = 58°
Step-by-step explanation:
m<ABD + m<DBC = m<ABC
2x + 23 + 9x — 5 = 95
11x + 18 = 95
-18 -18
--------------------
11x = 77
/11 /11
---------------------
x = 7
Now, plug this into the equation for m<ABD and m<DBC to find their values.
m<ABD = 2x + 23
= 2(7) + 23
= 14 + 23
= 37
m<DBC = 9x — 5
= 9(7) — 5
= 63 – 5
= 58
Now, check to see if our values are right or not.
2x + 23 + 9x — 5 = 95
2(7) + 23 + 9(7) — 5 = 95
14 + 23 + 63 – 5 = 95
100 – 5 = 95
95 = 95 CORRECT
Solve the equation. Check your solution.
Answer:
x = 5
Step-by-step explanation:
x^2/(x + 5) = 25/(x+5) Subtract the right side from both sides.
x^2/(x + 5) - 25/(x + 5) = 0
x^2 - 25
======= = 0
x + 5
(x + 5)(x - 5)
============= = 0
(x + 5)
Cancel x + 5 in the numerator and denominator.
x - 5 = 0
x = + 5
Does it check?
x^2/(x + 5) = 25/(x + 5)
x = 5
5^2/(10) = 25/10
25/10 = 25/10 Yes it checks.
what is 13 x 12 feet converted is how many inches?
i am supposed to use f(x) to solve these but there isn’t an x in them so i am confused, can someone help?
but there have given the formula of g(x) and f(x) ,put it
the volume of the cone is given by the formula V = 1/3 pie r^2 h, where r is the radius of the base and h is the height of the cone. based on this formula, whatis the height, h, of the cone in terms of the volume and height
answer is h=3v/pie r^2. need help with showing work
9514 1404 393
Answer:
h = 3V/(πr²)
Step-by-step explanation:
The formula can be solved for h by multiplying both sides by the inverse of the coefficient of h.
[tex]V=\dfrac{1}{3}\pi r^2h=\dfrac{\pi r^2}{3}h\\\\(\dfrac{3}{\pi r^2})V=(\dfrac{3}{\pi r^2})(\dfrac{\pi r^2}{3})h\\\\\boxed{\dfrac{3V}{\pi r^2}=h}[/tex]
_____
Additional comment
Whenever a variable has a coefficient you don't want, you can make that be 1 by multiplying the equation by the inverse of the coefficient. This is the same as dividing by the coefficient. This makes use of the fact that for any non-zero 'a', the ratio a/a has a value of 1. Anything multiplied by 1 is unchanged.
V = ah ⇒ V/a = (ah)/a = h(a/a) = h·1 = h
Note that we multiply the whole equation (both sides of the equal sign) by 1/a. The basic rule of equality is that you can do whatever you like to an equation, as long as you do it to both sides.
The center circle on a soccer field has a radius of 9 yards. What is the area of the center circle? Use 3.14 for pie
Answer:
[tex]\boxed {\boxed {\sf 254.34 \ yd^2}}[/tex]
Step-by-step explanation:
The area of a shape is the space occupied by the surface of an object. The area of a circle can be calculated using the following formula.
[tex]a= \pi r^2[/tex]
The radius (r) of the center circle on the soccer field is 9 yards. We are asked to use 3.14 for pi.
r= 9 yd π= 3.14Substitute these values into the formula.
[tex]a= (3.14)(9 \ yd)^2[/tex]
Solve the exponent.
(9 yd)² = 9 yd * 9 yd = 81 yd²[tex]a= (3.14)(81 \ yd^2)[/tex]
Multiply.
[tex]a= 254.34 \ yd^2[/tex]
The area of the center circle on the soccer field is 254.34 square yards.
I keep getting 30 but it’s not right. Can anyone tell me the steps?
2[10-3(4-2)]+1
Answer:
9
Step-by-step explanation:
[tex]2[10-3(4-2)]+1\\=2(10-3\times2)+1\\=2(10-6)+1\\=2\times4+1\\=9[/tex]
The tempature at 5 P.M. is 20 degrees f. The temperature at 10 P.M. is -5 degrees f. How many degrees did the temperature fall?
Answer:
25 degreea bestie hope thiis helped
please help me, if you help then thanks!
Answer:
B. [tex] {a}^{ - 7 - 10} [/tex] (second option)
Step-by-step explanation:
[tex] \frac{ {a}^{ - 7} }{ {a}^{10} } [/tex]
[tex] {a}^{ - 7 - 10} [/tex]
[tex] - 7 - 10 = - (7 + 10) = - 17[/tex]
Find the value of x.
9514 1404 393
Answer:
x = 6
Step-by-step explanation:
The angle bisector divides the sides proportionally.
(6x -1)/42 = (10x +5)/78
13(6x -1) = 7(10x +5) . . . . . . . multiply by 546 = LCM(42, 78)
78x -13 = 70x +35 . . . . . . . . eliminate parentheses
8x = 48 . . . . . . . . . . . . . . . . add 13-70x
x = 6 . . . . . . . . . . . . . . . . . divide by 8
A
person that weighs 150 pounds on
Earth will weigh 25 pounds on the Moon.
How much will a 90-pound person weigh
on the Moon?
A. 10 lb
B. 12 lb
C. 15 lb
D. 20 lb
Answer:
Step-by-step explanation:
Ans:15 lb
A 90-pound person will weigh 15lb as we weigh six times less on the moon than the earth. So to find out simply divide 90 by 6.
What is 12 divided by 2/5?
Answer:30
Step-by-step explanation:
State the gradient of the line perpendicular to the line y=3x-2
Answer:
-1/3
Step-by-step explanation:
3 is the gradient of the other line
m1×m2=-1 (equation for perpendicular lines)
m1×3= -1
m1= -1/3
Pls confirm if its correct
correct me if wrong
thanks! :)
Evaluate the expression if x = - 8 , y = 7 , and z = - 11 .
- 11 - z =?
Answer:
-11 - z
(-11) - (-11)
= 0
I hope I have helped.
Are these answers correct? Thxxx
Which of the following is equivalent to?
Answer:
Answer is 1/6
Step-by-step explanation:
[tex] {36}^{ - \frac{1}{2} } \\ = \frac{1}{ {36}^{ \frac{1}{2} } } \\ \\ = \frac{1}{ \sqrt{36} } \\ \\ = \frac{1}{6} [/tex]
Find AC someone help please. If you can please include steps
Answer:
AC = 15
Step-by-step explanation:
AC is the entire line split into two segments; AB and BC
We are given that AB = 8 and BC = 2x + 25 so we can combine these two and set them equal to AC ( = x + 24)
x + 24 = 8 + 2x + 25
Combine like terms and isolate x
x + 24 = 2x + 33
-9 = x
Now plug in -9 for x in the equation for line AC
(-9) + 24 = 15
find dy/dx x=a(cost +sint) , y=a(sint-cost)
Answer:
[tex]\begin{aligned} \frac{dy}{dx} &= \frac{\cos(t) + \sin(t)}{\cos(t) - \sin(t)} \end{aligned}[/tex] given that [tex]a \ne 0[/tex] and that [tex]\cos(t) - \sin(t) \ne 0[/tex].
Step-by-step explanation:
The relation between the [tex]y[/tex] and the [tex]x[/tex] in this question is given by parametric equations (with [tex]t[/tex] as the parameter.)
Make use of the fact that:
[tex]\begin{aligned} \frac{dy}{dx} = \quad \text{$\frac{dy/dt}{dx/dt}$ given that $\frac{dx}{dt} \ne 0$} \end{aligned}[/tex].
Find [tex]\begin{aligned} \frac{dx}{dt} \end{aligned}[/tex] and [tex]\begin{aligned} \frac{dy}{dt} \end{aligned}[/tex] as follows:
[tex]\begin{aligned} \frac{dx}{dt} &= \frac{d}{dt} [a\, (\cos(t) + \sin(t))] \\ &= a\, (-\sin(t) + \cos(t)) \\ &= a\, (\cos(t) - \sin(t))\end{aligned}[/tex].
[tex]\begin{aligned} \frac{dx}{dt} \ne 0 \end{aligned}[/tex] as long as [tex]a \ne 0[/tex] and [tex]\cos(t) - \sin(t) \ne 0[/tex].
[tex]\begin{aligned} \frac{dy}{dt} &= \frac{d}{dt} [a\, (\sin(t) - \cos(t))] \\ &= a\, (\cos(t) - (-\sin(t))) \\ &= a\, (\cos(t) + \sin(t))\end{aligned}[/tex].
Calculate [tex]\begin{aligned} \frac{dy}{dx} \end{aligned}[/tex] using the fact that [tex]\begin{aligned} \frac{dy}{dx} = \text{$\frac{dy/dt}{dx/dt}$ given that $\frac{dx}{dt} \ne 0$} \end{aligned}[/tex]. Assume that [tex]a \ne 0[/tex] and [tex]\cos(t) - \sin(t) \ne 0[/tex]:
[tex]\begin{aligned} \frac{dy}{dx} &= \frac{dy/dt}{dx/dt} \\ &= \frac{a\, (\cos(t) + \sin(t))}{a\, (\cos(t) - \sin(t))} \\ &= \frac{\cos(t) + \sin(t)}{\cos(t) - \sin(t)}\end{aligned}[/tex].
The width of a rectangle measures (2p - 9q) centimeters, and its length measures
(7p - 10q) centimeters. Which expression represents the perimeter, in centimeters,
of the rectangle?
Given Data : Length = (7p - 10q) and Breadth = (2p - 9q)
Calculation :
⟹ Perimeter = 2(Length + Breadth)
⟹ Perimeter = 2(7p - 10q + 2p - 9q)
⟹ Perimeter = 2(9p - 19q)
⟹ Perimeter = 18p - 38q centimetres
Answer : 18p - 38q centimetresThe required perimeter of the rectangle is 18p - 38q centimeters.
It is required to find the required perimeter of the rectangle.
What is rectangle?A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.
Given:
width of a rectangle = (2p - 9q) centimeters,
length measures= (7p - 10q) centimeters.
We know that
⟹ Perimeter = 2(Length + Breadth)
By put the value width and length in perimeter we get,
⟹ Perimeter = 2(7p - 10q + 2p - 9q)
⟹ Perimeter = 2(9p - 19q)
⟹ Perimeter = 18p - 38q centimeters
Therefore, the required perimeter of the rectangle is 18p - 38q centimeters.
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Three million, six hundred twenty nine in numbers
Answer:
3,000,629
Step-by-step explanation:
Start with three million as shown below.
Three million, six hundred twenty nine in numbers
3,000,000
"six hundred twenty nine" is simply
629
The number you want is 629 more than 3 million.
Now add the 639 to the 3 million.
Three million, six hundred twenty nine
3,000,629
1. If a = -1 , the value of3a + 1 is
Answer:
[tex]f(a) = 3a + 1 \\ Now,\: a = - 1 \\ f( - 1) = 3( - 1) + 1 \\ f( - 1) = - 3 + 1 \\ \boxed{ f( - 1) = - 2}[/tex]
Therefore, -2 is the right answer.In a charity triathlon, Mark ran half the distance and swam a quarter of the distance. When he took a quick break to get a drink of Gatorade, he was just starting to bike the remaining 24 miles. What was the total distance of the race?
The total distance of the race is D = 96 miles
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the equation be represented as A
Now , the value of A is
Substituting the values in the equation , we get
Let's denote the total distance of the race as "d" miles.
According to the given information, Mark ran half the distance and swam a quarter of the distance. This can be expressed as:
Distance Mark ran = d/2 miles
Distance Mark swam = d/4 miles
After Mark's quick break, he was just starting to bike the remaining 24 miles. Since he has already completed running and swimming, the total distance he has covered at that point is:
And this distance is equal to 24 miles, as given in the problem:
d/2 + d/4 + 24 = d
On simplifying the equation , we get
( 3/4 )d + 24 = d
Subtracting ( 3/4 )d on both sides , we get
( 1/4 )d = 24
Multiply by 4 on both sides , we get
d = 96 miles
Hence , the total distance of the race, denoted by "d", is 96 miles
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What's the X-Intercepts of (2x-5)(x+1)=9 or (2x-5)(x+1)-9
Answer:
Step-by-step explanation:
Either way works. It comes to the same thing.
(2x-5)(x+1)=9
F: 2x*x = 2x^2
O: 2x*1 = 2x
I: -5 * x = -5x
L: -5*1 = -5
2x^2 + 2x - 5x - 5 = 9 Subtract 9 from both sides
2x^2 - 3x - 14 =0 Divide by 2 (it makes life easier).
Factoring you get
(2x - 7)(x + 2)
2x - 7 = 0
2x = 7
x = 3.5
x + 2 = 0
x = -2
The x intercepts = (3.5,0) and (-2,0)
I've put a graph up for the given equation.
Round 57.5958961796 to the nearest hundredth.
Define a variable and write an inequality for each problem. Then solve.
15. Nineteen more than a number is less than 42.
16. The difference of three times a number and 16 is at least 8.
17. One half of a number is more than 6 less than the same number.
18. Five less than the product of 6 and a number is no more than twice that same number.
Answer:
15) n+19<42
16) 3n-16 (less or equal) 8
17) n/2 > n-6
18) 6n-5<2n
Step-by-step explanation:
ABC Company sells a certain product line at an established price of Br 42 per unit The variable cost per unit is Br 36. The fixed cost for the year amounts to Br 540,000 Next year the selling price is to be increased to Br 45perunit. How many units had to be sold at the old established price each year in order to Breakeven
90,000 units of the product has to be sold each year in other to break even.
The old established price = 42 per unit :
The break even unit is the number of units sold such that the net profit = 0
(expenses - income) = 0
The expenses = (Fixed cost + variable cost)
Fixed cost = 540000
Fixed cost = 540000Variable cost per unit = 36
Let the number of units required to break even = x
Expenses = income or revenue
(540000 + 36x) = 42x
540000 + 36x = 42x
540000 = 42x - 36x
540000 = 6x
x = 540000 / 6
x = 90000
Hence, 90,000 units has to be sold at the old established price in other to break even.
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