Pushing a chair is a law of______?

A. Law of friction
B. Law of interaction
C. Law of acceleration
D. Law of universal gravitation​


please help..

Answers

Answer 1
I believe your answer would be A. Due to the friction of pushing the chair while it’s on the floor
Answer 2

Answer:

A.Law of friction

Explanation:

because friction is the move chair floor


Related Questions

If a car skids to a stop in 3.8s while undergoing a uniform acceleration of -9.55 m/s2, what is the car’s velocity?

Answers

Answer:

36.29 m/s

Explanation:

We know from theory that [tex]v= v_0 +a\Delta t[/tex]. Let's replace the value we know in our equation and solve for the only value left.

[tex]0 = v_0 - 9.55 \cdot 3.8 \\ v_0 = 9.55 \cdot 3.8 = 36.29 m/s[/tex]

What advantage is there in measuring your distance from I1 to I1' and dividing by 2 rather than measuring the distance OI1 directly

Answers

Measuring the distance from  [tex]I_1 \ to \ I_1'[/tex] and dividing by 2 has advantage of achieving a more accurate result compared to measurement taking directly.

Measuring the distance from [tex]I_1 \ to \ I_1'[/tex] is equivalent to the double of the distance.

This method of measurement gives a more accurate result because it minimizes error that may result from taking readings form the intervals. It ensures more accurate result compared to the measurement obtained when [tex]OI_1[/tex] is measured directly.

[tex]OI_1 = \frac{I_1 + I_1'}{2}[/tex]

Thus, we can conclude that measuring the distance from  [tex]I_1 \ to \ I_1'[/tex] and dividing by 2 has advantage of achieving a more accurate result compared to measurement taking directly.

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Place a beaker covering its free surface with a paper over a coin as shown in the figure- 1. The coin can be seen through the sides of the beaker. (i) Fill the beaker with water. Is the coin seen through the sides of the beaker? If not, why? (ii) Drop water over the coin. Is the coin seen through the sides of the beaker? If yes, why?​

Answers

Answer:

bonjour

Explanation:

bye

PLEASE HELP!!!


If a 40cm rope with a 220g bob can hold a maximum tension of 3N
a) what are the maximum angular velocity and inclination angle it can reach before the rope break?
b) Angle of inclination​

Answers

Answer:

ω = 3.1 rad/s

θ = 36° from vertical

Explanation:

I will ASSUME that the bob and string is acting as a pendulum.

Please understand that the string will break when the bob is at the lowest point of the swing where the vectors of gravity and centripetal acceleration align. It will NOT break at the angle of maximum inclination measured from vertical. This angle is only a component of the maximum potential energy that gets converted to maximum kinetic energy at the lowest point of the swing.

At the bottom of the swing, the string must support the weight of the bob plus supply the required centripetal acceleration.

F = mg + mω²R

F/m = g + ω²R

F/m - g = ω²R

ω = √((F/m - g)/R)

ω = √((3/0.220 - 9.8)/0.40)

ω = 3.09691...

ω = 3.1 rad/s

Potential energy will convert to kinetic energy

       mgh = ½mv²

             h = v²/2g

R - Rcosθ = v²/2g

R(1 - cosθ) = v²/2g

   1 - cosθ = v²/2gR

        cosθ = 1 - v²/2gR

        cosθ = 1 - (Rω)²/2gR

        cosθ = 1 - Rω²/2g

        cosθ = 1 - 0.40(3.1²)/(2(9.8))

        cosθ = 0.804267

              θ = 36.46045...

              θ = 36°

An airplane has a mass of 33,000 kg and takes off under the influence of a constant net force of 44,000 N. What is the net force that acts on the plane's 70 kg pilot

Answers

Answer:

Explanation:

acceleration a = F/m = 44000/33000 = 1.3m/s²

F = ma = 70(1.3) = 93 N

Do you expect the normal dicrystalline resistance in the forward bias to be pure ohmic resistance or what ?!​

Answers

Answer:

yes

Explanation:

because is pure ohmic risistance

If a car travels 10 min 2 seconds, what is its speed?
A. 5 m/s
B. 0.2 m/s
C. 20 m/s
D. 2 m/s

Answers

If you meant the car travels 10 meters or miles then the answer would be 5m/s because v=d/t (v=10/2)

Describe how you can determine:
a) Volume of an irregular body
b) Density of a liquid​

Answers

Density of liquid try thank you so much

Answer:

  a) measure the change in volume when the object is immersed; compute from range data

  b) find the ratio of mass to volume for a measured mass and volume

Explanation:

a) The volume of a small enough irregular body can be found by measuring the difference in volume of the (semi-)fluid in which it is immersed, before and after immersion.

For irregular bodies for which that approach does not work, various 3D scanners are available for measuring volume and surface area. They may rely on optical (laser or camera), sonic, or radar measurements, and generally involve computation from distances to various points.

__

b) Density is the ratio of mass to volume. So, measurements of mass and volume of a liquid sample are sufficient to provide the basis for determining density.

Other methods include measuring buoyancy forces, and/or the depth of submersion of something that floats in the liquid. For specific liquids, hydrometers are available for measuring their density relative to that of water.

The refractive index of water with respect to air is 5/3 and that of glass is 3/2.What is the refractive index glass with respect to water?

Answers

Answer:

9/8

Explanation:

Please write a paragraph explaining the bible verse below in your own words.


Exodus 16:1-3

Answers

Answer: Moses

Explanation: The Israelites are angry at Aaron and Moses, because they lead them into this desert where there is no food, or water. It was told that after the Israelites left Egypt they would wander the desert for forty years. The Israelites complain that they would have had plenty of food if they had just stayed enslaved in Egypt. They are not grateful that God has liberated them from slavery.

50 points help

Column I Column II

______ 1. acceleration a. change in distance over time

______ 2. speed b. time interval

______ 3. velocity c. scalar

______ 4. Δt. d. change in position

______ 5. Magnitude only e. change in velocity over time

______ 6. Δx f. change in displacement over time

Answers

[tex]\\ \sf\longmapsto Acceleration\longrightarrow Change\:in\: Velocity\:over\:time[/tex]

[tex]\\ \sf\longmapsto Speed\longrightarrow Change\:in\: Distance\:over\:Time[/tex]

[tex]\\ \sf\longmapsto Velocity\longrightarrow Change\:in\: Displacement\: over\:time[/tex]

[tex]\\ \sf\longmapsto ∆t\longrightarrow Time\: interval [/tex]

[tex]\\ \sf\longmapsto Magnitude\:only\longrightarrow Scaler[/tex]

[tex]\\ \sf\longmapsto ∆x=Change\:in\: position [/tex]

Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

Answers

Answer:Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

Explanation:

Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

An electric force is given by F = (kqQ)/(r^2) where k is the constant 9x10^9, q and Q are the charges, and r is the distance between the charges.

Given that the charge of an electron is -1.6 x 10^-19 C, we can write the force equal to

((9x10^9)(-1.6x10^-19)^2)/(2x10^-9)

=> 1.152 x 10^-19 N

Note that the force is repulsive since the electrons are both negatively charged (the same sign).

pls help me… I missed the whole lesson and I have no clue what to do-

Answers

Answer:

1) 50 facing towards the right

2) 150 facing right

3) 200 facing right

4) 0- no direction

5) 50- facing left

6) 50 facing right

Explanation:

forces in opposite directions and equal magnitudes counteract each other. in number 2 they face the same direction so they would just be added. in number 4 they oppose each other so would be subtracted

What does it mean that " memory is organized in semantic
networks

Answers

Answer:

Semantic memory is a category of long-term memory that involves the recollection of ideas, concepts and facts commonly regarded as general knowledge. Examples of semantic memory include factual information such as grammar and algebra.

A photographer wants to determine the color of light he can use in the darkroom that will not expose the films he is processing. In one trial, he used a blue incandescent bulb. Which bulb can he use for another trial?
A. Red incandescent bulb C. Red fluorescent bulb
B. Blue incandescent bulb D. Blue fluorescent bulb

Answers

For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.

The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:

Control variablesDependent variables Independent variables

For this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.

The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.

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Change 1m2 in to cm2, mm2 and km2​

Answers

Answer:

1m² = 10000cm²

1m² = 1000000mm²

1m² = 1 × 10^-6

Explanation:

When coverting from square meter to square centimetre, multiply the area value by 10.

When coverting from square meter to millimetre, multiply the area value by 10⁶ ( 1 million )

When converting from meter square to kilometre square, divide the area value by 10^-6 ( 0.000001)

Lupert walked 5.8 m east in 8.9 s, stopped for 3.7 s, turned North and went 7.9 m in 12.5 s, stopped for 6.3s , and then went 3.2 m west in 4.7s. What was his average speed?

Answers

The average speed of Lupert for the entire journey is 4.58 m/s.

The given parameters;

initial position of Lupert, = 5.8 m easttime of motion, = 8.9 s, extra time = 3.7 ssecond position of Lupert, = 7.9 m, Northtime of motion, = 12.5 s, extra time = 6.3 sfinal position of Lupert = 3.2 m westtime of motion = 4.7 s

The average speed of Lupert is calculated as the ratio of the total distance to total time of motion;

[tex]average \ speed = \frac{(5.8 \times 8.9) \ + \ (7.9 \times 12.5) \ + \ (3.2 \times 4.7)}{8.9 \ + \ 3.7 \ + \ 12.5 \ + \ 6.3\ +\ 4.7} \\\\average \ speed = \frac{165.41}{36.1} \\\\average \ speed =4.58 \ m/s[/tex]

Thus, the average speed of Lupert for the entire journey is 4.58 m/s.

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Which of the following correctly compares gravitational force and distance between two objects?

A. As the distance increases, the gravitational force decreases.

B. As the distance decreases, the gravitational force decreases.

C. There is no relationship between gravitational force and distance between two objects.

D. As the distance increases, the gravitational force increases.

Help pls…

Answers

Answer:

a. as the distances increases , the gravitational force decreases

i need help guys please how to do it

Answers

Answering your question but a bit confusing lovesur

True or false. The buildings in cities are getting larger

Answers

Answer:

true

Explanation:

cuase the city is getting more people than before

which of the following is used to transport sound waves
A.medium
B.vacuum
C.mass
D.light​

Answers

I think the answer is d.right?

An object travels 120 m in 6 seconds. How fast is it moving?

Answers

Answer:

I actually don't understand what you are asking for....but if you denote second then...

Explanation:

Just divide 120/6=20

Hence, it's traveling 20m per second.

Answer:

20 m/s

Explanation:

Speed = Distance/Time

Speed = 120m/6s

Speed = 20 m/s

hey I just wanted to know if any of the guys here are able to help answer my physics questions , it would be a great thankyou xoxoxoxo

Answers

what's your question?

A car drives at a constant speed of 45km in 20mn. The speed of the car is..?​

Answers

Answer:

83.8851 mi/h              

How do energy and matter move in ecosystems?(1 point)

Energy and matter flow in one direction.

Matter flows in one direction, and energy cycles through the environment.

Energy flows in one direction, and matter cycles through the environment.

Energy and matter cycle through the environment.

Answers

Answer

Explanation:

Energy flows in one direction,and matter cycle the environment

Energy flows in one direction and matter cycles through the environment in an ecosystem.

What is an ecosystem?

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.There are many ecosystems present in the environment.

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What is metamarket ?

Answers

Answer:

metamarket (plural metamarkets) A group of businesses that offer products that are related from a consumer's perspective but which have no institutional connections. quotations . A market that trades in the medium of exchange of a lower-level market, such as money, derivatives, or credit. quotations.

Explanation:

The best examples of Meta Marketing can be selling family planning ideas or the idea of prohibition. ... Let's say a car selling in a Meta market would be a website, that sells cars but you will also find car parts there, add-ons for cars, colours for cars, mechanic's reviews, etc.

A group of businesses that offer products that are related from a consumer's perspective but which have no institutional connections.

5. A quarterback throws the football to a stationary receiver who is 31.5 m
down the field. If the football is thrown at an initial angle of 40.0° to the
ground, at what initial speed must the quarterback throw the ball for it
to reach the receiver? What is the ball's highest point during its flight?

Answers

The projectile launch equations allow to find the results for the questions about the movement of the ball are:

The initial velocity is:   v₀ = 17.7 m / s. The maximum height is:   y = 16 m.

Given parameters

Horizontal distance x = 31.5 m Launch angle tea = 40º

To find

The initial speed. Maximum height.

Projectile launching is an application of kinematics, where on the x-axis there is no acceleration and on the y-axis is the gravity acceleration.

The range is the distance traveled for the same departure height, see attached.

.

          R =[tex]\frac{v_o^2 \ sin 2\theta}{g}[/tex]  

         [tex]v_o^2 = \frac{ g R}{sin 2 \theta }[/tex]  

Let's calculate.

          v₀² = [tex]\frac{9.8 \ 31.5}{sin \ (2 \ 40)}[/tex]9.8 31.5 / sin (2 40.0)

          [tex]v_o = \sqrt{313.46}[/tex]o = ra 313.46

          v₀ = 17.7 m / s

At the point of maximum height the vertical speed is zero.

          v² = v₀² - 2 g y

          0 = v₀² - 2g y

          y = [tex]\frac{v_o^2}{2g}[/tex]  

Let's calculate.

         y = [tex]\frac{17.7^2}{2 \ 9.8}[/tex]  

         y = 16 m

In conclusion, using the projectile launch equations we can find the results for the questions about the movement of the ball are:

The initial velocity is: v₀ = 17.7 m / s The maximum height is:  y = 16 m.

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Required information
Medical testing has established that the maximum acceleration a pilot can be subjected to without losing consciousness is
approximately 5.00g. A pilot can avoid "blackout" at accelerations up to approximately 9.00g by wearing special "g-suits"
that help keep blood pressure in the brain at a sufficient level.
What is the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h?

Answers

Answer:

hi there is that OK for the weekend of the following week as well

Explanation:

6th of March is fine for me

The minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.

To determine the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop, we need to consider the maximum acceleration the pilot can withstand without losing consciousness.

Given:

Maximum acceleration without losing consciousness = 5.00g

Acceleration with g-suits to avoid blackout = 9.00g

First, we need to convert the speed of the F-15 from km/h to m/s:

Speed = 729 km/h = (729 * 1000) m/3600 s ≈ 202.5 m/s

Next, we'll calculate the acceleration experienced by the pilot in the circular loop. In a horizontal circular motion, the centripetal acceleration is given by:

Acceleration = ([tex]\rm Velocity^2[/tex]) / Radius

We can rearrange the equation to solve for the radius:

Radius = ([tex]\rm Velocity^2[/tex]) / Acceleration

Using the maximum acceleration of 5.00g, we convert it to [tex]\rm m/s^2[/tex]:

Maximum acceleration = 5.00g ≈ (5.00 * 9.8) [tex]\rm m/s^2[/tex] = 49 m/s^2

Now, we can calculate the minimum safe radius of curvature:

Radius = ([tex]\rm 202.5^2[/tex]) / 49 ≈ 838.1 meters

Therefore, the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.

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To see how visual encoding works, read over this list of words: car,
level, dog, truth, book, value. If you were asked later to recall the
words from this list, which ones do you think you'd most likely
remember? Why those words?

Answers

    I think I would most likely remember car, level, dog, and book. I think I would remember these words because car and level came first, I love dogs, and I like reading books. I can associate something with dogs and books so it helps me remember those words.

           [Visual encoding is when people remember things by pictures in their head, but I have aphantasia so I am honestly not the best person to answer this question

Lakepointe Tower in Chicago is the tallest apartment building in the United States (although not the tallest building in which there are apartments). Suppose you take the elevator from street level to the roof of the building. The elevator moves almost the entire distance at constant speed, so that it does 1.15x10^5 J of work on you as it lifts the entire distance. If your mass is 60.0 kg, how tall is the building? Ignore the effects of friction.

Answers

Given the information supplied in the question, the height of the building is  196 m.

The work done on you is a work done in a gravitational field. Recall that the work done in a gravitational field is given by mgh where;

m = mass of the body

g = acceleration due to gravity

h = height

Given that;

Work done = 1.15x10^5 J

Acceleration due to gravity = 9.8 ms-2

Mass =  60.0 kg

Substituting values;

h = W/mg

h =  1.15x10^5 J/ 60.0 kg ×  9.8 ms-2

h = 196 m

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