What is the axis of symmetry of the
parabola graphed below?
O x=4
Oy=2
Oy=4
Ox=2
Other:
Answer:
A
Step-by-step explanation:
i think so..sorry if im wrong
Coordinate plane with quadrilaterals EFGH and E prime F prime G prime H prime at E 0 comma 1, F 1 comma 1, G 2 comma 0, H 0 comma 0, E prime negative 1 comma 2, F prime 1 comma 2, G prime 3 comma 0, and H prime negative 1 comma 0. F and H are connected by a segment, and F prime and H prime are also connected by a segment. Quadrilateral EFGH was dilated by a scale factor of 2 from the center (1, 0) to create E'F'G'H'. Which characteristic of dilations compares segment F'H' to segment FH
Answer:
[tex]|F'H'| = 2 * |FH|[/tex]
Step-by-step explanation:
Given
[tex]E = (0,1)[/tex] [tex]E' = (-1,2)[/tex]
[tex]F = (1,1)[/tex] [tex]F' = (1,2)[/tex]
[tex]G = (2,0)[/tex] [tex]G' =(3,0)[/tex]
[tex]H = (0,0)[/tex] [tex]H' = (-1,0)[/tex]
[tex](x,y) = (1,0)[/tex] -- center
[tex]k = 2[/tex] --- scale factor
See comment for proper format of question
Required
Compare FH to F'H'
From the question, we understand that the scale of dilation from EFGH to E'F'G'H is 2;
Irrespective of the center of dilation, the distance between corresponding segment will maintain the scale of dilation.
i.e.
[tex]|F'H'| = k * |FH|[/tex]
[tex]|F'H'| = 2 * |FH|[/tex]
To prove this;
Calculate distance of segments FH and F'H' using:
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]
Given that:
[tex]F = (1,1)[/tex] [tex]F' = (1,2)[/tex]
[tex]H = (0,0)[/tex] [tex]H' = (-1,0)[/tex]
We have:
[tex]FH = \sqrt{(1- 0)^2 + (1- 0)^2}[/tex]
[tex]FH = \sqrt{(1)^2 + (1)^2}[/tex]
[tex]FH = \sqrt{1 + 1}[/tex]
[tex]FH = \sqrt{2}[/tex]
Similarly;
[tex]F'H' = \sqrt{(1 --1)^2 + (2 -0)^2}[/tex]
[tex]F'H' = \sqrt{(2)^2 + (2)^2}[/tex]
Distribute
[tex]F'H' = \sqrt{(2)^2(1 +1)}[/tex]
[tex]F'H' = \sqrt{(2)^2*2}[/tex]
Split
[tex]F'H' = \sqrt{(2)^2} *\sqrt{2}[/tex]
[tex]F'H' = 2 *\sqrt{2}[/tex]
[tex]F'H' = 2\sqrt{2}[/tex]
Recall that:
[tex]|F'H'| = 2 * |FH|[/tex]
So, we have:
[tex]2\sqrt 2 = 2 * \sqrt 2[/tex]
[tex]2\sqrt 2 = 2\sqrt 2[/tex] --- true
Hence, the dilation relationship between FH and F'H' is::
[tex]|F'H'| = 2 * |FH|[/tex]
Answer:NOTT !! A segment in the image has the same length as its corresponding segment in the pre-image.
Step-by-step explanation:
Quick can someone plot these in a scatter plot
(9.2,2.33)
(19.5,3.77)
(15.5,3.92)
(0.7,1.11)
(21.9,3.69)
(0.7,1.11)
(16.7,3.5)
(0.7,1.11)
(18,4)
(18,3.17)
The scatterplot is below.
I used GeoGebra to make the scatterplot. Though you could use other tools such as Excel or Desmos, or lots of other choices.
Side note: I'm not sure why, but you repeated the point (0.7,1.11) three times.
find the area of this unusual shape
Answer:
38 ft²
Step-by-step explanation:
The shape consists of a rectangle and two triangles.
Area of the shape = area of rectangle + area of the two triangles
✔️Area if the rectangle = L × W
L = 8 + 2 = 10 ft
W = 3 ft
Area of rectangle = 10 × 3 = 30 ft²
✔️Area of the large triangle = ½ × bh
b = 4 ft
h = 3 ft
Area of large triangle = ½ × 4 × 3 = 6 ft²
✔️Area of the small triangle = ½ × bh
b = 2 ft
h = 2 ft
Area of large triangle = ½ × 2 × 2 = 2 ft²
✅Area of the shape = 30 + 6 + 2 = 38 ft²
The starting salaries of individuals with an MBA degree are normally distributed with a mean of $40,000 and a standard deviation of $5,000. What percentage of MBA's will have starting salaries of $34,000 to $46,000
Answer:
The correct answer is "76.98%".
Step-by-step explanation:
According to the question,
⇒ [tex]P(34000<x<46000) = P[\frac{34000-40000}{5000} <\frac{x- \mu}{\sigma} <\frac{46000-40000}{5000} ][/tex]
[tex]=P(-1.2<z<1.2)[/tex]
[tex]=P(z<1.2)-P(z<-1.2)[/tex]
[tex]=0.8849-0.1151[/tex]
[tex]=0.7698[/tex]
or,
[tex]=76.98[/tex]%
What is the range of possible sizes for side x? Please help!
Answer:
x is smaller than 5.6 and greater than 0
Which formula can be used to describe the sequence?
Answer:
B could be used to show the formula to describe the sentence
5) If the local professional basketball team, the Sneakers, wins today's game, they have a 2/3 chance of winning their next game. If they lose this game, they have a 1/2 chance of winning their next game.
A) Make a Markov Chain for this problem; give the matrix of transition probabilities and draw the transition diagram.
B) If there is a 50-50 chance of the Sneakers winning today's game, what are the chances that they win their next game?
C) If they won today, what are the chances of winning the game after the next?
Answer:
If they win today's game, the probability to win the next game = 2/3
Therefore the probability that they lose the next game when they win today's game = 1-(2/3) =1/3.
If they lose today's game, the probability to win the next game = 1/2
so, the probability to lose is 1/2.
a) [tex]\begin{bmatrix} \frac{2}{3}&\frac{1}{2} & \\\\ \frac{1}{3}&\frac{1}{2} & \end{bmatrix}[/tex]
b) [tex]p=\begin{bmatrix} \frac{1}{2}\\\\ \frac{1}{2} \end{bmatrix}[/tex]
[tex]p^{'} =\begin{bmatrix} \frac{7}{12}\\\\ \frac{5}{12} \end{bmatrix}[/tex]
c) Let them win today's game
[tex]p=\begin{bmatrix} 1\\ 0 \end{bmatrix}\\\\\\p^{'} =\begin{bmatrix} \frac{2}{3}\\\\\frac{1}{3} \end{bmatrix}[/tex]
[tex]p^{''}= \left[\begin{array}{c}\frac{11}{18} \\\\\frac{7}{18} \end{array}\right][/tex]
The chances that they win their next game are 58.33%, while if they won today, the chances of winning the game after the next are 38.88%.
ProbabilitiesGiven that if the local professional basketball team, the Sneakers, wins today's game, they have a 2/3 chance of winning their next game, while if they lose this game, they have a 1/2 chance of winning their next game, to determine, if there is a 50-50 chance of the Sneakers winning today's game, what are the chances that they win their next game, and determine, if they won today, what are the chances of winning the game after the next, you must perform the following calculations:
(2/3 + 1/2) / 2 = X1,666 / 2 = X0.58333 = X((2/3 + 1/2 / 2) x 2/3 = X0.58333 x 0.666 = X0.3888 = XTherefore, the chances that they win their next game are 58.33%, while if they won today, the chances of winning the game after the next are 38.88%.
Learn more about probabilities in https://brainly.com/question/10182808
Please help …………………….
9514 1404 393
Answer:
(-3, 3)
Step-by-step explanation:
The blanks are trying to lead you through the process of finding the point of interest.
__
The horizontal distance from T to S is 9 . (or -9, if you prefer)
The ratio you're trying to divide the line into is the ratio that goes in this blank:
Multiply the horizontal distance by 2/3 . (9×2/3 = 6)
Move 6 units left from point T.
The vertical distance from T to S is 6 .
Multiply the vertical distance by 2/3 . (6×2/3 = 4)
Move 4 units up from point T.
__
Point T is (3, -1) so 6 left and 4 up is (3, -1) +(-6, 4) = (3-6, -1+4) = (-3, 3). The point that is 2/3 of the way from T to S is (-3, 3).
If u= 70% and o=5%, what % of scores fall within 3 standard deviations from the mean?
Answer:
"85%" is the right answer.
Step-by-step explanation:
Given:
[tex]\mu = 70[/tex] (%)
[tex]\sigma = 5[/tex] (%)
As we know,
The 99.7% observation fall within the 3rd standard deviation, then
⇒ [tex](\mu \pm \sigma ) = (70-(3\times 5)) \ to \ (70+(3\times 5))[/tex]
[tex]=(70-15) \ to \ (70+15)[/tex]
[tex]=55 \ to \ 85[/tex] (%)
Thus the above is the correct solution.
The product of 86 and the depth of the river
Answer:
Step-by-step explanation:
Are you trying to find a variable expression? the product of 86 means multiplication so 86*n or 86n. Other than that I dont understand the question.
Given the exponential function g(x)= 1∕2(2)^x, evaluate ƒ(1), ƒ(3), and ƒ(6).
A) ƒ(1) = 1, ƒ(3) = 4, ƒ(6) = 32
B) ƒ(1) = 2, ƒ(3) = 9, ƒ(6) = 64
C) ƒ(1) = 1, ƒ(3) = 2, ƒ(6) = 8
D) ƒ(1) = 4, ƒ(3) = 16, ƒ(6) = 128
Answer:
A) ƒ(1) = 1, ƒ(3) = 4, ƒ(6) = 32
Step-by-step explanation:
f(x)= 1∕2(2)^x,
Let x = 1
f(1)= 1∕2(2)^1 = 1/2 ( 2) = 1
Let x = 3
f(3)= 1∕2(2)^3 = 1/2 ( 8) = 4
Let x = 1
f(6)= 1∕2(2)^6 = 1/2 ( 64) = 32
Answer:
A) ƒ(1) = 1, ƒ(3) = 4, ƒ(6) = 32
Step-by-step explanation: I took the test
I need help with this
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do not show that
Rn(x) → 0.] Find the associated radius of convergence R.
f(x) = 8(1 − x)^−2
show step by step including finding the derivatives.
Recall that for |x| < 1, we have
[tex]\displaystyle \frac1{1-x} = \sum_{n=0}^\infty x^n[/tex]
Differentiating both sides gives
[tex]\displaystyle \frac1{(1-x)^2} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=0}^\infty (n+1)x^n[/tex]
and multiplying both sides by 8 gives the series for f(x) :
[tex]f(x)=\displaystyle \frac8{(1-x)^2} = \boxed{8\sum_{n=0}^\infty (n+1)x^n}[/tex]
and this converges over the same interval, |x| < 1, so that the radius of convergence is 1.
Write the quadratic function in the form g(x) = a (x-h)^2 +k.
Then, give the vertex of its graph.
g(x) = 2x^2 + 8x + 10
9514 1404 393
Answer:
g(x) = 2(x +2)² +2
vertex: (-2, 2)
Step-by-step explanation:
It is often easier to write the vertex form if the leading coefficient is factored from the variable terms:
g(x) = 2(x² +4x) +10
Then the square of half the x-coefficient is added inside parentheses, and an equivalent amount is subtracted outside.
g(x) = 2(x² +4x +4) +10 -2(4)
g(x) = 2(x +2)² +2
Comparing to the vertex form, we see the parameters are ...
a = 2, h = -2, k = 2
The vertex is (h, k) = (-2, 2).
The auto parts department of an automotive dealership sends out a mean of 6.3 special orders daily. What is the probability that, for any day, the number of special orders sent out will be exactly 3
Answer:
0.0765 = 7.65% probability that, for any day, the number of special orders sent out will be exactly 3
Step-by-step explanation:
We have the mean, which means that the poisson distribution is used to solve this question.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
The auto parts department of an automotive dealership sends out a mean of 6.3 special orders daily.
This means that [tex]\mu = 6.3[/tex]
What is the probability that, for any day, the number of special orders sent out will be exactly 3?
This is P(X = 3). So
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 3) = \frac{e^{-6.3}*6.3^{3}}{(3)!} = 0.0765[/tex]
0.0765 = 7.65% probability that, for any day, the number of special orders sent out will be exactly 3
A student writes
1 1/2 pages of a report in 1/2
an hour. What is her unit rate in pages per hour?
Answer:
3 pages per hour
Step-by-step explanation:
Take the number of pages and divide by the time
1 1/2 ÷ 1/2
Write the mixed number as an improper fraction
3/2÷1/2
Copy dot flip
3/2 * 2/1
3
9514 1404 393
Answer:
3 pages per hour
Step-by-step explanation:
To find the number of pages per hour, divide pages by hours.
(1.5 pages)/(0.5 hours) = 3 pages/hour
An absolute value function has
A. Curved lines that only increases and decreases.
B. Straight lines that do both increase ,decrease, or stay constant on the same graph
C.Straight line that do both increase and decrease on the same graph
D. Straight lines that only increase or decrease
E. Curved lines that do both increase and decrease on the same graph
Find the probability of 3 success for the binomial experiment with 7 trial and the success probability of 0.3. Then find the mean and standard deviation. Write the formula substitute
the values.
Answer:
[tex]P(x=3)=0.2269[/tex]
Mean=2.1
Standard deviation=1.21
Step-by-step explanation:
We are given that
n=7
Probability of success, p=0.3
q=1-p=1-0.3=0.7
We have to find the probability of 3 success for the binomial experiment and find the mean and standard deviation.
Binomial distribution formula
[tex]P(X=x)=nC_xp^{x}q^{n-x}[/tex]
Using the formula
[tex]P(x=3)=7C_3(0.3)^3(0.7)^{7-3}[/tex]
[tex]P(x=3)=7C_3(0.3)^3(0.7)^{4}[/tex]
[tex]P(x=3)=\frac{7!}{3!4!}(0.3)^3(0.7)^{4}[/tex]
[tex]P(x=3)=\frac{7\times 6\times 5\times 4!}{3\times 2\times 1\times 4!}(0.3)^{3}(0.7)^{4}[/tex]
Using the formula
[tex]nC_r=\frac{n!}{r!(n-r)!}[/tex]
[tex]P(x=3)=0.2269[/tex]
Now,
Mean, [tex]\mu=np=7\times 0.3=2.1[/tex]
Standard deviation, [tex]\sigma=\sqrt{np(1-p)}[/tex]
Standard deviation, [tex]\sigma=\sqrt{7\times 0.3\times 0.7}[/tex]
Standard deviation, [tex]\sigma=1.21[/tex]
A. If x:y= 3:5, find = 4x + 5 : 6y -3
Answer:
17 : 27
Step-by-step explanation:
x=3
y=5
4(3)+5 : 6(5)-3
= 12+5 : 30-3
= 17 : 27
Claims from Group A follow a normal distribution with mean 10,000 and standard deviation 1,000. Claims from Group B follow a normal distribution with mean 20,000 and standard deviation 2,000. All claim amounts are independent of the other claims. Fifty claims occur in each group. Find the probability the total of the 100 claims exceeds 1,530,000.
Answer:
0.0287 = 2.87% probability the total of the 100 claims exceeds 1,530,000.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n instances of a normal variable:
For n instances of a normal variable, the mean is [tex]n\mu[/tex] and the standard deviation is [tex]s = \sigma\sqrt{n}[/tex]
Sum of normal variables:
When two normal variables are added, the mean is the sum of the means, while the standard deviation is the square root of the sum of the variances.
Group A follow a normal distribution with mean 10,000 and standard deviation 1,000. 50 claims of group A.
This means that:
[tex]\mu_A = 10000*50 = 500000[/tex]
[tex]s_A = 1000\sqrt{50} = 7071[/tex]
Group B follow a normal distribution with mean 20,000 and standard deviation 2,000. 50 claims of group B.
This means that:
[tex]\mu_B = 20000*50 = 1000000[/tex]
[tex]s_B = 2000\sqrt{50} = 14142[/tex]
Distribution of the total of the 100 claims:
[tex]\mu = \mu_A + \mu_B = 500000 + 1000000 = 1500000[/tex]
[tex]s = \sqrt{s_A^2+s_B^2} = \sqrt{7071^2+14142^2} = 15811[/tex]
Find the probability the total of the 100 claims exceeds 1,530,000.
This is 1 subtracted by the p-value of Z when X = 1530000. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{1530000 - 1500000}{15811}[/tex]
[tex]Z = 1.9[/tex]
[tex]Z = 1.9[/tex] has a p-value of 0.9713
1 - 0.9713 = 0.0287
0.0287 = 2.87% probability the total of the 100 claims exceeds 1,530,000.
sin x - cos x - 1/√2 = 0
Find the value of x
Answer:
Step-by-step explanation:
Serkan teacher regularly buys 75 TL of gasoline in his car every week.
At the end of the 13th week, how much is the total gasoline expenditure made by the serkan teacher?
A)390 B)420 C)900 D)975
Answer:
d
Step-by-step explanation:
75 per week,
after 13 weeks, 75*13 = 975
solve above question
what is 24 subtracted from 8
Hi!
8 - 24 = -(24 - 8) = -16
Answer:
-16
Step-by-step explanation:
8-24=-16
Muhammad lives twice as far from the school as Hita. Together, the live a total of 12 km
from the school. How far away drom the school does each of them live?
Answer:
Muhammad lives 8 km away from the school.
Hita lives 4 km away from the school.
Step-by-step explanation:
First of all, find a number that, when you double that number and add both numbers, you will get 12. That number is 4. So double 4 and get 8. Then add both to get 12.
lisa used 880g of a container of sugar to bake a cake and 1/10 of the creaming sugar to make cookies. She then had 3/7 of the container of sugar left. How much sugar was in the container at first
Answer:
At the beginning, there were 2,678.26 grams of sugar in the container.
Step-by-step explanation:
Since Lisa used 880g of a container of sugar to bake a cake and 1/10 of the creaming sugar to make cookies, and she then had 3/7 of the container of sugar left, to determine how much sugar was in the container at first, the following calculation must be performed:
880 + 1 / 10X = 3 / 7X
880 + 0.1X = 0.4285X
880 = 0.4285X - 0.1X
880 = 0.3285X
880 / 0.3285 = X
2,678.26 = X
Therefore, at the beginning there were 2,678.26 grams of sugar in the container.
is “x = -3” a function
Answer:
No
Step-by-step explanation:
x = -3 is a vertical line at x= -3
Tow points on the line are
(-3,1) and (-3,2)
This means one x value goes to 2 different y values so it is not a function
Answer: No
Step-by-step explanation: The line x = -3 is a vertical or straight up and down line that is parallel to the y-axis. On the vertical line x = -3, when x = -3, y can be 0, 1, 2, -5, or any other number, there are in infinite number of possibilities.
The technical definition of a function is written as "a relation in which each element in the domain is paired with one and only one element in the range."
The edge roughness of slit paper products increases as knife blades wear. Only 2% of products slit with new blades have rough edges, 3% of products slit with blades of average sharpness exhibit roughness, and 4% of products slit with worn blades exhibit roughness. If 25% of the blades in the manufacturing are new, 60% are of average sharpness, and 15% are worn, what is the proportion of products that exhibit edge roughness
Answer:
The proportion of products that exhibit edge roughness is 0.029 = 2.9%.
Step-by-step explanation:
Proportion of products that exhibit edge roughness:
2% of 25%(new blades).
3% of 60%(average sharpness).
4% of 15%(worn). So
[tex]p = 0.02*0.25 + 0.03*0.6 + 0.04*0.15 = 0.029[/tex]
The proportion of products that exhibit edge roughness is 0.029 = 2.9%.
Samir estimates the value of Three-fifths times 16.1. Which estimate is reasonable?
3
9
12
15
Answer: 9
Step-by-step explanation:
[tex] \frac{3}{5} \times 16.1 = 9.66[/tex]
