Answer:
por que a mi saber, cuando te infectas con una enfermedad viral al contagiarte y después sanar tu cuerpo crea anticuerpos que estos asu vez hacen que seas inmune a ese virus y otras veces las enfermedades son erradicadas con la vacunación.
Use the coordinates of the labeled point to find the point-slope equation of
the line
-5
5
-5
(3.-5)
O A. y+ 5 = -3(x - 3)
B. y- 5 = -3(x+3)
C. y + 5 = 3(x+3)
O D. Y-3 - (x+5)
Answer:
A. y + 5 = -3(x - 3)
Explanation:
Given the following data;
Points on the graph (x1, y1) = (3, -5)
Points on the graph (x2, y2) = (0, 4)
First of all, we would determine the slope of the equation of line;
Mathematically, the slope of a line is given by the formula;
[tex] Slope, \ m = \frac {Change \; in \; y-axis}{Change \; in \; x-axis} [/tex]
[tex] Slope, \ m = \frac {y_{2} - y_{1}}{x_{2} - x_{1}} [/tex]
Substituting into the formula, we have;
[tex] Slope, \ m = \frac {4 - (-5)}{0 - 3} [/tex]
[tex] Slope, \ m = \frac {4 + 5}{0 - 3} [/tex]
[tex] Slope, \ m = \frac {9}{-3} [/tex]
Slope, m = -3
Next, to find the point-slope equation of the line, we would use the following formula;
y - y1 = m(x - x1)
y - (-5) = -3(x - 3)
y + 5 = -3x + 9
y = -3x + 9 - 5
y = -3x + 4 = mx + c
(URGENT) Which of these statements is correct about the ocean waves? (100 points)
A) Wave 1 and Wave 2 have the same wavelength.
B) Wave 2 and Wave 3 have the same wavelength.
C) Wave 1 and Wave 2 have the same amplitude.
D) Wave 2 and Wave 3 have the same amplitude
Answer:
D
Explanation:
Wave 2 and Wave 3 have the same amplitude.
Which of the following was not part of the original cell theory, but was added later after we learned more about cellular structure
where is full question man
how long does it take for a CRISPR to work?
The brain generally stores new information in its own different and unique netowrk but retrieves information by chunking it with information in netowkrs that contain similar characteristics or associations.
a. True
b. False
Should we clone animals that are going or have gone extinct (in other words bring them back
either from the brink of extinction or from extinction)? Explain your answer.
Answer:
I think we should but people are preventing this though
Explanation:
I think we should because it might benefit the world and let scientists to discover this animal. But then I don't think so because animals that are/were extinct could perhaps be from climate change. Nowadays, people don't take this matter seriously causing habitats to be destroyed and animals to be extinct :) Like icebergs are melting that mean penguins are at risk of being extinct,if we did something then this situation will be prevented. However dinosaurs did become extinct and they did not come back so its probably just life and this is how god planned it:)
An adult giraffe (Giraffa camelopardalis) has a heart that lies approximately 2 m below the top of the head when its neck is fully extended. Calculate the minimum diastolic pressure that a giraffe must have (in mm Hg). Hint: what is the absolute minimum blood pressure a giraffe could have at the very top of its head
Answer:
159.01 mmHg
Explanation:
position of Heart = 2m below the top of the head given that the neck is fully extended
Determine the minimum diastolic pressure
Minimum diastolic Pressure = 1060 kg/m^3 * 10 m/s^2 * 2m
= 21200 kg/m^2
convert the value to Pa
21200 kg/m^2 = 21200 Pa
( 1 pa = 0.00750062 mmHg )
Therefore : minimum diastolic pressure = 21200 * 0.00750062 = 159.01 mmHg
The minimum diastolic pressure that a giraffe must have is 150 mmHg
Diastolic Blood pressureDiastolic Blood pressure is the pressure on the walls of your arteries between heartbeats, that is when the heart is resting.
The minimum diastolic diastolic blood pressure = absolute minimum blood pressure a giraffe could have at the very top of its head.Pressure formulaP = hpg
where;
P = pressure
h = height difference
p = density
g = acceleration due to gravity
Density of blood = 1000 kg/m^3
h =2.0 m
g = 10 m/s^2
Pressure = 1000 × 2.0 × 10
Pressure = 20000 Pascal or 20 kpa
Converting to mmHg1 kpa = 7.50 mmHg
20 kpa = 20 × 7.50
Pressure = 150 mmHg
Therefore, the minimum diastolic pressure that a giraffe must have is 150 mmHg
Learn more about diastolic blood pressure at: https://brainly.com/question/14661197
A scientist finds that another molecule has contaminated the mixture he is working with in the lab. When he analyzes its chemical structure, he finds that it contains uracil, is single stranded, and contains phosphate. What molecule has likely contaminated his mixture?
nucleotide
protein
DNA
RNA
Answer:
RNA
Explanation:
A ribonucleic acid (RNA) is one of two types of nucleic acid made up of nucleotide subunits. RNA is a single stranded molecule unlike DNA, which is double stranded. The nucleotide unit of nucleic acids is composed of a nitrogenous base (Adenine, Guanine, Cytosine and Thymine/Uracil), a pentose sugar (ribose and deoxyribose) and a phosphate group.
One of the key structural differences between RNA and DNA is that RNA contains URACIL nitrogenous base instead of THYMINE in DNA.
According to this question, a scientist finds that another molecule has contaminated the mixture he is working with in the lab. When he analyzes its chemical structure, he finds that it contains uracil, is single stranded, and contains phosphate. This illustrates that the contaminating molecule is a specific type of nucleic acid called RNA.
Answer:
rna
Explanation:
Which best explains why sawdust burns more quickly than a block of wood of equal mass under the same conditions?
The molecules move more quickly in the sawdust than in the block of wood.
The pressure of oxygen is greater on the sawdust.
More molecules in the sawdust can collide with oxygen molecules.
Oxygen is more concentrated near the sawdust than the block of wood.
Which best explains why, under the same circumstances, sawdust burns more fast than a wood block of equivalent mass The molecules in the sawdust move more swiftly than those in the
A thermal burn is what?
An injury to the skin or other organic tissue known as a burn is one that is primarily brought on by heat, radiation, radioactivity, electricity, friction, or contact with chemicals. When hot liquids, heated solids, or flames come in touch with the skin and other tissues, part or all of the skin's cells are destroyed (flame burns)
What various sorts of Burns are there?
This tiny burn merely penetrates the skin's surface layer (epidermis). It might hurt and make you red. second-degree burn Both the epithelium and the next layer of skin are affected by this kind of burn (dermis). It could result in skin that is swollen, red, white, or patchy. The pain may become intense and blisters may form. Scarring may result from second-degree burns that are deep.
To know more about burns visit:
https://brainly.com/question/14152400
#SPJ1
Answer:
C.More molecules in the sawdust can collide with oxygen molecules.
Explanation:
real
In the lung alveoli, the oxygen partial pressure is about 100 mm of mercury, or 0.13 Atm. If blood was solely composed of a saline solution (lacking any hemoglobin), oxygen equilibrates with the alveolar air to a concentration of about 3 mg/L or 0.093 mm). In oxygen-saturated blood, however, the O2 concentration is about 0.008 M (8 mm).
Required:
a. What is the Henry's Law constant for oxygen in saline?
b. What is the Henry's Law constant for oxygen in blood?
c. How much does the presence of hemoglobin enhance oxygen solubility in blood (i.e. what is the ratio in blood vs saline)?
Answer:
Picture is attached.
According to a famous article by Max Kleiber, the scaling of the metabolic rate or energy consumption for mammals Pmetab (measured in kcal/day) with the body mass Mb (measured in kilograms) is Pmetab=70M0.75b.
a. What is the specific metabolic rate, i.e. the metabolic rate per kilogram of body mass for the following animals?a mouse whose mass is 30g. Give your answer to three significant figures.
b. What is the specific metabolic rate, i.e. the metabolic rate per kilogram of body mass for the following animals?a cow whose mass is 300kg. Give your answer to three significant figures.
Answer:
Explanation:
Given that:
The scaling of the specific metabolic rate is:
[tex]=\dfrac{P_{metab}}{m}[/tex]
where;
[tex]P_{metab} = 70M_b^{0.75}[/tex]
[tex]=\dfrac{ 70M_b^{0.75}}{m}[/tex]
(a) For a mouse whose mass = 30 g = 0.030 kg
The specific metabolic rate [tex]=\dfrac{ 70*(0.030)^{0.75}}{(0.030)}[/tex]
= 168.197 kg
≅ 168 kg to 3 significant fig.
(a) For a cow whose mass = 300 kg
The specific metabolic rate [tex]=\dfrac{ 70*(300)^{0.75}}{(300)}[/tex]
= 16.8197 kg
≅ 16.8 kg to 3 significant fig.
g Jack fell down and broke his crown. He broke the most anterior bone connected to the coronal suture. What LETTER is this, and what is the NAME of this bone
The negative effects of chemical control of weeds on rangelands
Answer:
Chemical residue remain on the vegetation.
Explanation:
The negative effects of chemical control of weeds on rangelands is that the chemical residue remain on the vegetation in rangeland which is dangerous for animals that feed on vegetation because the chemicals are toxic that cause serious damaged. Sometime the chemical also damaged the weeds as well as vegetation of rangelands and also kill the beneficial insects that is needed by the plants present in rangelands.
3. Explain the main difference between organisms of the
domains Bacteria and Archaea and organisms of the domain
Eukarya.
Answer:
Both Bacteria and Archaea are prokaryotes, single-celled microorganisms with no nuclei, and Eukarya includes us and all other animals, plants, fungi, and single-celled protists – all organisms whose cells have nuclei to enclose their DNA apart from the rest of the cell.
Explanation:
Both Bacteria and Archaea are prokaryotes, single-celled microorganisms with no nuclei, and Eukarya includes us and all other animals, plants, fungi, and single-celled protists – all organisms whose cells have nuclei to enclose their DNA apart from the rest of the cell.
phương pháp tạo vòng halo???
Answer:
lol
xplanation:
Answer:
jîâr erçvñ.
Explanation:
hñkgdà34vkffjGydlkydkeutskdeut
Which of the following are NOT examples of data?
a.
facts
b.
figures
c.
theories
d.
measurements
Please select the best answer from the choices provided
A
B
C
D
Answer:
b
Explanation:
becusen yes
Answer:
Your answer would be C
Explanation:
Theories are not proven, they are simply ideas we come up with
Explain why it is not advisable for two sickle cell carriers to marry.
Answer:
it results in pleiotropic effect and caused death of an offspring.
What is the dewpoint temperature when the dry-bulb temperature is 12°C and the wet-bulb
temperature is 4°C?
1. -9°C
2. 19°C
3. 8°C
4. 4°C
Answer:
-9°C That is the answer
Explanation:
hope it helps!
Provide details about Meiosis.
Two of the five types of taste buds are activated by directly hypopolarizing the taste buds; i.e. do not involve a second-messenger pathway. The tastes that activate these receptors are:
Answer: salty and sour
Explanation:
Taste buds consist of the taste receptor cells and they're the nerve endings on the tongue that provide the sense of taste.
Based on the information given, the tastes that activate these receptors are salty and sour. The tastes depolarize the cell receptor directly.
what type of properties change in a physical change?Give an example to support the answer?
Identify the phases of meiosis I described below
animals with scales on skin are called?
Answer:
Animals with scales on their skin are called reptiles..hope it helps
stay safe healthy and happy...The most common Class II variant is the F508del variant, which is missing the 508th amino acid in the protein but has an otherwise normal sequence. Loss of this amino acid leads to misfolding of the protein, and the misfolded protein is not properly transported to the membrane. Based on this information, how many nucleotides are deleted in the CFTR allele encoding this variant?
Answer:
The correct answer is - 3 (two codons of 507th that are U, C, and the first nucleotide of 508th codon U).
Explanation:
Each amino acid is coded by a three-nucleotide base long codon. So in the case of the F508del variant, there is a deletion of three nucleotides that is encoded for phenylalanine amino acid.
In this isoleucine is encoded by 507th codon that is AUG and 508th codon is UUU codes for Isoleucine.
In this case, two codons of 507th are U, C, and the first nucleotide of 508th codon U. So overall three nucleotides are deleted in the F508del variant..
I need help assay about Biopsychology can someone help me?
⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂⁂
✍︎ The core assumption of a biopsychological approach is the fact that illness and health come as a result of a given interplay. In this case it should be known that this interplay revolves around factors like psychological, social and even biological aspects. Most notably, there is always an initiative and attempt to understand the aspect of psychopathology that is done through proper examining.
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꧁❁ ⁱ ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ❁꧂
The pedigree below concerns the autosomal recessive disease phenylketonuria (PKU). The couple marked A and B are contemplating having a baby but are concerned about the baby having PKU. What is the probability of the first child having PKU
Answer: Hello your question some missing data attached below is the complete question
answer:
P( first child having PKU ) 0.25 ≤ x ≤ 0.5
Explanation:
The pedigree father has PKU ( pp ) ( From the top right )
pedigree mother = PP
The possible resultant progeny = Pp
Resultant progeny marries non-carrier ( Pp x PP ) = PP , PP, pP, pP
Hence B is either ; PP ( non carrier ) or Pp ( carrier )
From left
one of the Resultant progeny = pp ( affected ). this simply means pedigree parents where both carriers or sufferers i.e. Pp or pp
Hence A is either ; Pp or pp
The probability of their first child having PKU
= PP x Pp = PP, Pp, PP, Pp ( probability = 0 in this case )
= Pp x Pp = PP, Pp, pP, pp ( probability = 1/4 * 100 = 25% )
= Pp x pp = Pp, Pp, pp, pp ( probability = 2/4 * 100 = 50% )
P( first child having PKU ) 0.25 ≤ x ≤ 0.5
lets denote dominant Gene = PP, recessive Gene = pp
Which is true if energy in ecosystem
Explanation:
energy flows in only one direction through an ecosystem.
Toluene crosses pure lipid bilayers many hundreds of times faster than a related compound, phenylalanine. Suggest two different properties of these molecules that would account for this difference.
Answer:
The lipid bilayer is hydrophobic that is hydrophobic and it can easily cross the lipid bilayer.
Toulene is a hydrophobic and neutral molecule compound so it can easily pass through the bilayer. It is an aromatic compound with a methane group attached to the benzene ring. It is smaller in comparison to Phenylalanine.
Phenylalanine-- It is an amino acid with a benzene ring attached to it. This amino acid is less hydrophobic than the aliphatic amino acids. Because of its less hydrophobic nature, it travels slowly compared to Toluene. It is also larger and has amino and carboxyl groups attached to it. On the other hand, Phenylalanine is a polar compound which has -COOH and -NH2 group. which prevents its delay in its transport across the lipid bilayer.
Describe the normal process of osteogenesis for compact and spongy bone using the three different types of bone cells and their functions
Answer:
Osteoblasts penetrate the disintegrating cartilage and replace it with spongy bone. This forms a primary ossification center. Ossification continues from this center toward the ends of the bones. After spongy bone is formed in the diaphysis, osteoclasts break down the newly formed bone to open up the medullary cavity.
A mutation is identified in a tumor sequencing study. Which of the following pieces of evidence would most strongly suggest that the mutation is a passenger mutation?
a. The same gene is mutated in many other individuals with the same kind of cancer.
b. The mutation impacts the function of a known tumor suppressor gene.
c. The mutation is a silent point mutation in a protein-coding sequence.
d. The gene carrying the mutation is known to participate in the cell cycle.
Answer:
The mutation is a silent point mutation in a protein-coding sequence.
Explanation:
A mutation is a change or alteration in DNI sequences that introduce new variants. Many of these are eliminated, but some of them might succeed and be incorporated into each individual. Mutations can be damaging or beneficial.
There are two types of mutations in cancerous cells:
· Driver mutations, which refer to genetic changes that provide malign cells an adaptative advantage. These mutations drive the cells to tumoral evolution.
· Passenger mutations, also known as neutral mutations, refer to those that do not provide any advantage nor disadvantage to the cancerous cell. These mutations can be between DNI segments where the driver mutations are. Some of these passenger mutations might become driver mutations with time.
