Point C is the center of dilation. Line segment B A is dilated to create line segment B prime A prime. The length of C A is 4. The length of A A prime is 16. What is the scale factor of the dilation of line segment BA?

Answer:

all except the first

Step-by-step explanation:

do u really want an explanation

Answer:

y = a^x is an exponential function with an x intercept.

Step-by-step explanation:

y = a^x is the standard form of an exponential function.

Answer:

Step-by-step explanation:

Let's write that out completely:

[tex]ln_e(x)=7[/tex] The rule for going from log to exponential is what I call the "circular rule" in my classes and the kids never forget it. Take the base of the log, raise it to the power of the number on the other side of the equals sign, and then circle back to set it equal to the argument.

e is the base. Raise e to the 7th and circle back to set the whole thing equal to x (x is called the argument):

[tex]e^7=x[/tex] choice C.

Answer:

X1=6

X2=7

y1= -1

y2= 3

now,

slope = y2-y1/x2-x1

= 3+1/7-6

=4/1

=1

hence slope= 1

Answer:

SOH-CAH-TOA

[tex]\sin \left(x\right)=\frac{6}{\sqrt{49+36}}[/tex] = 40.60°

SOH = SIN = OPP/HYP

SIN(Θ) = 6/[tex]\sqrt{49+36 }[/tex]

Step-by-step explanation:

Answer:

x = 1

y=1.5

Step-by-step explanation:

3*1+2*1.5=6

The values of x and y in equation 6=3x+2y is for x is 1 and for y is 1.5.

We have given that,

x and y are integers and 0 < x < y.

6 = /3x+2y.

x=1 then

A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.

6=3+2y

6-3=2y

3/2=y

y=1.5

3*1+2*1.5=6

Therefore we get the values of x and y is for x is 1 and for y is 1.5.

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Answer:

An angle bisector

Step-by-step explanation:

An angle bisecter

Answer:

i think its all real numbers

Step-by-step explanation:

i think!! im not so sure

Answer:

x = 3

y = 2

Step-by-step explanation:

3x - y = 7   ------------(i)

2x - 2y = 2 ---------(ii)

Multiply equation (i) by (-2)

(i)*(-2)          - 6x + 2y = -14

(ii)                 2x  - 2y =2     {Add both equation. now y will be eliminated}

                    -4x         = -12          {Divide both sides by -4}

                             x = -12/-4

x = 3

Plug in x = 3 in equation (i)

2*3 - 2y = 2

6 - 2y = 2    

Subtract 6 from both sides

 -2y = 2 - 6

  -2y = -4

Divide both sides by 2

      y = -4/-2

y = 2

Answer:

x = 3, y = 2

Step-by-step explanation:

Given the 2 equations

3x - y = 7 → (1)

2x - 2y = 2 → (2)

Multiplying (1) by - 2 and adding to (2) will eliminate the y- term

- 6x + 2y = - 14 → (3)

Add (2) and (3) term by term to eliminate y

- 4x + 0 = - 12

- 4x = - 12 ( divide both sides by - 4 )

x = 3

Substitute x = 3 into either of the 2 equations and solve for y

Substituting into (1)

3(3) - y = 7

9 - y = 7 ( subtract 9 from both sides )

- y = - 2 ( multiply both sides by - 1 )

y = 2

solution is (3, 2 )

Answer:

AED 972

Step-by-step explanation:

Area of the wall = 9² = 81 m²

each m² costs AED 12

so 81 m² will cost 12×81 = AED 972

Answer:

1/8

Step-by-step explanation:

Let "A" = the next call of a customer's complaint

Let "B" = the next call completed under 5 minutes

P(A) = 1/4

P(B) = 1/2

So ----> P(AB) = P(A) times P(B) P(AB)

                       = 1/4 times 1/2 = 1/8

Answer:

[tex] = \frac{2}{4} \div \frac{1}{4} [/tex]

find reciprocal of ¼:

[tex] = \frac{2}{4} \times \frac{4}{1} \\ \\ = \frac{2}{1} \\ \\ = 2[/tex]

Answer:

2

Step-by-step explanation:

the first step is to change the sign from a division sign to a multiplication sign and when you change the sign you also have to swap one side by placing the numerator down and the denominator up

2/4÷1/4

2/4×4/1

8/4

2

I hope this helps

Answer:

[tex]\huge\boxed{width=12cm}[/tex]

Step-by-step explanation:

[tex]l-length\\w-width\\P-perimeter[/tex]

The formula of perimeter of the rectangle:

[tex]P=2l+2w=2(l+w)[/tex]

Substitute:

[tex]l=6w\\\\P=168cm[/tex]

[tex]168=2(6w+w)\\168=2(7w)\\168=14w\qquad|\text{divide both sides by 14}\\\\\dfrac{168}{14}=\dfrac{14w}{14}\\\\12=w\Rightarrow w=12(cm)[/tex]

Answer:

Width of rectangle = 12 cm

Step-by-step explanation:

Let us assume that,

→ Length = 6x

→ Width = x

→ Perimeter = 168 cm

Perimeter of rectangle,

→ P = 2(L + W)

Forming the equation,

→ 168 = 2(6x + x)

Now the value of x will be,

→ 168 = 2(6x + x)

→ 2 × 7x = 168

→ 14x = 168

→ x = 168/14

→ [ x = 12 ]

Then the length and width is,

→ Length = 6x = 6(12) = 72 cm

→ Width = x = 12 cm

Hence, required width is 12 cm.

Answer:

5.1

Step-by-step explanation:

ik i am in the future

Answer:

-0.6

Step-by-step explanation:

Answer:

⅗ as a decimal is -0.6

Answer:

b is the correct answer

Step-by-step explanation:

Let numerator be x

ATQ

[tex]\\ \sf\longmapsto x+x+2=12[/tex]

[tex]\\ \sf\longmapsto 2x+2=12[/tex]

[tex]\\ \sf\longmapsto 2x=12-2[/tex]

[tex]\\ \sf\longmapsto 2x=10[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{10}{2}[/tex]

[tex]\\ \sf\longmapsto x=5[/tex]

Now the fraction is

[tex]\\ \sf\longmapsto \dfrac{x}{x+2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{5}{5+2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{5}{7}[/tex]

-- Their sum is 12.

-- If they were equal, each would be 6.

-- To make them differ by 2 without changing their sum, move 1 from the numerator (make it 5), to the denominator (make it 7).

Step-by-step explanation:

5.

[tex](5 + 4 \sqrt{7} ){x}^{2} + (4 - 2 \sqrt{7} ) x- 1 = 0[/tex]

Simplify both radicals.

[tex](5 + \sqrt{112) {x}^{2} } + (4 - \sqrt{28} )x - 1 = 0[/tex]

Apply Quadratic Formula

First. find the discramnint.

[tex](4 - \sqrt{28} ) {}^{2} - 4(5 + \sqrt{112} )( - 1) = 64[/tex]

Now find the divisor 2a.

[tex]2(5 + \sqrt{112} ) = 10 + 8 \sqrt{7} [/tex]

Then,take the square root of the discrimant.

[tex] \sqrt{64} = 8[/tex]

Finally, add -b.

[tex] - (4 + 2 \sqrt{7} )[/tex]

So our possible root is

[tex] - (4 + 2 \sqrt{7} ) + \frac{8}{10 + 8 \sqrt{7} } [/tex]

Which simplified gives us

[tex] \frac{ 4 + 2 \sqrt{7} }{10 + 8 \sqrt{7} } [/tex]

Rationalize the denominator.

[tex] \frac{4 + 2 \sqrt{7} }{10 + 8 \sqrt{7} } \times \frac{10 - 8 \sqrt{7} }{10 - 8 \sqrt{7} } = \frac{ - 72 - 12 \sqrt{7} }{ - 348} [/tex]

Which simplified gives us

[tex] \frac{6 + \sqrt{7} }{29} [/tex].

6. The answer is 2.

9514 1404 393

Answer:

  5. x = (6 +√7)/29; a=6, b=1, c=29

  6. x = 2

Step-by-step explanation:

The quadratic formula can be used, where a=(5+4√7), b=(4-2√7), c=-1.

  [tex]x=\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{-(4-2\sqrt{7})+\sqrt{(4-2\sqrt{7})^2-4(5+4\sqrt{7}})(-1)}{2(5+4\sqrt{7})}\\\\=\dfrac{-4+2\sqrt{7}+\sqrt{16-16\sqrt{7}+28+20+16\sqrt{7}}}{10+8\sqrt{7}}=\dfrac{4+2\sqrt{7}}{2(5+4\sqrt{7})}\\\\=\dfrac{(2+\sqrt{7})(5-4\sqrt{7})}{(5+4\sqrt{7})(5-4\sqrt{7})}=\dfrac{10-3\sqrt{7}-28}{25-112}=\boxed{\dfrac{6+\sqrt{7}}{29}}[/tex]

__

Use the substitution z=3^x to put the equation in the form ...

  z² -3z -54 = 0

  (z -9)(z +6) = 0 . . . . . factor

  z = 9 or -6 . . . . . . . . value of z that make the factors zero

Only the positive solution is useful, since 3^x cannot be negative.

  z = 9 = 3^2 = 3^x . . . . use the value of z to find x

  x = 2

Answer:

–10m4n3 + 8m2n6 + 3m4n3 – 2m2n6 – 6m2n6 = -7m4n3

⇒It is a monomial with a degree of 7 is correct

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

64^1/3

cube root of 64 is

4

Answer:

C

Step-by-step explanation:

Using the rule of exponents

[tex]a^{\frac{1}{3} }[/tex] ⇔ [tex]\sqrt[3]{a}[/tex] , then

[tex]64^{\frac{1}{3} }[/tex] = [tex]\sqrt[3]{64}[/tex] = 4 → C

Answer:

3x+4

Step-by-step explanation:

You have to combine like terms to get 3x+4.

Answer: -1

Step-by-step explanation:

12x^2-7x-12 = (4x+3)(3x-4)

4x+3=0. X = -3/4

3x-4=0. X = 4/3

(-3/4) (4/3) = -1

Answer:

not enough info

Step-by-step explanation:

Answer:

1. Given

2. Def of Vertical Angles

3. Alternate Interior Angles

4. Def of Vertical angles

5. Opposite exterior angles

Step-by-step explanation:

9514 1404 393

Answer:

  c = 14

  no extraneous solutions

Step-by-step explanation:

You can subtract the right-side expression, combine fractions, and set the numerator to zero.

  [tex]\dfrac{c-4}{c-2}-\left(\dfrac{c-2}{c+2}-\dfrac{1}{2-c}\right)=0\\\\\dfrac{c-4}{c-2}-\dfrac{1}{c-2}-\dfrac{c-2}{c+2}=0\\\\\dfrac{(c-5)(c+2)-(c-2)^2}{(c-2)(c+2)}=0\\\\\dfrac{(c^2-3c-10)-(c^2-4c +4)}{(c-2)(c+2)}=0\\\\\dfrac{c-14}{(c-2)(c+2)}=0\\\\\boxed{c=14}[/tex]

__

Check

  (14 -4)/(14 -2) = (14 -2)/(14 +2) -1/(2 -14) . . . . substitute for c

  10/12 = 12/16 -1/-12

  5/6 = 3/4 +1/12 . . . . true

There is one solution (c=14) and it is a solution to the original equation. There are no extraneous solutions.

Answer:

765(7-()83)₹8_!_?84?8₹92092)8₹+!_()

Answer:

Plug x-7 in for y, in the bottom equation.

x - 7 = 2 + 2x - 4

x - 7 = 2x - 2

x = 2x + 5

-x = 5

x = -5