Plz help me I will give you 40 points and Brainly if it is right

Plz Help Me I Will Give You 40 Points And Brainly If It Is Right

Answers

Answer 1

Answer:

sorry I can't solve the problem

Answer 2
Umm I don’t know anything about this but message me if u needed anything else

Related Questions

If f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,
find f(x) – g(x).

Answer: x^2 - 4x + 3

Answers

Answer:

f(x) – g(x) = x^2 - 4x + 3

Step-by-step explanation:

f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,

f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)

Distribute the minus sign

f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2

  Combine like terms

f(x) – g(x) = x^2 - 4x + 3

 

describe the transformation of the equation below from the parent function of y=|x| y=|x-4| left 4, right 4, up 4, down4

Answers

Answer:

The transformation is right 4

Step-by-step explanation:

Since the transformation occurred inside the absolute value function, this means there will be a horizontal shift. Therefore, the transformation is right 4.

Observe the graph to view the transformation.

I need help anyone please

Answers

Answer:

Base: 7

Height:10

BH divided by two so

7 times 10 = 70 divided by two 35

Base: 7 yd

Height: 10 yd

Area: 35 square yd

         ([tex]A=\frac{h_{b}b }{2}[/tex] = [tex]\frac{10*7}{2}[/tex] = 35)

hope this helps....

Please answer the question in order please.

Answers

Answer:

Step-by-step explanation:

On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?

(2, 3)
(–2, 3)
(3, 2)
(3, –2)On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).
Trapezoid GHJK was rotated 180° about the origin to determine the location of G'H'J'K', as shown on the graph. What are the coordinates of pre-image point H?

(2, 3)
(–2, 3)
(3, 2)
(3, –2)

Answers

Answer:

the coordinates of pre - image point H is (3,2)

Answer:

c time for learning

Step-by-step explanation:

ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
prove triangle ACD and BCE are congruent​

Answers

Given:

ABC is an isosceles triangle in which AC =BC.

D and E are points on BC and AC such that CE=CD.

To prove:

Triangle ACD and BCE are congruent​.

Solution:

In triangle ACD and BCE,

[tex]AC=BC[/tex]                  (Given)

[tex]AC\cong BC[/tex]

[tex]\angle C\cong m\angle C[/tex]                  (Common angle)

[tex]CD=CE[/tex]                  (Given)

[tex]CD\cong CE[/tex]

In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.

[tex]\Delta ACD\cong \Delta BCE[/tex]           (SAS congruence postulate)

Hence proved.

Answer:

Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD

Given AB=AC

∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)

Given BE=CD

Then BE−DE=CD−DE

ORBC=CE......................................(2)

In ΔABD and ΔACE

∠ABD=∠ACE ( From 1)

BC=CE (from 2)

AB=AC ( GIven)

∴ΔABD≅ΔACE

So AD=AE [henceproved]

Please help!!! Urgent ….

Answers

9514 1404 393

Answer:

  ΔWZT ~ ΔWXY

Step-by-step explanation:

Angle XWY and angle ZWT are vertical angles, so congruent.

The sides on either side of those angles are proportional:

  WZ/WX = WT/WY

  11/22 = 10/20 = 1/2

so, we can claim similarity by the SAS Theorem.

  ΔWZT ~ ΔWXY

Plz help me solve this algebra problem

Answers

Answer:

Exact Form:

x = 2 √ 2 − 1 3 , − 2 √ 2 − 1 3

Decimal Form:

x = 2.49509379 , − 3.16176045

Step-by-step explanation:

Simplify the decimals as needed

A cylinder has a height of 12 inches and a radius of 1.5 inches. What is its voulme? Round your answer to the nearest tenth. Use 3.14 for
π
.

Answers

Find the area of the top, which is a circle.

Area of a circle = pi x r^2

Area = 3.14 x 1.5^2 = 7.065

Now for the volume multiply the area of the top by the height:

7.065 x 12 = 84.78 cubic inches

Round to the nearest tenth: 84.8 cubic inches

Answer:

Volume of cylinder is 84.78 inches.

Step-by-step explanation:

Volume of cylinder = π × r ² × h

Where,

r , is the Radius of cylinder. h ,is the height of cylinder.

And we have given that

Height of cylinder , h = 12 inchesRadius of the height , r = 1.5 inchesValue of π = 3.14

Substitute the values

Volume of cylinder = 3.14 × (1.5 inches) × 12 inches

= 3.14 × 2.25 inches² × 12 inches

multiply the values , we get

Volume of cylinder = 84.78 inches³.

84.8 inches³ is the round nearest to tenth.

Which choice shows (40+10)+30 correctly rewritten using the associative property and then correctly simplified?

40 + (10 + 30) = 40 + 40 = 80

40 + 30 + 10 = 70 + 10 = 80

40 + (10 +30) = 50 + 30 =80

(10 +40) + 30 = 50 + 30 =80

Answers

the last one, d, is the correct answer

What is the probability of tossing a penny and landing on heads 3 times in a row

Answers

Answer:

Suppose you have a fair coin: this means it has a 50% chance of landing heads up and a 50% chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4 = C, where C is a constant. Suppose that at a certain instant the volume is 400 cm^3 and the pressure is 80 kPa and is decreasing at a rate of 10 kPa/min. At what rate is the volume increasing at this instant?

Answers

Answer:

The volume increases at 35.71cm^3/min

Step-by-step explanation:

Given

[tex]PV^{1.4} = C[/tex]

[tex]V = 400cm^3[/tex]

[tex]P =80kPa[/tex]

[tex]\frac{dP}{dt} =-10kPa/min[/tex]

Required

Rate at which volume increases

[tex]PV^{1.4} = C[/tex]       [tex]V = 400cm^3[/tex]       [tex]P =80kPa[/tex]

Differentiate: [tex]PV^{1.4} = C[/tex]  

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]

By differentiating C, we have:

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]

Rewrite as:

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]

Solve for [tex]\frac{dV}{dt}[/tex]

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]

[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]

Substitute values

[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]

[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]

[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]

[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]

WILL GIVE BRAINLIST! PUT THESE NUMBERS ON THE PLOT

Answers

I wasn’t sure if I should include all the numbers if they were doubles but you get the idea. Hope this helps!

Answer:

"fair" srry im only in 8th so im d.u.m

Step-by-step explanation:

what pairs of degree measures NOT belong to the
group?

Answers

Answer:

B. 56° and 38°

Step-by-step explanation:

The sum of each of the two angles sums up to 90° ;

A.) 13° and 77°

Sum of A ; (13 + 77)° = 90°

B.) 56° + 38°

Sum = 56° + 38° = 94°

C) 37° and 53°

Sum = 37° + 53° = 90°

D.) 42° and 48°

Sum = 42° + 48° = 90°

Hence, the pair of degree measure which does not belong is B. 56° and 38°

What is the 8th term of a(n)=6•3^(n-1)

Answers

Answer:

13122

Step-by-step explanation:

a(n) = 6 * 3^(n -1)

a(8) = 6* 3^7

3^7 = 2187

a(8) =6 * 2187

a(8) = 13122

Write the following expression in standard place-value form.

Answers

Answer:

3408

Step-by-step explanation:

Anybody mind giving me the answer? Im struggling to get it rn

Answers

Answer:

nnn bjbjjjjjnn

Step-by-step explanation:

Answer:

c. 108

Step-by-step explanation:

do 12×12 and get 144 then do 6×6 to get 36 then do 144-36 and you get 108. hope this helps mate.

Which of the following ordered pairs is a solution to the equation 4x+6y=12? Select all that apply. Select all that apply: (−3,4) (1,3) (−6,6) (−13,10) (0,2)

Answers

The correct answers are (-3, 4) (-6, 6) (0, 2)

In ΔTUV, t = 7 inches, u = 9.4 inches and ∠V=18°. Find the area of ΔTUV, to the nearest 10th of a square inch.

Answers

Answer:

10 square inches

Step-by-step explanation:

that is the procedure above

Answer:

Area=10.167=10.2

Step-by-step explanation:

Area=1/2ab sin c

area= 1/2(7)(9.4)sin18

area = 10.167=10.2

this is for delta math

What should my answer be?

Answers

The answer should be X>10
The answer is X>10 :)

ON
16
aset
3rd
test
MATHEMATICS
Direction : Assemor all question, Tome and Shoul Work
1) A) use the newerberline (6) to find the finishing points for
these infegers
a)- 5110​

Answers

Answer:

what????????????????????

I need help solving for x

Answers

Answer:

x = 25

Step-by-step explanation:

Given a line parallel to a side of the triangle and intersecting the other 2 sides then it divides those sides proportionally, that is

[tex]\frac{40}{24}[/tex] = [tex]\frac{x}{15}[/tex] ( cross- multiply )

24x = 600 ( divide both sides by 24 )

x = 25

The correct answer to your question is X=25

Five less than Greg's age is less than 23 ​

Answers

Answer:

Greg is 28.

Step-by-step explanation:

Greg's age is y.

y - 5 = 23

y - 5 + 5 = 23 + 5

y = 28

The owner of a football team claims that the average attendance at games is over 74,900, and he is therefore justified in moving the team to a city with a larger stadium. An independent investigator will conduct a hypothesis test to determine whether his claim is accurate. This test is ________. Group of answer choices Two-sided Lower-tailed Upper-tailed

Answers

Answer:

Option c (Upper tailed) is the correct choice.

Step-by-step explanation:

Given that:

The average attendance is:

= 74,900

We will have to test:

[tex]H_0:\mu \leq \mu_0[/tex]

or,

   [tex]H_0: \mu \leq 74,900[/tex]

Verses,

⇒ [tex]H_1: \mu> \mu_0[/tex]

or,

    [tex]H_1: \mu >74,900[/tex]

The other given alternatives aren't connected to the given scenario. So the above is the correct one.

Two circles are concentric if they have the same center.


On a coordinate plane, a circle has center (4, 6) and has a radius of 2 units.


Which equation represents a circle that is concentric with the circle shown but has a radius that is twice as large?

Answers

9514 1404 393

Answer:

  (b)  (x – 4)^2 + (y – 6)^2 = 16

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

You want the equation for a circle with center (4, 6) and radius 4. That equation is ...

  (x -4)^2 +(y -6)^2 = 16

Answer:

B; (x – 4)2 + (y – 6)2 = 16

Step-by-step explanation:

correct on edge

Each sample of water has a 30% chance of containing a particular organic pollutant. Assume that the samples are independent with regard to the presence of the pollutant. Find the probability that, in the next 10 samples, two or less contain the pollutant. (Hint: using the tables in Appendix A will be faster than doing it by hand!)
a) 0.678
b) 0.028
c) 0.041
d) 0.383

Answers

Answer:

d) 0.383

Step-by-step explanation:

For each sample, there are only two possible outcomes. Either they contain the pollutant, or they do not. The probability of a sample containing the pollutant is independent of any other sample. Thus, the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

30% chance of containing a particular organic pollutant.

This means that [tex]p = 0.3[/tex]

Next 10 samples

This means that [tex]n = 10[/tex]

Probability that two or less contain the pollutant.

This is:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.028[/tex]

[tex]P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.121[/tex]

[tex]P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.233[/tex]

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.028 + 0.121 + 0.233 = 0.382[/tex]

A little rounding difference, but the correct answer is given by option d.

Identify the relationship between the graphs of these two equations. y = 5/6x + 5 y = 5/6x - 1

parallel
perpendicular
neither ​

Answers

Answer:

parallel

Step-by-step explanation:

the slope of each line is 5/6 which means the lines are parallel

(4-i)-(3-i) in standard form

Answers

Answer:

ifeywifheb

Step-by-step explanation:

hkefewib

What is the equation of the line that passes through (-3,-1) and has a slope of
2/5. Put your answer in slope intercept

Answers

Answer:

y = 2/5x + 1/5

Step-by-step explanation:

First, plug in the slope.

y = mx+b

y = 2/5x + b

Then, plug in the point given, in order to find b.

-1 = 2/5(-3) + b

-1 = -6/5 + b

1/5 = b

So the final equation is:

y = 2/5x + 1/5

Select the correct answer. Simplify. V75 options: A. 3v5 B. 15v5 C. 25v3 D. 5v3

Answers

3v5 because yea hope this helps
Other Questions
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