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Answer:

20 miles

Step-by-step explanation:

She ran 20miles, at the same point she passed her friend

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,  

                   103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +  

 xlim(c(70, 120)) +

 scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

 geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

 labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

Answer:

x is 7

EF is 10

FG is 12

Step-by-step explanation:

[tex]EF + FG = EG \\ (4x - 18) + (3x - 9) = 22 \\ 7x - 27 = 22 \\ 7x = 49 \\ x = 7[/tex]

then substitute:

[tex]EF = 4x - 18 \\ EF = 4(7) - 18 \\EF = 28 - 18 \\ EF = 10[/tex]

[tex]FG = 3x - 9 \\ FG = 3(7) - 9 \\FG = 21 - 9 \\ FG = 12[/tex]

First question:

BC + BA = CA

BC = CA - BA

BC = 36 - 9

BC = 27

Answer:

[tex]\|a\| = 5\sqrt{13}[/tex].

[tex]\|b\| = 3\sqrt{29}[/tex].

Step-by-step explanation:

Let [tex]m[/tex],[tex]n[/tex], and [tex]k[/tex] be scalars such that:

[tex]\displaystyle a = m\, (2\, \vec{i} + 3\, \vec{j}) = m\, \begin{bmatrix}2 \\ 3\end{bmatrix}[/tex].

[tex]\displaystyle b = n\, (2\, \vec{i} + 5\, \vec{j}) = n\, \begin{bmatrix}2 \\ 5\end{bmatrix}[/tex].

[tex]\displaystyle (a + b) = k\, (8\, \vec{i} + 15\, \vec{j}) = k\, \begin{bmatrix}8 \\ 15\end{bmatrix}[/tex].

The question states that [tex]\| a + b \| = 34[/tex]. In other words:

[tex]k\, \sqrt{8^{2} + 15^{2}} = 34[/tex].

[tex]k^{2} \, (8^{2} + 15^{2}) = 34^{2}[/tex].

[tex]289\, k^{2} = 34^{2}[/tex].

Make use of the fact that [tex]289 = 17^{2}[/tex] whereas [tex]34 = 2 \times 17[/tex].

[tex]\begin{aligned}17^{2}\, k^{2} &= 34^{2}\\ &= (2 \times 17)^{2} \\ &= 2^{2} \times 17^{2} \end{aligned}[/tex].

[tex]k^{2} = 2^{2}[/tex].

The question also states that the scalar multiple here is positive. Hence, [tex]k = 2[/tex].

Therefore:

[tex]\begin{aligned} (a + b) &= k\, (8\, \vec{i} + 15\, \vec{j}) \\ &= 2\, (8\, \vec{i} + 15\, \vec{j}) \\ &= 16\, \vec{i} + 30\, \vec{j}\\ &= \begin{bmatrix}16 \\ 30 \end{bmatrix}\end{aligned}[/tex].

[tex](a + b)[/tex] could also be expressed in terms of [tex]m[/tex] and [tex]n[/tex]:

[tex]\begin{aligned} a + b &= m\, (2\, \vec{i} + 3\, \vec{j}) + n\, (2\, \vec{i} + 5\, \vec{j}) \\ &= (2\, m + 2\, n) \, \vec{i} + (3\, m + 5\, n) \, \vec{j} \end{aligned}[/tex].

[tex]\begin{aligned} a + b &= m\, \begin{bmatrix}2\\ 3 \end{bmatrix} + n\, \begin{bmatrix} 2\\ 5 \end{bmatrix} \\ &= \begin{bmatrix}2\, m + 2\, n \\ 3\, m + 5\, n\end{bmatrix}\end{aligned}[/tex].

Equate the two expressions and solve for [tex]m[/tex] and [tex]n[/tex]:

[tex]\begin{cases}2\, m + 2\, n = 16 \\ 3\, m + 5\, n = 30\end{cases}[/tex].

[tex]\begin{cases}m = 5 \\ n = 3\end{cases}[/tex].

Hence:

[tex]\begin{aligned} \| a \| &= \| m\, (2\, \vec{i} + 3\, \vec{j})\| \\ &= m\, \| (2\, \vec{i} + 3\, \vec{j}) \| \\ &= 5\, \sqrt{2^{2} + 3^{2}} = 5 \sqrt{13}\end{aligned}[/tex].

[tex]\begin{aligned} \| b \| &= \| n\, (2\, \vec{i} + 5\, \vec{j})\| \\ &= n\, \| (2\, \vec{i} + 5\, \vec{j}) \| \\ &= 3\, \sqrt{2^{2} + 5^{2}} = 3 \sqrt{29}\end{aligned}[/tex].

Answer:

[tex] {2}^{1 \div 2[/tex]

Answer:

The common for the second question is 30

Answer:

39/30 Here 30 will be common in denominators

Step-by-step explanation:

6/15×2/2=12/30

3/10×3/3=9/30

3/5×6/6=18/30

= 12/30+9/30+18/30

39/30

Answer:

Yes, it is a polynomial, and the degree is 5

Step-by-step explanation:

A polynomial is a combination of terms separated using + or − signs and normally have exponents. So, this equation is a polynomial. The degree is just the highest exponential value, which is 5 because -5y is being raised to the 5th power

Answer:

False

Step-by-step explanation:

It only cuts the risk as stated and other factors such as lifestyle, age, bloodpressure and past medical background also have an impact so you can still have heart issues.

Answer:

square of 31 is 961

Step-by-step explanation:

31^2

31×31

=961

Step-by-step explanation:

Y=

[tex]y = 10 - 8x \\ put \: this \: in \: the \: second \: equation \\ 2(10 - 8x) - 4x = 40 \\ 20 - 16x - 4x = 40 \\ 20 - 20x = 40 \\ - 20 = 20x \\ x = - 1 \\ put \: the \: value \: of \: x \: in \: th \: first \: equation \\ y = 10 - 8( - 1) \\ y = 10 + 8 \\ y = 18[/tex]

Hence, x=-1 and y=18

Answer:

(- 1, 18 )

Step-by-step explanation:

Given the equations

y + 8x = 10 ( subtract 8x from both sides )

y = 10 - 8x → (1)

2y - 4x = 40 → (2)

Substitute y = 10 - 8x into (2)

2(10 - 8x) - 4x = 40 ← distribute and simplify left side

20 - 16x - 4x = 40

20 - 20x = 40 ( subtract 20 from both sides )

- 20x = 20 ( divide both sides by - 20 )

x = - 1

Substitute x = - 1 into (1) for corresponding value of y

y = 10 - 8(- 1) = 10 + 8 = 18

solution is (- 1, 18 )

Assuming you want to do a cartesian product, then you basically form items (x,y)  such that x is in set A, and y is in set A

More generally, A * B will consist of items of the form (x,y) such that x is in A and y is in B. However, we have B = A.

So,

A * A = {

(a,a), (a,b), (a,c)

(b,a), (b,b), (b,c)

(c,a), (c,b), (c,c)

}

I broke things up into separate rows to show that we can form a 3x3 table. Each row is a different x value from the set {a,b,c}. Each column is a different y value from the set {a,b,c}

In my opinion, this helps organize things much better than rather have it all on one single line like this

A * A = { (a,a), (a,b), (a,c), (b,a), (b,b), (b,c), (c,a), (c,b), (c,c) }

which in all honesty looks like a bit of a cluttered mess.

Answer:

Step-by-step explanation:

A={a,b,c}

A×A={a×a,a×b,a×c,b×a,b×b,b×c,c×a,c×b,c×c}

If one number is the multiple of another number, then the L.C.M. will be the smaller number (the number whose multiple the other number is).

Answer:

Divide 278 by 4 and the remainder value is the amount of leftover brownies.

278 ÷ 4 = 69, remainder of 2

Therefore, he had 2 brownies left.

Find the circumference of the pond:

Circumference = 2 x pi x radius

Circumference = 2 x 3.14 x 7.7 = 48.356 m

You want to go around 3 times so multiply the circumference by 3:

48.356 x 3 = 145.068m

Rounded to 1 decimal = 145.1m

Answer:

41

Ivan has just opened a small coffee shop. He paid a copy store 50.10 percopy to make

1,428 copies of the flyer to announce the opening of the shop an is having 14

distribute all 1 428 flyers, and he is paying them 50.25 tot sath Syer shey der He suure

each friend the same number of flyers

What is the total amount Ivan is paying each friend to

disor

Show your work

Answers

Answer:

1.) (2,1) is a solution

2.) (4,3) is NOT a solution

Step-by-step explanation:

1.) (2,1)

These are these mean (x,y)

2=x and 1=y

You want to substitute the numbers for the letters in the equation.

so.

2(2)+1=5

4+1=5

5=5, This statement is true so (2,1) is a solution.

2.) Same as above. 4=x and 3=y

4(4)-3(3)=10

16-9=10

7 Does Not Equal 10, Therefore, (4,3) is Not a solution to the equation.

9514 1404 393

Answer:

  C.  61.9°

Step-by-step explanation:

The sum of angles in a triangle is 180°, so the third angle is ...

  180° -35.5° -82.6° = 61.9°

Answer:

x = 7, EF = 10, FG = 12

Step-by-step explanation:

EF = 4x - 18

FG = 3x - 9

EG = 22

EG = 22

EF + FG = 22

4x - 18 + 3x - 9 = 22

4x + 3x - 18 - 9 = 22

7x = 22 + 18 + 9

7x = 49

x = 7

EF = 4x - 18

EF = 4*7 - 18

EF = 28 - 18

EF = 10

FG = 3x - 9

FG = 3*7 - 9

FG = 21 - 9

FG = 12

Answer:

No

Step-by-step explanation:

It can still be 8x - 2

first of all you collect like terms

5x + 3x - 2

= 8x -2

Answer:

0.0347 = constant of proportionality

[tex]1 * e^{0.0347t} = 15000[/tex]

Step-by-step explanation:

Given

[tex]1*e^{0.0347t}[/tex]

Solving (a): what does 0.0347 represent?

An exponential model is represented as:

[tex]f(t) = a * e^{kt}[/tex]

Where:

[tex]k \to[/tex] constant of proportionality

So, by comparison:

[tex]k = 0.0347[/tex]

Hence:

[tex]0.0347 \to[/tex] constant of proportionality

Solving (b): Formula to calculate when balance equals 15000

To do this, we simply equate the formula to 15000.

So, we have:

[tex]1 * e^{0.0347t} = 15000[/tex]

Answer:

(2x + y) ( x + 2y)

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

1

Answer:

y = - 3x - 22

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{3}[/tex] x + 1 ← is in slope- intercept form

with slope m = [tex]\frac{1}{3}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{3} }[/tex] = - 3 , then

y = - 3x + c ← is the partial equation

To find c substitute (- 6, - 4) into the partial equation

- 4 = 18 + c ⇒ c = - 4 - 18 = - 22

y = - 3x - 22 ← equation of perpendicular line

Answer:

5555+2929

= 8484

its an irrational no.

thanks

Answer: 4,000

Step-by-step explanation: To round 4,327 to the nearest thousand, we first find the digit in the rounding place, which in this case is the 4 in the thousands place. Next, we look at the digit to the right of the 4, which is 3.

According to the rules of rounding, since the digit to

the right of the rounding place is less than 5, we round down.

So the 4 in the rounding place stays the same

and all digits to the right of the 4 become 0.

So 4,327 rounded to the nearest thousand is 4,000.

From the calculation above, Dave may have jumped the expression

[tex](x+4)^2= 144[/tex]

Given the expression solved by Dave from step 1 as;

[tex]\dfrac{1}{3}(x+4)^2&=48[/tex]

In order to determine what Dave would have written, we will solve the expression above as shown

[tex]\dfrac{1}{3}(x+4)^2&=48\\(x+4)^2 = 3*48\\(x+4)^2 = 144 ..............eqn \ 2\\[/tex]

Take the square root of both sides

[tex]\sqrt{(x+4)^2} =\pm\sqrt{144}\\x+4=\pm12[/tex]

Hence from the calculation above, Dave may have jumped the expression in equation 2 as shown below;

[tex](x+4)^2= 144[/tex]

Learn more on radical equations here: https://brainly.com/question/20931859

Answer:

previous answer is correct

Step-by-step explanation:

Answer:

ljj

Step-by-step explanation:

llk

Yes , the series is an arithmetic sequence of common difference 2

What is Arithmetic Progression?

An arithmetic progression is a sequence of numbers in which each term is derived from the preceding term by adding or subtracting a fixed number called the common difference "d"

The general form of an Arithmetic Progression is a, a + d, a + 2d, a + 3d and so on. Thus nth term of an AP series is Tn = a + (n - 1) d, where Tₙ = nth term and a = first term. Here d = common difference = Tₙ - Tₙ₋₁

Sum of first n terms of an AP: Sₙ = ( n/2 ) [ 2a + ( n- 1 ) d ]

Given data ,

Let the number of terms n = 20

The number of tiles in the first row = 10 tiles

The number of tiles in the second row = 2 more than first row

The number of tiles in the second row = 12 tiles

The number of tiles in the third row = 14 tiles

So , the sequence will be , 10 , 12 , 14 , 16 ...

The number of terms n = 20

The first term a = 10

The common difference d = second term - first term

The common difference d = 12 - 10 = 2

The series is an arithmetic sequence and the 20th term of the sequence will be

a₂₀ = a + ( n - 1 )d

a₂₀ = 10 + ( 19 ) 2

a₂₀ = 10 + 38

a₂₀ = 48 tiles

Hence , the series is an arithmetic sequence

To learn more about arithmetic progression click :

https://brainly.com/question/1522572

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