economic importance of mosquito larva list five
Explanation:
economic importance of mosquito larva are
Mosquito larvae grow by consuming microorganisms such as algae and microbes that decompose decaying plant material. Larval mosquitoes contribute to aquatic food chains by serving as food sources for many predators, including fish and birds.i hope it will help you
which organism in the food web might be found in the first tropic level of a food chain
cougar
mouse
acorns
coyote
Answer:
Acorns would be found at the first trophic level of a food chain.
Explanation:
At her initial evaluation, Ms. Jones reports that she has lost 25 pounds over the past eight months despite an increase in her appetite. She complains of extreme fatigue, heart palpitations and irritability. Clinical observations reveal a protrusion of the eyeballs and hand tremors. You suspect that she might have:
a. hypothyroidism
b. diabetes mellitus
c. hypopituitarism
d. hyperthyroidism
Answer:
d. hyperthyroidism
Explanation:
Hyperthyroidism is a condition that occurs when the thyroid gland in our body secretes too much of the thyroxin hormone. Thyroid gland is a butterfly shaped gland that is located in our neck and it produces the hormone called thyroxin. Excess production of thyroxin leads to a condition named hyperthyroidism.
A person's metabolism increases when he or she is suffering from hyperthyroidism. One's weight is lost but the appetite increases. Other symptoms are extreme fatigue, irritability, heart palpitations, sweating and puffy eyes.
Thus in the context, Ms. Jones is suspect to have hyperthyroidism as she she is showing all the above symptoms.
Describe the biome in which you currently live, or one in which you want to live, or have lived. What are the atmospheric conditions (wind pattern, humidity level, etc), solar intensity, and geographic/oceanographic features that have produced this unique ecosystem
Answer:
Southern Texas
Explanation:
The Wind pattern often is represented by the westerlies, which are the winds that flow in the northern latitude of the world. The humidity level in this zone varies from 10-20%, since we are in the desert we do not have much humidity, the solar intensity is high, often found in the 9-10 uv range, it is not advised to spend more than 10 minutes on direct sun without solar protection. We have the Rio Grande to the south and some spare mountains.
Answer:
Southern Texas
Explanation:
Two different enzymes catalyze the same reaction and both exhibit the same Vmax. When Enzyme A was run with a 40 uM substrate, the initial rate (Vo) was 10 uM/min, and when g it was run with a 4 mM substrate, the Vo was 20 uM/min. Estimate the approximate Vmax and Km of Enzyme A. When Enzyme B was run with 80 uM substrate, the initial rate (Vo) was 10 uM per minute. Estimate the Km of Enzyme B.
Answer:
a) k_m = 4.08 uM
V_{max} = 20.07 uM/min
b) k_m = 8.16 uM
Explanation:
Given that:
For Enzyme A:
the substrate concentration [S] = 40 uM
the initial velocity rate v = 10 uM/min
when it was 4mM, v = 20 uM/min
i.e.
at 4mM = 4000 uM;
Using Michealis -menten equation;
when v = 10
[tex]V = \dfrac{V_{max}[S]}{k_m+[S]}[/tex]
∴
[tex]10 = \dfrac{V_{max}\times 40}{k_m + 40}[/tex]
[tex]10 (k_m + 40) = V_{max}40[/tex]
[tex]40V_{max} -10k_m = 400 --- (1)[/tex]
when v= 20
[tex]20= \dfrac{V_{max}\times 4000}{k_m + 4000}[/tex]
[tex]20 (k_m + 4000) = V_{max}4000[/tex]
[tex]4000V_{max} -20k_m = 8000 --- (2)[/tex]
equating equation (1) and (2):
[tex]40V_{max} -10k_m = 400 --- (1)[/tex]
[tex]4000V_{max} -20k_m = 8000 --- (2)[/tex]
let multiply equation (1) by 100 and equation (2) by 1
4000V_{max} - 1000K_m = 4000
4000V_{max} - 20 k_m = 8000
0 -980k_m = 4000
k_m = 4000/-980
k_m = 4.08 uM
replacing the value of k_m into equation (1)
40{V_max } - 10(4.08) = 400
40{V_max } - 40.8 = 400
40{V_max } = 400 + 40.8
40{V_max } = 440.8
V_{max} = 440.8/40
V_{max} = 11.02 uM/min
b)
Since V_{max} of A ie equivalent to that of B; then:
V_{max} of B = 11.02 uM/min
Here;
[S] = 80 uM
V = 10 uM/min
∴
[tex]10 = \dfrac{11.02 \times 80}{k_m + 80 }[/tex]
10(k_m +80) = 881.6
10k_m = 881.6 - 800
10k_m = 81.6
k_m = 81.6/10
k_m = 8.16 uM
