PLSS HELPPP

A ball is at rest on a trapdoor. State the forces acting on the ball, including the direction they act it.

PLSS HELPPP A Ball Is At Rest On A Trapdoor. State The Forces Acting On The Ball, Including The Direction

Answers

Answer 1

Explanation:

Weight/gravity - Downwards

Normal force - Upwards

keep in mind that the length of the arrows of both the weight and the normal forces have to be equal since these are vectors and are equal to each other to cancel each other out


Related Questions

Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357° C?

Answers

Answer:

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

Explanation:

Por definición de entropía ([tex]S[/tex]), medida en joules por Kelvin, tenemos la siguiente expresión:

[tex]dS = \frac{\delta Q}{T}[/tex] (1)

Donde:

[tex]Q[/tex] - Ganancia de calor, en joules.

[tex]T[/tex] - Temperatura del sistema, en Kelvin.

Ampliamos (1) por la definición de calor latente:

[tex]dS = \frac{L_{v}}{T}\cdot dm[/tex] (1b)

Donde:

[tex]m[/tex] - Masa del sistema, en kilogramos.

[tex]L_{v}[/tex] - Calor latente de vaporización, en joules

Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:

[tex]\Delta S = \frac{\Delta m \cdot L_{v}}{T}[/tex]

Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que [tex]m = 0.50\,kg[/tex],[tex]L_{v} = 2.7\times 10^{5}\,\frac{J}{kg}[/tex] and [tex]T = 630.15\,K[/tex], entonces el cambio de entropía es:

[tex]\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}[/tex]

[tex]\Delta S = 214.235 \,\frac{J}{K}[/tex]

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!

1. ¿Cuál es el valor del potencial eléctrico en un punto si para trasladar una carga de 5 μC desde el suelo hasta el, se realizó un trabajo de 40 X 10^(-6) J?
2. ¿Calcular el potencial eléctrico en un punto B que se encuentra a 50 cm de una carga positiva q = 8 X 10^(-6) C
3. Determina el valor de una carga transportada desde un punto a otro, al realizarse un trabajo de 8 x 10^(-5) J, si la diferencia de potencial es de 4 x 10^3 V.

Answers

Answer:

(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C

Explanation:

(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J

The electric potential is given by

W = q V

[tex]40\times10^{-6}=5 \times10^{-6}\times V\\\\V = 8 V[/tex]

(b)

charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m

Let the potential is V.

[tex]V =\frac{k q}{r}\\\\V =\frac{9\times 10^{9}\times 8\times 10^{-6}}{0.5}\\\\V =144000 V[/tex]

(c)

Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V

Let the charge is q.

W= q V

[tex]8\times10^{-5}= q\times 4000\\\\q =2\times 10^{-8} C[/tex]


Suggest one material that is used to make the trampoline surface.
Explain your answer.

Answers

Answer:

Polypropylene is the safest material for trampoline mats in the trampoline market. The fibers are heavily woven to make a buoyantly webbed fabric. The fabric is then thermally interlocked to provide a smoother stabilized surface that can withstand constant flexing and stress.

volume of CO2 at STP of 27.0 g​

Answers

Answer:

Volume of CO2 at STP = 13.8 liter (Approx.)

Explanation:

Given:

Mass of CO2 = 27 gram

Find:

Volume of CO2 at STP

Computation;

We know that;

At STP, Volume of 1 mol of gas = 22.4 liter

Molar mass of CO2 = 44 g/mole

So,

Volume of CO2 at STP = [Mass of CO2 / Molar mass of CO2 ][22.4]

Volume of CO2 at STP = [27/44][22.4]

Volume of CO2 at STP = [0.6136][22.4]

Volume of CO2 at STP = 13.8 liter (Approx.)

A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.750 m/s at a 33.30 angle. What is the velocity of the other ball?

Answers

Explanation:

We need to apply the conservation law of linear momentum to two dimensions:

Let [tex]p_{1}[/tex] = momentum of the 1st ball

[tex]p_{2}[/tex] = momentum of the 2nd ball

In the x-axis, the conservation law can be written as

[tex](p_{1} \cos \theta_{1})_{i} + (p_{2} \cos \theta_{2})_{i} = (p_{1} \cos \theta_{1})_{f} + (p_{2} \cos \theta_{2})_{f} [/tex]

or

[tex](m_{1}v_{1})_{i}= (m_{1}v_{1}\cos \theta_{1})_{f} + (m_{2}v_{2}\cos \theta_{2})_{f} [/tex]

Since we are dealing with identical balls, all the m terms cancel out so we are left with

[tex](v_{1})_{i} = (v_{1})_{f}\cos \theta_{1} + (v_{2})_{f}\cos \theta_{2}[/tex]

Putting in the numbers, we get

[tex]1.33 = (0.750) \cos(33.30) + (v_{2})_{f} \cos \theta_{2}[/tex]

[tex] = > (v_{2})_{f} \cos \theta_{2} = 0.703[/tex]

In the y-axis, there is no initial y-component of the momentum before the collision so we can write

[tex]0 = (v_{1}\sin \theta_{1})_{f} + (v_{2}\sin \theta_{2})_{f} [/tex]

or

[tex] = > (v_{2})_{f} \sin \theta_{2} = (0.750) \sin(33.30) = 0.412[/tex]

Taking the ratio of the sine equation to the cosine equation, we get

[tex] \frac{ \sin \theta _{2}}{ \cos \theta_{2} } = \tan \theta_{2} = \frac{0.412}{0.703} = 0.586[/tex]

or

[tex] \theta_{2} = { \tan}^{ - 1} (0.586) = 30.4[/tex]

Solving now for [tex](v_{2})_{f}[/tex],

[tex](v_{2})_{f} = \frac{0.412}{ \sin(30.4) } = 0.815 \: \frac{m}{s} [/tex]

what is the frequency range of Audible sound​

Answers

Answer:20Hz to 20000Hz

Explanation:

Humans can detect sounds in a frequency range from about 20 Hz to 20 kHz.

Which of the following would require a centripetal force?

A) All of these require a centripetal acceleration
B) An airplane slowing down
C) A train speeding up
D) A car turning right

Answers

D if not I believe A

A resistor of 500Ω and one of 2000Ω are placed in series with a 60V supply. What will be the reading on a voltmeter of internal resistance 2000Ω when placed across (i) 500Ω resistor and (ii) 2000Ω resistor?

Answers

Answer: 10 V, 40 V

Explanation:

Given

Resistors are [tex]500\Omega[/tex] and [tex]2000\Omega[/tex]

Power supply [tex]V=60\ V[/tex]

Voltmeter internal resistance [tex]r=2000\ \Omega[/tex]

When it connected around [tex]500\Omega[/tex] resistance, effective resistance becomes

[tex]\Rightarrow \dfrac{1}{R}=\dfrac{1}{500}+\dfrac{1}{2000}\\\\\Rightarrow R=\dfrac{2000}{5}\\\\\Rightarrow R=400\ \Omega[/tex]

Total resistance in series [tex]R_{net}=2400\ \Omega[/tex]

Current in circuit

[tex]I=\dfrac{60}{2400}=\dfrac{1}{40}\ A[/tex]

Voltage around [tex]500\Omega[/tex] resistance is

[tex]V=\dfrac{1}{40}\times 400\\\\V=10\ V[/tex]

(B) when voltmeter is connected around [tex]2000\Omega[/tex]  resistor

Net resistance around it

[tex]\Rightarrow \dfrac{1}{R}=\dfrac{1}{2000}+\dfrac{1}{2000}\\\\\Rightarrow R=1000\ \Omega[/tex]

Total resistance [tex]R_{net}=1500\ \Omega[/tex]

Current in circuit

[tex]I=\dfrac{60}{1500}=\dfrac{1}{25}\ A[/tex]

Voltage around [tex]2000\Omega[/tex] resistor

[tex]V=\dfrac{1}{25}\times 1000\\\\V=40\ V[/tex]

calcula el peso de un perro cuya masa es de 25 kg en la tierra

Answers

Answer:

El peso = 245 Newton

Explanation:

Dados los siguientes datos;

Masa = 25 kg

Para encontrar el peso del perro en la tierra;

El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.

Matemáticamente, el peso de un objeto viene dado por la fórmula;

[tex] El \; peso = mg [/tex]

Dónde;

m es la masa del objeto.

g es la aceleración debida a la gravedad.

Sabemos que la aceleración debida a la gravedad es igual a 9,8 m / s² en el planeta Tierra.

Sustituyendo en la ecuación, tenemos;

[tex] W = 25 * 9.8[/tex]

El peso = 245 Newton

Air pollution is an example of a. The underground economy. B. An external shock. C. A nonmarket activity. D. A negative externality.

Answers

Answer:

D. A negative externality.

Explanation:

Particulate pollution is a form of pollution that is responsible for the degradation of the environment.

Particulate matter is also referred to as particle pollution or atmospheric aerosol particles and it can be defined as a complex microscopic mixture of liquid droplets and solid particles that are suspended in air.

An externality is typically an unwarranted cost or benefit by a manufacturer or producer of goods and services that affects a third party.

In Economics, an externality could either be positive or negative depending on its effect on a third party.

A negative externality arises when the production or consumption of a finished product or service has negative impact (cost) on a third party.

In conclusion, air pollution is an example of a negative externality because it causes harm to a third party.

Find new resistance of wire if it is stretched to twice its
original length. Original resistance was 20 ohm. Also how its
resistivity will change

Answers

Answer:

Original Length = L1

Stretched length =L2

From

R = pl/A

R=Resistance

p=Resistivity

A=Cross-sectional Area

l= length of wire

We can see that Resistance is directly Proportional to Length... Meaning that Resistance Increases also as Length increases.

R1/L1 = R2/L2

From the question... The key to note is this sentence

"The Stretched length is TWICE the Original Length"

Meaning

L2 = 2L1 (So replace L2 as 2L1 when solving)

R1=20ohms

Let R2 = k

Applying the formula

20/L1 = k/2L1

kL1 = 20x 2 L1

KL1 = 40L1

L1 cancels on both sides

k=40ohms.

So As the length doubled... The Resistance did too

from 20ohms to 40ohms

Which is not true of friction? A. Causes wear and tear of the surfaces B. Helps us to fall easily on roads C. Produces heat D. Produces light E. Stops bodies when they move over each other.

Answers

Answer:

B.

Hope this helps

The answer is B

i need 20 works

A hypothesis is a(n) ______________, while a theory is a(n) ______________.

Answers

A hypothesis is a tentative explanation that can be tested by further investigation.

A theory is a well-supported explanation of observations.

A person notices water waves on the surface of the pond. 18 waves pass by a person in 12 seconds. Calculate the frequency of these water waves. Give the unit.

Answers

Answer:

f = 1.5 Hz

Explanation:

Given that,

18 waves pass by a person in 12 seconds.

We need to find the frequency of these water waves.

We know that,

Frequency = no. of waves per second

So,

[tex]f=\dfrac{18}{12}\\\\f=1.5\ Hz[/tex]

So, the frequency of these water waves is equal to 1.5 Hz.

100 point!! Question song!
You gotta keep 'em separated
Like the latest fashion
Like a spreading disease
The kids are strappin' on their way to the classroom
Getting weapons with the greatest of ease
The gangs stake their own campus locale
And if they catch you slippin' then it's all over pal
If one guys colors and the others don't mix
They're gonna bash it up
Hey - man you talkin' back to me?
Take him out
You gotta keep 'em separated
Hey - man you disrespecting me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
By the time you hear the siren
It's already too late
One goes to the morgue and the other to jail
One guy's wasted and the other's a waste
It goes down the same as the thousand before
No one's getting smarter
No one's learning the score
Your never ending spree of death and violence and hate
Is gonna tie your own rope
Hey - man you disrespecting to me?
Take him out
You gotta keep 'em separated
Hey - man you talking back to me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
It goes down the same as the thousand before
No one's getting smarter
No one's learning the score
Your never ending spree of death and violence and hate
Is gonna tie your own rope
Hey - man you talkin' back to me?
Take him out
You gotta keep 'em separated
Hey - man you disrespecting me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play

Answers

Answer:

It is a song called Come out and Play. It is released on 1994 in a Album called Smash. It comes under Punk-Rock.

I hope i answered your Question.

Answer:

Explanation:

Adding to the other answer, this song is about violence in streets and schools among young people involved in gangs; how they have little hope for their future. Band member Dexter got idea to make the song while he was in college.

For a specific volume of 0.2 m3/kg, find the quality of steam if the absolute pressure is (a) 40 kPa and (b) 630 kPa. What is the temperature of each case?

Answers

Answer:

[tex]x=0.0498[/tex]

[tex]x'=0.659[/tex]

Explanation:

Specific Volume [tex]V=0.2m_3/kg[/tex]

Absolute Pressure (a) [tex]P_a= 40kpa[/tex]

Giving

[tex]T_a=75.87[/tex]

[tex]v_f=1.265*10^{-3}m^3/kg[/tex]

[tex]v_g=3.993m^3/kg[/tex]

                               (b) [tex]P_a= 630kpa[/tex]

Giving

[tex]T_b=160.13C[/tex]

[tex]v_f'=1.10282*10^{-3} m^3/kg[/tex]

[tex]v_g'=0.30286 m^3/kg[/tex]

(a)

Generally the equation for quality of Steam X  is mathematically given by

[tex]x=\frac{v-v_f}{v_g-v_f}[/tex]

[tex]x=\frac{0.2-1.0265*10^{-3}}{3.993-1.0265*10^{-3}}[/tex]

[tex]x=0.0498[/tex]

(b)

Generally the equation for quality of Steam X  is mathematically given by

[tex]x'=\frac{v-v_f'}{v_g'-v_f'}[/tex]

[tex]x'=\frac{0.2-1.10*10^{-3}}{3.30-1.1*10^{-3}}[/tex]

[tex]x'=0.659[/tex]

Which statement explains why a red rose does not appear to be orange?
O A. Orange light is absorbed by the rose.
B. Red light is transmitted through the rose.
C. Orange light is transmitted through the rose.
O D. Red light is absorbed by the rose.

Answers

Answer:

A

Explanation:

you see red because it's reflected and other colors are absorbed, light transmitted through something is when it travels through something like glass or a gem

E
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A wave has a frequency of 30 Hz and a wavelength of 10 m. What's its speed?

Answers

Answer:

Speed = 300 m/s

Explanation:

Given the following data;

Frequency = 30 Hz

Wavelength = 10 m

To find the speed of the wave;

Mathematically, the speed of a wave is given by the formula:

[tex] Speed = wavelength * frequency [/tex]

Substituting into the formula, we have;

[tex] Speed = 10 * 30 [/tex]

Speed = 300 m/s

A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?
Please provide the formula and the working

Answers

Answer:

Explanation:

The equation for acceleration is

[tex]a=\frac{v_f-v_0}{t}[/tex] where vf is the final velocity and v0 is the initial velocity. For us, the final velocity is 25 m/s and the initial is 0 because the train started from resting position. Filling in and solving for a:

[tex]a=\frac{25-0}{30.0}[/tex] so

a = .83 m/s/s

un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en los 13 segundos

Answers

Answer:

Acceleration = 5.77 m/s²

Distance cover in 13 seconds = 487.56 meter

Explanation:

Given:

Final velocity of mobile device = 75 m/s

initial velocity of mobile device = 0 m/s

Time taken = 13 seconds

Find:

Acceleration

Distance cover in 13 seconds

Computation:

v = u + at

75 = 0 + (a)(13)

13a = 75

a = 5.77

Acceleration = 5.77 m/s²

s = ut + (1/2)(a)(t²)

s = (0)(t) + (1/2)(5.77)(13²)

Distance cover in 13 seconds = 487.56 meter

Which of the following nuclear configurations is most stable?​

Answers

Answer:

D. A nucleus of 2 protons and 2 neutrons.

Explanation:

A stable nucleus is one that do not disintegrate naturally, majorly due to the even number of its protons and neutrons. Thus they are not radioactive in nature.

From the given question, it would be observed that a nucleus of 2 protons and 2 neutrons would give a helium atom. And this is a stable atoms due to the magnetic number of the components of its nucleus.

Thus, the nuclear configuration that is most stable out of the given options is a nucleus of 2 protons and 2 neutrons. Option D.

que función cumple en la red las antenas o varillas en la red

Answers

Answer:

Explanation:

Para qué sirven las antenas que se colocan en la red

Las antenas de voleibol, también llamadas varillas, sirven para delimitar la zona de juego. Normalmente la red de voleibol es un poco más ancha que la zona de juego, es por ello que las varillas de voleibol se utilizan para demarcar el área de juego.

It is said that people often behave in unusual ways during a full moon. a)
Calculate the gravitational force that the moon would exert on a 50.0 kg
student in your physics class. The Moon is 3.84 x 108 m away from Earth
and has a mass of 7.35 x 1022 kg.

Answers

Answer: baby moon gravity

Sorry I dont know how to do it :/

Explanation:

moon + gravity = baby moon gravity

The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2 4. 6 8 10 Column 2 5 10 15 20 25 30 Column 1 should be titled "Time," and Column 2 should be titled "Velocity." Column 1 should be titled "Velocity," and Column 2 should be titled "Time." Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."​

Answers

Answer:

Explanation:

Since we are looking at speed over a time unit, we have an acceleration graph. The definition of acceleration mathematically is:

[tex]a=\frac{v_f-v_0}{t}[/tex] (that's the change in velocity over the change in time). The slope of any line in this graph wil represent the acceleration. Slope is rise over run, or y over x. Therefore, if acceleration is velocity over time, then the y axis is the velocity axis and the x axis is the time axis. It makes perfect, beautiful sense!!

can anyone help me with this question​

Answers

Answer:

6650km

Explanation:

Distance = (6.4 × 10³ + 250) km

= 6650 km

what is matter explain verifly​

Answers

Answer:

Matter is a substance that has inertia and occupies physical space. According to modern physics, matter consists of various types of particles, each with mass and size.Matter can exist in several states, also called phases. The three most common states are known as solid, liquid and gas.Matter is the Stuff Around You or Atoms and compounds are all made of very small parts of matter. Those atoms go on to build the things you see and touch every day. Matter is defined as anything that has mass and takes up space (it has volume).Solid ice, water and steam are few examples of matter touched in everyday life. Subatomic particles are also considered as matter.

Answer:

Matter is everything around you. Atoms and compounds are all made of very small parts of matter. Those atoms go on to build the things you see and touch every day. Matter is defined as anything that has mass and takes up space (it has volume).

hope it helps...

someone pls help fast

Answers

You forgot to add question...Add questions before asking so we can help
I think u forgot to add the question please add the question

What is surface tension ​

Answers

Answer:

Surface tension is a fundamental property of the surface of liquid. Surface tension is responsible for the curvature of the surfaces of air and liquids. Surface tension is responsible for the ability of some solid objects to “float” on the surface of a liquid.

hope it helps

stay safe healthy and happy.

Surface tension is the tendency of liquid surfaces at rest to shrink into the minimum surface area possible.Surface tension is what allows any object that is denser than water to float on water

hope this will help out

A sound wave has a frequency of 192 Hz and travels the length of a football field at a speed of 338.5 m/s. what is the wavelength of the wave?

Answers

Explanation:

everything can be found in the picture

What is the momentum, in kg m/s, of a tyre of mass 6 kg rolling along at a velocity of 3m/s?

Answers

Answer:

p = 18 kg-m/s

Explanation:

Given that,

The mass of tyre, m = 6 kg

The velocity of the tyre, v = 3 m/s

We need to find the momentum of the tyre. We know that, the momentum of an object is equal to the product of mass and velocity. SO,

p = mv

[tex]p=6\ kg\times 3\ m/s\\\\=18\ kg-m/s[/tex]

So, the momentum of the tyre is equal to 18 kg-m/s.

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