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Whats 2+2

Answer and Step-by-step explanation:

Convert the numbers into improper fractions.

[tex]\frac{25}{6} ,\frac{28}{5}[/tex]

Now, multiply the numbers.

[tex]\frac{700}{30}[/tex]

Finally, simplify.

[tex]\frac{70}{3}[/tex] is the answer.

#teamtrees #PAW (Plant And Water)

Answer: 20 laps

Step-by-step explanation:

Given

Roger just ran 5 laps and completes 20% of his goal

Suppose his goal is x laps

So, 20% of x must be equal to 5

[tex]\Rightarrow 20\%\times x=5\\\Rightarrow 0.2x=5\\\\\Rightarrow x=\dfrac{5}{0.2}\\\\\Rightarrow x=\dfrac{50}{2}\\\\\Rightarrow x=25\ \text{laps}[/tex]

So, he needs 20 more laps to complete his goal.

Answer:

2

Step-by-step explanation:

Answer:

21:30 (Both numbers are multiplied by 3)

35:50 (Both numbers are multiplied by 5)

Answer:

(B) Two number is the answer of your question.

Answer:

The function [tex]f(x) = \frac{x^{2}-4}{x^{3}-3\cdot x^{2}-10\cdot x}[/tex] has a zero: [tex]x = 2[/tex], and two poles: [tex]x = 0[/tex] and [tex]x = 5[/tex].

Step-by-step explanation:

Let be [tex]f(x) = \frac{x^{2}-4}{x^{3}-3\cdot x^{2}-10\cdot x}[/tex] a rational function armed with polynomial function. We proceed to factor the expression to the find the zeros and poles of the rational function:

1) [tex]f(x) = \frac{x^{2}-4}{x^{3}-3\cdot x^{2}-10\cdot x}[/tex] Given

2) [tex]f(x) = \frac{(x + 2)\cdot (x-2)}{x\cdot (x^{2}-3\cdot x -10)}[/tex]  [tex]a^{2} - b^{2} = (a + b)\cdot (a - b)[/tex]/Associative, commutative and distributive properties.

3) [tex]f(x) = \frac{(x+2)\cdot (x-2)}{x\cdot (x-5)\cdot (x+2)}[/tex] [tex]x^{2} -(a+b)\cdot x + a\cdot b = (x-a)\cdot (x-b)[/tex]

4) [tex]f(x) = \frac{x-2}{x\cdot (x-5)}[/tex] Commutative property/Existence of multiplicative inverse/Modulative property/Result

The function [tex]f(x) = \frac{x^{2}-4}{x^{3}-3\cdot x^{2}-10\cdot x}[/tex] has a zero: [tex]x = 2[/tex], and two poles: [tex]x = 0[/tex] and [tex]x = 5[/tex].

Answer:

B.) x + (x + 16) = 90

2x+16=90

2x=90-16

x=74/2

x=37

Answer:

I hope This will Help u.. Plz mark me as Brilliant please

Step-by-step explanation:

Before you get started, take this readiness quiz.

Simplify: 

If you missed this problem, review (Figure).

Solve Equations with Constants on Both Sides

In all the equations we have solved so far, all the variable terms were on only one side of the equation with the constants on the other side. This does not happen all the time—so now we will learn to solve equations in which the variable terms, or constant terms, or both are on both sides of the equation.

Our strategy will involve choosing one side of the equation to be the “variable side”, and the other side of the equation to be the “constant side.” Then, we will use the Subtraction and Addition Properties of Equality to get all the variable terms together on one side of the equation and the constant terms together on the other side.

By doing this, we will transform the equation that began with variables and constants on both sides into the form  We already know how to solve equations of this form by using the Division or Multiplication Properties of Equality.

Solve: 

Solution

In this equation, the variable is found only on the left side. It makes sense to call the left side the “variable” side. Therefore, the right side will be the “constant” side. We will write the labels above the equation to help us remember what goes where.



Since the left side is the “”, or variable side, the 8 is out of place. We must “undo” adding 8 by subtracting 8, and to keep the equality we must subtract 8 from both sides.

Use the Subtraction Property of Equality.Simplify.Now all the variables are on the left and the constant on the right.

The equation looks like those you learned to solve earlier.Use the Division Property of Equality.Simplify.Check:Let .

Solve: 



Solve: 



Solve: 

Solution

Notice, the variable is only on the left side of the equation, so we will call this side the “variable” side, and the right side will be the “constant” side. Since the left side is the “variable” side, the 9 is out of place. It is subtracted from the , so to “undo” subtraction, add 9 to both sides. Remember, whatever you do to the left, you must do to the right.

Answer:

Division property of equality

Step-by-step explanation:

[tex] - 2m = 40[/tex]

[tex]m = - 20[/tex]

Answer:

[tex]A: (-3,1)[/tex]

[tex]B:(-1,-1)[/tex]

[tex]d=\sqrt{(-3-(-1)^{2} +(-1(-1))^{2} }[/tex]

[tex]=\sqrt{(-2)^{2}+(2)^{2} }[/tex]

[tex]=\sqrt{4+4}=\sqrt{8}[/tex]

[tex]=2\sqrt{2} =2.8[/tex]

---------------------

hope it helps..

have a great day sis ^_^!!!

Answer:

Coordinates of :-

A= (-3,1)

B= (-1,-1)

Distance AB= [tex]\sqrt{-2+3)^{2}+(-1-1)^{2} }[/tex]

OAmalOHopeO

Answer:The answer is B

Step-by-step explanation:

The Missing numbers are :

Each term in the pattern is formed by the successive addition of " 0.5 " in the previous term.

therefore, the sequence will be like :

[tex] \hookrightarrow1.9, \: 2.4, \: 2.9, \: 3.4, \: 3.9, \: 4.4[/tex]

And, missing terms are :

1.9 and 3.4 respectively

[tex] \mathfrak{hope \: it \: helps \: you.....}[/tex]

Answer:

8 feet, 256 ft^2

Step-by-step explanation:

The function of the area can be graphically rapresented with a parabola that opens downwards

in this specific case the vertex is the maximum point of the parabola.

(X) Vertex = -64/-8 = 8 feet

(Y) Vertex = -4(64) + 512 = -256 + 512 = 256 ft^2

Answer:

Maximum Width = 8 feet.

Maximum area = 256 ft^2.

Step-by-step explanation:

Part A.

A = -4w^2 + 64w

Finding the derivative:

dA/dw = -8w + 64 = 0  for maxm/minm, so

-8w  = -64

w = 8

The second derivative is -8 so w = 8 gives a maximum.

Part B.

The maximum area = -4(8)^2 + 64*8

= -256 + 512

= 256 ft^2.

Answer:

2x²+5x-6 = 0

using the quadratic formula

x = 0.886 and x= -3.386

Answer:

$100

$120 in and $20 out

Step-by-step explanation:

Answer:

the answer is $100

because if the bank is loosing 2% they are having to pay $20 bc 0.02 x 1,000= 20, and they are earning 12% they getting 120 bc 0.12 x 1,000 = 120, and 120-20= $100. you have to subtract the $20 because that is what the bank is paying, so it's losing money

Answer:

[tex]9+y[/tex] ≤ [tex]16[/tex]

Step-by-step explanation:

The sum of [tex]9[/tex] and [tex]y[/tex] which is [tex]9+y[/tex] is less than or equal to 16, which is ≤ [tex]16[/tex]

Hope this is helpful.

Answer:

-1,024

Step-by-step explanation:

4×2=8

8×2=16

and so on repeating 7 times

Answer:

0

Step-by-step explanation:

37 + (-37)

open the bracket

remember when u multiply the bracket - sign and + sign also gets multiplied and (-) * (+) is( -) . So

37 - 37

0

Answer:

X= 7.5 Y=75

Step-by-step explanation:

Answer:

Height is 0.5

Step-by-step explanation:

height of parallelogram = area ÷ base

= 2.5 ÷ 5 = 0.5

Answer:

y = 1x - 4

Step-by-step explanation:

y2 - y1 / x2 - x1

0 - 4 / 4 - 8

-4 / -4

1

y = 1x + b

0 = 1(4) + b

0 = 4 + b

-4 = b

The question given is incomplete, find the possible version in the comment below.

Answer:

9765625 ways

Step-by-step explanation:

To solve questions of this kind, we can apply the product rule ;

We have 10 different questions, each with 5 alternative options, even though there is only one correct answer, the number of answers that can be chosen (either correct or incorrect) is 5 ;

Therefore, we have 5 possible choices for each question :

Question 1 = 5 ; question 2 = 5,....

This can be written as :

5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 = 5^10 = 9765625 ways

Answer:

white- 47%   Blue-23% Red- 30%

Step-by-step explanation:

White cars- (47/100)*100= 47%

Blue cars- (23/100)*100=23%

Red cars- (30/100)*100=30%

Answer:

postive

Step-by-step explanation:

positive collums so it's positive

Answer:

The area of a circle is pi times the radius squared (A = π r²). Learn how to use this formula to find the area of a circle when given the diameter.

Answer:

area of a circle=200.96a^12

Step-by-step explanation:

area of circle=πr^2

=3.14*([tex]8a^{6}[/tex])^2

=3.14*64a^12

=200.96a^12

Answer:

Answer:

x = 100

Step-by-step explanation:

365.12 x = 36512

36512 / 365.12 = x

x = 100

If my answer is incorrect, pls correct me!

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-Chetan K