Pls solve 60 points if you do

Hence, the cost of fencing the garden is ₹9485. Hence, the cost of plowing the garden is ₹756.

Perimeter is the total distance around the outside of a closed two-dimensional shape. It is the sum of the lengths of all the sides of the shape. For example, the perimeter of a rectangle is found by adding the lengths of all its four sides, whereas the perimeter of a circle is found by multiplying the diameter by π (pi). Perimeter is usually expressed in units of length, such as meters, centimeters, feet, or inches.

Here,

The perimeter of the rectangular garden is twice the sum of its length and width. So, the length of the fence needed to enclose the garden is:

2 × (length + width) = 2 × (175 m + 96 m) = 542 m

Therefore, the cost of fencing the garden at 17.50 per meter is:

Cost of fencing = length of fence × cost per meter

= 542 m × 17.50

= 9485

Hence, the cost of fencing the garden is ₹9485.

To find the cost of plowing the garden, we need to first calculate its area, which is given by:

Area = length × width

= 175 m × 96 m

= 16800 m²

Therefore, the cost of plowing the garden at 4.50 paise per square meter is:

Cost of plowing = area of garden × cost per square meter

= 16800 m² × 0.045

= 756

Hence, the cost of plowing the garden is ₹756.

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Given, [tex]$$(\sec n - \tan n) = \frac{1}{4}[/tex], so, using Trigonometry we can obtain [tex]$$\sec n + \tan n = 0$$[/tex].

Trigonometry is a branch of mathematics that deals with the study of relationships between the sides and angles of triangles. It involves the study of trigonometric functions such as sine, cosine, and tangent, and their applications to various fields such as engineering, physics, and navigation. Trigonometry helps in solving problems related to triangles, circles, and periodic phenomena such as waves and oscillations.

To find sec n + tan n using the given equation, we can use the following identity:

[tex]$$\sec^2 n - \tan^2 n = 1$$[/tex]

Multiplying both sides of the given equation by sec n + tan n, we get:

[tex]$$(\sec n - \tan n)(\sec n + \tan n) = \frac{1}{4}(\sec n + \tan n)$$[/tex]

Using the identity above, we can simplify the left-hand side of the equation as:

[tex]$$\sec^2 n - \tan^2 n = 1$$[/tex]

Therefore, we can substitute 1 for [tex]sec^2 n - tan^2[/tex] n in the equation above to get:

[tex]$$(\sec n - \tan n)(\sec n + \tan n) = \frac{1}{4}(\sec n + \tan n)$$[/tex]

[tex]$$1(\sec n + \tan n) = \frac{1}{4}(\sec n + \tan n)$$[/tex]

Simplifying further, we get:

[tex]\frac{3}{4} * $$(\sec n + \tan n) = 0[/tex]

Therefore, we can solve for sec n + tan n as:

[tex]$$\sec n + \tan n = \frac{0}{\frac{3}{4}}$$[/tex]

[tex]$$\sec n + \tan n = 0$$[/tex]

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Answer: 198 families live farther than 1 mile from the square.

Step-by-step explanation:

We know that there are 238 families that live within 1 mile of the village square. To find the number of families that live farther than 1 mile from the square, we can subtract 238 from the total number of families:

436 - 238 = 198

Therefore, 198 families live farther than 1 mile from the square. We can do this subtraction mentally without needing a calculator.

When evaluating a data set or statistics, the things to consider are sample size and data quality. It's important to consider these things because they provide insight into the validity of the data and the accuracy of the statistics that are being used.

When presented with a dataset or statistics, there are several things to consider.

Here are two examples of what you need to consider when evaluating a dataset or statistics:

1. Sample size: It's important to consider the sample size because small sample sizes are more likely to be biased. For example, a small sample size might be unrepresentative of a larger population. A sample size of 30 is commonly used to distinguish between small and large samples in statistics. Larger sample sizes are often more representative of the population and produce more reliable statistics.

2. Data quality: The quality of the data is also an important consideration. When evaluating statistics, you must ensure that the data is accurate, relevant, and up-to-date. This is important because using incorrect or outdated data can lead to incorrect conclusions. Additionally, if the data is missing or incomplete, you may not be able to get an accurate picture of the population that the dataset is supposed to represent. This can skew the results, making them less reliable or even completely useless. Therefore, data quality is an important consideration when evaluating statistics.

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The length of the third side must fall between 8 and 13. This is because the sum of the lengths of any two sides of a triangle must always be greater than the length of the third side.

X is a discrete random variable and Y is a discrete random variable because they both measure countable values rather than continuous values.

X is a discrete random variable because the time until the box arrives is measured in discrete, countable intervals such as days, weeks, or months. Y is a discrete random variable because the number of harmonicas that work properly is a countable number, rather than a continuous, measured value.

For example, the box could arrive in one week, or it could arrive in one month. Therefore,[tex]X[/tex] is discrete. Similarly, Y is discrete because there will be a certain number of harmonicas that work properly, such as 12, 15, 20, etc. So, Y is also discrete.

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Answer: The cost of painting is Rs.254.4

Step-by-step explanation:

let  l and b be the sides

        b=3m 20 cm=3.20m    

                                          = 5.30×3.20

                                           =16.96m²

We are given that, the measures of sides of blackboard are 5 m 30 cm and 3m 20 cm.

__________________________________________

[tex] \bf \implies5 m + 30 cm \\ [/tex]

[tex] \sf \implies 5 m + \dfrac{30}{100}m \\ [/tex]

[tex] \sf \implies 5 m + \dfrac{3\cancel{0}}{10\cancel{0}}m \\ [/tex]

[tex] \sf \implies 5 m + 0.3 m \\ [/tex]

[tex]\purple{ \bf \implies 5.3~ m } \\ [/tex]

[tex] \bf \implies3 m + 20 cm \\ [/tex]

[tex] \sf \implies 3 m + \dfrac{20}{100}m \\ [/tex]

[tex] \sf \implies 3 m + \dfrac{2\cancel{0}}{10\cancel{0}}m \\ [/tex]

[tex] \sf \implies 3 m + 0.2 m \\ [/tex]

[tex] \purple{\bf \implies 3. 2 ~m} \\ [/tex]

_______________________________________________

[tex] \pink{\frak{\implies Area _{(Blackboard) }= Length \times Breadth ~m^2}} \\ [/tex]

[tex] \sf \implies Area _{(Blackboard) } = 5.3 \times 3.2 ~m^2 \\ [/tex]

[tex] \sf \implies Area _{(Blackboard) } = 16.96 m^2 \\ [/tex]

[tex] \sf \implies 15 \times 16.96 \\ [/tex]

[tex] \pink{\sf \implies Rs ~254.4 } \\ [/tex]

The expression represents the difference of 7 and twice the product of a and b is 7 - 2ab

Let's break down the given problem step by step. First, we need to find the product of a and b, which is done by multiplying the two variables together using the multiplication symbol (*). Then, we need to multiply this result by 2, which is done by placing the entire product inside parentheses and then multiplying it by 2 using the multiplication symbol again.

Once we have found twice the product of a and b, we need to subtract it from 7. This can be done using the subtraction symbol (-), which we place between 7 and the expression we just found.

Putting it all together, the expression we get is:

7 - 2ab

where a and b are the two variables we were given.

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Combining these, we have[tex]$6 \times 6 = \boxed{36}$[/tex] different arrangements of the numbers [tex]${}1,$ ${}2,$ ${}3,$ ${}4,$ ${}5,$ $6$[/tex] in a row where the sum of any adjacent numbers is even.

Products intended for exporting after processing into goods or processed products are referred to as "basic products," as are goods planned for export after processing. Samples 1 - 3 Samples 2 - 3.

We may start by noting that at minimum one of the neighboring numbers must be even for the sum of both numbers to be even. This means that a even numbers (2, 4, 6) as well as the odd numbers (1, 3, 5) should be arranged in the appropriate positions.

Let's start by thinking about the even positions. The second, fourth, and sixth places are the only even positions. We can choose any variant of the 3 even numbers to occupy these spots, giving us[tex]$3! = 6$[/tex] ways.

Let's now think about the unusual positions. The first, third, and fifth positions are the only ones that are odd. We have an additional [tex]$3! = 6$[/tex]ways to fill these spots by using any combination of the 3 odd numbers.

Consider the odd locations now. The first, third, and fifth places are the three odd positions. We have an additional[tex]$3! = 6$[/tex]ways by using any permutation of the three odd numbers to fill these positions.

Together, this give us [tex]$6 \times 6[/tex] = [tex]\boxed{36}$[/tex] different ways to arrange the numbers [tex]${}1,$ ${}2,$ ${}3,$ ${}4,$ ${}5,$ $6$[/tex]in a row so that the sum of any two adjacent numbers is even.

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The phrase "He went to get milk but never came back" is often used as a humorous way to explain someone's absence or to imply that someone is unreliable or untrustworthy.

The phrase likely originates from a common experience where a child's parent, often their father, promises to go out to get something, like milk, but never returns. This can be a source of disappointment and confusion for the child, and the phrase has since been used in a joking manner to explain someone's failure to show up or fulfill a promise.

However, it is important to recognize that this experience can also be a source of trauma and should not be used to make light of someone's pain or loss.

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Over a year, the Blue Valley Glacier typically moves about the same distance as the Silver Lake Glacier, and Blue Valley has the same variability in its annual movement compared to Silver Lake.

The median annual movement of the Blue Valley Glacier is 300.2 feet, and the interquartile range is 14 feet.

The interquartile range indicates the spread of the data within the middle 50% of the data

So we know that the annual movement of the Blue Valley Glacier falls within a range of 300.2 ± 7 feet (i.e. 293.2 to 307.2 feet)

Similarly, the median annual movement of the Silver Lake Glacier is 300.4 feet, and the interquartile range is also 14 feet

So the annual movement of the Silver Lake Glacier also falls within a range of 300.4 ± 7 feet (i.e. 293.4 to 307.4 feet)

Since the ranges for both glaciers overlap and have the same size, we can conclude that they typically move about the same distance over a year, and that the variability in the annual movement of Blue Valley is comparable to that of Silver Lake.

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Answer:

y-intercept is (0,3) and the slope is 3

Step-by-step explanation:

Answer: the slope is 3x while 3 is the y-intercept.

Step-by-step explanation:

The example of 2×3 matrix A and a 3×2 matrix B such that, letting T(x)=Ax and U(x)=Bx is reflection Ab.

Matrices, the plural form of matrix, are the groupings of numbers, variables, symbols, or phrases in a rectangular table with varying rows and columns. These are rectangular arrays with specified operations such as addition, multiplication, and transposition. The elements of the matrix are the numbers or entries in it. The horizontal entries of matrices are referred to as rows, whereas the vertical elements are referred to as columns.

Let,

[tex]B = \left[\begin{array}{cc}0&1\\1&0&0&0\end{array}\right] , A = \left[\begin{array}{ccc}1&0&0\\0&1&0\\\end{array}\right][/tex]

Then,

[tex]AB =\left[\begin{array}{ccc}1&0&0\\0&1&0\\\end{array}\right] \left[\begin{array}{cc}0&1&1&0&0&0\\\end{array}\right] \\\\AB = \left[\begin{array}{cc}0&1&1&0\\\end{array}\right][/tex]

Therefore, Ab is reflection about y = x .

As U = Bx and T∘U    

A matrix is a rectangular array of integers, variables, symbols, or expressions that are defined for subtraction, addition, and multiplication operations. The number of rows and columns in a matrix determines its size (also known as the order of the matrix).          

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The formula relating I and P is I = kP

a) When P= $800, then I = $48

b) When I = $72, then P = $1200

If the interest $I on a loan of $P for a year at a rate of 6% varies directly as the loan, we can write:

I = kP

where k is a constant of proportionality. To find the value of k, we can use the given information that the interest rate is 6%, or 0.06 as a decimal. We know that when P = 100, the interest I = 0.06 × 100 = 6. Therefore:

I/P = 6/100 = 0.06 = k

Now we can use this value of k to answer the given questions,

a) When P = 800, the formula relating I and P is:

I = kP

I = 0.06 × 800

I = 48

Therefore, the interest on a loan of $800 for a year at a rate of 6% is $48.

b) When I = 72, the formula relating I and P is:

I = kP

72 = 0.06P

Solving for P:

P = 72/0.06

P = 1200

Therefore, a loan of $1200 for a year at a rate of 6% would have an interest of $72.

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Answer:

2125 ft/min

33,000 ft

y = -2125x + 33,000

Step-by-step explanation:

A. -2125 feet per minute. You get this number when you divide 17,000 by 8 (rise over run). You could also use the formula y2-y/x2-x1 with the points (0, 33,000) and (8, 17,000).

B. 33,000 feet is the height of the plane before it starts descending, so it must be the starting value.

C. Plug in the values you got for A and B into the slope formula y = mx + b

y = -2125x + 33,000

Answer:

The continuous compounding formula is:

A = Pe^(rt)

where A is the amount after t years, P is the initial principal, r is the annual interest rate as a decimal, and e is Euler's number (approximately 2.71828).

We are given that P = $5,000, r = 0.045, and A = $7,840. We want to find t, the number of years.

We can solve for t by isolating it on one side of the equation:

A = Pe^(rt)

A/P = e^(rt)

ln(A/P) = rt

t = ln(A/P) / r

Substituting in the values we have:

t = ln(7840/5000) / 0.045

t ≈ 11

So it will take about 11 years for the investment to grow to $7,840

The probability that the response indicated that the dog is small-sized given that they enjoyed the treat is 0.286 (or 2/7) in fraction in the lowest terms.

Bayes' theorem is used to update probabilities of a hypothesis or an event in light of new data or evidence. It is used to calculate the conditional probability of an event based on prior knowledge of the conditions that might be relevant to the event.In the given problem, we have to find the probability that the response indicated that the dog is small-sized given that they enjoyed the treat.

The probability that the dog is small-sized given that they enjoyed the treat is the conditional probability P(S|T), where S is the event that the dog is small-sized and T is the event that they enjoyed the treat. To find the value of P(S|T), we will use Bayes' theorem. Bayes' theorem states that P(S|T) = P(T|S) * P(S) / P(T) where P(T|S) is the probability that they enjoyed the treat given that the dog is small-sized, P(S) is the prior probability that the dog is small-sized, and P(T) is the probability that they enjoyed the treat.

P(S) = 3/7P(T|S) = 2/3P(T) = (2/3 * 3/7) + (1/4 * 4/7) = 18/84 + 4/28 = 1/3

(adding the probabilities of T given S and T given L)Therefore, P(S|T) = (2/3 * 3/7) / (1/3) = 2/7 = 0.285714...Rounding off to the nearest millionth, the probability is 0.286. Therefore, the probability that the response indicated that the dog is small-sized given that they enjoyed the treat is 0.286 (or 2/7) in fraction in the lowest terms.

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Answer:

not sure if this sign � was important did it the best way I could

Step-by-step explanation:

To solve this problem graphically, we will first set up a system of inequalities based on the given information:

x ≥ 8 (Fatoumata must work at least 8 hours lifeguarding)

y ≤ 12 - x (Fatoumata can work at most 12 total hours)

15x + 10y ≥ 140 (Fatoumata must earn a minimum of $140)

To graph these inequalities, we can plot the points (8,0), (12,0), and (0,14) on a coordinate plane and draw lines connecting them. The line between (8,0) and (12,0) represents the constraint on the number of hours Fatoumata can work, while the line between (8,0) and (0,14) represents the constraint on the amount of money she must earn. The shaded region that satisfies all three inequalities is the feasible region.

To find one possible solution, we can pick any point within the feasible region. One such point is (8,6), which represents working 8 hours lifeguarding and 6 hours tutoring. This point satisfies all three inequalities:

x ≥ 8 is true since x = 8

y ≤ 12 - x is true since y = 6 ≤ 12 - 8

15x + 10y ≥ 140 is true since 15(8) + 10(6) = 180 ≥ 140

Therefore, one possible solution is for Fatoumata to work 8 hours lifeguarding and 6 hours tutoring to earn at least $140 while not exceeding 12 total hours worked.

To find the derivative of the function f(x), we need to take the derivative of the natural logarithm (ln) of the function. We can do this by using the chain rule, which states that the derivative of the composition of two functions is equal to the derivative of the outer function times the derivative of the inner function.

The derivative of the outer function (ln) is 1/f(x), and the derivative of the inner function (14 - e-2x) is -2e-2x. So the derivative of f(x) is:

f'(x) = 1/f(x) × (-2e-2x)

f'(x) = 1/(ln(14 - e-2x)) × (-2e-2x)

f'(x) = -2e-2x/(14 - e-2x)

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a country exports crayfish to overseas markets. the buyers are prepared to pay high prices when the crayfish arrive still alive. if x is the number of deaths per dozen crayfish, the probability distribution for x is given by: a. Find k. b. Over a long period

A. To find k, you need to calculate the expected value of the random variable x, which is the number of deaths per dozen crayfish. This can be done by summing up the products of all the values of x multiplied by their respective probabilities. Thus,

                    k = ∑(xi * Pi)

                      = (1 * 0.3) + (2 * 0.3) + (3 * 0.2) + (4 * 0.2)

                      = 2.6

B. The mean number of deaths per dozen crayfish is given by the expected value of x, which is 2.6.

C. To find the standard deviation for the probability distribution, we need to calculate the variance of x. This can be done using the formula,

                 σ2 = ∑((xi - k)2 * Pi)

                      = (0 - 2.6)2 * 0.3 + (1 - 2.6)2 * 0.3 + (2 - 2.6)2 * 0.2 + (3 - 2.6)2 * 0.2

                      = 0.84

Therefore, the standard deviation for the probability distribution is σ = √0.84 = 0.92.

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The number of pitchers that she should produce and the price that she should charge in order to maximize profit is 0 and $5, respectively, and the maximum profit is $0.

Given that a retired potter can produce china pitchers at a cost of $5 each. She estimates her price function to be where p is the price at which exactly x pitchers will be sold per week.

The formula for the profit is given by,

Profit = Revenue - Cost

The revenue for selling x pitchers at a price p is xp.

The total cost of producing x pitchers is 5x.

Therefore, Profit [tex]= xp - 5x[/tex]

Profit can be expressed as a function of x using the formulae of the function,

[tex]y = xp - 5x= (p - 5)x[/tex] .............(1)

Now, the number of pitchers that she should produce and the price that she should charge in order to maximize profit can be found by finding the maximum value of the profit function (1).

Let the maximum profit be P. Maximize P with respect to x. To find the maximum of a function of x, we can find its derivative and equate it to zero.

[tex]dP/dx = 0P = (p - 5)x[/tex]

Differentiate P with respect to x again to determine whether it is a maximum or minimum.

[tex]d^2P/dx^2 = -5 < 0[/tex]

Since [tex]d^2P/dx^2[/tex] is negative, the value of P is a maximum.

Substitute the value of x from equation (1) in terms of P to find

[tex]p.P = (p - 5)*P/(p - 5) \\\\p = 5[/tex]

Therefore, the price to maximize profit is $5 and the number of pitchers to produce is,

[tex]x = P/(p - 5) = P/0 =[/tex] undefined

Maximum profit is [tex]P = (p - 5)x = (5 - 5)x = $0[/tex]

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The Area of Bella's garden as required to be determined in the task content is the difference of the area of the rectangular backyard and the right triangular fish pond.

It follows from the task content that the area of Bella's trapezoidal garden is to be determined from the given information.

Since the garden and the fish pond are from the rectangular backyard; the sum of their areas is equal to the area of the backyard.

Ultimately, the area of the garden is the difference of the area of the rectangular backyard and the right triangular fish pond.

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Option C. 6,160 yards. To convert miles to yards, we multiply the number of miles by 1,760 (which is the number of yards in one mile). So, 3.5 miles x 1,760 yards/mile = 6,160 yards.

To convert miles to yards, we need to know that there are 1,760 yards in one mile. Therefore, to find out how many yards are in three and one-half miles, we need to multiply 1,760 by 3.5:

1,760 x 3.5 = 6,160

Therefore, there are 6,160 yards in three and one-half miles.

The other options provided are:

4,400 yards: This is equivalent to 2.5 miles, since 1 mile is 1,760 yards. Therefore, this is not the correct answer.

5,280 yards: This is equivalent to 3 miles, since 1 mile is 1,760 yards. Therefore, this is also not the correct answer.

7,040 yards: This is equivalent to 4 miles, since 1 mile is 1,760 yards. Therefore, this is not the correct answer.

So, the correct answer is 6,160 yards, which is the result of multiplying 1,760 yards by 3.5 miles.

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Answer:

$11.22

Step-by-step explanation:

20% of 56.09 = 1/5 of 56.09

Now, we divide 56.09 by 5 to get our answer which when rounded becomes 11.22.

Answer:

$11.22

Step-by-step explanation:

20% = 0.2

We Take

56.09 x 0.2 = $11.218

Round $11.218 will be $11.22

So, the tip amount is $11.22

Answer:

11 weeks

Step-by-step explanation:

42 + 15 * x = 207

42 + 15x = 207

15x = 207 - 42

15x = 165

x = 11

Hope this helps <3

Answer:

1. n=6

2. n=19

3. n=15

4. n=20

5. n=40

6. n=16

7. n=19

8. n=6

9. n=2.4

10. n=30

Step-by-step explanation:

remember the priorities :

1. brackets

2. exponents

3. multiplications and divisions

4. additions and subtractions

inside every category you go usually from left to right, but you can use the commutative property where applicable.

4 + 5 - 3 = 4 + 5 - 3 = 4 + 5 - 3 = 4 - 3 + 5 = 6

8×3 - 5 = 24 - 5 = 19

15/3 + 10 = 5 + 10 = 15

8 + 3 - 1×2 = 8 + 3 - 2 = 9

14×3 - 2 = 42 - 2 = 40

(3 + 5)×2 = 8×2 = 16

10 + 7 + 2×1 = 10 + 7 + 2 = 19

16/8 + 4 = 2 + 4 = 6

7 + 5/5 = 7 + 1 = 8

20/4×6 = 5×6 = 30

There are 18 possible outcomes for Bonny to pick a card and spin a rolling cube at random.

There are a total of 6 outcomes for the rolling cube and 3 outcomes for picking a card. To find the total number of outcomes, we can use the multiplication rule of counting:

Total number of outcomes = number of outcomes for picking a card x number of outcomes for rolling a cube

Total number of outcomes = 3 x 6 = 18

Therefore, there are 18 possible outcomes for Bonny to pick a card and spin a rolling cube at random.

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The density function of the continuous random variable X, the total number of hours, in units of 100 hours, that a family runs a vacuum cleaner over a period of one year, is given in Exercise 3.7 on page 92 as f(x) = {x, 0 < x < 1, 2 - x, 1 ≤ x ≤ 2, 0, elsewhere.

To find the average number of hours per year that families run their vacuum cleaners, we must calculate the expected value of X. This is done by integrating the density function of X over the given range:

E(X) = ∫0,2 x * f(x) dx
      = ∫0,1 x2 dx + ∫1,2 (2-x) x dx
      = (1/3) + (-2 + 4 - 2/3)
      = 8/3

Therefore, the average number of hours per year that families run their vacuum cleaners is 8/3, or approximately 2.67 hours.

To find the proportion of individuals who can be expected to respond to a certain mail-order solicitation if X has the density function, we must calculate the cumulative density function of X. This is done by integrating the density function of X over the given range:

F(X) = ∫0,x f(x) dx
      = ∫0,x x dx + ∫x,2 (2-x) dx
      = (1/2)x2 + 2x - 2

Therefore, the proportion of individuals who can be expected to respond to a certain mail-order solicitation if X has the density function is (1/2)x2 + 2x - 2.

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Answer:

AB = 27

Step-by-step explanation:

AC = AB + BC

[tex]{ \rm{57 = 3x + (4x - 6)}} \\ \\ { \rm{57 = 7x - 6}} \\ \\ { \rm{7x = 57 + 6}} \\ \\ { \rm{7x = 63}} \\ \\ { \rm{x = 9}}[/tex]

Therefore;

[tex]{ \rm{AB = 3x = 3 \times 9}} \\ { \boxed{ \rm{AB = 27}}}[/tex]

Answer:

X≈ 2,37 cm

x= (-11+√637)/6 cm

Step-by-step explanation: