Answer:
9.89 m
Step-by-step explanation:
AC is the hypotenuse (H)
x is the opposite (O)
O and H are in sine
sin=O/H
H=O/sin
H=7.9/sin(53)
=9.89187169943418
3 SF
9.89 m
Answer:
AC= 13.144
Step-by-step explanation:
cos ∅ = Adjacent/ Hypotenuse
cos (53°) = x/AC
cos (53°) = 7.9/AC
(0.601).(AC)=7.9
AC=(7.9)/(0.601)
AC= 13.144 (3 S.F)
How many quarters are there in 5 3/4?
Answer:
One quarter= 1/4
5 3/4= 23/4
Number of quarters in 5 3/4= 23/4 divided by 1/4
23/4 ÷ 1/4
= 23/4 × 4
=23
I hope this helps!
Answer:
23
Step-by-step explanation:
5x4 + 3
5 x 4 = 20
20 + 3 (3 Is the fraction part)
what value of x makes this preportion true? (2.12.3) (15 points)
Answer:
A
Step-by-step explanation:
Given
[tex]\frac{x}{6}[/tex] = [tex]\frac{36}{24}[/tex] ( cross- multiply )
24x = 216 ( divide both sides by 24 )
x = 9 → A
a)Convert 7.5 cm into m b) convert 2 m into mm c) Convert 5 m into cm d) convert mg into 9 e)Convert 1.5 mg into kg f)convert 1 day into sec g)Convert 5 hour into sec
Answer:
0.075 metre
2000 mm
500 cm
0.001 gram
1.5 × 10-6 kilogram
86400 second
18000 second
Step-by-step explanation:
hope it helps
Answer:
a) 0.075 m
b) 2000 mm
c) 500 cm
d) ?
e) 0.0015 kg
f) 86400 seconds
g) 18000 seconds
Can someone help me? It's urgent and thank you!
Answer:
6 percent
Step-by-step explanation:
None
What is 63.48 rounded off to 1 decimal place?
Answer:
63.5
Step-by-step explanation:
Answer the following
Answer:
Step-by-step explanation:
The length of the base of an isosceles triangle is x. The length of a leg is 3x-4. The perimeter of the triangle is 97. Find x.
Answer I do not know i am not there yet i am sorry
Step-by-step explanation:
:(
Using the following image, find GH given HI = 1 and GI =
= 9.
Answer:
8
Step-by-step explanation:
Answer:
[tex]{ \tt{GH =GI - HI }} \\ = 9 - 1 \\ GH = 8[/tex]
If the cos of an angle is .75, what is the csc?
A. 1/√(5)
B. 9/√(6)
C. 6/√(2)
D. 3/√(9)
E. 4/√(7)
F. 2/√(3)
Answer: Choice E. 4/sqrt(7)
This is the same as writing [tex]\frac{4}{\sqrt{7}}[/tex]
=================================================
Explanation:
0.75 = 3/4
Recall that cosine is the ratio of adjacent over hypotenuse.
That means if cos(theta) = 3/4, then the adjacent is 3 units and the hypotenuse is 4 units.
Through the pythagorean theorem, we would then find that
a^2+b^2 = c^2
a = sqrt(c^2 - b^2)
a = sqrt(4^2 - 3^2)
a = sqrt(7)
This is the opposite side of reference angle theta.
From here, we can say
csc(angle) = hypotenuse/opposite
csc(theta) = 4/sqrt(7)
which points to choice E as the final answer.
Show √7 , √5 on a number line.
please hurry up my cissy and oppa
Answer:
Draw the number line like in the picture.
Step-by-step explanation:
√5 is about 2.236, meaning it's kind of close to 2.25.
√7 is about 2.646, meaning it's very close to 2.625.
Name the identical triangles and measurement of side BA
Step-by-step explanation:
BE/BC=BD/BA
tHE TWO SIMILAR TRIANGLES ARE BED AND BC. tHE PROPORTION ABOVE REPRESENTS USE OF THE TWO SIMILAR TRIANGLES.
4/(4 + 10) = 5/(5+X) Cross Multiply
4(5+x) = 5(4+10)m
20 +4x=20 +50 subtract 20 from both sides
4x = 50 divide by 4
x =12.5
12 points!! Please help out if you can! Means so much!!
Answer:
(2w+2)(w+8) ≤ 100
Step-by-step explanation:
The diagram shows a rectangle PQRS.
PQ = 14 cm and QR = 9 cm.
The point A lies on PS so that PA = 5 cm.
The point Blies on SR so that BR = 8 cm.
Answer:
a) The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is approximately 14.866 centimeters.
Step-by-step explanation:
a) The procedure consist in subtracting the areas of triangles APQ, ASB and BRQ of the area the rectangle, that is to say:
[tex]A = (9\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (5\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (8\,cm)\cdot (9\,cm) -\frac{1}{2}\cdot (4\,cm) \cdot (6\,cm)[/tex]
[tex]A = 43\,cm^{2}[/tex]
The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is determined by Pythagorean Theorem:
[tex]AQ = \sqrt{AP^{2}+PQ^{2}}[/tex] (1)
[tex]AQ = \sqrt{(5\,cm)^{2}+(14\,cm)^{2}}[/tex]
[tex]AQ \approx 14.866\,cm[/tex]
The length of the line segment AQ is approximately 14.866 centimeters.
Please help me lovee<3
solve for x
7x/2+5=8
o x=6/7
o x=26/7
o x=21/2
o x=91/2
Answer:
x = 6/7
Step-by-step explanation:
7x/2+5=8
Subtract 5 from each side
7x/2+5-5=8-5
7x/2 = 3
Multiply each side by 2/7
2/7 * 7/2x = 3*2/7
x = 6/7
[tex]\huge{\boxed{\bold{ANSWER}}}[/tex]
╭⋟───────────────
[tex] \frac{7x}{2} + 5 = 8 \\ \frac{7x}{2} = 8 - 5 \\ \frac{7x}{2} = 3 \\ 7x = 3 \times 2 \\ 7x = 6 \\ x = \frac{6}{7} [/tex]
So, the answer is [tex]\boxed{x = \frac{6}{7}}[/tex]
───────────────⋞╯
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
Atividade 12 Observe o sistema de equações abaixo. {m−3n=16m+5n=−8 Quais são os valores de "m" e "n" que satisfazem esse sistema de equações? m=1en=3. m=7en=–3. m=52en=–12. m=–20en=–12.
Responder:
m = 7; n = - 3
Explicação passo a passo:
Dada a equação:
m − 3n = 16m + 5n = −8
Resolvendo a equação:
m − 3n = 16 - - - (1)
m + 5n = - 8 - - - (2)
Subtraia 1 de 2
m - m - 3n - 5n = 16 - - 8
-3n - 5n = 16 + 8
-8n = 24
n = 24 / - 8
n = - 3
Coloque n = - 3 em (1)
m − 3n = 16
m - 3 (-3) = 16
m + 9 = 16
m = 16 - 9
m = 7
What percent of all students are middle schools
What is the solution to the system of equations?
One-fourth x minus one-half y = 8
One-half x + three-fourths y = negative 5
(–8, –12)
(–8, 12)
(8, 12)
(8, –12)
Answer:
(8 - 12 )
Step-by-step explanation:
Given
[tex]\frac{1}{4}[/tex] x - [tex]\frac{1}{2}[/tex] y = 8
[tex]\frac{1}{2}[/tex] x + [tex]\frac{3}{4}[/tex] y = - 5
Multiply both equations through by 4 to clear the fractions
x - 2y = 32 → (1)
2x + 3y = - 20 → (2)
Multiplying (1) by - 2 and adding to (2) will eliminate the x- term
- 2x + 4y = - 64 → (3)
Add (2) and (3) term by term to eliminate x
0 + 7y = - 84
7y = - 84 ( divide both sides by 7 )
y = - 12
Substitute y = - 12 into either of the 2 equations and solve for x
Substituting into (1)
x - 2(- 12) = 32
x + 24 = 32 ( subtract 24 from both sides )
x = 8
solution is (8, - 12 )
Answer:D:(8,-12)
Step-by-step explanation:took a test:D
Sanjana wants to buy a computer that she can use for school next year which is 9 months away. She discovers that she can buy a computer for $400 at a discount electronics store in town. How much does Sanjana have to save every MONTH to buy the computer? ANSWER: $400 / 9 months = $44.44/mo How much does Sanjana have to save every WEEK to buy the computer? ANSWER: $44.44 / 4 weeks = $11.11/wk How much does Sanjana have to save every DAY to buy the computer? ANSWER: $11.11 / 7 days = $1.59/day
Answer: ANSWER: $400 / 9 months = $44.44/mo How much does Sanjana have to save every WEEK to buy the computer? ANSWER: $44.44 / 4 weeks = $11.11/wk How much does Sanjana have to save every DAY to buy the computer? ANSWER: $11.11 / 7 days = $1.59/day
Step-by-step explanation:
10 points!!!!!! 16-20 please answer correctly and hurry please
Answer:
[tex] \large{ 16.}[/tex]
Two adjacent angles form a linear pair if the sum of those angles is 180°.[tex] \: \large{\tt{❃ \: m \: \angle \: 1 + m \: \angle \: 2 = 180 \degree \: ( \: SUM \: OF \: ANGLE \: IN \: LINEAR \: PAIR)}}[/tex]
[tex] \large{ \tt{⟶ \: 47 \degree + m \angle \: 2 = 180 \degree}}[/tex]
[tex] \large{ \tt{⟶ \: m \angle \: 2 \: = 180 \degree - 47 \degree}}[/tex]
[tex] \large{ \boxed{ \tt{⟶ \: m \: \angle \: 2 = 133 \degree}}}[/tex]
–––––––––––––
[tex] \large{17}.[/tex]
When two lines intersect , the Ames formed opposite to each other are called vertically opposite angles. Vertically opposite angles [ VOA ] are always equal to each other.[tex] \large{ \tt{↝ \: m \angle \: 6 = m \angle5 = \boxed{ 99.5\degree }\: ( \: BEING \: VOA)}}[/tex]
–––––––––––––
[tex] \large{18.}[/tex]
[tex] \large{ \tt{✻ \: m \angle \: JHL = m \angle \: JHK + m \: \angle \: KHL\: }}[/tex]
[tex] \large{ \tt{⤏ \: m \angle \: JHL= 60 \degree + 46 \degree}}[/tex]
[tex] \large{ \boxed{\tt{⤏ \: m \angle \: JHL = 106 \degree}}}[/tex]
Note that m ∠ KHL = 46° [ being vertically opposite angle ]–––––––––––––––
[tex] \large{ {19.}}[/tex]
Firstly , find out m ∠ JHP :[tex] \large{ \tt{❁ \: m \: \angle \: JHK + m \: \angle JHP+ m \: \angle PHN= 180 \degree \: ( \: sum \: of \: angle \: in \: straight \: line)}}[/tex]
[tex] \large{ \tt{↣ \: 60 \degree + m \angle \: JHP+ 46 \degree = 180 \degree}}[/tex]
[tex] \large{ \tt{↣ \: m \angle \: JHP = 74 \degree}}[/tex]
Now , find out m ∠ JHN :[tex] \large{ \tt{☂ \: m \angle \: JHN = m \angle \: JHP + m \angle \: PHN}}[/tex]
[tex] \large{ \tt{↦m \angle \: JHN = 74 \degree + 46 \degree}}[/tex]
[tex] \large{ \boxed{ \tt{ ↦m \angle \: JHN = 120 \degree}}}[/tex]
––––––––––––––––
[tex] \large{ 20.}[/tex]
[tex] \large{ \tt{✺ \: m \angle \: KHP = m \angle \: KHJ + m \angle \: JHP}}[/tex]
[tex] \large{ \tt{ ↬ \: \: m \angle \: KHP = 74 \degree + 60 \degree}}[/tex]
[tex] \large{ \boxed{\tt{↬ \: m \angle \: KHP = 134 \degree}}}[/tex]
And we're done! Yeyy :) . Also , Let me know if you have any questions regarding my answer !––––––––––––––––
[tex] \large{ \tt{ \# \: StayInAndExplore \: !}}[/tex]
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
How many wax warmers will she make when she makes 77 candles
A.75
B.55
C.40
D.69
Solve -2x + 6 = -20. -7 -13 7 13
Answer:
13
Step-by-step explanation:
-2x + 6 = -20
Step 1 subtract 6 from both sides
6 - 6 cancels out
-20 - 6 = -26
We now have -2x = -26
Step 2 divide both sides by -2
-2x/-2 = x
-26/-2 = 13
We're left with x = 13
if α and β are the zeroes of the polynomial 3x^2 - 8x − 3 then find the value of i) α^2 + β^2 ii) α^-1 + β^-1
Step-by-step explanation:
the answer is in the above image
120 to 150 find the percentage of increase
Answer:
25%
Step-by-step explanation:
increase by = 150 - 120
=30
increase percent = 30/120 * 100%
=3000/120
=25 %
Answer:
25%
Step-by-step explanation:
Percentage increase=(new value-original value)/(original value) x 100%
Percentage increase=(150-120)/120 x 100%
Percentage increase=30/120 x 100%
Percentage increase=1/4 x 100%
Percentage increase=25%
PLEASE HELP!! I’ve added an attachment. Please help me find the type of statement for this mathematical question. TYSM!!
Answer:
Step-by-step explanation:
Statements Reasons
1). AD ≅ BC 1). Given
2). ∠D ≅ ∠C 2). Given
3). ∠DEA ≅ ∠CEB 3). Vertically opposite angles
4). ΔADE ≅ Δ BCE 4). AAS postulate of congruence
5). AE ≅ BE 5). CPCTC
Hence, proved.
What is the equation of the line that passes through the points
(-3, 6) and (-3, 8)?
Answer:
[tex]x=-3[/tex]
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0).
Typically, we would start with finding the slope of the line. However, notice how the two x-coordinates in the given points are both -3. This means that this is a vertical line, with an undefined slope.
Vertical lines have their equations organized differently: [tex]x=d[/tex] where d is the x-intercept, or the value of x when y is 0.
Because the x-coordinates in all the points a vertical lines passes through are the same, the x-intercept would therefore be -3. Plug this into the equation [tex]x=d[/tex]:
[tex]x=-3[/tex]
I hope this helps!
4. The expression (3x –8)(2x+5)-(x+1)(2x+5) can be written as the product of 2x+5
with what other binomial?
(1) 4x-7
(3) 2x-7
(2) 2x-9
(4) 4x-9
Answer:
option 3 : (2x - 7 )
Step-by-step explanation:
ax + bx = x(a+ b)
a(x+ y) + b(x+y) = (x+y)(a+b)
[tex](3x - 8 ) ( 2x + 5) - (x + 1)(2x + 5)\\\\(2x+5)[ (3x - 8) - (x+1) ][/tex] [ (2x + 5) is common is both terms ]
[tex](2x+ 5)(3x -8 -x + 1)\\\\(2x+ 5)(2x - 7)[/tex]
Therefore , the binomial is ( 2x - 7)
Question 7 of 27
Which of the following is an element in the sample space for first rolling a
number cube and then tossing a coin?
Answer:
TH is an element on the sample space for first rolling a die and then tossing a coin. A coin has both heads and tails.
The sample space for rolling a number cube and then tossing a coin is:
{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}
The elements can be any of the elements in the sample space.
What is sample space?It is the total number of possible outcomes from a given set.
We have,
The sample space for rolling a number cube and then tossing a coin consists of all possible outcomes from rolling the number cube and tossing the coin.
Each outcome is a pair consisting of a number from 1 to 6 (the possible outcome from rolling the number cube) and a head or tail (the possible outcome from tossing the coin).
Therefore, an element in the sample space can be represented as an ordered pair (n, h/t), where n is the number rolled on the number cube and h/t is the outcome of the coin toss (either head or tail).
So,
The sample space for rolling a number cube and then tossing a coin is:
{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}
For example, (3, H), (6, T), (1, H), and (4, T) are all elements in the sample space.
Thus,
The sample space for rolling a number cube and then tossing a coin is:
{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}
Learn more about sample space here:
https://brainly.com/question/24273864
#SPJ7
For what values of x is the expression below defined?
x +3 + x1 - x
O A. 35xs1
O B. 3 > XS-1
O C. 3 >x>1
O D. -3 sx< 1
Answer:
D. - 3 ≤ x < 1
Step-by-step explanation:
The numerator cannot be the square root of a neg. no.
So, x + 3 ≥ 0 or x ≥ -3
The denominator cannot be a neg. no. or 0.
So, 1 - x > 0
1 > x or x < 1
So, altogether - 3 ≤ x < 1
Therefore, D is the correct answer.
HOPE IT MAY HELP YOU
PLEASE MARK AS BRAINLIST
what is 11010^2 - 1101^2
Answer:
-120,007,899
Step-by-step explanation:
Given :
[tex]11010^{2} -1101^{2}[/tex]
It can be solved as :
[tex]11010^{2} -1101^{2}[/tex]
121,220,100-1212201
-120,007,899
Therefore, answer will be -120,007,899
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{11,010^2 - 1,101^2}[/tex]
[tex]\mathsf{11,010^2}[/tex]
[tex]\mathsf{= 11,010 \times 11,010}[/tex]
[tex]\mathsf{= \boxed{\bf 121,220,100}}[/tex]
[tex]\mathsf{\bold{121,220,100} - 1,101^2}[/tex]
[tex]\mathsf{1,101^2}[/tex]
[tex]\mathsf{= 1,101 \times 1,101}[/tex]
[tex]\mathsf{= \boxed{\bf 1,212,201}}[/tex]
[tex]\mathsf{121,220,100 - \bf 1,212,201}[/tex]
[tex]\mathsf{= \boxed{\underline{\bf 120,007,899}}}[/tex]
[tex]\boxed{\boxed{\huge\textsf{Answer: \underline{\bf 120,007,899}}}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]