Please take a look at the picture

Im pretty sure the only prime number in between 90 and 100 is 97

Answer:

Calculate the mass of a body that is applied with a force that pushes the right side of 230 N and another force that pushes the left side of - 150N. Consider that the acceleration it acquires is 2 m / s2.

Step-by-step explanation:

230 e dos

Step-by-step explanation:

sqrt(5x)×(sqrt(8x²) - 2×sqrt(x)) =

sqrt(5x × 8x²) - 2×sqrt(5x × x) =

sqrt(40x) × x - 2x × sqrt(5) =

2x×sqrt(10x) - 2x×sqrt(5)

therefore, the last option is correct.

Answer:

That would be negative 45 or - 45

Please correct me if im wrong

Answer: The place value of 8 is in the hundredths. This would be called four and eight hundredths.

Would appreciate brainly <3

Hello there!

The value of 8 is:

Hundredths

The second number after the decimal point is in the hundredths place.

Hope it helps!

Please mark brainliest!

~Just a determined gal

[tex]MysteriousNature[/tex] here to help

Using the t-distribution, it is found that since the test statistic is less than the critical value for the left tailed test, there is not enough evidence to show that the patients with schizophrenia have less TBV on average than a  patient that is considered normal.

At the null hypothesis, we test if patients with schizophrenia do not have less TBV on average than a  patient that is considered normal, that is, the subtraction is not negative, hence:

[tex]H_0: \mu_S - \mu_N \geq 0[/tex]

At the alternative hypothesis, we test if they have less, that is, if the subtraction is negative, hence:

[tex]H_1: \mu_S - \mu_N < 0[/tex]

Regarding each sample, the mean and standard deviation are found using a calculator.

[tex]\mu_N = 1463339.2, s_N = 125458.28 , n_N = 32[/tex]

[tex]\mu_S = 1445132.3, s_S = 171355.8, n_S = 30[/tex]

We have the standard deviation for each sample, hence, the t-distribution will be used.

The standard errors are given by:

[tex]Se_N = \frac{125458.28}{\sqrt{32}} = 22178.1[/tex]

[tex]Se_S = \frac{171355.8}{\sqrt{30}} = 31285.1[/tex]

The distribution of the difference has mean and standard error given by:

[tex]\overline{x} = \mu_S - \mu_N = 1445132.3 - 1463339.2 = -18206.9 [/tex]

[tex]Se = \sqrt{Se_N^2 + Se_S^2} = \sqrt{22178.1^2 + 31285.1^2} = 38348.7[/tex]

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{Se}[/tex]

In which [tex]\mu[/tex] is the value tested at the hypothesis.

Hence:

[tex]t = \frac{\overline{x} - \mu}{Se}[/tex]

[tex]t = \frac{-18206.9 - 0}{38348.7}[/tex]

[tex]t = -0.47[/tex]

The critical value for a left-tailed test, as we are testing if the mean is less than a value, with a significance level of 0.1 and 32 + 30 - 2 = 60 df is [tex]t^{\ast} = 2[/tex]

Since the test statistic is less than the critical value for the left tailed test, there is not enough evidence to show that the patients with schizophrenia have less TBV on average than a  patient that is considered normal.

A similar problem is given at https://brainly.com/question/13873630

Answer:

PLEASE MARK ME AS BRANLIEST!!!!!

Step-by-step explanation:

a1 = first term; an= an-1 + d a1 = the first term in the sequence an = the nth term in the sequence an-1 = the term before the nth term n = the term number d = the common difference.

{10, 15, 20, 25, 30, 35, } first term = 10, common difference = 5 recursive formula: a1= 10; an= an-1 + 5

f(n) = f(n-1) + 12

f(1) = 7

f(2) = (7-1) + 12 = 18

f(3) = (18-1) + 12 = 29

f(4) = (29-1) + 12 = 40

f(5) = (40-1) + 12 = 51

7, 18, 29, 40, 51

Answer:

Fertilizer puts nitrogen into the soil, so using fertilizer puts more nitrogen into the carbon cycle.

When you use fertilizer, its because a certain plant you are planting uses all the nitrogen in the soil, so it won't grow next time. Too much fertilizer, though, would burn up your plant (not literally). Some plants put their own nitrogen into the soil. I can't think of one off the top of my head, but I believe potatoes do. Anyways, this is where crop rotation came into play.

Things like corn take a lot of nitrogen, so the next time you had to plant whatever plant potatoes, which again may be wrong, in order to get nitrogen for the corn to grow next season. Today we have fertilizer, so we can give them nitrogen while they grow, instead of putting in other plants, taking more time.

So really, it doesn't do much, because your plant takes all the nitrogen that the Fertilizer adds.

Answer:

People have been converting atmospheric nitrogen into nitrogen fertilizers and then applying the fertilizers to plants in to grow more crops. This has previously been quite effective, allowing individuals to farm on previously unproductive lands, and provide adequate food for expanding populations of people. Unfortunately, fertilizers are frequently overused, which can lead to issues.

Nitrogen from fertilizers excretes into soils, typically promoting the growth of weeds rather than native vegetation. Nitrogen then washes into streams, resulting in a nutrient overload, a phenomenon known as eutrophication.

Eutrophication causes aquatic weeds to proliferate excessively in freshwater lakes. These aquatic weeds  occasionally occupy entire lakes, streams, or rivers. Green algae cloud the water, and gooey algal slime covers the shallow rocks. 

When nitrogen-rich waters flow down into the ocean, they worsen the situation. High nitrogen concentrations in the Mississippi River Delta have generated a 'dead zone' where the water flows into the Gulf of Mexico. This has occurred every summer for over 30 years. In 2001, this dead zone, where oxygen levels are too low for species to thrive, encompassed over 8000 square miles of water. It occurs when nitrogen in the water enables algae to quickly grow out of control.

Step-by-step explanation:

Great article to look at for more information -

https://www.nytimes.com/2017/07/27/climate/nitrogen-fertilizers-climate-change-pollution-waterways-global-warming.html

Answer:

Area: (3+√7) x (1+2√7) = 17+7√7 = 35.52

Perimeter: 2(3+√7) + 2(1+2√7) = 8+6√7 = 23.87

Answer:

I dont know

Step-by-step explanation:

Can you type in the question please and ty

The amount that Kim Barney spends is $342 for medical expenses.

Buying cost is the cost at which someone buys or is willing to buy shares, bonds.( including the tax)

here, we have,

Given that,

Kim Barney pays a $290.00 yearly premium for a $500.00 deductible insurance plan. 80 percent of the remaining cost is covered by the business. If Kim has medical costs of $2,500.00

To find : The amount that Kim barney spends for the medical expenses.

If the business covers 80% of the remaining balance ($1710), they will be responsible for paying $1368 of it.

10% of 1710 is 171

171x8=1368

The insurance provider covers the $1368.

Kim Barney spends $342.

Consequently, Kim Barney spends the following amount on medical costs $342.

To learn more about the cost click here:

brainly.com/question/30045916

#SPJ2

Answer:

The answer is 9

Step-by-step explanation:

1/2 of 4 is 2, so you plug that in

2+7=9

Answer:

Step-by-step explanation:

x² + (x + 17)² = 25²

x² + x² + 34x + 289 = 625

2x² + 34x - 336 = 0

x² + 17x - 168 = 0

x = (-17 ±√(17² - 4(1)(-168))) / (2(1))

x = 7 or - 24   the negative distance makes no sense, but if we plug our good answer of 7 ft in for the base length, the height comes out to be + 24 ft

base = 7 ft

height = 24 ft

Answer:

the second train will Cath up with the first after 15 hours hence time will be at (5pm+15hours= 8:00am

Step-by-step explanation:

Answer:

7/12

Step-by-step explanation:

1/2 + 1/12?

To add fractions, find the LCD and then combine.

Exact Form:

7 /12

Decimal Form:

0.583

Answer:

18/12 or 3/2

Hope this helps!

Answer:

81 - a

Step-by-step explanation:

Decreased

means to subtract

81 –

by an unknown number

means a variable such as a or x

therefor

81 – a

Here, we have been asked to find the order of rotational symmetry of a symmetry of a regular pentagon. First let us learn about rotational symmetry and some basic terms related to it.

1. Rotational Symmetry: -

It is the property a shape has when it looks the same after some rotation by a partial turn. For example: - an equilateral triangle will look the same after a partial rotation of 120∘

2. Centre of rotation: -

The fixed point around which the rotation occurs is called the centre of rotation. For example: - the centre of rotation of a fan is the centre of the fan from which its blade originates.

3. Angle of Rotational Symmetry: -

The angle of rotational symmetry is the smallest angle for which the figure can be rotated to coincide with itself. For example: - the angle of rotation of an equilateral triangle is 120∘

4. Order of Rotational Symmetry: -

The order of rotational symmetry of a shape is the number of times it can be rotated around a full circle and still look the same. For example: - an equilateral triangle can be rotated 3 times around a full circle, each time at the angle of 120∘

, so its order of rotation will be 3.

In general, a regular polygon having n – sides have ‘n’ lines of symmetry and their order of rotational symmetry is ‘n’.

Now, let us come to the question. We have to find the order of rotational symmetry of a regular pentagon.

We know that a regular pentagon has 5 sides.

Answer:

2142.30435

Step-by-step explanation:

The answer is 2142 and leaves remainder

Answer:

9/10

Step-by-step explanation:

To add fractions, find the LCD and then combine.

Exact Form:

9/10

Decimal Form:

0.9

Answer:

5.25m

Step-by-step explanation:

32 papers will make in 1 minute

(168 copies/32copies)×1min = 5.25m

x = the whole pie.

well, Don ate (1/8)x, how much was it left?  [tex]x -\cfrac{1}{8}x\implies \cfrac{x}{1} -\cfrac{x}{8}\implies \cfrac{8x-x}{8}\implies \cfrac{7x}{8}[/tex]

well, so that's the remainder.

Then Ron ate 1/7 of the remainder [tex]\cfrac{7x}{8}\div 7\implies \cfrac{7x}{8}\div \cfrac{7}{1}\implies \cfrac{7x}{8}\cdot \cfrac{1}{7}\implies \cfrac{x}{8}[/tex]

well, how much is it left?  [tex]\stackrel{\textit{Don leftover}}{\cfrac{7x}{8}}-\stackrel{\textit{Ron's bite}}{\cfrac{x}{8}}\implies \cfrac{6x}{8}\implies \cfrac{3x}{4}[/tex]

well, there are 5 friends how much did each one get from the whole pie?

[tex]\cfrac{3x}{4}\div 5\implies \cfrac{3x}{4}\div \cfrac{5}{1}\implies \cfrac{3x}{4}\cdot \cfrac{1}{5}\implies \implies \cfrac{3x}{20}\implies \stackrel{\textit{each friend}}{\boxed{\cfrac{3}{20}x}}[/tex]

Answer:

13.77777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777

Answer:

Step-by-step explanation:

An easy way is to substitute values into both equations and compare:

A. x = 0.8

B. x = 0.9

C. x = 1.9

D. x = 1.1

As we see the most accurate one is A

Let's graph both function(Attached)

Let's round 0.775

[tex]\\ \sf\longmapsto 0.775[/tex]

[tex]\\ \sf\longmapsto 0.77[/tex]

[tex]\\ \sf\longmapsto 0.8[/tex]

Option A is correct