First pair of equations :
[tex]\dfrac{1}{2}x+y=15\ ..(i)\\\\-x-\dfrac{1}{3}y=-6\ ..(ii)[/tex]
Multiply 2 to equation (i), we get
[tex]x+2y=30\ ..(iii)[/tex]
By Elimination Method, Add (i) and (ii) (term with x eliminate), we get
[tex]2y-\dfrac{1}{3}y=30-6\\\\\Rightarrow\ \dfrac{5}{3}y=24\\\\\Rightarrow\ y=\dfrac{24\times3}{5}=14.4[/tex]
put y= 14.4 in (iii), we get
[tex]x+2(14.4)=30\Rightarrow\ x=30-28.8=1.2[/tex]
hence, x=1.2 and y =14.4
Second pair of equations :
[tex]\dfrac{5}{6}x+\dfrac13y=0\ ..(i)\\\\ \dfrac12x-\dfrac{2}{3}y=3\ ..(ii)[/tex]
Multiply 2 to equation (i), we get
[tex]\dfrac{5}{3}x+\dfrac{2}{3}y=0\ ..(iii)[/tex]
Elimination Method, Add (i) and (ii) (term with y eliminate) , we get
[tex]\dfrac53x+\dfrac12x=3\Rightarrow\ \dfrac{10+3}{6}x=3\\\\\Rightarrow\ \dfrac{13}{6}x=3\\\\\Rightarrow\ x=\dfrac{18}{13}[/tex]
put [tex]x=\dfrac{18}{13}[/tex] in (i), we get
[tex]\dfrac{5}{6}(\dfrac{18}{13})+\dfrac{1}{3}y=0\\\\\Rightarrow\ \dfrac{15}{13}+\dfrac{1}{3}y=0\\\\\Rightarrow\ \dfrac{1}{3}y=-\dfrac{15}{13}\\\\\Rightarrow\ y=-\dfrac{45}{13}[/tex]
hence, [tex]x=\dfrac{18}{13}[/tex] and [tex]y=\dfrac{-45}{13}[/tex] .
The data represent the membership of a group of politicians. If we randomly select one politician, what is the probability of getting given that a was selected?
Complete Question
The data represent the membership of a group of politicians. If we randomly select one politician, what is the probability of getting a Republican given that a male was selected?
Republican Democrat Independent
Male 11 6 0
Female 70 17 7
The probability is approximately_____?
Answer:
The probability is [tex]P(k) = 0.647[/tex]
Step-by-step explanation:
From the question we are told that
The sample size of male is [tex]n_m = 11 + 6 =17[/tex]
The number of male Republican is [tex]k = 11[/tex]
Generally the probability of getting a Republican given that a male was selected is
[tex]P(k) = \frac{k}{n_m}[/tex]
substituting values
[tex]P(k) = \frac{ 11}{17}[/tex]
[tex]P(k) = 0.647[/tex]
please this is easy show working out and please get correct
Answer:
$ 180,000
Step-by-step explanation:
All we are being asked to do in this question is take the simple interest, given a principle value of $100,000, with 8 percent interest each year over a course of 10 years. This is given the simple interest formula P( 1 + rt ).
Simple Interest : P( 1 + rt ),
P = $ 100,000 ; r = 8% ; t = 10 years,
100,000( 1 + 0.08( 10 ) ) = 100,000( 1 + 0.8 ) = 100,000( 1.8 ) = 180,000
Therefore you will have to pay back a total of $ 180,000
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50. (Round your answer to two decimal places.)
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Pregnancy length in horses. Bigger mammals tend to carry their young longer before giving birth. The length of horse pregnancies from conception to birth varies according to a roughly Normal distribution, with mean 336 days and standard deviation 3 days. Use the 68–95–99.7 rule to answer the following questions.Required:What percent of horse pregnancies are longer than 339 days?
Answer:
16%
Step-by-step explanation:
The difference between the time of interest (339 days) and the mean (336 days) is 3 days, which is exactly 1 standard deviation.
The 68-95-99.7 rule tells you that 68% of pregnancies will be within 1 standard deviation. The remaining 32% will be evenly split between pregnancies that are longer than 339 days and ones that are shorter than 333 days. So, half of 32%, or 16%, will be longer than 339 days.
if a flight to europe takes about 13 hours and you make one round trip flight per month how many total days do you travel in a year
Answer:
13 days
Step-by-step explanation:
Given that a one-way flight to europe will take 13 hours
A round trip will take = 13 hrs x 2 = 26 hours
Also given that we make one round trip per months for 12 months (1 year)
We will take a total of 12 round trips per year
Number of hours taken for 12 round trips
= 26 hours per round trip x 12 round trips
= 26 x 12
= 312 hours
Recall that there are 24 hours in a day, hence to convert 312 hours into days, we have to divide this by 24.
Number of days = number of hours ÷ 24
= 312 ÷ 24
= 13 days
simplify the expression 10 divided by 5 times 3
Answer:
= 2/3
Step-by-step explanation:
10 / (5*3)
= 10/15
= 2/3
Explain why within any set of ten integers chosen from 2 through 24, there are at least two integers with a common divisor greater than 1 g
Step-by-step explanation:
Here are some examples of ten integers (in this case prime numbers) chosen from 2 to 24;
2, 3, 5, 7, 9, 15, 17, 19, 21, 23
Lets take for example the integers 15 and 21, they have a common divisor 3 which is greater than 1. Which implies that the number 3 can divide through 15 and 21 without a remainder, that is, 21 ÷ 3 = 7, 15 ÷ 3 = 5. Also note that 3 is a divisor of 9.
Therefore, we could right say that within any set of ten integers chosen from 2 through 24, there are at least two integers with a common divisor greater than 1.
Hey! i've been working on these questions but I have no idea how to solve this one, could anybody help me? Thanks in advance!
Answer:
1) [tex]\boxed{p(x) = x^3-x^2+x-1}[/tex]
2) [tex]\boxed{p(x) = x^2+x-2}[/tex]
3) [tex]\boxed{p(x) =- 2x^2+2x+4}[/tex]
4) [tex]\boxed{p(x) = 2x^2+x-4}[/tex]
Step-by-step explanation:
Part (1)
[tex]p(x) = x^3-x^2+x-1[/tex]
As we have to determine it by ourselves, this is the polynomial having a degree of 3. p(x) with a degree of 3 means that the highest degree/exponent of x should be 3.
Part (2)
[tex]p(x) = x^2+x-2[/tex]
This can be the polynomial having the factor x-1 because if we put:
x - 1 = 0 => x = 1 in the above polynomial, it gives us a result of zero which shows us that (x-1) "is" a factor of the polynomial.
Part (3)
[tex]p(x) = -2x^2+2x+4[/tex]
This can be the polynomial for which p(0) = 4 and p(-1) = 0
Let's check:
[tex]p(0) =- 2(0)^2+2(0)+4\\p(0) = 0 + 0+4\\p(0) = 4[/tex]
[tex]p(-1)= -2(-1)^2+2(-1)+4\\p(-1) = -2(1)-2+4\\p(-1) = -2-2+4\\p(-1) = 0[/tex]
So, this is the required polynomial determined by "myself".
Part (4):
[tex]p(x) = 2x^2+x-4[/tex]
This is the polynomial having a remainder 6 when divided by (x-2)
Let's check:
Let x - 2 = 0 => x = 2
Putting in the above polynomial
[tex]p(x) = 2(2)^2+(2)-4\\Given \ that \ Remainder = 6\\6 = 2(4) +2-4\\6 = 8+2-4\\6 = 10-4\\6 = 6[/tex]
So, Proved that it has a remainder of 6 when divided by (x-2)
Find the area of the shaded regions:
Answer: 125.6 in^2
Step-by-step explanation:
First, we have that the radius of this circle is r = 10in
Now, we know that the area of a circle is:
A = pi*r^2
Now, if we got only a section of the circle, defined by an angle x, then the area of that region is:
A = (x/360°)*pi*r^2
Notice that if x = 360°, then the area is the same as the area of the full circle, as expected.
Then each shaded area has an angle of 72°.
A = (72°/360°)*3.14*(10in)^2 = 62.8 in^2
And we have two of those, both of them with the same angle, so the total shaded area is:
2*A = 2*62.8 in^2 = 125.6 in^2
Which statement about this function is true?
O A.
The value of a is positive, so the vertex is a minimum.
OB.
The value of a is negative, so the vertex is a minimum.
OC.
The value of a is negative, so the vertex is a maximum.
OD
The value of a is positive, so the vertex is a maximum.
Answer:
b
Step-by-step explanation:
The value of a is negative, so the vertex is a minimum.
Design a nonlinear system that has at least two solutions. One solution must be the ordered pair: (-2, 5). Tell how you came up with your system and give the entire solution set for the system.
Answer:
[tex] \begin{cases} (x - 2)^2 + (y - 2)^2 = 25 \\ y = 5 \end{cases} [/tex]
Solutions: x = 6, y = 5 or x = -2, y = 5
Step-by-step explanation:
Use a graph.
Plot point (-2, 5). That will be a point on a circle with radius 5.
From point (-2, 5), go right 4 and down 3 to point (2, 2). (2, 2) is the center of the circle.
You now need the equation of a circle with center (2, 2) and radius 5.
Use the standard equation of a circle:
[tex] (x - h)^2 + (y - k)^2 = r^2 [/tex]
where (h, k) is the center and 5 is the radius.
The circle has equation:
[tex] (x - 2)^2 + (y - 2)^2 = 25 [/tex]
To have a single solution, you need the equation of the line tangent to the circle at (-2, 5), but since you want more than one solution, you need the equation of a secant to the circle. For example, use the equation of the horizontal line through point (2, 5) which is y = 5.
System:
[tex] \begin{cases} (x - 2)^2 + (y - 2)^2 = 25 \\ y = 5 \end{cases} [/tex]
To solve, let y = 5 in the equation of the circle.
(x - 2)^2 + (5 - 2)^2 = 25
(x - 2)^2 + 9 = 25
(x - 2)^2 = 16
x - 2 = 4 or x - 2 = -4
x = 6 or x = -2
Solutions: x = 6, y = 5 or x = -2, y = 5
An example of a nonlinear system that has at least two solutions, one of which is (-2,5) are,
⇒ x² + y² = 29
⇒ 3x + 4y = -2
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Now, This system by starting with the equation of a circle centered at the origin with radius sqrt(29), which is,
⇒ x² + y² = 29.
Then, Added a linear equation that intersects the circle at (-2,5) to create a system with two solutions.
The entire solution set for this system is: (-2, 5) and (7/5, -19/10)
Thus, An example of a nonlinear system that has at least two solutions, one of which is (-2,5) are,
⇒ x² + y² = 29
⇒ 3x + 4y = -2
Learn more about the mathematical expression visit:
brainly.com/question/1859113
#SPJ3
Simplify (x + 4)(x2 − 6x + 3). x3 − 14x2 + 3x + 12 x3 − 6x2 − 17x + 12 x3 − 10x2 − 27x + 12 x3 − 2x2 − 21x + 12
Answer:
36 x^3 - 32 x^2 + (x + 4) (x^2 - 6 x + 3).x^3 - 62 x + 12
Step-by-step explanation:
Answer:
x^6-2x^5-21x^4+48x^3-32x^2-62x+12
Step-by-step explanation:
Mark me as brainliest!!!!
Chapter: Simple linear equations Answer in steps
Answer:
6x-3=21
6x=24
x=4
........
6x+27=39
6x=39-27
6x=12
x=2
........
8x-10=14
8x=24
x=3
.........
6+6x=22
6x=22-6
x=3
......
12x-2=28
12x=26
x=3
.....
8-4x=16
-4x=8
x=-2
.....
4x-24=3x-3
4x-3x=24-3
x=21
....
9x+6=6x+12
9x-6x=12-6
3x=6
x=2
Answer:
Step-by-step explanation:
1. 3(2x - 1) = 21
= 6x - 3 = 21
= 6x = 24
= x = 24/6 = 4
------------------------------
2. 3(2x+9) = 39
= 6x + 27 = 39
= 6x = 39 - 27
= 6x = 12
= x = 12/6 = 2
--------------------------------
3. 2(4x - 5) = 14
= 8x - 10 = 14
= 8x = 14+10
= x = 3
-------------------------------
A kites string is fastened to the ground. the string is 324ft long and makes an angle of 68 degrees with the ground. A model of this is shown below. use the law of sites (sin A/a=sin B/b) to determine how many feet the kite is above the ground (x). Enter the value, rounded to the nearest foot. (PLEASE)
Answer:
x = 300 feet
Step-by-step explanation:
In the given right triangle,
Length of the string of the kite = 324 feet
Angle between the string and the ground = 68°
By applying law of Sines in the given right triangle,
[tex]\frac{\text{SinA}}{a}=\frac{\text{SinB}}{b}=\frac{\text{SinC}}{c}[/tex]
Now we substitute the values of angles and sides in the formula,
[tex]\frac{\text{Sin68}}{x}=\frac{\text{Sin90}}{324}[/tex]
[tex]\frac{\text{Sin68}}{x}=\frac{1}{324}[/tex]
x = 324 × Sin(68)°
x = 300.41 feet
x ≈ 300 feet
Therefore, measure of side x = 300 feet will be the answer.
The ball bearing have volumes of 1.6cm cube and 5.4cm cube . Find the ratio of their surface area.
Answer:
64 : 729
Step-by-step explanation:
Ratio of surface area
= (ratio of linear dimensions) ^2
= 1.6^2 : 5.4^2
= 256 : 2916
= 64 : 729
Assume that when adults with smartphones are randomly selected, 57% use them in meetings or classes. If 8 adult smartphone users are randomly selected, find the probability that exactly 4 of them use their smartphones in meetings or classes. The probability is
Answer:
≈ 0.2526
Step-by-step explanation:
The number of combinations of 4 out of 8:
8C4 = 8!/(4!(8-4)!)= 8*7*6*5/(1*2*3*4)= 70Success factor is:
57% = 0.57and failure factor is:
(100 - 57)%= 43%= 0.43Probability:
0.57⁴*0.43⁴*70 ≈ 0.2526Angles One angle is 4º more than three times another. Find
the measure of each angle if
a. they are complements of each other.
b. they are supplements of each other.
[tex] \Large{ \boxed{ \bf{ \color{purple}{Solution:}}}}[/tex]
Let the smaller angle be x
Then, Larger angle would be x + 4°
Case -1:❍ They are complementary angles.
This means, they add upto 90°So,
➙ x + x + 4° = 90°
➙ 2x + 4° = 90°
➙ 2x = 86°
➙ x = 86°/2 = 43°
Then, x + 4° = 47°
So, Our required answer:
Smaller angle = 43°Larger angle = 47°Case -2:❍ They are supplementary angles.
This means, they add upto 180°So,
➙ x + x + 4° = 180°
➙ 2x + 4° = 180°
➙ 2x = 176°
➙ x = 176°/2 = 88°
Then, x + 4° = 92°
So, Our required answer:
Smaller angle = 88°Larger angle = 92°✌️ Hence, solved !!
━━━━━━━━━━━━━━━━━━━━
What’s the largest fraction: 7/8, 5/8, 7/13, and 11/19
Answer:
7/8
Step-by-step explanation:
7/8 = 0.875
5/8 = 0.625
7/13 = 0.538
11/19 = 0.579
So 7/8 is the largest
Robert is putting new roofing shingles on his house. Each shingle is 1 2/3 feet long. The north part of the house has a roof line that is 60 feet across. How many shingles can be placed (side by side) on the north part of the house?
Answer: 36 shingles can be placed on the north part of the house.
Step-by-step explanation:
Given: Length of each shingle = [tex]1\dfrac23[/tex] feet = [tex]\dfrac53[/tex] feet.
The north part of the house has a roof line that is 60 feet across.
Then, the number of shingles can be placed on the north part of the house = (Length of roof line in north part) ÷ (Length of each shingle)
[tex]=60\div \dfrac{5}{3}\\\\=60\times\dfrac{3}{5}\\\\=12\times3=36[/tex]
Hence, 36 shingles can be placed on the north part of the house.
A. f(x) = -x^2 - x - 4
B. f(x) = -x^2 + 4
C. f(x) = x^2 + 3x + 4
D. f(x) = x^2 + 4
Answer:
B: -x^2 + 4
Step-by-step explanation:
If the equation was [tex]f(x)=x^2[/tex], then the vertex would be at 0, and the "U" would be facing straight up. Here, the "U" is upside down, so that means the "x^2" would have to be a negative number ([tex]-x^2[/tex]) to get the upside-down "U". Then, we could see that the vertex is at positive 4, so that means that the parabola moved up 4 units, so the equation should end in +4.
Our answer is:
B: -x^2 + 4
If the item regularly cost d dollars and is discounted 12percent which of the following represents discount price dollar
Answer:
-12
Step-by-step explanation:
Hospitals typically require backup generators to provide electricity in the event of a power outage. Assume that emergency backup generators fail 18% of the times when they are needed. A hospital has two backup generators so that power is available if one of them fails during a power outage. Required:a. Find the probability that both generators fail during a power outage.b. Find the probability of having a working generator in the event of a power outage. Is that probability high enough for the hospital?c. Is that probability high enough for the hospital?
Answer:
a. 0.36
b. 0.1296
c. No.
Step-by-step explanation:
1. Note the probability of emergency backup generators to fail when they are needed = 18% or 0.18. Thus,
a. Probability of both emergency backup generators failing = P (G1 and G2 fails) where G represents the generators.
= P (G1 falls) x P ( G2 fails)
= 0.18 x 0.18
= 0.36
b. The probability of having a working generator in the event of a power outage = G1 fails x G2 works + G2 works x G2 fails
= 0.36 x 0.18 + 0.18 x 0.36
= 0.1296
c. Looking at the probability of any of the generators working, it is not meeting safety standards as lives could be lost if the backup generators needed to perform an emergency surgery operation fails.
A car dealer recommends that transmissions be serviced at 30,000 miles. To see whether her customers are adhering to this recommendation, the dealer selects a random sample of 40 customers and finds that the average mileage of the automobiles serviced is 30,456. The standard deviation of the population is 1684 miles. By finding the P-value, determine whether the owners are having their transmissions serviced at 30,000 miles. Use α = 0.10. Are the owners having their transmissions serviced at 30,000 miles?
Answer:
No, the owners are not having their transmissions serviced at 30,000 miles.
Step-by-step explanation:
We are given that a car dealer recommends that transmissions be serviced at 30,000 miles.
The car dealer selects a random sample of 40 customers and finds that the average mileage of the automobiles serviced is 30,456. The standard deviation of the population is 1684 miles.
Let [tex]\mu[/tex] = true average mileage of the automobiles serviced.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 30,000 miles {means that the owners are having their transmissions serviced at 30,000 miles}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 30,000 miles {means that the owners are having their transmissions serviced at different than 30,000 miles}
The test statistics that will be used here is One-sample z-test statistics because we know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\bar X[/tex] = sample average mileage serviced = 30,456 miles
[tex]\sigma[/tex] = population standard deviation = 1684 miles
n = sample of customers = 40
So, the test statistics = [tex]\frac{30,456-30,000}{\frac{1684}{\sqrt{40} } }[/tex]
= 1.71
The value of z-statistics is 1.71.
Also, the P-value of the test statistics is given by;
P-value = P(Z > 1.71) = 1 - P(Z [tex]\leq[/tex] 1.71)
= 1 - 0.9564 = 0.0436
For the two-tailed test, the P-value is calculated as = 2 [tex]\times[/tex] 0.0436 = 0.0872.
Since the P-value of our test statistics is less than the level of significance as 0.0872 < 0.10, so we have sufficient evidence to reject our null hypothesis as the test statistics will fall in the rejection region.
Therefore, we conclude that the owners are having their transmissions serviced at different than 30,000 miles.
AB||CD. Find the measure of
Answer:
135 degrees
Step-by-step explanation:
3x+15 = 5x - 5 because of the alternate interior angles theorem.
20 = 2x
x = 10
3(10) + 15 = 30+15 = 45
Remember that a line has a measure of 180 degrees. So we can just subtract the angle we found from 180 degrees to get BFG.
180-45 = 135.
A graph is shown below: A graph is shown. The values on the x axis are 0, 2, 4, 6, 8, and 10. The values on the y axis are 0, 4, 8, 12, 16, and 20. Points are shown on ordered pairs 0, 16 and 2, 12 and 4, 8 and 6, 4 and 8, 0. These points are connected by a line. What is the equation of the line in slope-intercept form?
Answer:
Graph is image, and equation is from the work result below:
Step-by-step explanation:
Take two points find the slope and y-intercept:
Slope = -2
Y-intercept = (0,16)
Equation =
y = − 2 x + 16
check work for one point (to make sure equation works):
(2,12)
y = -2x + 16
12 = -2(2) + 16
12 = -4 + 16
12 = 12
The equation is correct: y = − 2 x + 16
Image below are the points given:
Find the equation of the line passing through the point (–1, –2) and perpendicular to the line y = –1∕2x + 5. Question options: A) y = –1∕2x – 5∕2 B) y = 1∕2x – 5∕2 C) y = 2x D) y = –1∕2x
Answer:
The answer is option CStep-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the question
y = - 1/2x + 5
Comparing with the general equation above
Slope / m = -1/2
Since the lines are perpendicular to each other the slope of the other line is the negative inverse of the original line
That's
Slope of the perpendicular line = 2
Equation of the line using point (–1, –2) and slope 2 is
y + 2 = 2( x + 1)
y + 2 = 2x + 2
y = 2x + 2 - 2
We have the final answer as
y = 2xHope this helps you
Answer:
C) y = 2x
Step-by-step explanation:
I got it right in the test !!
Write the phrase "the product of 19 and a number" as a mathematical expression.
A 19 + x
B) 19/x
C) 19 x
(D) 19 -x
Answer:
19x
Step-by-step explanation:
product means multiply
19*x
19x
Answer:
The answer is C.
Step-by-step explanation:
if a number and a variable are next to each other, it is assumed they will be multiplied.
A function y = g(x) is graphed below. What is the solution to the equation g(x) = 3?
Answer:
See below.
Step-by-step explanation:
From the graph, we can see that g(x)=3 is true only when x is between 3 and 5. However, note that when x=3, the point is a closed circle. When x=5, the point is an open circle. Therefore, the solution is between 3 and 5, and it includes 3 but not 5.
In set-builder notation, this is:
[tex]\{x|x\in \mathbb{R}, 3\leq x<5\}[/tex]
In interval notation, this is:
[tex][3,5)[/tex]
Essentially, these answers are saying: The solution set for g(x)=3 is all numbers between 3 and 5 including 3 and not including 5.
Salaries of 42 college graduates who took a statistics course in college have a mean, , of . Assuming a standard deviation, , of $, construct a % confidence interval for estimating the population mean .
Answer:
The 99% confidence interval for estimating the population mean μ is ($60,112.60, $68087.40).
Step-by-step explanation:
The complete question is:
Salaries of 42 college graduates who took a statistics course in college have a mean, [tex]\bar x[/tex] of, $64, 100. Assuming a standard deviation, σ of $10,016 construct a 99% confidence interval for estimating the population mean μ.
Solution:
The (1 - α)% confidence interval for estimating the population mean μ is:
[tex]CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]
The critical value of z for 99% confidence interval is:
[tex]z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.57[/tex]
Compute the 99% confidence interval for estimating the population mean μ as follows:
[tex]CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]
[tex]=64100\pm 2.58\times\frac{10016}{\sqrt{42}}\\\\=64100+3987.3961\\\\=(60112.6039, 68087.3961)\\\\\approx (60112.60, 68087.40)[/tex]
Thus, the 99% confidence interval for estimating the population mean μ is ($60,112.60, $68087.40).
nishan bought 7 marbles Rs.x per each. if he gave Rs.100 to the shop keeper. what is the balance he would receive?
