Answer:
Hill 1: F(x) = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)
Hill 2: F(x) = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)
Hill 3: F(x) = 4(x - 2)(x + 5)
Step-by-step explanation:
Hill 1
You must go up and down to make a peak, so your function must cross the x-axis six times. You need six zeros.
Also, the end behaviour must have F(x) ⟶ -∞ as x ⟶ -∞ and F(x) ⟶ -∞ as x⟶ ∞. You need a negative sign in front of the binomials.
One possibility is
F(x) = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)
Hill 2
Multiplying the polynomial by -½ makes the slopes shallower. You must multiply by -2 to make them steeper. Of course, flipping the hills converts them into valleys.
Adding 3 to a function shifts it up three units. To shift it three units to the right, you must subtract 3 from each value of x.
The transformed function should be
F(x) = -2(x +1)(x)(x -2)(x -3)(x - 6)(x - 7)
Hill 3
To make a shallow parabola, you must divide it by a number. The factor should be ¼, not 4.
The zeroes of your picture run from -4 to +7.
One of the zeros of your parabola is +5 (2 less than 7).
Rather than put the other zero at ½, I would put it at (2 more than -4) to make the parabola cover the picture more evenly.
The function could be
F(x) = ¼(x - 2)(x + 5).
In the image below, Hill 1 is red, Hill 2 is blue, and Hill 3 is the shallow black parabola.
-2x-7+9-2= Please can i have an answer
Answer:
-2x
Step-by-step explanation:
-2x-7+9-2
Combine like terms
-2x +0
-2x
Answer:
-2x
Step-by-step explanation:
from the question
-2x-7+9-2=
step 1
collect the like terms
we have,
-2x-7+9-2
-2x + 2 -2
-2x + 0
-2x
therefore the answer to the question -2x-7+9-2 is equal to -2x
Which of the following images shows a scale copy of the trapezoid using a scale factor of 1/2
PLEASE HELP
Answer:
1
Step-by-step explanation:
split the shape to triangle and a rectangle
the rectangle at the original trapezoid has 2 squares in width and 3 squares for height multiply those numbers by 1/2 you will get 1 square for width and 1.5 squares for the height which is showen in option 1
Please help,thanks!(:
Answer:
<4=<2
x+30=2x+15
x=15
therefore <4=(15)+30
=45°
The sum of the ages of Noi's and Noy's is 26 years. The different between four times Noi's age and two times Noy's age is 28 years. Find the age of Noi and Noy.
WRITE AS AN EQUATION
Answer:
The age of Noi is 13.333 Years and the age of Noy is 12.67 years
Step-by-step explanation:
The given information are;
The sum of the ages of Noi and Noy = 26 years
Four times Noi's age - Two times Noy's age = 28
Let the age of Noi = X and let the age of Noy = Y
We have;
X + Y = 26 years.................(1)
4X - 2Y = 28 years.............(2)
Divide equation (2) by 2 to get;
(4X - 2Y)/2 = (28 years)/2 which gives;
2X - Y = 14 years.................(3)
Add equation (3) to equation (1), to get;
X + Y + 2X - Y = 26 years + 14 years
3X = 40 years
X = 40/3 = 13.333 Years
From equation (1), X + Y = 26 years, therefore;
Y = 26 - X = 26 - 13.33 = 12.67 years
Therefore, the age of Noi = 13.333 Years and the age of Noy = 12.67 years.
70 POINTS! PLEASE HELP! Explain the difference between the following equation formats: Slope-Intercept, Point-Slope and Standard
Answer and Step-by-step explanation:
1. slope intercept
2. point-slope form
3. standard
Explanation:
1. A slope intercept form equation is when it's set up as y = m x + b
m = slope
b = y-intercept
2. A point-slope form is when a line passes through a point
and the equation is set up as y −b = m ( x−a)
m = slope
(a, b) A point that the line passes through
3. standard lope form is when the equation is set up as
Ax + By = C
Will someone please help me with this problem!! **It's multiple choice!
A = (-7,-6)
B = (8,-9)
Find the slope of line AB
m = (y2-y1)/(x2-x1)
m = (-9-(-6))/(8-(-7))
m = (-9+6)/(8+7)
m = -3/15
m = -1/5
The slope of line AB is -1/5.
Flip the fraction and the sign to go from -1/5 to +5/1 = 5. The perpendicular slope is 5.
Let m = 5.
Use the coordinates of point C (2,12) along with the perpendicular slope to get
y - y1 = m(x - x1)
y - 12 = 5(x - 2)
y - 12 = 5x - 10
y = 5x - 10+12
y = 5x + 2
Lastly, convert this to standard form
y = 5x + 2
5x+2 = y
5x+2-y = 0
5x-y = -2
Choice A is the closest match, but the -56 should be -2 instead. It seems like your teacher made a typo somewhere.
Answer:
5x - y = -2.
Step-by-step explanation:
The equation of this altitude line has a slope = -1/m where m is the slope of line AB . It will also pass through the point C.
The slope of line AB = (-9 - (-6)) / (8 - (-7))
= -3/15
= -1/5
So the slope of the required line = -1 / -1/5 = 5.
Using the point C and the point-slope form of a line:
y - y1 = m(x - x1)
y - 12 = 5(x - 2)
y - 5x = -10 + 12
y - 5x = 2
5x - y = -2.
Find the area of the following shape. Show all work
Best way to solve this is by using
[tex] \sqrt{s(s - a)(s - b)(s - c)} [/tex]
[tex]where \: s = \frac{a + b + c}{2} [/tex]
s=(12+8+17)/2
=18.5
using the formulae
area =43.5
La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el peso del auto y el cuadrado de la velocidad del mismo. Supongamos que 400 libras de fuerza evitan que un auto que pesa 1600 libras derrape en una curva cuyo radio mide 800 si viaja a 50mph. ¿Cuánta fuerza evitaría que el mismo auto derrapara en una curva cuyo radio mide 600 si viaja a 60mph ?
Answer:
768 libras de fuerza
Step-by-step explanation:
Tenemos que encontrar la ecuación que los relacione.
F = Fuerza necesaria para evitar que el automóvil patine
r = radio de la curva
w = peso del coche
s = velocidad de los coches
En la pregunta se nos dice:
La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.
F ∝ 1 / r
Y luego con el peso del auto
F ∝ w
Y el cuadrado de la velocidad del coche
F ∝ s²
Combinando las tres variaciones juntas,
F ∝ 1 / r ∝ w ∝ s²
k = constante de proporcionalidad, por tanto:
F = k × w × s² / r
F = kws² / r
Paso 1
Encuentra k
En la pregunta, se nos dice:
Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.
F = 400 libras
w = 1600 libras
r = 800
s = 50 mph
Tenga en cuenta que desde el
F = kws² / r
400 = k × 1600 × 50² / 800
400 = k × 5000
k = 400/5000
k = 2/25
Paso 2
¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?
F = ?? libras
w = ya que es el mismo carro = 1600 libras
r = 600
s = 60 mph
F = kws² / r
k = 2/25
F = 2/25 × 1600 × 60² / 600
F = 768 libras
Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.
please help me i offered all my points and this is really important!!! The question is attached.
Answer:
25[tex]\sqrt{3}[/tex] +60
Step-by-step explanation: The first thing you need to do is realize that, this figure is a isosceles trapezoid due to the markings on each side.
So now we know both sides are 10.
We also know the the top two angles are congruent to each other and so are the bottom two angles due to the trapezoid being isosceles.
So the top two angles are 120 degrees and bottom two angles are 60 degrees.
It seems like we can't find the sides, let's try drawing two lines from each top angle all the way down to form two right triangles.
Wow, these two triangles are special right triangles in the form of
30 - 60 - 90 degrees.
shorter side = n
longer side = n[tex]\sqrt{3}[/tex]
hypotenuse = 2n
So, 2n = 10
n = 5 for the short side
The bottom base is 4[tex]\sqrt{3}[/tex] + 5 + 5 = 10 + 4[tex]\sqrt{3}[/tex]
The longer side is 5[tex]\sqrt{3}[/tex].
The area of trapezoid = (base1 + base2)/2 * height
= (4[tex]\sqrt{3}[/tex] + 10 + 4[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (10 + 8[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (5+4[tex]\sqrt{3}[/tex])*5[tex]\sqrt{3}[/tex] = 25[tex]\sqrt{3}[/tex] +60
So, 25[tex]\sqrt{3}[/tex] + 60 is our answer.
Answer:
60 +25√3
Step-by-step explanation:
In the figure of the isosceles trapezoid below, the angles at C and D are supplementary to the given angle, so are 60°. That makes triangle BDE a 30°-60°-90° right triangle, which has side length ratios ...
DE : BE : BD = 1 : √3 : 2 = 5 : 5√3 : 10
Triangle BDE can be relocated to the other end of the figure to become triangle CAD'. Then the area of concern is that of the rectangle with height 5√3 and length 5+4√3. The area is then ...
Area = lh = (5√3)(5 +4√3) = 5·5√3 +5·4·3
Area = 60 +25√3 . . . square units
_____
In the figure, 6.93 = 4√3, and 8.66 = 5√3, 16.93 = 10+4√3.
Find the amplitude of y = -2 sin x
Answer:
Amplitude = 2
Step-by-step explanation:
The amplitude of this sine wave is 2 denoted by the coefficient -2 in front of the sin(x). The negative of the coefficient denotes that the sine wave is the opposite of the standard sine wave.
Cheers.
5
What is the equation, in point-slope form, of the line that
is parallel to the given line and passes through the point
(-3, 1)?
4
3
2
(-3, 1)
42.27
1
5 4 3 2 1
2 3 4 5 x
y-1=-{(x+3)
y-1=-{(x + 3)
y-1= {(x + 3)
y-1= {(x + 3)
(-2, 4)
Answer: [tex]y-1=\dfrac32(x+3)[/tex]
Step-by-step explanation:
Slope of a line passes through (a,b) and (c,d) = [tex]\dfrac{d-b}{c-a}[/tex]
In graph(below) given line is passing through (-2,-4) and (2,2) .
Slope of the given line passing through (-2,-4) and (2,2) =[tex]\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}[/tex]
Since parallel lines have equal slope . That means slope of the required line would be .
Equation of a line passing through (a,b) and has slope m is given by :_
(y-b)=m(x-a)
Then, Equation of a line passing through(-3, 1) and has slope = is given by
[tex](y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)[/tex]
Required equation: [tex]y-1=\dfrac32(x+3)[/tex]
A bag contains 2
2
blue marbles, 2
2
red marbles, and 2
2
yellow marbles.
If Jenna randomly draws a marble from the bag (and puts it back) 15
15
times, how many times should she expect to pull a yellow marble?
Answer:
5 times
Step-by-step explanation:
Jenna wil most likely pull a yellow marble 1/3 of the time, because the total number of marbles is 6, and there are 2 yellow marbles, 2/6 which is 1/3. 1/3 times 15 is 5. So Jenna will most likely pull a yellow marble 5 times.
Scouts of ABC school made to run around a regular hexagonal ground fig 9, of perimeter 270 m .If they started running from point X and covered two fifth (2/5th) of the total distance.Which side of the ground will they reach?
Answer:
Scouts are on the third side in the sense they are running
Step-by-step explanation:
A regular hexagonal shape of perimeter 270 has each side of 270/6 = 45
Let´s call d the run distance then
d = 2/5 * 270 d = 108 m
We don´t have fig 9 available therefore if X is a vertex in the hexagon or at the middle point of one side, scouts are 108 m from the starting point which means they had run 2,4 sides of the hexagon. If X is not either a vertex or a middle point of a side then, we have two solutions for the question depending on the sense the scouts took when began the run (clockwise or counterclockwise)
The number of polynomials having zeros as -2 and 5 is a)1 b)2 c)3 d)more than 3
Answer:
d) More than 3.
Step-by-step explanation:
The polynomial (x - 5)(x + 2) ( = x^2 - 3x + 10) has zeros of -2 and 5 but so have the polynomials formed by multiplying this by any integer:
- for example 2(x - 5)(x + 2) , 4(x - 5)(x + 2) and so on.
Black Diamond Ski Resort charges $25 for ski rental and $10 an hour to ski. Bunny Hill Ski Resort charges $50 for ski rental and $5 an hour to ski. Create an equation to determine at what point the cost of both ski slopes is the same.
Answer:
25 + 10h = 50+5h
Step-by-step explanation:
Black Diamond Ski Resort
25 + 10h
Bunny Hill Ski Resort
50+5h
We want when they are equal
25 + 10h = 50+5h
Answer:
10x + 25 = 5x + 50
Step-by-step explanation:
Bryan decides he wants to help pay for a birthday party for his little brother at the ice rink. It cost $50 to rent the party room and then $4 for each person attending. Bryan only has $100 to spend at the party. a) What are the constraints for this situation? b) Find the domain and range for this situation. Make sure you include all values for each using correct notation.
Answer:
a) 4*x + 50 ≤ 100
b) Domain x (0 ; 12 ) Range f(x) ( 50 ; 98 )
Step-by-step explanation:
The constraint is:
4*x + 50 ≤ 100 where "x" is the number of persons
b) Domain for x
x = 0 up to x = 12 x (0 ; 12 )
c) Range for f(x)
f(x) = 4*x + 50
f(0) = 4*0 + 50 f(0) = 50
f(12) = 4*12 + 50 f (12) = 98
f(x) ( 50 ; 98 )
Help with this find the image of (1 ,2) after a reflection about y=x followed by a reflection about y=-x
Answer: (-1, -2)
Step-by-step explanation:
so at first you have (1, 2)
then you were asked to reflect about y=x which is (x, y) = (y, -x)
(1, 2) = (2, -1)
then followed by y=-x which is (x, y) = (-y, -x)
(2, -1) = (-1, -2)
I hope this helps!
Change histul
bols
A store pays two fees when a customer uses a credit card to make a purchase. These fees include:
A flat fee of $0.15
A processing fee equal to 1.75% of the dollar amount of the purchase
There is no sales tax on the purchase.
What is the amount, in dollars and cents, the store pays in fees for a $60.00 purchase by a customer using a credit
card?**
Answer:
So the amount to pay is $1 and 20 cents ( or a total of 120 cents)
Step-by-step explanation:
Here, we want to know the amount paid as fees for a $60 purchase given that the store has to pay a flat fee of $0.15 and a processing fee of 1.75% of the amount of purchase.
Firstly, we establish that there are two fees to be paid.
We already have a fee of $0.15
The other fee to pay is 1.75% of $60
Mathematically that would be;
1.75/100 * 60 = $1.05
Thus, the fees to be paid on the $60 purchase is $1.05 + $0.15 = $1.20
What is the reason: if a+c=b+c then a=b
Step-by-step explanation:
Example 1:
a+c=b+c then a=b
First let the value of a and b be different (not equal)
a=5
b=7
c=10
a+c=b+c
5+10=7+10
15≠17
Example 2:
Let the value a and b be equal (the same)
a=5
b=5
c=10
a+c=b+c
5+10=5+10
15=15
So when,
a+c and b+c is equal, a and b are always equal.
Hope this helps ;) ❤❤❤
Answer:
a=b
Step-by-step explanation:
Reason:
a+c=b+c
a-b=c-c
c-c would be 0
if a-b=c-c=0
a-b=0
Only if a=b can a-b=0
You can also take it as:
b-a=c-c (a+c=b+c)
b-a=0=c-c
Therefore b=a
By the way even I am a BTS army
Given: m∠V=103°, m∠VRT=71°, RS ∥ VU Find: m∠TRS, m∠U
Answer:
m∠U = 103° and m∠TRS = 6°
Step-by-step explanation:
In the given circle O,
Since, RS║VU, and VR is a transverse,
Therefor, m∠V + m∠R = 180° [Consecutive interior angles]
m∠R + 103° = 180° [m∠R = 103° given]
m∠R = 180° - 103°
m∠R = 77°
Since m∠R = m∠VRT + m∠TRS
77° = 71° + m∠TRS
m∠TRS = 77° - 71° = 6°
Quadrilateral RTUV is a cyclic quadrilateral.
Therefore, m∠U + m∠R = 180°
m∠U + 77° = 180°
m∠U = 180° - 77° = 103°
what is the coefficient of the variable in the expression 4-3x
As per the question,
We have to find what's the coefficient.
Let's start to seperate the expression.
Here,
x is the variable,
4 is a number.
-3 is also a number.
4, -3x
The number with x here is -3 in (-3x) as the coefficient is (-3) in the given equation.
Answer:
Hey there!
Rearrange the expression to: -3x+4
The coefficient would be -3.
Let me know if this helps :)
Which graph solves the following system? x+2y=4 5x−2y=8
Answer:
elimination method
x+2y=4 1
5x-2y=8 2
1+2
6x=12
x=2
plug into x+2y=4
2+2y=4
2y=4-2
2y=2
y=1
(2,1)
so graph 1
The height of the sail on a boat is 7 feet less than 3 times the length of its base. If the The area of the sail is 68 square feet, find its height and the length of the base.
Step-by-step explanation:
It is given that,
The height of the sail on a boat is 7 feet less than 3 times the length of its base.
Let the length of the base is x.
ATQ,
Height = (3x-7)
Area of the sail is 68 square feet.
Formula for area is given by :
[tex]A=lb\\\\68=x(3x-7)\\\\3x^2-7x=68\\\\3x^2-7x-68=0[/tex]
x = 8 feet and x = -3.73 feet
So, length is 8 feet
Height is 3(8)-7 = 17 feet.
So, its height and the length of the base is 17 feet and 8 feet respectively.
PLEASE HELP ASAP!!
The image above shows two dilated figures with lines IJ and JK drawn. If the smaller figure was dilated by a scale factor of 2, what relationship do lines IJ and KL have?
Answer:
[tex] IJ = 2(KL) [/tex]
Step-by-step explanation:
From the information given, the smaller figure was dilated on a scale factor of 2, to produce the bigger figure. In essence, the bigger figure is times 2 of the smaller figure.
Therefore, line IJ would be twice the length of KL.
The relationship that both lines have can be represented as: [tex] IJ = 2(KL) [/tex]
Weather balloons burst at an altitude of 27.5 km. What is the altitude in meters?
Answer:
27500
Step-by-step explanation:
meters are 100 times more than kilometers hope this helps:)
every rational number is a
a. whole number b. natural number c. integer d. real number
Greetings from Brasil...
a - whole number
FALSE
3/5, for example isnt a whole number
b. natural number
FALSE
0,457888..., for example isnt a natural number
c. integer
FALSE - like a
d. real number
TRUE
The set of real numbers contains the set of rational numbers
ℝ ⊃ ℚ
The diagonal of rhombus measure 16 cm and 30 cm. Find it's perimeter
Answer:
P = 68 cmStep-by-step explanation:
The diagonals of the rhombus divide it into 4 congruent right triangles.
So we can use Pythagorean theorem to calculate side of a rhombus.
[tex](\frac e2)^2+(\frac f2)^2=s^2\\\\e=30\,cm\quad\implies\quad\frac e2=15\,cm\\\\f=16\,cm\quad\implies\quad\frac f2=8\,cm\\\\15^2+8^2=s^2\\\\s^2=225+64\\\\s^2=289\\\\s=17[/tex]
Perimeter:
P = 4s = 4•17 = 68 cm
Thomas had 19 problems correct of the 25 problems on a recent math quiz. What percent of the
problems on the quiz did he answer correctly?
A.
24%
B. 36%
C. 76%
D.95%
Hey There!!
Your best choice is 76%
Because, 19/25 = x/100
25x = 1900
x = 76
°He got 76% correct!!°
By °Itsbrazts°
Answer:
76%
Step-by-step explanation:
Thomas got 19/25 marks.
** Note: Percents are always out of 100.
We don't know how many marks he got out of 100.
=> 19/25 = x/100
There are two ways to solve it from now.
=> Multiply 19 and 100; 25 and x
=> 25x = 1900
Next, Divide 25 on each side.
=> 25x/25 = 1900/25
=> x = 76
He got 76% on the quiz.
Another way is:
=> 19/25 = x/100
=> We need to divide 25 from 100.
=> We get 4.
So, 25 x 4 = 100
=> 19 x 4 = x
=> x = 76
He got 76% on the quiz.
Both ways are correct.
Triangle Q M N is shown. The length of Q M is 18, the length of M N is 17, and the length of Q N is 20. Law of cosines: a2 = b2 + c2 – 2bccos(A) What is the measure of AngleQ to the nearest whole degree? 43° 49° 53° 58°
The measure of angle Q in the triangle QMN is 52.83°
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
For a triangle with sides a, b, c and respective opposite angles A, B, C, cosine rule is:
a² = b² + c² - 2bc * cos(A)
In triangle QMN, QM = 18, MN = 17, QN = 20, hence:
17² = 18² + 20² - 2(18)(20) * cos(Q)
Q = 52.83°
The measure of angle Q in the triangle QMN is 52.83°
Find out more on equation at: https://brainly.com/question/2972832
#SPJ2
Answer:
53
Step-by-step explanation:
its rounded
3.03 times 10^-3 in scientific nation
Answer:
3.03 • 10⁻³ is scientific notation
0.00303 is decimal form