PLEASE HELP!!


Find the area of the following triangle enter the exact answer as a decimal

Answer:

2011: 567 2012: 567*(1-.015) 2013: 567*(1-.015)*(1-.015) 2014: 567*(1-.015)567*(1-.015)*(1-.015) you see the pattern; and, if so, you can build an little equation giving you the answer

Answer:

339

Step-by-step explanation:

a = 567 (.95)¹⁰

a = 339.4838445482

Rounded

339

Answer:

c) 72

hope this helps!

please give brainiest<3

Answer:

72

Step-by-step explanation:

Substitution:

4^3 + 4 x 6 - 16

64+24-16=72

Answer:

The coefficient is 3, the number right before the variable.

Answer:

3

Step-by-step explanation:

Answer:

there is one more zero

Step-by-step explanation:

now it's 8 million rather than 800 thousand.

Answer:

14

Step-by-step explanation:

Triangle=180

180-90 (RA) = 90

90-41= 39

(2x+11)=39

2x=28

x=14

Answer:

root 324=18

root 441=21

root 529=23

Step-by-step explanation:

root 324 = 18

root 441 = 21

root 524 = 23

Answer:

b. Pure Imaginary Numbers.

Step-by-step explanation:

[tex] (i \sqrt{3})^2 = i^2 \times (\sqrt{3})^2 = -1 \times 3 = -3 [/tex]

-3 is an integer, a complex number, and a rational number.

Answer: b. Pure Imaginary Numbers.

Answer:

Sara can buy 2 notebooks with the money that she has and she will have a remainding 23.1

Step-by-step explanation:

93.1-35-35=23.1

Answer:

Possible outcomes = 6

Step-by-step explanation:

Since the spinner is divided into red, yellow, orange, purple, blue and pink

Total of 6 colors.

Answer:

11 unit

Step-by-step explanation:

Applying,

s = √[(y₂-y₁)²+(x₂-x₁)²]...................... Equation 1

Where s = length of the side formed.

From the question,

Given: x₁ = -2, x₂ = 9, y₁ = 5, y₂ = 5

Substitute these values into equation 1

s = √[(9+2)²+(5-5)²]

s = √(11²)

s = 11 unit.

Hence the length of the side formed by the vertices is 11 unit

answer is

B. 6√2

hope this helps!

Answer:

152 and 9

Step-by-step explanation:

Answer: A. preserves length, angle measures and distance between points

Rigid motions or isometries are any of the three transformations below

Any of those three transformations will keep the figure the same size and shape. That means distances between any two points are kept the same, and angle measures are kept the same as well. Everything is kept the same. The only difference is that the figure is in a different location, is rotated somehow, or it is reflected some way. You can use a series of transformations to undo everything to get the original figure back.

If you wanted to change the size of the figure, then you would apply dilation, which isn't an isometry.

Answer:

3mm brainliest please

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

9mm times 1:3 of the rectangle is 245

Answer:

El número de facturas

5 lempiras = 10 billetes

20 lempiras = 15 billetes

Step-by-step explanation:

Vamos a representar

El número de facturas de

5 lempiras = x

20 lempiras = y

Nuestro sistema de ecuaciones se da como:

x + y = 25 ..... Ecuación 1

x = 25 - y

5 × x + 20 × y = 350

5x + 20y = 350 .... Ecuación 2

Sustituiríamos x por 25 - y en la ecuación 2

5 (25 - años) + 20y = 350

125 - 5 años + 20 años = 350

125 + 15 años = 350

15 años = 350 - 125

15 años = 225

y = 225/15

y = 15

Resolviendo para x

x = 25 - y

x = 25 - 15

x = 10

Por lo tanto, el número de facturas

5 lempiras = 10 billetes

20 lempiras = 15 billetes

Answer:

[tex] \frac{15 \sqrt{209} }{209} [/tex]

Step-by-step explanation:

Objective: Understand and work with trig identies.

Recall multiple trig identies and manipulate them to get from cosecant to secant.

Given

[tex] \csc(a) = \frac{60}{16} [/tex]

Apply reciprocal identity csc a = 1/sin a.

[tex] \sin(a) = \frac{16}{60} [/tex]

Apply pythagorean identity to find cos a.

[tex]( \frac{16}{60}) {}^{2} + \cos(x) {}^{2} = 1[/tex]

[tex] \frac{256}{3600} + \cos(x) {}^{2} = 1[/tex]

[tex] \cos(x) {}^{2} = \frac{3600}{3600} - \frac{256}{3600} [/tex]

We can simplify both expression

[tex] \cos(x) {}^{2} = \frac{225}{225} - \frac{16}{225} [/tex]

[tex] \cos(x) = \frac{ \sqrt{209} }{15} [/tex]

Cosine is positve on quadrant 1 so that cos(a)

Apply reciprocal identity sec a= 1/ cos a.

The answer is

[tex] \sec(a) = \frac{15}{ \sqrt{209} } [/tex]

Rationalize the denominator.

[tex] \frac{15}{ \sqrt{209} } \times \frac{ \sqrt{209} }{ \sqrt{209} } = \frac{15 \sqrt{209} }{209} [/tex]

Answer:

119.4

Step-by-step explanation:

The Area of the Rectangle : 132 cm

Area of the Circle : 12.6 cm

Shade=  MINUS - 132 cm  - 12.5 cm = 119.4!

Happy To Help! :)

Answer:

Y < 3x+2

Step-by-step explanation:

Alright so if you ever get stuck on something like this, Go on demos and put in (0,2) and then add in (-3,-7) and then add in the other answers to see if they match.

So your answer is:

y>3x+2

Answer:

105mm

Step-by-step explanation:

To find the rainfall during the month of April simply multiply the number of days in April times the average daily rainfall

Number of days in April: 30

Average daily rainfall: 3.5mm

Rainfall during the month = 30 * 3.5 = 105mm

Answer:

C = 4 pi ft

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

Solving for r

4 pi = pi r^2

Dividing each side by pi

4 = r^2

Taking the square root of each side

sqrt(4) = sqrt(r^2)

2 = r

Now we can find the circumference

C = 2 * pi *r

C = 2*pi*2

C = 4 pi ft

Answer:

OA . -6

Step-by-step explanation:

correct me if I'm wrong

Answer:

x=5

Step-by-step explanation:

7x - 4y = 23 and x + y = 8

Multiply the second equation by 4

4x + 4y = 32

Add this to the first equation

7x - 4y = 23

4x + 4y = 32

------------------------

11x    = 55

Divide each side by 11

11x/11 = 55/11

x = 5

Answer:

[tex]\huge\boxed{x=5}[/tex]

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}7x-4y=23\\x+y=8&|\text{subtract}\ x\ \text{from both sides}\end{array}\right\\\left\{\begin{array}{ccc}7x-4y=23&(1)\\y=8-x&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\7x-4(8-x)=23\qquad|\text{use the distributive property}\\\\7x+(-4)(8)+(-4)(-x)=23\\\\7x-32+4x=23\qquad|\text{combine like terms}\\\\(7x+4x)-32=23\qquad|\text{add 32 to both sides}\\\\11x-32+32=23+32\\\\11x=55\qquad|\text{divide both sides by 11}\\\\\dfrac{11x}{11}=\dfrac{55}{11}\\\\x=5[/tex]

Answer:

The answer is [tex]3^3\times 2^2[/tex].

Step-by-step explanation:

According to the rules of exponents

a^n = a x a x a x .... n times

So,

[tex]3^{2}\times (2^{3}+4)\\\\=9\times (8 +4)\\\\=108\\\\=3^{3}\times 2^{2}[/tex]

Answer:

raj

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

Have a nice day

Answer:

y=2

Step-by-step explanation:

3 = (y+7)/3

Multiply each side by 3

3*3 = (y+7)/3 *3

3*3 = y+7

9 = y+7

Subtract 7 from each side

9-7 = y+7-7

2 =y

Answer:

2 = y

Step-by-step explanation:

3 = y + 7 ÷ 3

multiply both side of equation by 3

3 × 3 = y + 7 ÷ 3 / 3

9 = y + 7

subtract 7 from both side

9 - 7 = y + 7 - 7

2 = y

Answer:

(x, y) = (10, 290)

Step-by-step explanation:

From the table

Total fees = fixed + variable

Fixed:

When number of times Ahmed mowed, x = 0

y = 40

When x = 2, y = 65

Rate of change = y2 - y1

= 65 - 40

= 25

y = 40 + 25x

Where,

y = total fees charged

40 = fixed fee

25x = variable fee

Total amount Ahmed will make for mowing 10 times

when x = 10

y = 40 + 25x

y = 40 + 25(10)

= 40 + 250

= 290

y = 290

(x, y) = (10, 290)

Answer:

-5, -3

Step-by-step explanation:

Answer:

hypotenuse = 7.3

Step-by-step explanation:

here 7 and 2 are the legs og the right triangle .we should find hypotenuse.

let the legs of the right triangle be a nd b respectively . And c be hypotenuse

using pythagoras theorem to find hypotenuse

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.28 = c

7.3 =c

Answer:

7.3

Step-by-step explanation:

[tex]7^{2} + 2^{2} = x^{2} \\ 53 = x^{2}\\\sqrt{53} = \sqrt{x^{2}} \\x = 7.3[/tex]

Answer:

HCF×LCM=a×b

6×60=a×b

a×b=360

So the numbers are whose product is 360 and LCM is 60

These two numbers can be 6,60 or 12,30