Please help meeeeeeeeeeeeeeeeee??????????!!!!!?!!??!!?!!!?

Answer:

7.2 N

Explanation:

Applying,

F = BIL................. Equation 1

Where F = Force due to current through the element, B = magnetic field, L = Length of the element.

From the question,

Given: B = 12 Tesla, L = 6 cm = 0.06 m, I = 10 A

Substitute these values into equation 1

F = 12(0.06)(10)

F = 7.2 N

Hence the force through the element is 7.2 N

Answer:

True

Explanation:

because they can hold marine organism inside

Complete question:

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?

Answer:

The acceleration of the ball is 78.98 m/s², directed inwards

Explanation:

Given;

mass of the ball, m = 175 g

radius of the circle, r = 0.5 m

angular speed of the ball, ω = 2 rev/s

The magnitude of the centripetal acceleration of the ball is calculated as follows;

[tex]a_c = \omega^2 r\\\\where;\\\omega \ is \ angular \ speed \ in \ rad/s\\\\a_c = (2\ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} )^2 \times (0.5 \ m)\\\\a_c =78.98 \ m/s^2[/tex]

The centripetal acceleration is directed inwards.

Answer:

Answer is 98 joules

Explanation:

P. E=2*9.8*3=98

S.i unit of potential energy ⚡ is joules

So answer is 98 joules

Answer:

a) The distance is 30 km

The time duration is 5 hours

b) s₁ is approximately 28.142 km or s₁ is approximately 1.505 km

Explanation:

The initial speed with of the person, v₁ = 6 km/h

The distance the walked by the person, d = From point A to point B

The rate at which the person increases the speed, Δv = 1.5 km/h

The time it takes for the person to arrive at point B from point A at the new speed, t₂ = 1 hour earlier than when walking at 6 km/h

a) Let t₁ represent the time it takes the person walking from point A to point B at 6 km/h, we have;

t₂ = t₁ - 1...(1)

d/t₁ = 6...(2)

d/t₂ = 6 + 1.5 = 7.5

∴ d/t₂ = 7.5...(3)

From equation (2), we have;

d = 6 × t₁ = 6·t₁

Plugging in d = 6·t₁, and t₂ = t₁ - 1 in equation (3) gives;

d/t₂ = 7.5

∴ 6·t₁/t₁ - 1 = 7.5

6·t₁ = 7.5 × (t₁ - 1) = 7.5·t₁ - 7.5

7.5·t₁ - 6·t₁ = 7.5

1.5·t₁ = 7.5

t₁ = 7.5/1.5 = 5

t₁  = 5

The time it takes the person walking from point A to point B at 6 km/h, t₁  = 5 hours

The distance from point A to point B, d = 6 km/h × 5 hours = 30 km

b) The distance the person travels at the initial speed, v₁ (6 km/h) = s₁

The duration the person pauses for a rest = 15 minutes = 1/4 hours

The speed with which he walks the rest of the journey, v₂ = 7.5 km/h

The time earlier than expected that he arrives, Δt = 30 minutes = 0.5 hours

We note that the total distance, d = 30 km

The expected time, t₁ = 5 hours

Therefore, we have;

s₁ + s₂ = 30 km

s₂ = 30 - s₁

v₁/s₁ + 1/4 + v₂/s₂ = t₁ - 0.5

Therefore;

6/s₁ + 1/4 + 7.5/(30 - s₁) = 5 - 0.5 = 4.5

6/28.142+ 1/4 + 7.5/(30 - 28.142) = 5 - 0.5 = 4.5

6/s₁ + 7.5/(30 - s₁) = 4.5 - 1/4 = 4.25

-(3·s₁ + 360)/(2·s₁²- 60·s₁) = 4.25

2·s₁²- 60·s₁) × 4.25 + 3·s₁ + 360 = 0

17·s₁²- 504·s₁ + 720 = 0

s₁ = (504 ± √((-504)² - 4 × 17 × 720))/(2 × 17)

s₁ ≈ 28.142 or s₁ = 1.505

The distance the individual travels at v₁ = 6 km/h, s₁ ≈ 28.142 km or 1.505 km

Explanation:

4) The net torque on the on the meter stick is equal to zero in order to have no rotation.

[tex]\tau_{1} = \tau_{2}[/tex]

[tex]F_{1}d_{1} = F_{2}d_{2}[/tex]

[tex](8 \:N)(0.3\: m) = F_{2}(0.1 \:m)[/tex]

[tex]F_{2} = \frac{(8 \:N)(0.3 \:m)}{(0.1 \:m)} = 24 \:N[/tex]

5) We are going the same equations in #4 here.

[tex]F_{1}d_{1} = F_{2}d_{2}[/tex]

[tex](500 \:N)(2.4 \:m) = F_{2}(3.0 \:m)[/tex]

[tex]F_{2} = \frac{(500 \:N)(2.4 \:m)}{(3.0 \:m)} = 400 \:N[/tex]

Answer:

big half like whale is so big

Answer:

Option D. ²³⁹₉₃Np

Explanation:

Let the unknown be ʸₓA.

Thus, the equation becomes:

²³⁹₉₂U —> ⁰₋₁e + ʸₓA

Next, we shall determine the x, y and A. This can be obtained as follow:

92 = –1 + x

Collect like terms

92 + 1 = x

93 = x

x = 93

239 = 0 + y

239 = y

y = 239

ʸₓA => ²³⁹₉₃A => ²³⁹₉₃Np

Thus, the complete equation is:

²³⁹₉₂U —> ⁰₋₁e + ²³⁹₉₃Np

Answer:

The Answer is FRICTION!

Answer:

both

Explanation:

and I'm serious he is literally both

Answer:

mark me as the brainliest plss

Answer:

7 seconds

Explanation:

he went down -28 m/s so 7 times -4 equals -28 m/s which is what he needed to slowness down to 10 m/s

Answer:

In antiquity, systems of measurement were defined locally: the different units might be defined independently according to the length of a king's thumb or the size of his foot, the length of stride, the length of arm, or maybe the weight of water in a keg of specific size, perhaps itself defined in hands and knuckles.

Systems of Measurement: there are two main systems of measurement in the world: the Metric (or decimal) system and the US standard system. ... The US Standard system uses units that have no predictable relationship to each other. For example, there are 2 cups in a pint, but 4 quarts in a gallon.

Answer:

Explanation:

The vertical component is found in the magnitude of the force times the sine of the angle; the horizontal component is found in the magnitude of the force times the cosine of the angle. Thus:

vertical component = [tex]60.0sin(30.0)=30.0[/tex] and

horizontal component = [tex]60.0cos(30.0)=52.0[/tex]

Answer:

Image not full.

Explanation:

From what I can see, Displacement is 175m,

Distance will be = 100 + 50 + the hidden value on the bottom right

Answer: Conduction occurs more readily in solids and liquids, where the particles are closer to together, than in gases, where particles are further apart.

Answer:

conduction occurs when gas becomes liquid.

Answer:

[tex]{ \tt{volume = \pi {r}^{2} h}}[/tex]

Answer:

there it is fella tried o. ma own consciousness

Answer:

option 3, as circuit breakers are mostly used as precautions

Answer:

242.4 V

Explanation:

Applying,

Q = cm(t₂-t₁)................ Equation 1

Where Q = amount of  heat, c = specific heat capacity, m = mass, t₁ = initial temperature, t₂ = final temperature.

But this heat is produced by electrical power

Therefore,

P = Q/t

Where P = Electrical power, t = time

Also,

P = V²/R

Where V = voltage, R = resistance

Therefore

V²/R = Q/t......................... Equation 2

Substitute equation 1 into equation 2

V²/R = cm(t₂-t₁)/t................. Equation 3

Given: R = 250 ohms, m = 4.6 kg, t₁ = 22°C, t₂ = 32°C, t = 15 min. = (15×60) = 900 seconds

Constant: c = 4600 J/kg.°C

Substitute these values into equation 2

V²/250 = 4600(4.6)(32-22)/900

V²/250 = 235.11

V² = 250×235.11

V² = 58777.78

V = √58777.78

V = 242.4 V

Answer:

False

Explanation:

Friction is a force exerted by a surface against the motion of a body across its surface. Therefore, friction is a type of contact force only.

Answer:

Explanation:

If the hippo is laying on the rock, I'm assuming that there is no movement going on at all, in either the hippo or the rock. If no movement occurs, there is no work being done.

Answer:

Explanation:

If the object is falling straight down it is in free fall.  The difference between that and two-dimensional motion is that 2D motion is parabolic (projectile)

Answer:

d) All the above

Explanation:

Therefore, as all of the physical quantities have the same SI units, the answer is d) all of the above.

Answer: The statement gaining potential energy is always associated with a force field, is true about potential energy.

Explanation:

The energy acquired by an object due to its position is called potential energy.

Basically, a force field exerts a force that gives rise to potential energy of an object. For example, gravity, spring force etc.

This means that gaining potential energy is always associated with a force field.

A change in position does not always means that an object gains potential energy. For example, a spring will have more potential energy when it is compressed or stretched.

Hence, change in position of an object not necessarily means always gain in potential energy.

There are two types of potential energy that is, gravitational potential energy and elastic potential energy.

Thus, we can conclude that the statement gaining potential energy is always associated with a force field, is true about potential energy.

Answer:

Explanation:

The first one and the last one are the correct answer.

Answer:

an open circuit (A battery, bulb, wire,switch)

Explanation:

the battery supplies the power the wire carries the current from the battery to the bulb but the circuit is not completed if the switch is not connected (Switch )

Answer:

Primera Ley de Newton, también llamado Ley de la Inercia de Newton.

Explanation:

Este concepto es la Primera Ley de Newton o Ley de la Inercia de Newton, la cual dice textualmente que todo cuerpo al cual no se aplica ninguna fuerza externa neta no nula sobre sí se encuentra en reposo o desplazándose a velocidad constante.

Entiéndase a la inercia como la tendencia de un cuerpo a oponerse al cambio en su estado de movimiento.

(a) 39 V

(b) 7.8 V

(a) Neglecting the internal resistance of the battery, the voltage drop (V) across the battery is found from Ohm's law as follows;

V = IR                -------------------------(i)

Where;

I = current through the battery

R = total resistance of the circuit.

From the question;

I = 0.75A

R = 52.0Ω

Substitute the values of I and R into equation (i)

=> V = 0.75 x 52.0

=> V = 39Volts

Therefore, the voltage drop across the battery is 39 Volts

(b) Since the set of lanterns is connected in series, then the same current flows through each of the lanterns. Also, since the lanterns are identical, the resistance ([tex]R_{L}[/tex]) of each of them is given by the total resistance (R = 52.0Ω) divided by the number of lanterns. i.e

[tex]R_{L}[/tex] = [tex]\frac{52.0}{5}[/tex]

[tex]R_{L}[/tex] = 10.4Ω          [Each lantern has a resistance of 10.4Ω]

The current flowing through them is the same as the current (I = 0.75A) flowing the circuit.

Therefore, using Ohm's law, the voltage drop ([tex]V_L[/tex])across each load (lantern) is

[tex]V_L[/tex] = I x [tex]R_{L}[/tex]

[tex]V_L[/tex] = 0.75 x 10.4

[tex]V_L[/tex] = 7.8Volts

Therefore, the voltage drop across each load is 7.8 Volts