Answer:
Extracting out that inner right angle.
Hypotenuse = 8
Height = h
Adjacent :
[tex] = \frac{10}{5} = 2[/tex]
Height, h :
[tex]{ \tt{h = \sqrt{ {8}^{2} - {5}^{2} } }} \\ { \tt{h = \sqrt{64 - 25} }} \\ { \tt{h = \sqrt{39} }} \\ the \: height \: is \: { \boxed{6.2}} \: units[/tex]
please help i need to finnish this!
Answer:
56
Step-by-step explanation:
f(x)=6*x^2+2 =6*3^2+2=56
Answer:
56
Step-by-step explanation:
6(x^2) + 2 = 0replace x = 3 => 6 x (3 ^ 2) + 2 = 56
HELP ITS DUE IN THE MORNING AND ITS 3:57
Answer:
A " (1,-2)
B " (4,0)
C " (6,-3)
Step-by-step explanation:
Hope it helped.
° ° °
Atlantic Hurricanes
Number
1925
1930
1935
1940
1945
1950
1955
1960
1965
1970
1975
Year
Between which years was
the biggest change in the
number of hurricanes?
Answer:
1950
Step-by-step explanation:
because 1950 column has the most highest number which is 11
Answer:
Between 1945 and 1950 ( from 5 to 11 ),
Step-by-step explanation:
hurry PLEASE i'm unsure of this
Answer:
Infinite solutions
Step-by-step explanation:
x + 4y = 7 --------------(I)
8y = 14 - 2x
⇒ 2x + 8y = 14 -----------(II)
[tex]\frac{a_{1}}{a_{2}}=\frac{1}{2}\\\\\frac{b_{1}}{b_{2}}=\frac{4}{8}=\frac{1}{2}\\\\\frac{c_{1}}{c_{2}}=\frac{7}{14}=\frac{1}{2}\\\\\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{2}[/tex]
So, infinite solutions
Answer:
G
Step-by-step explanation:
Given the 2 equations
x + 4y = 7 → (1)
8y = 14 - 2x → (2)
make x the subject of (1) by subtracting 4y from both sides
x = 7 - 4y
Substitute x = 7 - 4y into (2)
8y = 14 - 2(7 - 4y) ← distribute
8y = 14 - 14 + 8y
8y = 8y
Since both sides are equal this indicates the system has infinite solutions
helpppppppppppppp meeeeeeeeeeeeeeeee plsssssssssssssssss!!!!!!!!!!!!!
Answer:
a=13
Step-by-step explanation:
-90=-6a-12
-6a=-78
a=13
Answer:
a=13 well as u can see the other comment already gave an explanation of y it is a=13 and i completely agree with it have a nice afternoon,night,or day to u
Step-by-step explanation:
2x²+3x²+3.(-1) =5x.x+5x .1
[tex]\\ \sf\longmapsto 2x^2+3x^2+3(-1)=5x.x+5x.1[/tex]
[tex]\\ \sf\longmapsto 5x^2-3=5x^2+5x[/tex]
[tex]\\ \sf\longmapsto 5x^2-5x^2-3=5x[/tex]
[tex]\\ \sf\longmapsto 5x=-3[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-3}{5}[/tex]
The circumference of a circle is 20π. What is the area of the circle?
Answer:
The area of the circle is 100 square units.
Step-by-step explanation:
We are given that the circumference of a circle is 20π, and we want to determine its area.
Recall that the circumference of a circle is given by the formula:
[tex]\displaystyle C = 2\pi r[/tex]
Substitute:
[tex]20 \pi = 2 \pi r[/tex]
Solve for the radius:
[tex]\displaystyle r = \frac{20\pi}{2\pi} = 10[/tex]
The area of a circle is given by:
[tex]\displaystyle A = \pi r^2[/tex]
Since the radius is 10 units:
[tex]\displaystyle A = \pi (10)^2[/tex]
Evaluate:
[tex]\displaystyle A = 100\pi\text{ units}^2[/tex]
In conclusion, the area of the circle is 100 square units.
Divide. Write your answer as a fraction in simplest form. − 10 2/7÷(−4 4/11)=
Answer:
33/14
Step-by-step explanation:
[tex] - 10 \frac{2}{7} + ( - 4 \frac{4}{11} )[/tex]
[tex] = - \frac{72}{7} \div - ( \frac{48}{11} )[/tex]
[tex] = \frac{72}{7} \times \frac{11}{48} [/tex]
[tex] = \frac{3}{7} \times \frac{11}{2} [/tex]
[tex] = \frac{33}{14} [/tex]
stan dreamcatcher
a two-digit number is 5 times as large as the sum of its digits. What number is it?
Answer:
45
Step-by-step explanation:
CHECK ANSWER:
45 *5 = 225
45+5 = 50
50 < 225
sum < times
I hope this helped !
find the mean value of the following. 5, 11, 4, 10, 8, 6
a store sells a 1 1/4 pound of turkey for 9 dollars what is the unit price of the turkey in the package
Answer:
7.20 dollars
Step-by-step explanation:
1 1/4 can be expressed as 5/4 ((1*4+1) /4)
If price of 5/4 pound of turkey = $9
Price of 1 pound of turkey = $9 / (5/4)
( Same way you'd divide the price of 2 pounds by 2 to get the price of 1 pound)
$9 / (5/4) = $7.2
I don't understand need help?
9514 1404 393
Answer:
2. (only)
Step-by-step explanation:
The Pythagorean theorem tells you the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse. To determine if these are right triangles, determine if that condition is met.
1. 3^2 +5^2 = 9 + 25 = 34 ≠ (√35)^2 . . . . not a right triangle
2. 5^2 +4^2 = 25 +16 = 41 = (√41)^2 . . . a right triangle
3. 6^2 +8^2 = 36 +64 = 100 ≠ (√10)^2 . . . . not a right triangle
4. 3^2 +3^2 = 9 +9 = 18 ≠ (3√3)^2 = 27 . . . . not a right triangle
How many gallons equal 26 liters
Answer:
6.8 gallions i believe. im not quite sure
If you have to invest in an account that pays 5.3 compound annually, after 10 years how much interest is earned
[tex]\\ \sf\longmapsto Interest=Rate\times Time[/tex]
[tex]\\ \sf\longmapsto Interest=5.3(10)[/tex]
[tex]\\ \sf\longmapsto Interest =53[/tex]
It means that if your principal is $100 after 10years you will receive $53 as interest
Step-by-step explanation:
[tex]thank \: you[/tex]
2^12÷2^(k/2 )= 32 find k
Answer:
k = 14
Step-by-step explanation:
Prime factorize 32
32 = 2 * 2 * 2 * 2 * 2 = 2⁵
[tex]\frac{2^{12}}{2^{\frac{k}{2}}}= 32\\\\\frac{2^{12}}{2^{\frac{k}{2}}}=2^{5}\\\\2^{12-\frac{k}{2}}=2^{5}[/tex]
Both sides base are same.So, compare exponents
[tex]12-\frac{k}{2}=5\\[/tex]
Subtract 12 from both side
[tex]-\frac{k}{2}=5-12\\\\-\frac{k}{2}=-7\\[/tex]
Multiply both sides by (-2),
[tex](-2)*(-\frac{k}{2})=-7*(-2)\\\\k = 14[/tex]
Can some help please
Answer:
Step-by-step explanation:
2 * 10^7 You are to use a single digit. That's the 2 on the left. Then count what it takes to get the decimal between the 2 and the 3. It's 7
0.000136
Count the number of zeros. Add a minus 1. You want the number to be counted until you get minus 1 which is the number of powers after the 1.
1 * 10^-4
26837 becomes 2 * 10^4. 4 is the number of digits you have before you get to a number between 1 and 10.
0.0302 becomes 3 * 10^-(1 + 1) = 3 * 10^-2
Given: j(x) = x2 - 2x + 1
Which set of values represents the range of the function for the domain {0, 1, 5}?
Answer:
{1, 0, 16}
Step-by-step explanation:
given..
j(x) = x^2-2x+1
put all given values of domain (1,0 and 5 ) in the equation..
the values you get are range of the function
Answer: 1
Step-by-step explanation
0(2)-2(0)+1=0+0+1= 1
1(1)-(2)(1)+1=1-2+1= 1
(5)(2)-(2)(5)+1=10-10+1= 1
Si Juana tiene dos perros y lo simbolizamos y 2p y le regalan un hato y lo simbolizamos por g como se representa en el leguaje algebraico.
A) 3P
B) 3G
C) 2PTG
D) 2P-G
u4gent help needed
help me with the question of o.math
Answer:
1≤f(x)≤5
Step-by-step explanation:
-1≤x≤1
-2≤2x≤2 (Multiplied by 2 both side)
-2+3≤2x+3≤2+3 (Adding three both sides)
1≤f(x)≤5
Find the surface area of the triangular prism
a sum of money Doubles itself in 5 years what is rate of simple interest
Step-by-step explanationIf you are reading this say
thank u
Find the first three terms of the sequence given by the following.
a
n = 25-3(n − 1), n= 1, 2, 3, ...
A. 28, 25, 22
B. 25, 22, 19
C. 25, 28, 31
D. 28, 31, 34
the answer is
A. 28, 25, 22
I need help please help me
Answer:
I found x for you, right there.
Answer: x is 12 and y is 5
Step-by-step explanation:
If 75% is 10 days, how many days is the remaining 25%?
Answer:
10/3 days or 3 1/3 days
Step-by-step explanation:
Let d = number of days total
75% of the days is 10
.75 d = 10
d = 10/.75
d = 40/3 days
We want to know how man is 25% of d
d * 25%
(40/3) *.25
10/3 days
the area of a parallelogram is 48cm².if the two adjacent sides are 8cm and 6cm, find the length of its diagonal .
Answer:
10cm
Step-by-step explanation:
Assuming the shape is a rectangle since it's already stated that it's a parallelogram, and the area is stated, we can use the Pythagorean theorem to find the length
[tex]a^{2} +b^2=c^2[/tex], where c will be the length
isolate c
[tex]c^2=a^2+b^2[/tex]
[tex]c=\sqrt{a^2+b^2}[/tex]
substitute for a and b
[tex]c=\sqrt{8^2+6^2}[/tex]
[tex]c=\sqrt{64+36}[/tex]
[tex]c=\sqrt{100}[/tex]
[tex]c=10[/tex]
Add.
(3x2 – 2x) + (4x-3)
O A. 7x2- 5x
O B. 12x3 - 14x2 + 6x
O C. 3x2 - 6x + 3
O D. 3x2 + 2x-3
Answer:
O D. 3x2 + 2x-3
Answer:
A.7x2-5x questions 2of 20
Is the following number rational or irrational?
-117
Choose 1 answer:
Rational
Irrational
Answer:
-117 is irrational number
Answer:
Irrational
Step-by-step explanation:
Irrational number can't be written as a faction, -11pie can't be written as a fraction. Therefore it is a irrational number.
K is between J and M. L is
between K and M. M is
between K and N. If JN = 30, KM = 8, and JK = KL = LM, what is MJ?
(please do step-by-step fully)
Answer:
12
Step-by-step explanation:
for this you need to draw a straight line and plot the points J,K,L,M,N according to the question.
here,
given K lies between J and M, L is between K and M , M is between K and N.
JN= 30, KM=8
JK=KL=LM
MJ= ?
according to the question,
J--------K-------L--------M-------N
KM= 8
KL+LM= 8 (KL+LM=KM)
KL+KL=8 ( given, LM=KL)
2KL= 8
KL=4
so,
JK= KL=4 and LM= KL= 4
now,
MJ= ?
we know
MJ= JK+KM = 4+8= 12
Trigonometric ratios
class 9
please answer my questions
Step-by-step explanation:
Hi there!
Please see the answer in the picture.
Hope it helps!
1. Approach
One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,
[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]
Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.
2. Problem (9)
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
As per the attached image, the following statements regarding the value of each ratio can be made:
[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]
Substitute,
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
Simplify,
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]
Thus, this equation is true.
2. Problem (10)
Use a similar strategy to evaluate this equation,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
Use the attached image to evaluate the ratios.
[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]
Substitute,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
Simplify,
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
Rationalize the denominator,
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]
[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]
[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]
[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]
[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]
Therefore, this equation is also true.
What is the common ratio of the geometric
the answer is B. 7
Step-by-step explanation:
it's the number u see the most therefore its the most common
Answer:
D. 10 maybe?
Step-by-step explanation:
because it moves a decimal with every number. im not sure I hope it's correct. it adds on a zero