please help me please help me​

Please Help Me Please Help Me

Answers

Answer 1

Answer:

largest 4 digit number × largest 3 digit number

=9999 × 999

(10000-1)×(1000-1) = (a-b)(c-b)= ac-ab-bc+b^2

10000000-10000-1000+1 = 9989001


Related Questions

PLEASE HELP ME AND BE CORRECT BEFORE ANSWERING

Answers

Answer:

False, true

Step-by-step explanation:

I’m not 100% sure but I think that’s the answer

can someone please help me?

Answers

Step-by-step explanation:

D. RAMONA SAVED THE MOST IN 2006

D. Ramona saved the most in 2006

Determine f(-1) if the graph of f(x) is given below.

Answers

Answer:

[tex]f(-1) = -2[/tex]

Step-by-step explanation:

Given

The attached graph

Required

[tex]f(-1)[/tex]

This is the point where

[tex]x = -1[/tex]

On the attached graph;

[tex]f(x) = -2[/tex] when [tex]x = -1[/tex]

Hence:

[tex]f(-1) = -2[/tex]

th of
cm.
4 Mrs. Ayer is painting the outside of her son's toy
box, including the top and bottom. The toy box
measures 3 feet long, 1.5 feet wi de, and 2 feet high.
What is the total surface area she will paint?
1) 9.0 ft
2) 13.5 ft?
3) 22.5 ft?
4) 27.0 ft

Answers

27.0 ft should be the answer

Which function below has the following domain and range?
Domain: {-7, - 5,2, 6, 7}
Range: {0, 1,8}

Answers

Answer:

{(2,0),(-5,1),(7,8),(6,0),(-7,1)

Given the following formula, solve for y.

Answers

Answer:

b) y=x -2(w+z)

Step-by-step explanation:

multiply both sides, move the terms and write on parametric form

how many models does the following set have? 5,5,5,7,8,12,12,12,150,150,150

Answers

Answer:  3 modes

The three modes are 5, 12, and 150 since they occur the most times and they tie one another in being the most frequent (each occurring 3 times).

Only the 7 and 8 occur once each, and aren't modes. Everything else is a mode. It's possible to have more than one mode and often we represent this as a set. So we'd say the mode is {5, 12, 150} where the order doesn't matter.

Which of the following best describes the expression 4(y + 6)?
The product of a constant factor of four and a factor with the sum of two terms
The sum of a constant factor of six and a factor with the product of two terms
The product of two constant factors four and six plus a variable
The sum of two constant factors four and six plus a variable

Answers

Answer:

The product of a constant factor of four and a factor with the sum of two terms

Step-by-step explanation:

4(y + 6)

This is two terms, a constant 4 and a term with y+6

We a multiplying so we have a product

Answer:

A

Step-by-step explanation:

I believe A is the best answer because 4 is the constant factor with the sum of y + 6. I just think it best rrepresents the equation! :)

answer plz no explanation needed

Answers

Answer:

x is 1. i looked it up so that's all you need

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Answers

Answer:

[tex]f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.[/tex]

Step-by-step explanation:

Given

[tex]9 < x < 10[/tex] --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

[tex]v = x^3[/tex]

For a uniform distribution, we have:

[tex]x \to U(a,b)[/tex]

and

[tex]f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.[/tex]

[tex]9 < x < 10[/tex] implies that:

[tex](a,b) = (9,10)[/tex]

So, we have:

[tex]f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex]

Solve

[tex]f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex]

[tex]f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex]

Recall that:

[tex]v = x^3[/tex]

Make x the subject

[tex]x = v^\frac{1}{3}[/tex]

So, the cumulative density is:

[tex]F(x) = P(x < v^\frac{1}{3})[/tex]

[tex]f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex] becomes

[tex]f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.[/tex]

The CDF is:

[tex]F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx[/tex]

Integrate

[tex]F(x) = [v]\limits^{v^\frac{1}{3}}_9[/tex]

Expand

[tex]F(x) = v^\frac{1}{3} - 9[/tex]

The density function of the volume F(v) is:

[tex]F(v) = F'(x)[/tex]

Differentiate F(x) to give:

[tex]F(x) = v^\frac{1}{3} - 9[/tex]

[tex]F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}[/tex]

[tex]F'(x) = \frac{1}{3}v^{-\frac{2}{3}}[/tex]

[tex]F(v) = \frac{1}{3}v^{-\frac{2}{3}}[/tex]

So:

[tex]f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.[/tex]

Substituting the equation y = 4x + 1 into the equation 2y = -x – 1 will produce the equation ________.

Answers

Answer:

Step-by-step explanation:

Substituting y = 4x+1 into 2y = -x-1 gives the equation

2(4x+1) = -x-1

Solve the equation:

8x+2 = -x-1

9x = -3

x = -⅓

Substituting y = 4x+1 into 2y = -x-1 will produce the equation 2(4x+1) = -x-1

What are the equations?

A mathematical statement known as an equation is made up of two expressions joined together by the equal sign. Based on the degree, there are four different main types of equations. Equations that are linear, quadratic, cubic, and polynomial

Given,  the equation y = 4x + 1 and another equation 2y = -x – 1.

Substituting equation 1 into equation 2 we will get

2(4x+1) = -x-1

Solve the equation:

8x+2 = -x-1

9x = -3

x = -⅓

Therefore, The equation 2(4x+1) = -x-1 is created when y = 4x+1 is substituted into 2y = -x-1.

Learn more about equations here:

https://brainly.com/question/16255566

#SPJ2

which choice are equivalent to the expression below? Check all that apply
I could not get the expressions to type correctly because I am new so I am sending a picture. I am having trouble working backwards to figure out which once to choose.

Answers

Answer:

A, B, and E apply

Step-by-step explanation:

One thing we can do is to make everything in the same format, under one square root, with no non-square roots.

First, we can say that 6 is equal to √36 as 6² =36, and 6 ≥ 0. Therefore, 6√3 = √36 * √3 = √108

For A, √3 * √36 = √108, so this applies

For B, √18 * √6 = √108, so this applies

For C, 108² = √something bigger than 108 = √11664, so this does not apply

For D, √54 ≠ √108, so this does not apply

For E, √108 = √108, so this applies

For F, √3 * √6 = √18, so this does not apply

If x and y are positive integers such that 5x+3y=100, what is the greatest possible value of xy? please include steps. Thank you!

Answers

Answer:

The greatest possible value of xy is 165.

Step-by-step explanation:

CAN SOMEONE PLEASE ANSWER MY QUESTION?!

Answers

Answer:

0.02 m/sec

Step-by-step explanation:

26/30=0.89 —> 0.89 min —> 53.4 sec

42/50=0.84 meters

speed=0.84 / 53.4 = 0.015 m/sec = 0.02 m/sec

PLEASE HELP!!!!!! (answer in decimal!!!!)

Answers

Answer:

0.706....

Step-by-step explanation:

Find the solution to the system of equations.
You can use the interactive graph below to find the solution.
\begin{cases} y=-2x+7 \\\\ y=5x-7 \end{cases}









y=−2x+7
y=5x−7


x=x=x, equals
y=y=y, equals

Answers

Answer:

x=2

y=3

Step-by-step explanation:

y=−2x+7

y=5x−7

Set the two equations equal since they are both equal to y

−2x+7 =5x−7

Add 2x to each side

-2x+7+2x = 5x-7+2x

7 = 7x-7

Add 7 to each side

7+7 = 7x-7+7

14 =7x

Divide by 7

14/7 = 7x/7

2 =x

Now find 7

y = 5x-7

y = 5(2) -7

y = 10-7

y = 3

Given that y=y=y,

→ -2x+7 = 5x-7

Let's find the value,

→ -2x+7 = 5x-7

→ 7 = 5x+2x-7

→ 7 = 7x-7

→ 7+7=7x

→ 14 = 7x

→ x = 14/7

→ [x = 2]

Then we can find 7,

→ y = 5x-7

→ y = 5(2) -7 y = 10-7

→ [y = 3]

This is required answer.

Chau Took 5 3/8 hours to clean the bedroom. Then he took a 1/2 to clean the den. How much total time did he take to clean two rooms.

Answers

Answer:

It took Chau 5 hours, 52 minutes, and 30 seconds to clean both rooms.

Step-by-step explanation:

Given that Chau took 5 3/8 hours to clean the bedroom, and then he took a 1/2 to clean the den, to determine how much total time did he take to clean two rooms the following calculation must be performed:

5 + 3/8 + 1/2 = X

5 + 0.375 + 0.5 = X

5.875 = X

0.875 = 7/8

60/8 x 7 = 52.5

Therefore, it took Chau 5 hours, 52 minutes, and 30 seconds to clean both rooms.


What are the zeros of f(x) = (x - 2)(x + 7)? Select all that apply.
A. X= -7
B. X = -2
C. X = 2
D. X = 7

Answers

Answer:

2 = x          -7 = x

Step-by-step explanation:

f(x) = (x - 2)(x + 7)

y  = (x - 2)(x + 7)

Set y = 0

0 = (x - 2)(x + 7)

Using the zero product property

0 = x-2    0 = x+7

2 = x          -7 = x

Answer:

Zeros happen when f(x) = 0. There are two zeros in the given function:

when (x - 2) = 0when (x + 7) = 0

Therefore solve both equations above and you'll get:

Zero #1 = 2Zero #2 = -7

Lakisha wants to buy some bitcoins. The exchange rate is $1 USD to 0.004 bitcoin. How many bitcoins can she buy with $400?

Answers

Answer:

1.6 Bitcoins

Step-by-step explanation:

Given data

We have the rate as

$1 USD to 0.004

Hence $400 will buy x bitcoins

Cross multiply to find the value of x

1*x= 400*0.004

x=1.6

Hence $400 will get you 1.6 Bitcoins

A BYU-Idaho professor took a survey of his classes and found that 82 out of 90 people who had served a mission had personally met a member of the quorum of the twelve apostles. Of the non-returned missionaries that were surveyed 86 of 110 had personally met a member of the quorum of the twelve apostles. Calculate a 99% confidence interval for the difference in the two proportions.

Answers

Answer:

The 99% confidence interval for the difference in the two proportions is (-0.0247, 0.2833).

Step-by-step explanation:

Before building the confidence interval, we need to understand the Central Limit Theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

A BYU-Idaho professor took a survey of his classes and found that 82 out of 90 people who had served a mission had personally met a member of the quorum of the twelve apostles.

This means that:

[tex]p_S = \frac{82}{90} = 0.9111[/tex]

[tex]s_S = \sqrt{\frac{0.9111*0.0888}{90}} = 0.045[/tex]

Of the non-returned missionaries that were surveyed 86 of 110 had personally met a member of the quorum of the twelve apostles.

This means that:

[tex]p_N = \frac{86}{110} = 0.7818[/tex]

[tex]s_N = \sqrt{\frac{0.7818*0.2182}{110}} = 0.0394[/tex]

Distribution of the difference:

[tex]p = p_S - p_N = 0.9111 - 0.7818 = 0.1293[/tex]

[tex]s = \sqrt{s_S^2+s_N^2} = \sqrt{0.045^2+0.0394^2} = 0.0598[/tex]

Calculate a 99% confidence interval for the difference in the two proportions.

The confidence interval is:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower bound of the interval is:

[tex]p - zs = 0.1293 - 2.575*0.0598 = -0.0247[/tex]

[tex]p + zs = 0.1293 + 2.575*0.0598 = 0.2833[/tex]

The 99% confidence interval for the difference in the two proportions is (-0.0247, 0.2833).

If a + b = s and a - b = t, then which of the following expresses the value of ab in terms of s and t?

Please help me out

Answers

Answer:

   =(s^2 - t^2)/4

Step-by-step explanation:

a + b = s and a - b = t,

Add the two equations together

a + b = s

a - b = t

----------------

2a = s+t

a = (s+t)/2

Subtract the two equations

a + b = s

- a + b = -t

-------------------

2b =(s-t)

b = (s-t)/2

We want to find ab

ab = (s+t)/2 *  (s-t)/2

FOIL

    =(s^2 - t^2)/4

Please look at the file below. (No links will give brainiest)

Answers

Answer:

3.564 m^2

Step-by-step explanation:

The area of the original garden is

A = 5.4 * 1.5 = 8.1

The new garden is

5.4*1.2 = 6.48 by 1.5*1.2 =1.8

The area is

A = 6.48*1.8=11.664

The increase in area is

11.664-8.1=3.564

The given information is,

To find the increase in area of the garden.

Formula we use,

→ Area = Length × Width

Area of the real garden is,

→ 5.4 × 1.5

→ 8.1 m

The new garden will be,

→ 5.4 × 1.2 = 6.48 m

→ 1.5 × 1.2 = 1.8 m

The area of the new garden is,

→ 6.48 × 1.8

→ 11.664

Then the increase in area of the garden,

→ 11.664 - 8.1

→ 3.564 m²

Hence, 3.564 m² is the increase in area.

Given the function

f(x)=7x2−2x+5.Calculate the following values:

f(−2)=

f(−1)=

f(0)=

f(1)=

f(2)=

Answers

This is the answers and their coordinates

3-6÷12
simplyfication​

Answers

hope this helps! feel free to clarify

Multiply the following and combine terms where possible. -a(a-b-3)

Answers

Answer:

-a^2 +ab +3a

Step-by-step explanation:

-a(a-b-3)

Distribute

-a*a -a*(-b) -a *(-3)

-a^2 +ab +3a

What procedure might one use to solve percent problems using proportions ?

Answers

Answer:

Proportions and percent

Hi, hiw do we do this question?​

Answers

[tex]\displaystyle \int\sec x\:dx = \ln |\sec x + \tan x| + C[/tex]

Step-by-step explanation:

[tex]\displaystyle \int\sec x\:dx=\int\sec x\left(\frac{\sec x+ \tan x}{\sec x + \tan x}\right)dx[/tex]

[tex]\displaystyle = \int \left(\dfrac{\sec x\tan x + \sec^2x}{\sec x + \tan x} \right)dx[/tex]

Let [tex]u = \sec x + \tan x[/tex]

[tex]\:\:\:\:\:\:du = (\sec x\tan x + \sec^2x)dx[/tex]

where

[tex]d(\sec x) = \sec x\tan x\:dx[/tex]

[tex]d(\tan x) = \sec^2x\:dx[/tex]

[tex]\displaystyle \Rightarrow \int \left(\frac{\sec x\tan x + \sec^2x}{\sec x + \tan x}\right)\:dx = \int \dfrac{du}{u}[/tex]

[tex]= \ln |u| + C = \ln |\sec x + \tan x| + C[/tex]

Suppose you are conducting a study to determine if women are better drivers than men. You send your survey to over 1000 students on your campus and 5 students respond that women are better drivers and 4 students respond that women are not better drivers. What is the sample proportion for women as the better drivers using the large-sample method?

Answers

Answer:

555.56

Step-by-step explanation:

Purpose of the study:  To determine if women are better drivers than men.

Survey or Opinion population:  1,000

You are experimenting on 9 out of a thousand opinions.

5 of these opinions are that women are better drivers

4 of these opinions are that women are not better drivers

You want to know the sample (full sample size is 9) proportion for women as better drivers; using the large sample method. This method is also called the asymptotic method.

This involves approximating the desired statistic, with just a small fraction of the population; in this case, 9/1000.

This approximation will get more and more accurate as sample size increases and you know that a larger sample size gives a better representation and interpretation of the population preference!

So using ratio, the sample proportion for women as the better drivers is given by:

5/9 x 1000   = 555.56 opinions

Which table shows a proportional relationship between x and y?
OA.
X
у
N
4
3
.6
4
9
ОВ.
X
y
3
4
9
16
15
20
C.
x
у
12
4. 5
15
6
18
D.
х
y
1
4
N
00
3
15

Answers

C is the answer. Hope this helps

Find the product :
1) 6/10 × 10/6 × 5/9
2) 6/10 × 4/3 × 10/20​

Answers

Hello!

1) 6/10 × 10/6 × 5/9 = 1/10 × 10 × 5/9 = 1 × 5/9 = 5/9 or 0,5

2) 6/10 × 4/3 × 10/20 = 6 × 4/3 × 1/20 = 2 × 4 × 1/20 = 2 × 1/5 = 2/5 or 0,4

Good luck! :)

Answer:

1) 5/9

2) 2/5

Explanation:

1) 6/10 × 10/6 × 5/9=

Multiply all the denominators and all the numerators then simplify= 300/540 = 5/9

2)  6/10 × 4/3 × 10/20=

Multiply all the denominators and all the numerators then simplify= 240/600 = 2/5

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