Please help, I really need this

Answer:

Range → {y| y ≥ -11}

Step-by-step explanation:

Range of a function is the set of of y-values.

Given function is,

f(x) = 2x² + 6x - 8

By converting this equation into vertex form,

f(x) = [tex]3(x^2+2x-\frac{8}{3})[/tex]

     = [tex]3(x^2+2x+1-1-\frac{8}{3})[/tex]

     = [tex]3[(x+1)^2-\frac{11}{3}][/tex]

     = [tex]3(x+1)^2-11[/tex]

Vertex of the parabola → (-1, -11)

Therefore, range of the function will be → y ≥ -11

The range of the function f(x) = 3x² + 6x - 8 is {y|y ≥ -11}

The range of a function is the set of output values of the function

Since f(x) = 3x² + 6x - 8, we differentiate f(x) = y with respect to x to find the value of x that makes y minimum.

So, df(x)/dx = d(3x² + 6x - 8)/dx

= d(3x²)/dx + d6x/dx - d8/dx

= 6x + 6 + 0

= 6x + 6

Equating the experssion to zero, we have

df(x)/dx = 0

6x + 6 = 0

6x = -6

x = -6/6

x = -1

From the graph, we see that this is a minimum point.

So, the value of y = f(x) at the minimum point is that is a t x = - 1 is

y = f(x) = 3x² + 6x - 8

y = f(-1) = 3(-1)² + 6(-1) - 8

y = 3 - 6 - 8

y = -3 - 8

y = -11

Since this is a minimum point for the graph, we have that y ≥ -11.

So, the range of the function is {y|y ≥ -11}

So, the range of the function f(x) = 3x² + 6x - 8 is {y|y ≥ -11}

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Given:

The cost function is:

[tex]C(x)=0.28x^2-0.7x+1[/tex]

where C(x) is the cost per hour in millions of dollars and x is the number of items produced per hour in thousands.

To find:

The minimum production cost.

Solution:

We have,

[tex]C(x)=0.28x^2-0.7x+1[/tex]

It is a quadratic function with positive leading efficient. It means it is an upward parabola and its vertex is the point of minima.

If a quadratic function is [tex]f(x)=ax^2+bx+c[/tex], then the vertex of the parabola is:

[tex]\text{Vertex}=\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)[/tex]

In the given function, [tex]a=0.28, b=-0.7, c=1[/tex]. So,

[tex]-\dfrac{b}{2a}=-\dfrac{-0.7}{2(0.28)}[/tex]

[tex]-\dfrac{b}{2a}=1.25[/tex]

Putting [tex]x=1.25[/tex] in the given function to find the minimum production cost.

[tex]C(x)=0.28(1.25)^2-0.7(1.25)+1[/tex]

[tex]C(x)=0.28(1.5625)-0.875+1[/tex]

[tex]C(x)=0.4375+0.125[/tex]

[tex]C(x)=0.5625[/tex]

Therefore, the minimum production cost is 0.5625 million dollars.

Answer:

The minimum cost is 0.5625.

Step-by-step explanation:

The cost function is

C(x) = 0.28x^2 - 0.7 x + 1

Differentiate with respect to x.

[tex]C = 0.28x^2 - 0.7 x + 1\\\\\frac{dC}{dt} = 0.56 x - 0.7\\\\\frac{dC}{dt} = 0\\\\0.56 x - 0.7 = 0\\\\x = 1.25[/tex]

The minimum value is

c = 0.28 x 1.25 x 1.25 - 0.7 x 1.25 + 1

C = 0.4375 - 0.875 + 1

C = 0.5625

Answer:

Given the proposed interrogate, as well as the graph provided, the correct answer is B. Y = 1/2 x + 4

Step-by-step explanation:

To evaluate such, a comprehension of linear Cartesian planes are obligated:

Slopes = rise/run

X- intercept: The peculiar point in which linear data is observed to intersect the x-axis.

Y- intercept: The peculiar point in which linear data is observed to intersect the y-axis.

Slope: 1/2 as for every individual space endeavored, a space of 2 to the right is required.

Y- intercept: (4,0)

Thus, the ameliorated answer to such interrogate is acknowledged as B. Y = 1/2 x + 4.

*I hope this helps.

For this question it’s asking for it in slope intercept form. So all you need to find is the slope and the y intercept.To find the y int look at where the line passes y. In this case it is y=4, then find slope by finding change in y/ change once which is 1/2, so you get y=1/2x+4

Answer:

Step-by-step explanation:

We have:

Substitute x and solve for y:

Find x:

Tom's speed is 12.5 mph

Carl's speed is 7.5 mph

Now

From eq(2)

From eq(1)

Adding these recent two

Putting in eq(1)

Answer:

you forgot to add an image I dont know what angles your talking about

Step-by-step explanation:

use the equation of the straight line

y-y1=m (x-x1)

y-2=-2(x+4)

y-2= -2x-8

y= -2x-8+2

y= -2x-6

I hope this helps

Answer:

C

Step-by-step explanation:

you can divide y/x

1.2/4= 0.3

2.4/8= 0.3

3.9/13= 0.3

9514 1404 393

Answer:

  y = 16

Step-by-step explanation:

Perhaps you want to solve ...

  10 +√y = 14

  √y = 4 . . . . . . subtract 10

  y = 4² = 16 . . . square both sides

Saving percentage=100-80=20%

Saving amount:-

[tex]\\ \sf\longmapsto 4300\times 20\%[/tex]

[tex]\\ \sf\longmapsto 4300\times \dfrac{20}{100}[/tex]

[tex]\\ \sf\longmapsto 43\times 20[/tex]

[tex]\\ \sf\longmapsto 860[/tex]

[tex]\\ \sf\longmapsto 12\times 860[/tex]

[tex]\\ \sf\longmapsto Rs10320[/tex]

Step-by-step explanation:

i think this will be help you

9514 1404 393

Answer:

  120 days

Step-by-step explanation:

Using the formula for simple interest, we can solve for t:

  I = Prt

  t = I/(Pr) = 608/(22800×.08) = 608/1824 = 1/3 . . . . year

For "ordinary interest", a year is considered to be 360 days, so 1/3 year is ...

  (1/3)(360 days) = 120 days

It will take 120 days for the loan to earn 608 in interest.

Answer:

60 sq in

Step-by-step explanation:

Perimeter = 2l + 2w

If l = w+4

Perimeter = 2(w+4) + 2w

Perimeter = 4w+8

32 = 4w + 8

24 = 4w

6 = w

If w = 6, l = 6+4 = 10

Area = l * w

Area = 10 * 6

Area = 60

Answer:

How should we proceed with this question

f(x) = 2x³ - 3x² + 7

f(-1) = 2(-1)³ - 3(-1)² + 7

=> f(-1) = 2(-1) - 3(1) + 7

=> f(-1) = -2 -3 + 7

=> f(-1) = 2

f(1) = 2(1)³ - 3(1)² + 7

=> f(1) = 2(1) - 3(1) + 7

=> f(1) = 2 -3 + 7

=> f(1) = 6

f(2) = 2(2)³ - 3(2)² + 7

=> f(2) = 2(8) - 3(4) + 7

=> f(2) = 16 - 12 + 7

=> f(2) = 11

Answer:

4 is E, 5 is A

Step-by-step explanation:

4) Divide both sides by 5 to get |2x + 1| = 11, then solve for x to get 5 and -6.

5) Add 7 to both sides to get ½|4x - 8| = 10. Multiply both sides by 2 to get |4x - 8| = 20, then solve for x to get 7 and -3.

Answer:

1197 miles.

Speed(s) = 63 mph

Time(t) = 19 hours

Distance(d) = ?

We know,

D = S × T

= 63 × 19

= 1197 miles

Answer:

[tex]M = \log(10000)[/tex]

Step-by-step explanation:

Given

[tex]M = \log(\frac{I}{I_o})[/tex]

[tex]I = 10000I_o[/tex] ---- intensity is 10000 times reference earthquake

Required

The resulting equation

We have:

[tex]M = \log(\frac{I}{I_o})[/tex]

Substitute the right values

[tex]M = \log(\frac{10000I_o}{I_o})[/tex]

[tex]M = \log(10000)[/tex]

The equation that calculates the magnitude of an earthquake with an intensity 10,000 times that of the reference earthquake is A. M = ㏒10000

Since the magnitude of an earthquake on the Richter sscale is M = ㏒(I/I₀) where

Since we require the magnitude when the intensity is 10,000 times the reference intensity, we have that I = 10000I₀.

So, substituting these into the equation for M, we have

M = ㏒(I/I₀)

M = ㏒(10000I₀./I₀)

M = ㏒10000

So, the equation that calculates the magnitude of an earthquake with an intensity 10,000 times that of the reference earthquake is A. M = ㏒10000

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Step-by-step explanation:

6 carpets=1month

10 carpets=?

1month=31 days

10 /6*31

51

Step-by-step explanatio

Answer:

16.17 cm

Step-by-step explanation:

The solution triangle attached below :

To obtain BC ; we use the sine rule ;

a/ sin A = b / sin B

A = (180 - (68 + 24))

A = 180 - 92

A = 88°

a / Sin 88 = 15 / sin 68

Cross multiply :

(a * sin 68) = (15 * sin 88)

a = 14.990862 / sin 68

a = 16.168165

a = 16.168 cm

Answer:

3.51%

Step-by-step explanation:

From the given information:

For the first stream, the present value can be computed as:

[tex]= 100 +\dfrac{200}{(1+i)^n}+ \dfrac{300}{(1+i)^{2n}}[/tex]

Present value for the second stream is:

[tex]=\dfrac{600}{(1+i)^{10}}[/tex]

Relating the above two equations together;

[tex]100 +\dfrac{200}{(1+i)^n}+ \dfrac{300}{(1+i)^{2n}} =\dfrac{600}{(1+i)^{10}}[/tex]

consider [tex]v = \dfrac{1}{1+i}[/tex], Then:

[tex]\implies 100+200v^n + 300v^{2n} = 600 v^{10}[/tex]

where:

[tex]v^n = 0.75941[/tex]

Now;

[tex]\implies 100+200(0.75941) + 300(0.75941))^2 = 600 (v)^{10}[/tex]

[tex](v)^{10} = \dfrac{100+200(0.75941) + 300(0.75941))^2 }{600}[/tex]

[tex](v)^{10} = 0.7082[/tex]

[tex](v) = \sqrt[10]{0.7082}[/tex]

v = 0.9661

Recall that:

[tex]v = \dfrac{1}{1+i}[/tex]

We can say that:

[tex]\dfrac{1}{1+i} = 0.9661[/tex]

[tex]1 = 0.9661(1+i) \\ \\ 0.9661 + 0.9661 i = 1 \\ \\ 0.9661 i = 1 - 0.9661 \\ \\ 0.9661 i = 0.0339 \\ \\ i = \dfrac{0.0339}{0.9661} \\ \\ i = 0.0351 \\ \\ \mathbf{i = 3.51\%}[/tex]

Answer:

Step-by-step explanation:

gradient is essentially the slope of a straight line.  

Use (y2-y1)/(x2-x1):

(q-0)/(0-6) = -3/2

q = 9

Answer:

Here is your answer.....

Hope it helps you....

Answer: Volume of Cylinder A is                          pi times the area of the base times the height

                                                             π r2 h = (3.1416)(4)(4)(15) = 753.98 ft3

Volume of Cylinder B is likewise             pi times the area of the base times the height

                                                             π r2 h = (3.1416)(6)(6)(7)   = 791.68 ft3

After pumping all of Cyl A into Cyl B

there will remain empty space in B         791.68 – 753.98 = 37.7 ft3  

The percentage this empty space is

of the entire volume is                            37.7 / 791.68 = 0.0476 which is 4.8% when rounded to the nearest tenth  

.

Step-by-step explanation: I hope that help you.

Note: you may not need to type in the percent sign.

===========================================================

Explanation:

Let's find the volume of water in container A.

Use the cylinder volume formula to get

V = pi*r^2*h

V = pi*5^2*8

V = 200pi

The full capacity of tank A is 200pi cubic feet, and this is the amount of water in the tank since it's completely full.

We have 200pi cubic feet of water transfer to tank B. We'll keep this value in mind for later.

-----------------------

Now find the volume of cylinder B

V = pi*r^2*h

V = pi*6^2*6

V = 216pi

Despite being shorter, tank B can hold more water (since it's more wider).

-----------------------

Now divide the results of each section

(200pi)/(216pi) = 200/216 = 25/27 = 0.9259 = 92.59%

This shows us that 92.59% of tank B is 200pi cubic feet of water.

In other words, when all of tank A goes into tank B, we'll have tank B roughly 92.59% full.

This means the percentage of empty space (aka air) in tank B at this point is approximately 100% - 92.59% = 7.41%

Then finally, this value rounds to 7.4% when rounding to the nearest tenth of a percent.

Answer:

the above is the answer

hope this is helpful

Answer:

Option (1)

Step-by-step explanation:

Fundamental theorem of Algebra states degree of the polynomial defines the number of roots of the polynomial.

8 roots means degree of the polynomial = 8

Option (1)

f(x) = (3x² - 4x - 5)(2x⁶- 5)

When we multiply (3x²) and (2x⁶),

(3x²)(2x⁶) = 6x⁸

Therefore, degree of the polynomial = 8

And number of roots = 8

Option (2)

f(x) = (3x⁴ + 2x)⁴

By solving the expression,

Leading term of the polynomial = (3x⁴)⁴

                                                     = 81x¹⁶

Therefore, degree of the polynomial = 16

And number of roots = 16

Option (3)

f(x) = (4x² - 7)³

Leading term of the polynomial = (4x²)³

                                                    = 64x⁶

Degree of the polynomial = 6

Number of roots = 6

Option (4)

f(x) = (6x⁸ - 4x⁵ - 1)(3x² - 4)

By simplifying the expression,

Leading term of the polynomial = (6x⁸)(3x²)

                                                     = 18x¹⁰

Degree of the polynomial = 10

Therefore, number of roots = 10

Answer:

<T = 81

x = 10, angle = 60

Angle 5 and Angle 3 are vertical angles.  They are acute angles

Step-by-step explanation:

Supplementary angles add to 180

(7x+11) + (8x+19) = 180

Combine like terms

15x + 30 = 180

Subtract 30 from each side

15x +30-30 = 180-30

15x= 150

Divide by 15

15x/15 = 150/15

x = 10

We want angle T

T = 7x+11 = 7(10)+11 = 70+11 = 81

The two angles add to 90

5x+10 + 30 = 90

Combine like terms

5x+40 = 90

5x+40-40 = 90-40

5x = 50

Divide by 5

5x/5 = 50/5

x=10

5x+10 = 5(10) +10 = 50+10 = 60

Angle 5 and Angle 3 are vertical angles.  They are acute angles

Step-by-step explanation:

here are the answers for your problems

Answer:

see explanation

Step-by-step explanation:

Using the identities

tan x = [tex]\frac{sinx}{cosx}[/tex] , sin²x = 1 - cos²x

sin2x = 2sinxcosx

Consider left side

cosθ × sin2θ

= [tex]\frac{sin0}{cos0}[/tex] × 2sinθcosθ ( cancel cosθ )

= 2sin²θ

= 2(1 - cos²θ)

= 2 - 2cos²θ

= right side , then established

Answer:

No

Explanation:

A coin which has a head and a tail has 1/2 probability of each which is a 50% chance of getting either a head or a tail. This means that given two sides of a coin, probability looks at the number of favorable outcomes and total number of outcomes, a formula that reflects a pattern seen in past experiences. Probability isn't absolute but relative. When we say there is a 50% chance of getting a head in a coin flip, it is relative to past experiences but doesn't assure of particular future occurrences regarding the coin flip.

Step-by-step explanation:

Just using the Pythagoras theorem

Answer: 13.5 Okay! Here's the method count the legs of the right triangle

The formula we'll use will be

A^2 + B^2 = C^2

In this case we're counting by twos

The base is 11 so we times it by itself =110

The leg is 8.5 so we going to times itself to make 72.25 add those together so 110+ 72.25 = 182.25 then we \|-----

182.25

Then you have got ur answer of 13.5

Step-by-step explanation: